what is 3/5 divide 1/3

Answer: B.12 years

Step-by-step explanation:

Answer:

No

Step-by-step explanation:

The relation given as represented by the table of values is definitely not a function. This is because, 1 domain value (x-value), is having two range values (y-values), 2 and 5, that are assigned to it.

A function cannot have two y-values assigned to one x-values.

Answer:

1.48 miles

Step-by-step explanation:

If the trail is 14.8 miles and Rita has hiked 1/10 of it. Then just multiply 14.8 by 1/10.

14.8 * 1/10 = 1.48 miles.

Answer:

1.48

Step-by-step explanation:

I know the answer is correct

Answer:

42.25

Step-by-step explanation:

Answer:

[tex]\frac{169}{4}[/tex] or 42.25

Step-by-step explanation:

If you turn the fractions into decimals they become easier to multiply.

1)  3.25 x 6.50 = 21.25

2) 21.25 x 2 = 42.25

Answer:

m = .45

p = .45w

______

.45 = 9/20

Explanation:

m is the rate of change equal to the price over the weight or p/w.

Because this relationship is proportional, each weight divided by its corresponding price must equal the same fraction because it is constant.

We can prove this by dividing each price by its weight to find this proportion.

1.35/3 = 2.7/6 = 27/60 = 9/20 = 0.45

1.71/3.8 = 171/380 = 9/20 = 0.45

2.34/5.2 = 234/520 = 117/260 = 9/20 = 0.45.

Since equal the same value, this means that 9/20 or .45 is our proportion.

in terms of p = mw

p/w = 9/20.

p = mw → p/w = m → m = p/w = .45 .

Thus, p = .45w,

so m = .45.

Which means that for every .45 or 9/20 w or weight, there is a price of $1.

Answer: 71

Step-by-step explanation: 100x (5\7) = 71.4

Answer:

71.5

Step-by-step explanation:

5/7 of 100=(5×100)÷7=500÷7=71.5

Answer:

angle RQS

Step-by-step explanation:

Answer:

 [tex]\frac{df}{dr} = (-r) + log(\frac{1}{r} )( 2 r)[/tex]

Step-by-step explanation:

Explanation

Given function f(r) = r² log r  ....(i)

Apply derivatives formula

              [tex]\frac{d}{dx} UV = U^{l} V + V^{l} U[/tex]

             [tex]\frac{d}{dx}x^{n} = nx^{n-1}[/tex]

            [tex]\frac{d}{dx}log x = \frac{1}{x}[/tex]

Differentiating equation (i) with respective to 'r' , we get

                [tex]\frac{df}{dr} = r^{2} (\frac{1}{\frac{1}{r} } )\frac{d}{dr} (\frac{1}{r } )+ log(\frac{1}{r} ) 2 r[/tex]

                [tex]\frac{df}{dr} = r^{2} (\frac{1}{\frac{1}{r} } )(\frac{-1}{r^{2} } )+ log(\frac{1}{r} ) 2 r[/tex]

Final answer:-                

               [tex]\frac{df}{dr} = (-r) + log(\frac{1}{r} )( 2 r)[/tex]

Answer:

11/4

29/6

32/5

Step-by-step explanation:

Answer: 11/4, 29/6, 32/5

Step-by-step explanation:

This is going to help trust me

X=22

14 plus 8 gives you x

[tex]\frac{x}{20} =\frac{14}{8} \\x=\frac{14}{8} \times 20=35[/tex]Answer:

35

Step-by-step explanation:

Answer:

4, 7 ,2

Step-by-step explanation:

Answer: a is equal to b

Step-by-step explanation:

Answer:

a is parallel to b

Step-by-step explanation:

Answer:

you're scale is 1.6666667

Step-by-step explanation:

because if you do 30 decided by 18 it gives u 1.6666667

Answer:

944 cubic feet

Step-by-step explanation:

You need to take the area of the figure separately.

[tex]8*10*5=400[/tex]

[tex]17*8*4=544[/tex]

400 + 544 =944

Answer:

Rick sells each guitar for 90$

Answer:

20,since each kilo of rice fills two bags so he i'll have 40 bags.

Answer:

6. 225 feet in 3 minutes = 75 feet in 1 minute (slower)

   360 feet in 5 minutes = 72 feet in 1 minute

7. $4 for 5 ounces = $0.80 for 1 ounce (most expensive)

   $14 for 20 ounces = $0.70 for 1 ounce

8. 72 people in 6 hours = 12 people in 1 hour

    117 people in 9 hours = 13 people in 1 hour (greater rate per hour)

Answer:

A = 369 feet in 5 minutes B = $4 for 5 ounces C = 117 people in 9 hours

Answer:

B. -8+10

Step-by-step explanation: keep the -8 change - sign to +sign then change -10 to 10 .

Hope it helps :)

Answer:

0

6

Step-by-step explanation:

<3

The ranges are:

f(x): {y | y ≤ infinity}

g(x): {y | y ≤ infinity}

A relation between a collection of inputs and outputs is known as a function. A function is a connection between inputs in which each input is connected to precisely one output. Each function has a range, co-domain, and domain.

For the function f(x) = (4/5)x, any input value of x will be multiplied by 4/5 and produce a corresponding output value y.

Since the fraction 4/5 is less than 1, the output values of f(x) will always be smaller than the input values of x.

Therefore, the range of f(x) will be all real numbers less than or equal to the greatest possible output value.

The greatest possible output value will occur when x is the greatest possible input value, which is infinity. So, the range of f(x) is:

f(x): {y | y ≤ infinity}

For the function g(x) = (4/5)x + 6, any input value of x will be multiplied by 4/5, then 6 will be added to the result to produce a corresponding output value y.

The fraction 4/5 is less than 1, so the output values of g(x) will always be less than the input values of x plus 6.

Therefore, the range of g(x) will be all real numbers less than or equal to the greatest possible output value, which occurs when x is infinity. So, the range of g(x) is:

g(x): {y | y ≤ infinity}

To learn more about the function;

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Answer:

The slope of this equation is 11/2. The point is (1/2, 0)

Step-by-step explanation:

I hope this is the right answer, good luck!

Answer:

y = -3x + 7

Step-by-step explanation:

[tex]y = mx + b[/tex]

m = slope

b = y intercept

eq:

[tex]y = - 3x + 7[/tex]

Answer:

how bad do u need this answer 1 through 10

Answer: After 19 days, the dragon filled half of the cave.

Step-by-step explanation:

The dragon doubled in size every day and after 20 days he filled the cave.

So, one day before, the dragon occupied half of the cave.

20 - 1 = 19  [days]

After 19 days did the dragon half-fill the cave.

The dragon doubles in size every day, and after 20 days, it completely fills the cave.

To find out when the dragon half-filled the cave, we need to determine how many days it took for the dragon to reach half of the cave's capacity.

we know that,

On the 20th day, the dragon filled the entire cave.

and, The dragon doubled in size every day.

so, we have,

On the 19th day, the dragon's size would have been half of what it was on the 20th day.

On the 18th day, the dragon's size would have been half of what it was on the 19th day.

And so on...

We can see that every day before the 20th day, the dragon's size was halved.

So, on the 19th day, the dragon's size was half of the size it was on the 20th day.

Therefore, on the 19th day, the dragon half-filled the cave, and on the 20th day, it filled the entire cave.

Hence, After 19 days did the dragon half-fill the cave.

To learn more on subtraction click:

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Answer:

13 away

i used my fingers

Answer:

12

Step-by-step explanation:

-8_-7_-6_-5_-4_-3_-2_-1_0_1_2_3_4

Just count he bottom lines

Answer:

The triangles are congruent

Step-by-step explanation:

Given

[tex]P(5,-4), Q(-3, 7), R(0, 2), X(-2,-1), Y(9, 7), Z(3, 2)[/tex]

Required

Determine if PQR = XYZ

To do this, we make use of distance formula.

[tex]D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

For PQ:

[tex](x_1,y_1) = (5,-4)[/tex] and [tex](x_2,y_2) = (-3,7)[/tex]

So:

[tex]PQ = \sqrt{(-3-5)^2+(7-(-4))^2}[/tex]

[tex]PQ = \sqrt{(-8)^2+(7+4)^2}[/tex]

[tex]PQ = \sqrt{(-8)^2+(11)^2}[/tex]

[tex]PQ = \sqrt{64+121}[/tex]

[tex]PQ = \sqrt{185}[/tex]

For XY:

[tex](x_1,y_1) = (-2,-1)[/tex]

[tex](x_2,y_2) = (9,7)[/tex]

So:

[tex]XY = \sqrt{(9-(-2))^2+(7-(-1))^2}[/tex]

[tex]XY = \sqrt{(9+2)^2+(7+1)^2}[/tex]

[tex]XY = \sqrt{(11)^2+(8)^2}[/tex]

[tex]XY = \sqrt{121+64}[/tex]

[tex]XY = \sqrt{185}[/tex]

For QR:

[tex](x_1,y_1) = (-3,7)[/tex] and [tex](x_2,y_2) = (0,2)[/tex]

So:

[tex]QR = \sqrt{(0-(-3))^2 + (2-7)^2}[/tex]

[tex]QR = \sqrt{(0+3)^2 + (-5)^2}[/tex]

[tex]QR = \sqrt{(3)^2 + 25}[/tex]

[tex]QR = \sqrt{9 + 25}[/tex]

[tex]QR = \sqrt{34}[/tex]

For YZ:

[tex](x_1,y_1) = (9,7)[/tex] and [tex](x_2,y_2) = (3,2)[/tex]

So:

[tex]YZ = \sqrt{(3-9)^2+(2-7)^2}[/tex]

[tex]YZ = \sqrt{(-6)^2+(-5)^2}[/tex]

[tex]YZ = \sqrt{36+25}[/tex]

[tex]YZ = \sqrt{61}[/tex]

For PR:

[tex](x_1,y_1) = (5,-4)[/tex] and [tex](x_2,y_2) = (0,2)[/tex]

So:

[tex]PR = \sqrt{(0-5)^2+(2-(-4))^2}[/tex]

[tex]PR = \sqrt{(-5)^2+(2+4)^2}[/tex]

[tex]PR = \sqrt{(-5)^2+(6)^2}[/tex]

[tex]PR = \sqrt{25+36}[/tex]

[tex]PR = \sqrt{61}[/tex]

For XZ:

[tex](x_1,y_1) = (-2,-1)[/tex] and [tex](x_2,y_2) = (3,2)[/tex]

So:

[tex]XZ = \sqrt{(3-(-2))^2+(2-(-1))^2}[/tex]

[tex]XZ = \sqrt{(3+2)^2+(2+1)^2}[/tex]

[tex]XZ = \sqrt{5^2+3^2}[/tex]

[tex]XZ = \sqrt{34}[/tex]

From the calculations above:

[tex]PQ = XY = \sqrt{185[/tex]

[tex]QR = XZ = \sqrt{34[/tex]

[tex]PR = YZ = \sqrt{61[/tex]

Hence, the triangles are congruent base on SSS (Sides- Sides-Sides)

Answer:

SOOOOOO

Step-by-step explanation:

YOU MAKE  IT 1/5 + -2/3

INTOOO

3/15+-10/15

THENNNN

YOU ADD THEMMM

AND UU GETTTT

-7/15

SOOO THAT UR ANSWER ITSS A THE FIRST ONE

-7/15

Answer:

yes what that guy said is right