Which of the following is true regarding the speed of earthquake waves?
OA.
S waves travel faster than P waves and surface waves.
ОВ.
Surface waves travel faster than P waves and S waves.
OC.
P waves, S waves, and surface waves all have the same speed.
OD.
P waves travel faster than S waves and surface waves.

Answers

Answer 1

Answer:

p waves travel faster than s waves and surface waves

Answer 2

Answer:

p waves travel faster than s waves and surface waves

Explanation:

I took a quiz and got this right.


Related Questions

If the magnitude of the electric field of an electromagnetic wave is 3x10^3 V/m, what is the the magntude of the magnetic field?
a. 1.1 x 10^-12 T
b. 9 x 10^11 T
c. 10^5 T
d. 10^-5 T
e. 3 x 10^3 T

Answers

Answer:

The value of the  magnetic field is [tex]B = 1.0*10^{-5} \ T[/tex]

The correct option is d

Explanation:

From the question we are told that  

    The magnitude of the electric field is  [tex]E = 3*10^{3} \ V/m[/tex]

     Generally the magnitude of  the magnetic field is mathematically represented as

        [tex]B = \frac{E}{c}[/tex]

Here  c is the speed of  light [tex]c = 3.0*10^{8} \ m/s[/tex]

=>     [tex]B = \frac{E}{c}[/tex]

=>      [tex]B = \frac{3.0*10^{3}}{ 3.0*10^{8}}[/tex]

=>      [tex]B = 1.0*10^{-5} \ T[/tex]

A. A piece of paper near a magnet
B. An aluminum nail near a magnet
C. An iron nail, not near a magnet
D. An iron nail near a magnet

Answers

Answer:

it’s c not d

Explanation:

took the test

Answer: D!!!

Explanation: jus got it wrong from the other answer.

Collision Lab
This activity will help you meet these educational goals:

You will explain or predict phenomena by exploring qualitative relationships between variables.
You will use positive and negative numbers to represent quantities in real-world contexts.
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write a brief evaluation of your work.
Activity
Open this collision simulator and click Introduction. You’ll use the simulator to explore and compare elastic collisions and inelastic collisions. The mass and starting velocity of the colliding objects are kept constant. Follow the instructions in each part, and then answer the questions that follow. Use the math review if you need help with adding and subtracting negative numbers.

Question 1: Elastic Collisions
In this question, you will investigate elastic (bouncy) collisions. Be sure that the slider is to the extreme right (elasticity 100%).

Part A
Click Show Values in the upper-right corner. Study the boxes on the screen. What are the mass and initial velocity of ball 1 and ball 2?

I NEED HELP!


Part B
Part B
Click Play, and watch the balls collide. Then click Pause. What are the final velocities of ball 1 and ball 2?


The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the value mathematically, and check it using the number line.

a number line showing an ending velocity of -0.50 meter/second and a starting velocity of 1.00 meter/second

Answers

Answer:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

Explanation:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

What is Collision?

A collision is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.

The following are a few instances of physical encounters that scientists might classify as collisions. Legs of an insect are said to collide with a leaf when it falls on one.

Every contact of a cat's paws with the ground while it strides across a lawn is seen as a collision, as is every brush of its fur with a blade of grass.

Therefore, Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

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What is the magnitude of the centripetal force that must be applied in order for a 2kg ball on a 2.0 m string to spin with uniform circular motion at 5.0 m/s

Answers

The ball needs to accelerate with a magnitude a (pointed towards the center of the circle) of

a = (5.0 m/s)² / (2.0 m) = 12.5 m/s²

Then the required tension F in the string would need to be

F = (2 kg) (12.5 m/s²) = 25 N

because centripetal force equals mv^2/r, we can plug in our known values to result in (2(5)^2)/2, which is equal to 25 n.

which of the following to all food chains depend on in an ecosystem

Answers

Answer:

The sun is the ultimate source of energy for all food chains. Through the process of photosynthesis, plants use light energy from the sun to make food energy. Energy flows, or is transferred through the system as one organism consumes another.

Which is the largest gas that occurs in our atmosphere?
Helium
Nitrogen
Other Gases
Oxygen

Answers

Answer:

OXYGEN

Explanation:brainlyist me

Answer:

Nitrogen

Explanation:

Oxygen is second

Describe the motion of an object as it accelerates. IN YOUR OWN WORD!! ASAP

Answers

Answer:

The aceleration of an object is in the direction of the net force. If you push or pull an object in a particular direction, it accelerates in that direction. The aceleration has a magnitude directly proportional to the magnitude of the net force.

Explanation:

Hope this helps Plz mark brainliest

There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N. The bell has ____________
energy.

Answers

Answer:

The bell has a potential energy of 8550 [J]

Explanation:

Since the belt is 45 [m] above ground level, only potential energy is available. And this energy can be calculated by means of the following equation.

[tex]E_{p}= W*h\\E_{p} = 190*45\\E_{p}=8550[J][/tex]

which energy resource is renewable
A. oil
B. natural gas
C. moving water
D. Fossil fuel

Answers

Answer:

It's C. Moving Waterrrr

It’s C moving water. Oil, natural gas, and fossil fuels are non-renewable.

The change in motion (acceleration) of an object depends on
The size of the force
The mass of the object
BOTH the size of the force AND the mass of the object

Answers

Answer:

BOTH the size of the force AND the mass of the object

Explanation:

Acceleration of an object is the rate of change of its velocity.

The relation between force, mass and acceleration is given by the formula as follows :

F = ma

m is mass

a is acceleration

It would mean that the change in motion or the acceleration of an object depends on both the size of the force and the mass of the object. Hence, the correct option is (c).

Which of the following is not an example of work being done on an object?

Pushing on a rock that will not move

Paddeling a canoe down a river

Lifting a bag of groceries

Throwing a ball across a field​

Answers

Answer:

Lifting a bag of groceries

Answer:

paddeling a canoe down a river :D or throwing a ball across a field

Explanation:

An object with a mass of 32 kg has an initial energy of 500). At the end of the experimentthe velocity of the object is recorded as 5.1 m/s . the object travelled 50 m to get to this point, what was the average force of friction on object during the tripAssume no potential energy Show all work

Answers

Answer:

 F = 1.68 N

Explanation:

Let's solve this exercise in parts.

Let's use the concept of conservation of the mechanical nerve

initial

    Em₀ = 500 J

The energy is totally kinetic

     Em₀ = K = ½ m v₀²

     v₀ = [tex]\sqrt{\frac{2 Em_{o} }{m} }[/tex]

     v₀ = √ (2 500/32)

     v₀ = 5.59 m / s

now with kinematics we can find a space

      v² = v₀² - 2 a x

the negative sign is because the body is stopping

       a =[tex]( \frac{v_{o}^{2} - v^{2} }{2x} )[/tex]  

let's calculate

       a = (5.59² - 5.1²) / 2 50  

       a = 0.0524 m / s²

Finally let's use Newton's second law

     F = ma

     F = 32 0.0524

     F = 1.68 N

A metal box of weigh 20 N rests on its 1 m by 0.6m side on floor. How
much is the pressure exerted by the metal box on the floor? Take g=
10 m/s

Answers

Answer:

P = 33.33 [Pa]

Explanation:

The pressure can be calculated by the relationship of the force over the area.

[tex]P =F/A[/tex]

where:

F = force = 20 [N]

A = area = 1 x 0.6 = 0.6 [m²]

Now replacing:

[tex]P=20/0.6\\P=33.33 [Pa][/tex]

A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m from where it was launched.
-Find the hang time for the projectile.
-Find the initial speed of a projectile.
-What are the x and y components of the projectile’s velocity the moment before it strikes the ground?
-At what speed will the projectile strike the ground?

Answers

Answer:

a)t  = 1,43 s

b) V = 10,49 m/s

c) V₀ₓ = 10,49 m/s   ;    V₀y = 14,01 m/s

d) Vf = 17,5 m/s

Explanation:

According to the problem statement

V₀ = V₀ₓ    and  V₀y = 0

And at the end of the movement t = ?  the distance y = 10 m

Therefore as

h = V₀y - (1/2)*g*t²

Vertical distance y = h = 10 = V₀y*t - 0,5 (-9,8)*t²

10 = 4,9*t²

t² = 10/4,9    ⇒  t² = 2,04 s

t  = 1,43 s

a) 1,43 s is the time of movement

b) V₀ = V₀ₓ        V₀y = 0     and  V₀ₓ = Vₓ     ( constant )

Just before touching the ground, the horizontal distance is

hd = 15 = Vₓ * t

Then  15 /1,43 = Vₓ = V₀ₓ

Vₓ = 10,49 m/s

Then initial speed is V = 10,49 m/s    since V₀y = 0

Vf² = Vₓ² + Vy²

Vyf = V₀y - g*t

Vyf =  0 - 9,8 *1,43

Vyf = - 14,01 m/s

And finally the speed when the projectile strike the ground is:

Vf² = Vₓ² + Vy²

Vf = √ (10,49)² + (14,01)²

Vf = 17,50 m/s

what is the portion of an electric circuit that is being powered​

Answers

Answer:

Component

Explanation:

All circuits have some basic parts, called components. One component is the power source, also called a voltage source. The power source is what pushes the electricity through the circuit.

The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How
high will the water spray into the air?

Answers

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

A 80 kg parent and a 20 kg child meet at the center of an ice rink. They place their hands together and push. The parent pushes the child with a force of 25 N, what is the force acting on the parent?

Answers

Answer:

force acting on the parent = 25 N .

Explanation:

According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .

Answer is 25 N .

d. If a dog has a mass of 12 kg, what is its weight on Neptune?
11.7N/kg

Answers

Answer:

133.8 N

Explanation:

Recall that the acceleration of gravity in Neptune is estimated as 11.15 m/s^2

Therefore, the weight of the dog on this planet would be:

Weight = mass x acceleration of gravity = 12 kg x 11.15 m/s^2 = 133.8 N

find the base area of a cylinder with diameter 1m​

Answers

Answer:

AB=0.79

Explanation:

hope this helped

on the moon which object would fall with the same acceleration?

Answers

Answer:

Since there is no air resistance on the Moon, all objects would be in free fall at 1.6 m/s2. This means that they would all hit the ground at the same time if released simultaneously from the same height, but at a slower speed compared to objects free falling in a vacuum on Earth.

Explanation:

A 20 kg wagon is rolling to the right across a floor. A person attempts to catch and stop the crate and applies a force of 70 N, 180.0 on it. If the coefficient of friction is 0.18, calculate the deceleration rate of the wagon as it is caught.

Answers

Answer:

1.736m/s²

Explanation:

According to Newton's second law;

[tex]\sum F_x = ma_x\\[/tex]

[tex]Fm - Ff = ma_x\\[/tex] where;

Fm is the moving force = 70.0N

Ff is the frictional force acting on the body

[tex]Ff = \mu R\\Ff = \mu mg\\[/tex]

[tex]\mu[/tex] is the coefficient of friction

m is the mass of the object

g is the acceleration due to gravity

a is the acceleration/deceleration

The equation becomes;

[tex]Fm - Ff = ma_x\\Fm - \mu mg = ma\\[/tex]

Substitute the given parameters

[tex]Fm - \mu mg = ma\\70 - 0.18(20)(9.8) = 20a\\70-35.28 = 20a\\34.72 = 20a\\a = \frac{34.72}{20}\\a = 1.736m/s^2\\[/tex]

Hence the deceleration rate of the wagon as it is caught is 1.736m/s²

The voltage provided by the battery of a circuit was 12 V, if the total
resistance in the circuit was 6 ohms, calculate the total current present.
options:
72 A
2A
0.5 A
7.2 A​

Answers

Answer:

2 Amps

which agrees with the second option in the list of answers

Explanation:

Use Ohm's law:

V = R * I

which with the information given to us becomes:

12 = 6 * I

then solving for I we get:

I = 12 V / 6 Ω = 2 Amps

A rocket falls from the apogee (0 meters per second) until it hits the ground with a speed of 10 meters per second. Gravity pulled it down with an acceleration of 9.8m/s^2. The time during which the ball is in free fall is approximately what time?

Answers

Answer:

Approximately 1.02 seconds

Explanation:

Use the final velocity (vf) formula for a uniformly accelerated movement under "g" (acceleration of gravity):

[tex]v_f=v_i+g\,*\,t[/tex]

in our case:

[tex]10=0+9.8\,*\,t\\t=10/9.8\\t\approx 1.02\,\,sec[/tex]

The effect of gravity on a falling object can be modeled by a ball dropped from different heights. What is a limitation of this model?

A. Not all objects bounce, even though balls do.

B. Some balls float in water, while others sink.

C. The ball can be dropped from varying heights.

D. Friction with air also affects the fall of the object.

Correct answer is D

Answers

Answer:

D.

Explanation:

try it..  *lil uzi vert's voice*

The limitation of the model of a ball dropped from different heights is that friction with air also affects the fall of the object. Hence, option (D) is correct.

What is Galileo's Leaning Tower of Pisa experiment?

According to a biography written by Galileo's student Vincenzo Viviani in 1654 and published in 1717, between 1589 and 1592, the Italian scientist Galileo Galilei, who was then a professor of mathematics at the University of Pisa, is said to have dropped two spheres with the same volume but different masses from the Leaning Tower of Pisa to show that their time of descent was independent of their mass. A few decades previously, Italian experimenters had already proven the fundamental tenet.

Galileo, it is said, discovered through this experiment that the items fell with the same acceleration, confirming his prediction and refuting Aristotle's theory of gravity in the process (which states that objects fall at speed proportional to their mass). The majority of historians believe it to have been more of a thought experiment than a physical test.

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An element or compound used to enhance a semiconductor is called a(n) ____.

Answers

What ^ he/she said !.!.!

Hope you guys have a good day! And, Merry Christmas!

Be/stay safe, and enjoy your break!

The element named boron can be used to enhance the properties of semiconductors.

What is a semiconductor?

A semiconductor is a material that has electronic properties and has the value that falls in between a conductor. It can be a metallic copper or an insulator.

The rise in temperatures leads to a fall in resistivity. The element named boron can improve the electrical properties of the semiconductor as they form the impurities.

Find out more information about the element.

brainly.com/question/12389810

Need help fast it’s on forces!

Answers

i think the answer is h if am wrong am sorry

Explanation:

The amount of oxygen in the reactants is 4 atoms. In the products, the oxygen is distributed to water (H2O) and O2 gas. Which coefficients would be placed in front of water and oxygen? 2 in front of water and 2 in front of oxygen 1 in front of water and 2 in front of oxygen 1 in front of water and 1 in front of oxygen 2 in front of water and 1 in front of oxygen

Answers

Answer:

2 in front of water and 1 in front of oxygen

Explanation:

Answer:

the correct answer is D

Explanation:

What is the algebraic sign (+ or -) for designating the distance and velocity vectors for an object in free fall?

Answers

Answer:

positive- downward

negative- upward

Explanation:

A vector is a quantity described by a magnitude and a direction.

The algebraic sign, positive (+) and negative (-) are used to designate the distance and velocity vectors for an object in free fall where positive represents downward  and negative represents an upward movement of the object.

Hence, the correct answer is "positive- downward  and negative- upward".

At the instant its angular displacement is 0.32 rad, the angular acceleration of a physical pendulum is -630 rad/s2. What is its angular frequency of oscillation?
6.6 rad/s
14 rad/s
20 rad/s
44 rad/s
200 rad/s

Answers

Answer:

200rad/s

Explanation:

The angular frequency of oscillation of the pendulum is 44.3 rad/s.

What is meant by angular frequency ?

Angular frequency is defined as the rate of change of angular displacement in a simple harmonic motion.

Here,

Angular displacement of the pendulum, θ = 0.32 rad

Angular acceleration, α = -630 rad/s²

We know that the equation for angular acceleration is given by,

α = -ω²θ

where ω is the angular frequency

ω² = -α/θ

ω² = 630/0.32

ω² = 1968.8

Therefore,

Angular frequency, ω = √1968.8

ω = 44.3 rad/s

Hence,

The angular frequency of oscillation of the pendulum is 44.3 rad/s.

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A 60-kg jogger runs up a long flight of
stairs in 4.0 s. The vertical height of the
stairs is 4.5 m.
a. Estimate the jogger's power
output in watts and horsepower.
b. How much energy did this
require?

Answers

Explanation:

Given parameters:

Mass of Jogger  = 60kg

Time  = 4s

Vertical height  = 4.5m

Unknown:

Jogger's power output  = ?

Energy required  = ?

Solution:

The power output of the jogger is defined as the rate at which work is done.

 Power  = [tex]\frac{force x distance}{time}[/tex]  

Now insert the parameters and solve;

  Work done = Force x distance = mgh

   m is the mass

   g is the acceleration due to gravity = 9.8m/s²

    h is the height

  Work done  = 60 x 9.8 x 4.5  = 2646J

 Power = [tex]\frac{2646}{4}[/tex]   = 661.5W

Energy required;

 The work done here is also the energy required;

 Energy required  = 2646J

The energy required is 2646 J and the jogger's power output 661.5 W.

Given here,

Mass of Jogger  = 60 kg

Time  = 4s

Vertical height  = 4.5 m

The power output of the jogger is defined as the rate of energy tranfer  work is done.

Power  =  W/t

Where,

W- work = mgh = 60 kg  x  9.8 m/s² x 4.5 m = 2646 J

t - time - 4 s

Put the values, we get

Power = 661.5W

To know more about power,

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