A toy car, initially travelling in a straight line at 30.0 cm/s, slows down with a constant linear acceleration of 3.0 cm/s2. How much time passes before the toy car comes to a halt?

Answer:

A

Explanation:

I know that it's true

Answer:

Runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole

Explanation:

We can find when their paths will cross as follows:

[tex] X_{f} = X_{0} + v_{0}t + \frac{1}{2}at^{2} [/tex]

Where:

[tex]X_{f}[/tex] is the final position

[tex]X_{0}[/tex] is the initial position

v₀ is the initial speed

t is the time

a is the acceleration = 0 (since they are running with a constant velocity)

When their paths cross we have:

[tex]X_{fA}+X_{fB}=5.8+4.9=10.7 km[/tex]

[tex]V_{A}t+V_{B}t=10.7[/tex]

[tex]8.6t+7.1t=10.7[/tex]

[tex]t = 0.68 h[/tex]

Now we can find the final distance of each runner.

[tex]X_{fA}=V_{A}*0.68[/tex]

[tex]X_{fA}=8.6*0.68 km[/tex]

[tex]X_{fA}=5.85 km[/tex]

[tex]X_{fB}=V_{B}*0.68[/tex]

[tex]X_{fB}=7.1*0.68[/tex]

[tex]X_{fB}=4.83 km[/tex]

Therefore, runner A will be 0.05 km from the flagpole, and runner B will be 0.07 km from the flagpole.

I hope it helps you!

Answer:

a correct

Explanation:

a hypothesis is a supposition made of a basis of limited evidence

Answer:

inner planets are the first couple of planets by the sun so for the character for the internal planets are what they are like are they made up of gas, rock/solid stuff and the atomsphere is like is it toxic or safe to breath

Answer:

It will roll up to its initial height from which it rolled from on the first hill

Explanation:

The given information are;

The height from which the ball is rolled = 3 feet[

The equation of the potential energy of the ball as it rolled down the frictionless inclined plane is given by the following equation;

m × g × h₁ = 1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r]

Where;

m = The mass of the ball

h = The from which the ball is rolled down

v = The velocity of the ball

r = The radius of the ball

Therefore, all the potential energy, m × g × h, is converted into kinetic energy when the ball reached the ground

Similarly, as the ball rolls up on the other side, by the principle of energy conservation, all the kinetic energy is transformed into potential energy as follows

1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₂, therefore, we have;

1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₁ =  m × g × h₂

Therefore since m × g × h₁ =  m × g × h₂, then h₁ = h₂, the ball rises to the same height it started rolling from on the first hill.

Answer:

The shortest possible stopping distance of the car is 175.319 meters.

Explanation:

In this case we see that driver use the brakes to stop the car by means of kinetic friction force. Deceleration of the car is directly proportional to kinetic friction coefficient and can be determined by Second Newton's Law:

[tex]\Sigma F_{x} = -\mu_{k}\cdot N = m \cdot a[/tex] (Eq. 1)

[tex]\Sigma F_{y} = N-m\cdot g = 0[/tex] (Eq. 2)

After quick handling, we get that deceleration experimented by the car is equal to:

[tex]a = -\mu_{k}\cdot g[/tex] (Eq. 3)

Where:

[tex]a[/tex] - Deceleration of the car, measured in meters per square second.

[tex]\mu_{k}[/tex] - Kinetic coefficient of friction, dimensionless.

[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.

If we know that [tex]\mu_{k} = 0.0735[/tex] and [tex]g = 9.807\,\frac{m}{s^{2}}[/tex], then deceleration of the car is:

[tex]a = -(0.0735)\cdot (9.807\,\frac{m}{s^{2}} )[/tex]

[tex]a = -0.721\,\frac{m}{s^{2}}[/tex]

The stopping distance of the car ([tex]\Delta s[/tex]), measured in meters, is determined from the following kinematic expression:

[tex]\Delta s = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex] (Eq. 4)

Where:

[tex]v_{o}[/tex] - Initial speed of the car, measured in meters per second.

[tex]v[/tex] - Final speed of the car, measured in meters per second.

If we know that [tex]v_{o} = 15.9\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex] and [tex]a = -0.721\,\frac{m}{s^{2}}[/tex], stopping distance of the car is:

[tex]\Delta s = \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(15.9\,\frac{m}{s} \right)^{2}}{2\cdot \left(-0.721\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\Delta s = 175.319\,m[/tex]

The shortest possible stopping distance of the car is 175.319 meters.

Answer: Particles in a suspension are usually more than 1,000 nm, while those in a colloid range from 1-1,000 nm. Unlike those in a suspension, particles in a colloid do not separate when sitting still. ... Particles in a suspension can be seen by the naked eye, but those in a colloid must be viewed using a light microscope.

hope this helps:)

Explanation:

Answer:

42 hour

Explanation:

It is given that,

Speed of a car, v = 40 mph

Distance covered by the car, d = 1680 miles

We need to find the time taken by the car to cover this distance. We can find it using the formula of speed which is equal to the distance covered divided by the time taken. Let the time is t.

speed = distance/time taken

[tex]t=\dfrac{d}{s}\\\\t=\dfrac{1680\ \text{miles}}{40\ \text{mph}}\\\\t=42\ \text{hour}[/tex]

Hence, the car will take 42 hours to cover 1680 miles with a speed of 40 mph.

Answer:

We have a mass of 200g (0.2kg) moving at 20m/s

Kinetic Energy KE = ½ mv^2 where m is mass and v is velocity

Actually, v is a vector quantity, so KE = ½ mv•v

The dot product of 2 vectors a and b is abCosθ where θ is the angle between the vectors.

Obviously v•v = v^2 Cos0 = v^2

In this case, we have KE = ½ (0.2)(20^2) = 40kg-m^2/s^2 = 40J

So we have kinetic energy in the amount of 40 Joules.

Explanation:

The right answer is "2.7 J"

Answer explanation:

Remember to convert grams to kilograms first by dividing by 1000.

Kinetic energy

= 1/2 × mass × speed2

= 1/2 × 0.2 kg × (5.2 m/s)^2

= 2.7 J (to 2 sig. fig.)

Hope it helps ✨✨

Answer:

Astrophobia

Explanation:

heop it help

Answer: true

Plz mark brainliest:)

Answer:

True

Explanation:

The term 'plyometrics' is used interchangeably with the term 'jump training'. The technique can be used for training in sports that require explosive movements.

Answer:

Explanation:

1). Distance traveled during the first minute (A-B)

    = Distance from A to C + Distance from C to D + Distance from D to B

    = 40 + 100 + 40

    = 180 m

   Option (4) will be the answer.

2). Displacement after first minute (A-B)

    = Distance from A to B

    = 180 m East

    Option (2) is the answer.

3). Distance traveled during the first 2 minutes (A - B - C)

    = Distance from A to B + Distance from B to C

    = 180 + 140

    = 320 m

    Option (3) will be the answer.

4). Displacement after first 2 minutes (A-B-C)

    = Distance between A and C

    = 40 m towards east

    Option (1) is the answer.

5). Distance traveled during 3 minutes (A-B-C-D)

    = Distance between A to B + Distance between B to C + Distance between C to D

    = 180 + 140 + 100

    = 420 m

   Option (4) is the answer.

6). Displacement after total 3 minutes (A-B-C-D)

    = Distance between A and D

    = Distance between A to C + distance between C to D

    = 40 + 100

    = 140 m

     And the direction is towards East.

     Option (3) is the answer.

Answer:

A

Explanation:

the air is the medium man

Answer:

the desk

Explanation:

Answer:

21.3V

Explanation:

Explanation

E = V + Ir

V = E- Ir

V = 24 - {(24/36) x 4}

V = 21.3V

Answer: C. Trial 3

Explanation:

Trial 1 and 2 equal 1.5, Trial 3 equals 1 and Trial 4 equals 3. Trial 3 is the smallest current .

The trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

To know the trial which generates the smallest current, we need to determine the current in each trial.

Since current I = V/R where V = voltage and R = resistance.

For trial 1, V = 1.5 V and R = 200 Ω

So, I = 1.5 V/200 Ω

= 0.0075 A

= 7.5 mA

For trial 2, V = 1.5 V and R = 100 Ω

So, I = 1.5 V/100 Ω

= 0.015 A

= 15 mA

For trial 3, V = 3 V and R = 200 Ω

So, I = 3 V/200 Ω

= 0.015 A

= 15 mA

For trial 4, V = 3 V and R = 100 Ω

So, I = 3 V/100 Ω

= 0.03 A

= 3 mA

Trial 2 and trial 3 both produce a the smallest current of 15 mA.

So, the trial for which the students would measure the smallest current is the circuit is trial 2 and trial 3.

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Answer:

c) marketing and selling products that use ore materials

Answer:

(a). The relative humidity is 20.57%

(b). The dew point is 79.114°F

(c). It take for the air to reach saturation is 17 hours.

(d). The water is 7.6g/kg.

Explanation:

Given that,

Temperature = 35°

Mixing ratio = 7.6 g/kg

(a). We need to calculate the relative humidity

Using formula of relative humidity

[tex]relative humidity=\dfrac{mixing\ ratio}{36}\times100[/tex]

[tex]relative humidity=\dfrac{7.6}{36.94}\times100[/tex]

[tex]relative humidity=20.57\%[/tex]

(b). We need to calculate the dew point

Using formula of dew point

[tex]dew\ point=T^{\circ}F-\dfrac{(100-relative\ humidity)}{5}[/tex]

Put the value into the formula

[tex]dew\ point=95-\dfrac{100-20.57}{5}[/tex]

[tex]dew\ point=79.114^{\circ}F[/tex]

(c). If the room temperature decreases by 5°C per hour

We need to calculate the time

Using formula of time

[tex]t=\dfrac{T_{a}-increase\ temperature}{5}[/tex]

Put the value into the formula

[tex]t=\dfrac{95-10}{5}[/tex]

[tex]t=17\ hours[/tex]

(d). If the temperature of the room continues to decrease for one more hour,

We need to calculate the how many grams of water vapor

Using given data

The water of 7.6g/kg vapour will have to condense out of air for the maintain relative humidity at 100%

Hence, (a). The relative humidity is 20.57%

(b). The dew point is 79.114°F

(c). It take for the air to reach saturation is 17 hours.

(d). The water is 7.6g/kg.

Answer:

temp: 35° c (95°f)

MR:7.6

SMR: 36.5

RH: 21% (20.82)

Dew Point: 10° C 

5°c per hour: 5 hours for the 35°c air temp to reach the 10°c dew point

1 more hour: Temperature will decrease to 5°c, half the water molecules dewpoint "size" I view it as, and 3.8g/kg of water vapour has condensed out

so

1. 21%

2. 10° C 

3. 5 hours

4. 3.8g/kg

A current of 15 amperes is flowing with a resistance of 0.10 ohms, then the voltage will be equal to 1.5 volts.

When put in an electromagnetic field, charged matter experiences a force due to the fundamental property of electric charge. Positive or negative electrical ions are possible.

When two charges are in opposition to one another, they repel one another. The term "neutral" refers to an object that has no net charge. The early understanding of the way charged particles interact is now referred to as classical electrodynamics, and it is still true for issues that do not demand taking into account quant phenomena.

Electrical charge is a preserved attribute, meaning that the net charge of an isolated system—that is, the sum of the positive and negative charges—cannot change. Particles at the subatomic level carry an electric charge.

As per the data given in the question,

Current, I = 15 A

Resistance, R = 0.10 ohms

Then, the voltage (V) will be,

V = RI

V = 15 × 0.10

V = 1.5 volts.

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Answer:

According to Newton's third law of motion, the reaction force is equal to the action force.

Explanation:

Newton's third law of motion states that for every action there is an equal and opposite reaction. This means that if one object exerts a force on a second object, the second object exerts an equal force in the opposite direction. When Plate X pushes on Plate Y with the action force (Fx), Plate Y must push back with an equal force (Fy).

Therefore, the best explanation is that according to Newton's third law of motion, the reaction force is equal to the action force.

For every action, there has equal and opposite reaction - this statement best describes the action and reaction forces on the plates.

As a result of this interaction, there are two forces: one from plate X and one from plate Y. The third law of motion of Newton deals with these two forces, which are referred to as action and reaction forces. Newton's third law is officially expressed as follows: There is an equal and opposite reaction to every action.

The implication of the statement is that there are always two forces acting on the two interacting objects. The force acting on the first object is equal in size to the force acting on the second. The force acting on the first object is acting in the opposite direction to the force acting on the second object. Force pairs—equal and opposing action-reaction force pairs—always exist in pairs.

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Answer:

wave speed =344.1 m/s

using v=fΠ

where v is the speed

The wave speed will be 344.1 m/sec. The wave speed is found as the product of the wavelength and the frequency of the wave.

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The given data in the problem is;

v is the speed = ?

f is the frequency= 370 Hz

λ is the wavelength of the wave=0.96 m

The relationship between the wave's wavelength, frequency, and speed is given as;

wavelength = speed of wave / frequency

[tex]\rm \lambda = \frac{v}{f} \\\\ v = \lambda \times f \\\\ v = 0.93 \times 370 \ Hz \\\\ v= 344.1 \ m/sec[/tex]

Hence, the wave speed will be 344.1 m/sec.

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If you increased the amount of force applied on your chosen Item, rate of increase of  its velocity with time will increase.

An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.

The definition of force in physics is: the push or pull on a mass-containing item changes its velocity.

An external force is an agent that has the power to alter the resting or moving condition of a body. It has a direction and a magnitude. The application of force is the location at which force is applied, and the direction in which the force is applied is known as the direction of the force.

So, if you increased the amount of force applied on your chosen Item, its acceleration will be increased and rate of increase of velocity with time will increase.

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Answer:

situational irony

Explanation:

Based on the scenario being described, this seems to be an example of situational irony. That is because the irony in this scenario is that Tim's most popular and world-renown cooking creations are made of meat but Tim is a vegan and does not consume meat, which all revolves around the situation that Tim is in. Since he can't enjoy the meals with his fans because he does not eat the ingredients in his own creation. Therefore, being specific to the situation that Tim has created.

Answer:

384,000

Explanation:

Time taken by light to travel from earth to moon t=1.28s

Let us assume that the speed of light = c

So, the distance traveled by light in this time = c x t

this will be the distance which light traveled to reach moon, so this will be the distance between earth and moon.

The speed of light is 300000 km/s

By putting the values

we get

Distance = c x t

= 300000 x 1.28 km

=384000 km

Answer:

electrons will flow from lower (lithium) to higher (zinc)

You can make a stronger battery by having a larger electron affinity difference.

Hope this helps \(-._.-)/

Answer:

v = gt

Explanation:

From the question given, we obtained the following information:

Initial velocity (u) = 0 m/s

Acceleration due to gravity (g) = g

Time (t) = t

Final velocity (v) =.?

Thus, we can obtain the velocity as illustrated below:

v = u + gt

v = 0 + gt

v = gt

Thus, the equation for the velocity is

v = gt

===========================================================

Explanation:

Consider a mass of 10 kg, so m = 10

Let's say we apply a net force of 20 newtons, so F = 20

The acceleration 'a' is...

F = ma

20 = 10a

20/10 = a

2 = a

a = 2

The acceleration is 2 m/s^2. Every second, the velocity increases by 10 m/s.

---------------

Now let's double the net force on the object

F = 20 goes to F = 40

m = 10 stays the same

F = ma

40 = 10a

10a = 40

a = 40/10

a = 4

The acceleration has also doubled since earlier it was a = 2, but now it's a = 4.

---------------

In summary, if you double the net force applied to the object, then the acceleration doubles as well.

Acceleration is directly proportional to the net force on an object, and inversely proportional to its mass.

So if an object's mass stays the same while the net force on it doubles, then its acceleration will also double.

We don't know anything about the "trials".  This sounds like it might be a follow-up to a lab experiment that was performed when we weren't there.

We also don't know anything about "question 1".

Answer:

The soccer discs will be change.

Explanation:

Given that,

Opposing force = 5 N

We know that,

Drag force :

Drag force is directly proportional to the square of velocity.

[tex]F_{d}\propto v^2[/tex]

[tex]F_{d}=\dfrac{1}{2}C\rho Av^2[/tex]

Where, C = drag constant

[tex]\rho[/tex] = density

A = area

v= velocity

We need to find what happen to  the soccer discs velocity

According to drag force,

If we applies a force of 5 N opposing the motion of the disc then the velocity of the soccer discs will be change.

Hence, The soccer discs will be change.