Which is the equation of a circle with a radius of 6 and a center of (3,-1)?
(x - 3)2 + (y+1)2 = 36
(x+3)2 + (y - 1)2 = 36
(x+3)2 + (y - 1)2 = 6
(x-3)2 + (y+ 1)2 = 6

Answer:

4th on should be the correct

Answer:

151.5 cm = 1.515 m

151.5 cm = 1515/1000 m

[tex]A = \dfrac 12 (b_1 + b_2)h\\\\\implies 2A = (b_1+b_2) h\\\\\implies h =\dfrac{2A}{b_1+b_2}[/tex]

Answer:

1,200

Step-by-step explanation

Multiply 720 and 100 = 72,000

Divide by 60 = 1,200

Answer:

The answer is 1,200

Step-by-step explanation:

First Multiply 720 and 100 which = 72,000

Then Divide 72,000 by 60 = 1,200

[tex]\text{Given that,}\\\\\\f(x) = \ln(x^4 +e^{2x})\\\\\\f'(x) = \dfrac{1}{x^4 + e^{2x}} \left(4x^3+2e^{2x}\right) = \dfrac{2(2x^3+e^{2x})}{x^4 + e^{2x}}~~~~;[\text{Chain rule}]\\\\\\\text{Note:}\\\\\dfrac{d}{dx} \ln x = \dfrac 1x\\\\\dfrac{d}{dx} x^n = nx^{n-1}\\\\\dfrac{d}{dx} e^{mx} = m e^{mx}[/tex]

After solving the given equation, the value obtained is equal to [tex]\frac{2(2x^3+e^2^x)}{x^4+e^2^x}[/tex].

If a mathematical operation includes at least two words that are connected by an operator and either comprise numbers, variables, or both, it is referred to as an expression.

The operations with reflection coefficients include adding, subtracting, multiplying, and dividing. To include terms in an expression, a mathematical operation like reduction, addition, multiplication, or division is used.

As per the given data in the question,

f(x) = ln (x⁴ + e²ˣ)

[tex]f'(x)=\frac{1}{x^4+e^2^x}(4x^3+2e^2^x)[/tex]

Now, use the chain rule,

[tex]\frac{2(2x^3+e^2^x)}{x^4+e^2^x}[/tex]

Also, note some points,

d/dx ln (x) = 1/x

[tex]\frac{d}{dx}x^n=nx^n^-^1[/tex]

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Answer: x=10

Step-by-step explanation:To find the x-intercept, you have to set y=0.

4x-5y=40

4x-5(0)=40

4x-0=40

4x=40

Then divide both sides by 4 to get x=10

Hope this helps! :D

Answer:

24 packages

Step-by-step explanation:

One dozen is 12, so 4 x 12 = 24

Answer:

The domain corresponds to the values of the x and the range to the values of the y. So:

D: {-3, 0, 3}

R: {-6, 0, 6}

Answer:

[tex]\huge\boxed{A.}[/tex]

Step-by-step explanation:

Domain:

"Set of values on x-axis"

Domain = {-3,0,3}

Range:

"Set of values on y-axis"

Range = {-6,0,6}

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

C

Step-by-step explanation:

There isnt rly a lot of information from this question but my best guess would be C.  It says "1 drop in each eye bid every 10 days", so assuming that 1 drop equals 1 ml and knowing we have to do it in "each eye bid" we could assume 2ml of eye drops would be used every 10 days.

Sorry if im wrong but i hope this helps have a great day and happy holidays (｢•-•)｢

Answer:

5.96 x 36 = 214.56.

286.08 - 214.56 = 71.52

71.52 divided by 8.94 = 8.

He worked 8 additional hours.

Answer:

The worker worked about 8 hours overtime.

Step-by-step

First we figure out how much they made without overtime.

Multiply 5.96 x 36 and you would get 214.56

Then we figure out how many hours he worked overtime

Multiply 8.94 times 8 and you would get 71.52

Then take 214.56 and add 71.52, you would get 286.08, the answer is 8 hours overtime.

Answer:

new equation : 1.09t = new price

Step-by-step explanation:

1.09(15.99) = 17.4291

it's about $17

Step-by-step explanation:

you have to be careful what you are typing.

the way you wrote the numbers Asia would be a tiny place with very few people.

but I think you meant to say :

area is 4.46 × 10⁷ km²

with 3.70 × 10⁹ people.

people / km² = 3.70/4.46 × 10⁹/10⁷ =

= 0.829596413... × 10² = 82.9596413... =

= 82.96 people/km²

The population density will be equal to 82.96 people/km2. The correct option is B.

Expression in maths is defined as the collection of numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Numbers (constants), variables, operations, functions, brackets, punctuation, and grouping can all be represented by mathematical symbols, which can also be used to indicate the logical syntax's order of operations and other features.

Given that the area is 4.46 × 10⁷ km² with 3.70 × 10⁹ people. The population density will be calculated as below:-

Density = people / km² = ( 3.70 × 10⁹ ) / ( 4.46 x 10⁷ )

Density = 0.829596413... × 10² = 82.9596413

Density = 82.96 people/km²

Therefore, the population density will be equal to 82.96 people/km2. The correct option is B.

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[tex]\mathfrak{ x ^ { 2 } + b x - 4 = 0} [/tex]

[tex]\mathfrak{bx-4=-x^{2} } [/tex]

[tex]\mathfrak{bx=-x^{2}+4 } [/tex]

[tex]\mathfrak{xb=4-x^{2} } [/tex]

[tex]\mathfrak{\frac{xb}{x}=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{ b=\frac{4-x^{2}}{x} } [/tex]

[tex]\mathfrak{b=-x+\frac{4}{x} } [/tex]

AnSwEr

[tex]\boxed{\mathfrak{b=-x+\frac{4}{x},x\neq 0 } }[/tex]

 ღ ꪑ꠸᥅ꫀꪊ

x = 27

Step-by-step explanation:

The two angles shown are called co-exterior angles and by definition, their sum is equal to 180° so we can write

[tex](3x - 3) + (4x - 6) = 180[/tex]

[tex]\Rightarrow 7x - 9 = 180[/tex]

Simplifying this further, we get

[tex]7x = 189 \Rightarrow x = 27[/tex]

Answer:

Step-by-step explanation:

Mathew decided to have a picnic with his 4 friends. They were each assigned to bring 10 different foods. The food were to be brought in 15 bags total. How much food are there in each bag in total?

Answer:

.6 miles

Step-by-step explanation:

Answer:

0.6 miles

Step-by-step explanation:

6 × t = 4 × (15 - t)

6t = 60 - 4t

6t + 4t = 60 - 4t + 4t

10t = 60

t = 6

6 × [tex]\frac{1}{10}[/tex] = 0.6

Answer:

6x sec2 (x2+5) the number to are in the top of x a c.

Answer: -1 = (-3/3)

Step-by-step explanation

You go from one point to another, i started from 3,1 and went to 3,0. I got down -3 which is my rise and right 3 for the run. Tell me if this is correct

Answer:

This is not a linear function, as it isn't any function because 3 has two outputs.

Step-by-step explanation:

Explained above

Answer:

  82/63

Step-by-step explanation:

The sum can be found using the formula ...

  [tex]\dfrac{a}{b}+\dfrac{c}{d} =\dfrac{ad+bc}{bd}[/tex]

For the given fractions, the sum is ...

  [tex]\dfrac{6}{7}+\dfrac{4}{9} =\dfrac{6\cdot9+7\cdot4}{7\cdot9}=\dfrac{54+28}{63}=\boxed{\dfrac{82}{63}}[/tex]

_____

Additional comment

When the denominators have no common factor, the least common denominator is their product, as here.

Answer:

For this question, you can make the denominators the same to get the answer.

LCM of 7 and 9 = 63

[tex]\frac{6}{7} + \frac{4}{9} = \frac{54}{63} + \frac{28}{63} \\[/tex]

         = [tex]\frac{82}{63}[/tex]

         = 1[tex]\frac{19}{63}[/tex]

Answer:

0,0

Step-by-step explanation:

because it is in the centre of the graph

The given triangles ΔDOA and ΔABC are right triangles that have a

common vertex at point A.

Reasons:

The given parameters are;

The diameter of the circle with center O = AB

DO ⊥ AB (DO is perpendicular to AB)

Required:

Prove that ∠AEC = ∠ODA

A two column proof is presented as follows;

Statement [tex]{}[/tex]                                                 Reason

1. AB is the diameter of circle     [tex]{}[/tex]                 1. Given

2. DO is perpendicular to AB [tex]{}[/tex]                     2. Given

3. ∠DOA = 90° [tex]{}[/tex]                                             3. Definition of DO ⊥ AB

4. ∠BCA = 90°   [tex]{}[/tex]                                             4. Thales theorem

5. ∠BCA ≅ ∠BCA [tex]{}[/tex]                                         5. Reflexive property

6. ΔDOA ~ ΔABC   [tex]{}[/tex]                                        6. AA similarity postulate

7. ∠ABC ≅ ∠ODA   [tex]{}[/tex]                                       7. CASTC

8. ∠ABC = ∠ODA   [tex]{}[/tex]                                        8. Definition of congruency

9. ∠AEC ≅ ∠ABC   [tex]{}[/tex]                                        9. Angles in the same segment

10. ∠AEC = ∠ABC   [tex]{}[/tex]                                       10. Definition of congruency

11. ∠AEC = ∠ODA   [tex]{}[/tex]                                        11. Transitive property of equality

In statement 6, ΔDOA is similar to ΔABC by Angle-Angle, AA, similarity

postulate, therefore, the three angles of ΔDOA are congruent to the three

angles of ΔABC.

Therefore ∠ABC ≅ ∠ODA by Corresponding Angles of Similar Triangles

are Congruent, CASTC.

Learn more about circle theorem here:

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Answer:

48.1

Step-by-step explanation:

Seven rounds up.

Hope this helped! :)

[tex](1-\sin^2 x) \tan x \\\\=\cos^2 x \cdot \dfrac{\sin x}{\cos x}\\\\=\cos x \sin x[/tex]