Neve built the following graph to model the flight of a rocket from Earth to outer space. Which of the following domains is appropriate for the graph and the context?

A) All Positive Real Numbers and Zero
B) All Real Numbers
C) All Negative Real Numbers and Zero
D) 0 to 2

Answer:

20 miles.

Step-by-step explanation:

To solve this problem, we will have to set two expressions representative of Enterprise Rentals & Hertz Rental equal to each other.

Let [tex]m[/tex] equal the number of miles.

If Enterprise Rentals charges $100 plus $3 per mile, we can represent this as:

[tex]100+3m[/tex]

If Hertz Rental charges $8 per mile, we can represent this as:

[tex]8m[/tex]

Set the expressions equal to each other:

[tex]8m=100+3m[/tex]

Subtract [tex]3m[/tex] from both sides of the equation:

[tex]5m=100[/tex]

Divide both sides of the equation by the coefficient of [tex]m[/tex], which is [tex]5[/tex]:

[tex]m=20[/tex]

Therefore, after 20 miles, the total cost for both companies will be the same.

_

Check your work by substituting the solved value of [tex]m[/tex] (20), into the initial equation:

[tex]8(20)=100+3(20)[/tex]

[tex]160=100+60[/tex]

[tex]160=160[/tex]

As the total costs are equal to each other, our answer is correct!

Answer:

20 miles

Step-by-step explanation:

160=$3(20)=100

8x20=160

Answer:

2 and 1/3 ---->>> 2 1/3

Step-by-step explanation:

At 4, its 4 cm

Within 3 hours it has gained 7 cm

7/3=2.33333

2 1/3 would be the mixed number

can i get brainliest please?

Answer:

The projectile will reach a height of 200 ft after 1.910 seconds and 13.090 seconds of being launched.

Step-by-step explanation:

This projectile is experimenting a free fall, that is, an uniform accelerated motion of the projectile due to gravity and in which effects of air friction and Earth's rotation are neglected. Given that initial and final heights, initial velocity and gravitational acceleration are known, we need to calculate time by solving the appropriate equation of motion described below:

[tex]y = y_{o} +v_{o}\cdot t +\frac{1}{2}\cdot g \cdot t^{2}[/tex] (Eq. 1)

Where:

[tex]y_{o}[/tex] - Initial height of projectile, measured in feet.

[tex]y[/tex] - Final height of projectile, measured in feet.

[tex]v_{o}[/tex] - Initial velocity of projectile, measured in feet per second.

[tex]g[/tex] - Gravitational acceleration, measured in feet per square second.

As we must remember, quadratic functions have two roots and if we get that [tex]y_{o} = 0\,ft[/tex], [tex]y = 200\,ft[/tex], [tex]v_{o} = 120\,\frac{ft}{s}[/tex] and [tex]g = -16\,\frac{ft}{s^{2}}[/tex], then, the quadratic function is:

[tex]-8\cdot t^{2}+120\cdot t -200 = 0[/tex]

Roots are found by the Quadratic Formula:

[tex]t_{1,2} = \frac{-120\pm \sqrt{120^{2}-4\cdot (-8)\cdot (-200)}}{2\cdot (-8)}[/tex]

Whose solutions are:

[tex]t_{1} \approx 13.090\,s[/tex] and [tex]t_{2} \approx 1.910\,s[/tex].

Both roots are physically reasonable, first root represents the instant when the projectile reaches 200 feet when it is moving downwards, whereas second root represents the projectile moving upwards. Therefore, the projectile will reach a height of 200 ft after 1.910 seconds and 13.090 seconds of being launched.

Answer:

It will take 2.5 s to reach a height of 200ft.

Step-by-step explanation:

Answer:

90

if 15 is 1 6th then yo need 5 more 15s to find out the whole number

Answer:

Yes its less than 0

Step-by-step explanation:

it would go behind the 0 on a number line

If it is ....

[tex]3 {x}^{2} - 2x + 1 = [/tex]

The coefficient of x² is (( 3 ))

& the coefficient of x is (( -2 ))

_________________________________

If it is .....

[tex]3x - 2x + 1[/tex]

[tex]x + 1[/tex]

The coefficient of x² is (( zero 0 ))

& the coefficient of x is (( 1 ))

Answer:

y-int = -10, x-int = 15/2

Step-by-step explanation:

y int:

-4(0)+3y=-30

3y=-30

y=-10

x int:

-4x+3(0)=-30

-4x=-30

x=30/4=15/2

Answer:

1.6

Step-by-step explanation:

1 x 20

6 x 1

=

20

6

You can use our handy GCF calculator to work this out yourself if you want to. We already did that, and the GCF of 20 and 6 is 2.

We can now divide both the new numerator and the denominator by 2 to simplify this fraction down to its lowest terms.

20/2 = 10

6/2 = 3

10/3

The complete and simplified answer to the question what is 1/6 of 20 is:

3 1/3 = 1.6

so basically what i did is convert 3 1/3 as a simplified fraction and got 1.6

Answer:

a) 20 - 3^2 = 11

b) 5th, 20 - 5^2 = -5

Step-by-step explanation:

The answer assumes your terms begin at 1. If the terms begin at zero

a) 16

b) 6th term

if you chose to be extremely technical you would take the square root of 20.1 or 20.00000009 but I'm assuming they want whole numbers

Answer:

a)11

b)5th term

Step-by-step explanation:

Answer:

(2,-2)

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

the answer is 63

Step-by-step explanation

18 x 3.5=63

Answer: 63 pages

Explanation: 18 times 3 equals 54 and then for half an hour that's 9 minutes added to 54 which is 63 pages.

Answer:

249.5 (Note: I am not really sure of my answer so sorry)

Step-by-step explanation:

Let 'x' be the population in 1990.

The population in 2015 is 321.9 million.

The increase in x by 29% = 321.910^6

129% of x = 321.910^6

1.29x = 321.910^6

x = 321.910^6/1.29

x = 249.510^6

x = 249.5 million.

249.5 is the answer

i used siri

Answer:

x=0 is the solution

Step-by-step explanation:

Notice that the graph is that of a parabola with vertex at the point (0, 0).

When we solve for x in the equation:

- x^2 = 0

then we divide by -1 both sides an get: x^2 = 0/(-1) = 0

and finally use the square root property to find the answer and we get:

[tex]x=+/- \sqrt{0} = +/- 0 = 0[/tex]

Since +0 = - 0 (this is the null value), there is only one solution: x = 0.

Answer: 0.038

Step-by-step explanation:

Given: Total games : n= 375

Number of games won by  the team that was winning the game at the end of the third quarter. = 300

The proportion (p) of the team that was winning the game at the end of the third quarter: [tex]p=\dfrac{300}{375}=0.8[/tex]

Critical z-value for 90% confidence: z* = 1.645

Margin of error =[tex]z^*\sqrt{\dfrac{(1-p)p}{n}}[/tex]

The margin of error in a 90% confidence interval estimate of p [tex]=1.645\sqrt{\dfrac{0.2\times0.8}{300}}\\= 1.645\times\sqrt{0.00053333}\\\\=1.645\times0.0231\\\\=0.0379995\approx$$0.038[/tex]

Hence, the required margin of error = 0.038

Answer:

90

Step-by-step explanation:

Answer:the equation would be

8.4x=23.94

Step-by-step explanation: I know my math :)

Answer:

a) He will take 76 minutes in the triathlon

Step-by-step explanation:

He runs  1/5 of a mile in 1/20 f hour then, by simple inspection

1/5    ⇒    1/20       then    1/5 miles* 10    = 2 miles

                                        1/20*hours*10    = 1/10 hours

10/10 of an hour is 60 minutes

1/10 of an hour is 6 minutes

swimming

1/3 of a mile in 1/9 of hours then

1/3mile *6   = 2 miles

1/9 of an hour * 6 = 6/9 hours  or 2/3 of an hour

3/3 of an hour is 1 hour   = 60 minutes

2/3 of an hour is    =  40 minutes

In bike

4 miles  in  1/4 hour   then

4 miles *2   = 8 miles

1/4 hour* 2  =  1/2 hour = 30 minutes

Then he will do the triathlon in:

6 minutes running

40 minutes swimming

30 minutes in bike

Total 76 minutes

Answer:

6.333

Step-by-step explanation:

Our triangle vertices are

(1,1)(5,1)(2,9)

We are to perform interpolation at point(3,5)

x and y values are interpolated

On vertices (5,1)(2,9)

x = 3

x1 = 5

X2 = 2

Y1 = 1

Y2 = 9

Formula for interpolation

Y = [y1+(x-x1)(y2-y1)]/x2-x

Y = 1+(3-5)(9-1)/2-5

Y = 1+[-2*8/-3]

Y = 1+16/3

From here we use use LCM to get:

19/3 = 6.333

This question is Incomplete

Complete Question

Researchers recorded the speed of ants on trails in their natural environments. The ants studied, Leptogenys processionalis, all have the same body size in their adult phase, which made it easy to measure speeds in units of body lengths per second (bl/s). The researchers found that, when traffic is light and not congested, ant speeds vary roughly Normally, with mean 6.20 bl/s and standard deviation 1.58 bl/s. (a) What is the probability that an ant's speed in light traffic is faster than 5 bl/s? You may find Table B useful. (Enter your answer rounded to four decimal places.)

Answer:

0.7762

Step-by-step explanation:

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean

σ is the population standard deviation.

Population mean = 6.20 bl/s

Standard deviation = 1.58 bl/s.

x = 5 bl/s

z = 5 - 6.20/1.58

z = -0.75949

The probability that an ant's speed in light traffic is faster than 5 bl/s is P( x > 5)

Probability value from Z-Table:

P(x<5) = 0.22378

P(x>5) = 1 - P(x<5)

= 1 - 22378

= 0.77622

Approximately to 4 decimal places = 0.7762

The probability that an ant's speed in light traffic is faster than 5 bl/s is 0.7762

Answer: C. 3 cups

Step-by-step explanation:

Given: In recipe for 5 people, Required Gulf shrimp = [tex]1\dfrac14[/tex] cups

Since, [tex]1\dfrac14=\dfrac{5}{4}[/tex]

Required Gulf shrimp = [tex]\dfrac54[/tex] cups

Then, for 1 people Gulf shrimp required = [tex]\dfrac{5}{4}\div 5[/tex]

[tex]=\dfrac54\times\dfrac{1}{5}[/tex]

[tex]=\dfrac14[/tex] cup

For 12 people, it is required = [tex]12\times\dfrac14 = 3\text{ cups}[/tex]

Hence, 3 cups of gulf shrimp is required for new recipe.

So, correct option is C. 3 cups

Answer:

60 is your answer :)

Step-by-step explanation:

hope this helps :)

Answer:

-12/3

Step-by-step explanation:

Whole numbers can't be negative!

Answer:

d. your welcome

Step-by-step explanation:

Step-by-step explanation:

The measure of CED is p degree.

In triangle ABC and EDC,(Given)(Vertical opposite angles)

By AA rule of similarity,

Corresponding angles of similar triangles are same.

Therefore the measure of CED is p degree.

pls give brainest