when do we say a curvilinear motion is accelerated?​

Answers

Answer 1

Answer:

There always is an acceleration in a curvilinear motion, as the velocity vector changes, so always.


Related Questions

the distance between student home and school is 1.5 km what is the distance traveld bythe students in a week​

Answers

Answer:

10.5k

Explanation:

1.5x7=10.5

If the speed of the magnet is doubled, the induced voltage is ________ . twice as great four times as great half as great unchanged

Answers

If the speed of the magnet is doubled, the induced voltage is twice as great

Faraday's law of induction states that whenever relative motion exists between a coil and magnetic field, a voltage will induce in the circuit and this voltage is proportional to the rate of change of the flux. The expression for the motional emf is as follows:

ε=Blv

Here, ε is the motional emf, B is the magnetic field, l is the length of the conductor, and v is the velocity at which the magnetic field changes.

The induced voltage by the moving magnet is directly proportional to the speed of the magnet. Therefore, an increase in the speed of the magnet will increase the induced voltage.

If the speed of the magnet is doubled, the induced voltage is twice as great

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If a force of 20kn acts on a circular rod of a diameter 10mm, calculate the stress of the rod

Answers

σ = F/A = F/ (πD²/4) = 20000 / (π0.10²/4) = 2.55 MN/m²

In the following free body diagram, what is the net force on the object?
A.10n
B.5 N to the right
C.20 N to the right
D.7 N to the right

Answers

Answer:

B

Explanation:

Simply take all forces pointing to the right of the box as positive and all of the forces pointing to the left of the box as negative and add all values.

ΣF = 7 + 18 + (-20) = 5N to the right

A common type of succession that occurs on a surface where an ecosystem has previously existed

Answers

Secondary succession, the more common type of succession, occurs on a surface where an ecosystem has previously existed. It occurs in ecosystems that have been disturbed or disrupted by humans, animals, or by natural processes such as storms, floods, earthquakes, and volcanoes.

A 0.050 kg metal bolt is heated to an unknown initial temperature. It is then dropped into calorimeter containing 0.15 kg of water with an initial temperature of 21.0°C. The bolt and the water then reach a final temperature of 25.0°C. If the metal has a specific heat capacity of 899 J/kg•°C, find the initial temperature of the metal.

Answers

The initial temperature of the metal bolt is 80.8 °C

We'll begin by calculating the heat absorbed by the water.

Mass of water (M) = 0.15 Kg Initial temperature (T₁) = 21 °CFinal temperature (T₂) = 25 °CChange in temperature (ΔT)  = T₂ – T₁ = 25 – 21 = 4 °CSpecific heat capacity of water (C) = 4184 J/KgºCHeat absorbed (Q) =?

Q = MCΔT

Q = 0.15 × 4184 × 4

Q = 2510.4 J

Finally, we shall determine the initial temperature of the metal bolt.

Heat absorbed by water = 2510.4 JHeat released by metal (Q) = –2510.4 JMass of metal (M) = 0.050 Kg Final temperature (T₂) = 25 °CSpecific heat capacity of metal (C) = 899 J/Kg°CInitial temperature (T₁) =?

Q = MC(T₂ – T₁)

–2510.4 = 0.050 × 899 (25 – T₁)

–2510.4 = 44.95 (25 – T₁)

Clear bracket

–2510.4 = 1123.75 – 44.95T₁

Collect like terms

–2510.4 – 1123.75 = –44.95T₁

–3634.15 = –44.95T₁

Divide both side by –44.95

T₁ = –3634.15 / –44.95

T₁ = 80.8 °C

Thus, the initial temperature of the metal is 80.8 °C.

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Hello I am absolutely stumped on these six physics problems. Please help me on them.

Answers

Answer:

Explanation:

20° from the normal = 110° from parallel

1a) τ = (200sin90)[6] + (75sin110)[3] - (100sin110)[3]

     τ = 1,129.52305... = 1100 N•m CCW

1b) τ =  200(6)(sin90) + 75(-3)(sin(360-110)) + 100(3)(sin(270 + 20)

     τ = 1,129.52305... = 1100 N•m CCW

1c) My directions agree, both are positive z by right hand rule.

1d) Moment of inertia for a thin rod about an axis perpendicular to its center is

I = (1/12)mL²

τ = Iα

α = τ/I = 1129.523 / ((1/12)(200)(12²)) = 0.4706 rad/s²

θ = ½αt²

θ = ½(0.4706)(2•60)² = 3,388.56916... radians

θ = 3400 radians

at which time is is spinning about 9 revolutions per second

A moving car initially has kinetic energy K. The car then moves in the opposite direction with four times its initial speed. What is the kinetic energy now

Answers

If initial speed was v, Kinetic energy was K = 1/2mv^2

When speed will be 4v, KE will be:

= 1/2 m (4v)^2

=1/2m 16 v^2

=16K

Now kinetic energy will become 16 times of initial Kinetic Energy

How is the A He related to the A Hof a reaction?​

Answers

Answer:

by giving a person to person

A rifle is aimed horizontally at a target 47 m away. The bullet hits the target 2.3 cm below the aim point.

Answers

Answer:

Is your question asking for the muzzle velocity of the bullet?

Explanation:

I will assume it does

The bullet travels horizontally to the target in the same amount of time it falls 2.3 cm from vertical rest

s = ½at²

t = √(2s/g) = √(2(0.023) / 9.8) = 0.0685118...s

v = d/t = 47/0.0685118 = 686.01242...

v = 690 m/s

Below are three graphs. The shape of graph 3 shows that the current flowing through this component is __________ proportional to the potential difference across it. What one word completes the sentence?

Answers

The relationship between variables might be either directly porportional to each other or inversely proportional to each other. For instance, the current flowing is _directly_ proportional to the potential difference across it.

---------------------

Since I do not have the graph, I will propose two potential options and I will describe each of them.

I suggest you to choose the one that matches the shape of graph 3.

GraphsProbably your graph is composed of the X and Y axes, perpendicularly placed, in a way in which four quadrants are formed.

You might see that one of the axes represents the current (I), and the other one represents the potential difference (V).

And a straight line that represents the relationship between the current and the potential difference.

The direction of the straight line reflects the relationship between variables.

The change on each variable is proportional to the change on the other variable. Now we have to analyze how that change occurs. Option 1

The current flowing through this component is __DIRECTLY__ proportional to the potential difference across it.

If this is the case of your graph, you should see the straight line crossing from the left inferior quadrant to the right superior one.

The direction of the line suggests that one of the variables increases as the other one increases too. The current increases as the potential increases.

This is the case of the Ohm's law.

Option 2

The current flowing through this component is __INVERSELY__ proportional to the potential difference across it.

If this is the case of your graph, you should see the straight line crossing the right quadrant from the superior left corner to the inferior right one.

The direction of the line suggests that the variable represented in the Y ax decreases as the other one increases.

For instance, The current decreases as the potential increases. Or the potential decreases as the current increases.

In the attached files you will find graphs of both options.

-------------------------

You can learn more about the Ohm's law at  

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You can learn more about the relationship between variables at

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https://brainly.com/question/21627823?referrer=searchResults

Answer: The relationship between variables might be either directly proportional to each other or inversely proportional to each other. For instance, the current flowing is directly proportional to the potential difference across it.

Explanation:

Which one is it??? The question and the choice are in the photo.

Answers

The answer is:

That they are switched on

A change
1. Ricardo has purchased a forklift for his business. The forklift can put out 4950 W of power. If the forklift is operating at full capacity, how much work can it do in 2.40 seconds?
O 2060)
O 4950)
O 6490)
O 11,900

Answers

The work done if the forklift is operating at full capacity is 11,900 J.

We have to recall that power is defined as the rate of doing work. The rate of doing work is defined as;

Power = Work done/time taken

When;

Power = 4950 W

Time taken = 2.40 s

Work done = Power × time taken

Work done = 4950 W × 2.40 s

Work done = 11,900 J

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Why is it important that we learn about our solar system, the sun, and planets in our solar system other than Earth?

Answers

Answer:

To understand all the different kind of elements and how they work. Nature is a beautiful thing and it is important we understand how they survive and how we can help. The solar system is a mandatory nature. Learning about other planets also helps us feel safe and more knowledgable.

please help me rn rn​

Answers

Answer:

merry Christmas ⛄

A baseball is hit with a speed of 27.0 m/s at an angle of 47.0 ∘ . It lands on the flat roof of a 10.0 m -tall nearby building. Part A If the ball was hit when it was 1.3 m above the ground, what horizontal distance does it travel before it lands on the building?

Answers

Answer:

H = Vy t - 1,2 g t^2            formula for height of ball after t sec

H = 10 - 1.3 = 8.7 m

Vy = 27 sin 47 = 19.7 m/s     vertical speed of ball

8.7 = 19.7 t - 9.8/2 t^2       height of ball after t sec

4.9 t^2 - 19.7 + 8.7 = 0       rearranging

[19.7 ± (388 - 170)^1/2] / 2 *4.9 = [19.7 ± 14.7] / 9.8 = .51 ,3.5 sec

.51 sec would be on the way up and 3.5 sec on the way down

Sx = 27 * cos 47 * 3.5 = 64.4 m around 200 ft seems reasonable

a 2000kg car initially traveling at a speed of 15 m/s is accelerated by a constant force of 10000 n for 3 seconds. the new speed of the car is

Answers

Mass of the car (m) = 2000 KgInitial velocity (u) = 15 m/sForce (F) = 10000 NTime (t) = 3 sLet the acceleration be a.By using the formula, F = ma, we get,10000 N = 2000 Kg × aor, a = 10000 N ÷ 2000 Kgor, a = 5 m/s^2Let the final velocity be v.By using the formula, v = u + at, we get,v = 15 m/s + 5 m/s^2 × 3 sor, v = 15 m/s + 15 m/sor, v = 30 m/s

Answer:

The new speed of the car is 30 m/s.

Hope you could get an idea from here.

Doubt clarification - use comment section.


The average value of the load between A and B is 6.0 N. The spring has an unstretched length
increases from 4.0 cm to 6.0 cm.

Answers

The change in the length of the spring as it stretches from 4.0 cm to 6.0 cm is 2.0 cm.

The change in length of the spring can be calculated by subtracting the initial unstretched length (4.0 cm) from the final stretched length (6.0 cm).

Change in length = Final length - Initial length

Change in length = 6.0 cm - 4.0 cm

Change in length = 2.0 cm

Therefore, the change in the length of the spring as it stretches from 4.0 cm to 6.0 cm is 2.0 cm. This means the spring elongates by 2.0 cm under the applied load between points A and B.

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The complete question is:

The average value of the load between A and B is 6.0 N. The spring has an unstretched length increases from 4.0 cm to 6.0 cm. What is the change in the length of the spring as it stretches from 4.0 cm to 6.0 cm?

A. 4.0 cmB. 1.0 cmC. 2.0 cmD. 6.0 cm

a bicycle with tires 68 cm in diameter travels 9.2 km. how many revolutions do the wheels make

Answers

Answer:

Explanation:

Circumference in meters is

C = πD = 0.68π

9200 m / 0.68π m = 4,306.545518...

4,306.5 revolutions

A bicycle with tires 68 cm in diameter travels 9.2 km. the number of revolutions made by the wheel would be 4309

What is Velocity?

The total displacement covered by any object per unit of time is known as velocity. It depends on the magnitude as well as the direction of the moving object.  It can also be represented by the infinitesimal rate of change of displacement with respect to time. The unit of velocity is meter/second.

The mathematical expression for velocity is given by

velocity= displacement  / time taken

As given in the problem a bicycle with tires 68 cm in diameter travels 9.2 km

Diameter = 68 cm

radius = diameter /2

          = 68/2

         = 34 cm

The distance covered by the tire in one cycle would be

distance in one revolution = 2π×Radius

                                            = 2×3.14× 34

                                            = 213.52 cm

                                            =2.13 m

The number of revolutions by wheel = total distance/distance in one revolution

number of revolutions = 9200/2.135

                                    =4309 revolutions

Thus, the number of revolutions made by the wheel would be 4309

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What net force acting on a 6 kg car produces an acceleration of 6 m/s2?

Answers

Explanation:

Mass (m) = 6 kgAcceleration (a) = 6 m/s²Force (F) = ?

We know that,

• F = ma

→ F = (6 × 6) N

F = 36 N

Therefore, the net force is 36N.

What is an element?
1. A substance made of more than one type of atom.
2. A substance that is made of water.
3. A substance that is made of no atoms.
4. A substance made of only one type of atom.

Answers

Answer:

Hey Friend...

Explanation:

This is ur answer.....

4. A substance made of only one type of atom.

Hope it helps!

Brainliest pls!

Follow me! :)

Answer:

4

Explanation:

element is a substance that cannot be broken down into any other substance which means every element is made up of its own type of atom

Wtz the answer to this question? I need to get it right

Answers

Answer: Next time you create a question, add an image or PDF. Because I do not know the question. So, may you please create a new question?

PLEASE HELP ASP WILL GIVE 50 POINT AND BRAINLIEST!!!!!!!!!!!!!

A. In the Bohr model of the hydrogen atom, the speed of the electron is approximately
2.16 × 10⁶ m/s. Find the central force acting on the electron as it revolves in a circular orbit of radius 5.17 × 10⁻¹¹ m.
Answer in units of N.

B. Find the centripetal acceleration of the electron

Answers

Explanation:

A. The centripetal force experienced by an electron as it goes around a hydrogen nucleus is given by

[tex]F_c = m_e\dfrac{v^2}{r}[/tex]

where [tex]m_e = \text{electron\:mass} = 9.11×10^{-31}\:\text{kg}[/tex]

[tex]r = 5.17×10^{-11}\:\text{m}[/tex] = orbital radius

[tex]v = 2.16×10^6\;\text{m/s}[/tex] = orbital velocity

so the centripetal force is

[tex]F_c = (9.11×10^{-31}\:\text{kg})\dfrac{(2.16×10^6\;\text{m/s})^2}{5.17×10^{-11}\:\text{m}}[/tex]

[tex]\;\;\;=8.22×10^{-8}\:\text{N}[/tex]

B. The electron's centripetal acceleration is given by

[tex]a_c = \dfrac{v^2}{r}[/tex]

Using the values from (A), we get

[tex]a_c = \dfrac{(2.16×10^6\;\text{m/s})^2}{5.17×10^{-11}\:\text{m}}[/tex]

[tex]\;\;\;=9.02×10^{22}\:\text{m/s}^2[/tex]

The potential difference between the (high-voltage) inner shell of a Van de Graaff accelerator and a point where the charge is injected into the moving belt is 3.4 MV. What is the minimum power required to pull the belt when the belt transfers the charge to the case at 2.8 mC/s?

Answers

Explanation:

this is the answer to the questions

Destination is your Destination ​

Answers

Answer:

woah awesome so cool

Explanation:

Answer:

woah excellent!

HELP PLEASE WILL MARK BRAINLIEST

Outside wooden steps may get slippery when they are wet. How could you make them less slippery?

Answers

There are many ways you can get wooden steps to be less slippery even when they are wet. Some ways are:  

*You can put a carpet on the steps. The fibers in a carpet usually have some friction which will give you a grip as you climb up and/or down and prevent you from falling.  

*You can apply anti-slip coatings like a paint on the steps. If you add some sand to the paint to add traction and lessen the slippery nature. Alternatively, If the wood has been waxed, you may consider using a wax remover.  

*You can fix a hand railing so that you can hold on to it when you go up and down the steps.

4. Trilobites are animals that lived during the Paleozoic era. They populated all parts of the
ocean showed consistent evolution over time and left behind fossils that are large
enough to be studied without a microscope. All of these characteristics make trilobites
the ideal
a. Trace fossil
b. Keystone species
c. Index fossil
d. Reference point
dnreserve the remains of dead

Answers

Answer:

c. index fossil

Explanation:

Trilobite fossils are found worldwide, with many thousands of known species. Because they evolved rapidly, and molted like other arthropods, trilobites serve as excellent index fossils. (Arthropods periodically shed their old exoskeletons, or molt.) An index fossil is one that is useful for dating and correlating the strata in which it is found.

Where do hyperbolic comets originate?
A. the Oort cloud
B. the asteroid belt
C. the Kuiper belt
D. interstellar space

Answers

Answer:A.the Oort cloud

Explanation:

Answer:

try answer A..the Ootor cloud

n earthquake emits both P-waves and S-waves that travel at different speeds through the Earth. A P-wave travels at 9 000 m/s and an S-wave at 4 000 m/s. If P-waves are received at a seismic station 34.0 s before an S-wave arrives, how far is the station from the earthquake center

Answers

Answer:

Yes , i also need answer

Explanation:

n earthquake emits both P-waves and S-waves that travel at different speeds through the Earth. A P-wave travels at 9 000 m/s and an S-wave at 4 000 m/s. If P-waves are received at a seismic station 34.0 s before an S-wave arrives, how far is the station from the earthquake center

Question: Self-test 3.12 Calculate the change in G for ice at -10°C, with density 917 kg mº, when the pressure is increased from 1.0 bar to 2.0 bar.​

Answers

The change in the Gibb's free energy per mole (G) is 1.96 J.

The given parameters:

Density of the ice, ρ = 917 kg/m³Initial pressure, P₁ = 1.0 barFinal pressure, P₂ = 2.0 barTemperature, T = - 10 CMass of water = 18 g

The change in the Gibb's free energy per mole (G) is calculated as follows;

[tex]\Delta G = V(P_2-P_1) \\\\[/tex]

where;

V is the volume of the ice

[tex]Density = \frac{Mass}{Volume} \\\\Volume = \frac{Mass}{Density} \\\\Volume = \frac{18 \times 10^{-3} \ kg}{917 \ m^3} \\\\Volume = 1.96 \times 10^{-5} \ m^3\\\\Volume = 1.96 \times 10^{-5} \ m^3 \times \frac{1000 \ L}{m^3} \\\\Volume = 0.0196 \ L[/tex]

Change in pressure;

[tex]P_2 - P_1 = 2.0 \ bar \ - \ 1.0 \ bar = 1.0 \ bar = 0.987 \ atm[/tex]

The change in the Gibb's free energy per mole (G);

[tex]\Delta G= V(P_2-P_1)\\\\\Delta G = 0.0196\ L \times 0.987\ atm \\\\\Delta G = 0.0193 \ L.atm\\\\1 \ L.atm = 101.325 \ J\\\\\Delta G = 0.0193 \ L.atm \times \frac{101.325 \ J}{1 \ L.atm} \\\\\Delta G = 1.96 \ J[/tex]

Thus, the change in the Gibb's free energy per mole (G) is 1.96 J.

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