what is Cobalt (II) iodide and sodium carbonate net ionic equation

Answers

Answer 1

Answer:

Co2+ + CO32- → CoCO3

Explanation:

The molecular equation for the reaction between cobalt (II) iodide and sodium carbonate is:

CoI2 + Na2CO3 → CoCO3 + 2NaI

To write the net ionic equation, we need to eliminate the spectator ions, which are the ions that appear on both the reactant and product side of the equation and do not participate in the reaction. In this case, the spectator ions are Na+ and I-.

The net ionic equation for this reaction is:

Co2+ + CO32- → CoCO3

Therefore, the net ionic equation for the reaction between cobalt (II) iodide and sodium carbonate is:

Co2+ + CO32- → CoCO3


Related Questions

Use equivalent weights to calculate 81.00 mg/L calcium carbonate (CaCO3) in terms of mg/L as dihydrogen phosphate (H2PO4-)

Answers

According to the question Therefore, 81.00 mg/L CaCO3 is equivalent to 162.00 mg/L H2PO4-.

What is CaCO3 ?

Calcium Carbonate, also known as CaCO3, is a naturally occurring mineral which is found in rocks, shells, and pearls. It is composed of the elements calcium, carbon, and oxygen, and is a major component of sedimentary rocks. Calcium Carbonate is an important building material, and is used in a range of industries, from paper and plastic to pharmaceuticals and cement. It is also used as an additive in many food products, such as baking powder and cheese.

To calculate this, we must first convert 81.00 mg/L CaCO3 to moles.

81.00 mg/L CaCO3 = 0.00045 moles CaCO3

Next, we need to convert from moles of CaCO3 to moles of H2PO4-. The molar ratio between CaCO3 and H2PO4- is 1:2, so for every mole of CaCO3, there are two moles of H2PO4-.

Therefore, 0.00045 moles CaCO3 = 0.00090 moles H2PO4-

Finally, we must convert the moles of H2PO4- back to mg/L:

0.00090 moles H2PO4- = 162.00 mg/L H2PO4-

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What are the examples of tests performed on aspirin

Answers

Most frequently, a salicylates component is used to: Aid in the diagnosis of sudden or progressive aspirin toxicity. When you take a lot of aspirin at once, you might get acutely poisoned.

Can aspirin be detected in blood tests?

Blood test results are frequently impacted by prescription medicines, non-prescription pharmaceuticals (such as aspirin, cold medicine, and vitamins), and alcohol consumption. In order to properly interpret the findings of your blood tests, your doctor needs a thorough and candid picture of your medication use.

What laboratory results does aspirin impact?

Aspirin Reaction Units are used to report test findings (ARU). 350-549 ARU is the therapeutic range for people on an antiplatelet regimen to effectively suppress platelets. Those who are not taking aspirin or whose treatment is ineffectively suppressing platelet function have values of 550–700 ARU.

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Given the following balanced equation, determine the mass of H2 if you start with 4.55x1025 molecules of C5H12.
C5H12-->C5H8+2H2

Answers

If you start with 4.55 x 10²⁵ molecules of C₅H₁₂, you would produce 1.82 x 10²⁶ g of H₂.

What is the mass of H₂ ?

The balanced equation shows that for every one molecule of C₅H₁₂ that reacts, 2 molecules of H₂ are produced.

C₅H₁₂ --> C₅H₈ + 2H₂

To determine the mass of H₂ produced, we need to convert the number of molecules of C₅H₁₂ to molecules of H₂ using the stoichiometry of the balanced equation:

1 molecule of C₅H₁₂ produces 2 molecules of H₂

4.55 x 10²⁵ molecules of C₅H₁₂ x (2 molecules of H₂ / 1 molecule of C₅H₁₂) = 9.10 x 10²⁵ molecules of H₂

Now, to find the mass of H₂ produced, we need to use the molar mass of H₂, which is approximately 2 g/mol:

9.10 x 10²⁵ molecules of H₂ x (2 g/mol) = 1.82 x 10²⁶ g of H₂

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Answer:

9.10 x 10²⁵ molecules of H₂ x (2 g/mol) = 1.82 x 10²⁶ g of H₂

Explanation:

(i) Calculate the mass of CO2(g) in gram produced by the reaction between 3 mol of CH4(g) and 2 mol of
O2(g) according to the equation : CH4(g) + 2O2(g) CO2(g) + 2H2O(g)

Answers

Answer: 0.1334983576 g

Explanation:

The mass must be conserved on both sides of the equation. Mass put in must must = mass put out. So we must start by finding the mass of the reactants and then the mass of 2H2O. Then we must subtractio the mass of the reactants from the mass of 2H2O which will gives us the mass of CO2.

Mass of CH4:

(12.0107)+ 4(1.00794) = 16.48246 g/mol

we are given three mols of CH4 so divide 3 mol by 16.48246 g/mol

3 mol/ 16.48246 g/mol = 0.1820116657 g CH4

Mass of 2O2:

2(15.99994) = 31.99988 g/mol

we are given 2 moles of 2O2 so divide 2 mol by 31.99988 g/mol  

2 mol/ 31.99988 g/mol = 0.0625002344 g 2O2

Mass of 2H2O:

2(1.00794)+(15.99994) = 18.01582 g/mol

we are given 2 moles of 2H2O so divide 2 mol by 18.01582 g/mol

2 mol/ 18.01582 g/mol = 0.1110135425 g 2H20

Now we add up the grams on the reactatnt side and subtract that number from the mass of 2H2O:

0.1820116657 g CH4 + 0.0625002344 g 2O2 = 0.2445119001 g (total of g of reactants)

0.2445119001 g -  0.1110135425 g =  0.1334983576 g CO2

Which of the following is NOT a synthetic material?

Multiple choice question.
cross out

A)
polyester

cross out

B)
bone china

cross out

C)
wood

cross out

D)
concrete

Answers

Answer: C) wood cross out

what factors should you consider to determining what variables to measure for the control of chemical process? answer quantitatively

Answers

One should consider factors such as the process constraints, the process dynamics, and process output requirements.

What are process constraints?

Process constraints are limitations on the process variables due to physical, chemical, or economic factors. A constraint is a limitation or bias on the variability or possibilities of change in the sort of such elements. A constraint is an effort by a group of elements to reduce the degrees of freedom of the elements of a system.

The selection of variables to measure for the control of a chemical process can be quantified using a process flow diagram and a process control hierarchy. The process flow diagram shows the process variables and their relationships, while the process control hierarchy shows the control loops and the measurement and control variables for each loop. The number and type of variables to measure depend on the complexity of the process, the desired control objectives, and the available instrumentation and control technologies.

Therefore, process constraints, the process dynamics, and process output requirements are the factors.

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8. What's the volume of 108g of a material if the material has a density of 0.90 g/mL?

A. 108.9 mL
B. 97.2 mL
C. 120 mL
D. 107.1 mL

Answers

Answer:

density = mass/volume

Rearranging, we get:

volume = mass/density

Substituting the given values, we get:

volume = 108g / 0.90 g/mL

volume = 120 mL

Therefore, the volume of the material is 120 mL. Answer: C

The density of a substance is its mass by volume. Then, the volume of the 108 g of material with a density of 0.90 g/ml is 120 mL.

What is density ?

Density is a physical property of matter that describes the amount of mass in a given volume of a substance. It is defined as the ratio of an object's mass to its volume.

Mathematically, density is expressed as:

Density = Mass / Volume

The unit of density depends on the units of mass and volume used. For example, in the SI system, the unit of mass is kilograms (kg) and the unit of volume is cubic meters (m³), so the unit of density is kg/m³.

Given that, density = 0.90 g/ml

mass = 108 g

then volume = mass/densiy

v = 108 g/0.900 g/ml = 120 mL.

Therefore, density of the material is 120 mL.

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the density of a fluid is given by the empirical equation p=70.5exp




the density fluid is given by the empirical equation p=70.5exp (82700000p) where rho is density (lbm/ft3)and p is the pressure (lbf/in2) a, what are the unit of 70.5 and 82700000

Answers

Answer:

The density equation is given by:

p = 70.5 * exp(82700000 * p)

where p is the pressure in pounds per square inch (lbf/in²) and ρ is the density in pounds per cubic foot (lbm/ft³).

To determine the units of the constants 70.5 and 82700000 in short, we can use dimensional analysis.

The unit of the exponential term is dimensionless, so we only need to consider the units of the constant term.

The unit of the density (ρ) is lbm/ft³, and the unit of the pressure (p) is lbf/in².

So, we can write the equation as:

ρ = (70.5 lbm/ft³) * exp(82700000 * p)

To get the units of the constant 70.5, we can divide both sides by the exponential term and simplify:

ρ / exp(82700000 * p) = 70.5 lbm/ft³

Therefore, the units of 70.5 are lbm/ft³.

To get the units of the constant 82700000, we can rearrange the equation and take the natural logarithm of both sides:

ln(ρ/70.5 lbm/ft³) = 82700000 * p

The units of the left-hand side are dimensionless, and the units of the right-hand side are 1/in². So, the units of the constant 82700000 are 1/in².

Compared with the rate of water loss before soaking, what difference, if any, would you expect in the rate of water loss after soaking the hand in alcohol? (Clue: Fats are soluble in alcohol.)

Answers

Lipids dissolve in alcohol, a solvent. It removes the skin's lipids, particularly from the stratum corneum.

Because the lipids that normally prevent water loss are removed during alcohol soaking, the rate of water loss increases.

Why does alcohol evaporate water?

Therefore, water may evaporate more slowly than other liquids despite having a lower molecular weight. The molecules of ethyl (rubbing) alcohol, which are more loosely bound than those of water, evaporate almost five times faster than water. Lower-energy, lower-temperature molecules are left behind when energetic molecules leave a liquid.

Question incomplete:

The rate of water loss from the skin of a hand was measured. Following the measurement, the hand was soaked in alcohol for 15 minutes. After all the alcohol had been removed from the hand, the rate of water loss was again measured. Compared with the rate of water loss before soaking, what difference, if any, would you expect in the rate of water loss after soaking the hand in alcohol?

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How many moles of S2 are needed to produce
.750 moles of SO2 gas?

Answers

Number of moles of S2 needed to produce 750 moles of SO2 is 375.

Mole calculationS2 + 202 ---> 2SO2 750 moles of SO2 = 375 moles of S2750 Mole Units750 ÷ 2 =375Balance the equation in step one. Chemical equations never have their individual components lost or destroyed; the yield of a reaction must precisely match the original reagents.Step 2: Converting the Units of a Substance Provided to Mole Conversion factors are applied during the conversion of supplied units into moles. Below, you'll find the most crucial conversion factors for converting between moles and grams, moles and gas volumes, moles and molecules, and moles and solutions. Similar to the ones outlined in the preceding section, these conversion factors also work Moreover, keep in mind that while these conversion factors are geared toward converting from one unit to another to determine moles, they can also be used to determine another unit to determine moles.

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Which set of reactants will be the most efficient (LEAST wasteful of materials) for the reaction?

Answers

We need to calculate the stoichiometric ratios of the reactants and choose the set that provides the required ratios with the least amount of excess or unused reactants.

How to determine most efficient chemicals?

To determine the most efficient set of reactants for a reaction, we should consider the stoichiometry of the reaction, which tells us the ratios of the reactants and products that are involved in the reaction. The most efficient set of reactants will be the one that produces the desired product with the least amount of excess or unused reactants, and hence the least amount of waste.

What is the example for that?

2A + 3B → 4C If we have 4 moles of A and 6 moles of B, we have the exact stoichiometric amounts required for the reaction to proceed, and all the reactants will be consumed completely to form 8 moles of product C. In this case, there will be no waste of materials, and the reaction will be the most efficient. On the other hand, if we have an excess of one of the reactants, for example, if we have 6 moles of A and 6 moles of B, then only 4 moles of A can react with 6 moles of B to produce 8 moles of C, and the remaining 2 moles of A will be unused and wasted. In this case, the reaction will be less efficient.

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check bracket.The temperature of an/
(dt h)²-(q nn)²( ja ki)⁴ /oven being heated using a pulsed resistance heater varies as T = 120 + 5cos(25t+30°) where t is the time in seconds. The temperature of the oven is being measured with a ther mo couple having a time constant of 5 s. ( a ) What are the maximum and minimum temperatures indicated by the thermocouple? ( What is the maximum difference between the actual temperature and the indicated temperature? ( c ) What is the time lag between the actual temperature and the indicated temperature?​

Answers

a. The maximum and minimum temperature of a thermocouple is   [tex]-200^{o} C to 350^{o} C[/tex].

Therefore the difference between the actual and indicated temperature is indicated as [tex](125*5 = 625^{o} C/s)[/tex]

c.The time lag between the actual temperature and the indicate temperature is equal to the time constant of the thermocouple.

What do you mean thermocouple ?

A sensor that detects temperature is a thermocouple. It is made up of two distinct metals that are attached at one end. A voltage is produced that is linked to temperature when the junction of the two metals is heated or cooled.

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if 100.0 ml ethyl alcohol weighs 78.5g ;determine the volume in litres occupied by 1,59 kg of ethyl alcohol​

Answers

Answer: 2.025

Explanation: Set up the ratio 100ml/78.5g = xml/1.59kg

Once you have your units in order, solve for x and then convert to liters and there you have your answer!

A sample of the compound weighs 80 grams. How many grams of cobalt are in the sample?

Answers

The mass of the unknown element cobalt is obtained as 40 g. This can be seen from the calculation that we have in the solution.

How can you use the molar mass of the compound to find the relative atomic mass of the unknown element?

If you have a compound that contains an unknown element, you can use the molar mass of the compound to find the relative atomic mass of the unknown element

We can see that the question has already given us the mass of the sample as we have and the percentage of the cobalt that we have in the sample.

50 = x/80 × 100

x = 50/100 × 80

= 40 g

Thus we would have a total of about 40 g of cobalt in the sample.

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Missing parts;

A sample of the compound weighs 80 grams.  If the mass percent of cobalt is 50%, How many grams of cobalt are in the sample?

What is the pressure exerted by a .50 mol sample of N₂ gas in a 10.0L container
at 298K?

Answers

The pressure exerted by the nitrogen gas in the container of volume 10.0L  at a temperature of 298K is 12.14 atm.

What is pressure in chemistry?

Pressure in chemistry is defined as the force per unit area exerted by a gas on the walls of its container. It is the result of the constant, random motion of gas molecules colliding with the walls of the container.

To find the pressure exerted by the N₂ gas, we can use the ideal gas law:

PV = n*R*T

R is the universal gas constant, whose value is constant and is given by 0.0821 L·atm/mol·K

To solve for P:

P = n*R*T/V

Substituting the given values, we get:

P = (0.50 mol) *  (298 K) / (10.0 L)* (0.0821 L·atm/mol·K)

P = 12.14 atm

Therefore, the pressure exerted by the N₂ gas in the 10.0L container at 298K is 12.14 atm.

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If I leave 800 mL of 0.70 M sodium chloride solution uncovered on a windowsill and 300 mL of the solvent evaporates, what will the new concentration of the sodium chloride solution be?



Answers

Answer:

the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.

Explanation:

To calculate the new concentration of the sodium chloride solution after 300 mL of solvent evaporates, we need to first determine how many moles of solute are present in the original solution:

moles of solute = concentration x volume

moles of solute = 0.70 M x 0.800 L

moles of solute = 0.56 moles

Next, we can calculate the new volume of the solution after 300 mL evaporates:

new volume = original volume - amount evaporated

new volume = 0.800 L - 0.300 L

new volume = 0.500 L

Finally, we can calculate the new concentration of the solution using the moles of solute and the new volume:

new concentration = moles of solute / new volume

new concentration = 0.56 moles / 0.500 L

new concentration = 1.12 M

Therefore, the new concentration of the sodium chloride solution after 300 mL of solvent evaporates is 1.12 M.

Start with a 1.0 L solution with a 0.40 M concentration of sulfuric acid. The above solution is divided into two equal parts of the same volume. To the first part, 0.50 L of water is added. To the second part 1.5 L of water are added. After the previous procedure, the two parts are mixed and 2.0 L of 0.1 M sulfuric acid are added to this new solution. Determine the final molar concentration.

It’s urgent, please!

Answers

Answer:

Explanation:Before dividing the initial solution:

Initial volume = 1.0 L

Initial concentration = 0.40 M

After dividing into two equal parts:

Each part has a volume of 0.5 L

The first part has a concentration of 0.40 M

The second part has a concentration of 0.20 M (diluted by 50% with 1.5 L of water)

When the two parts are mixed:

Total volume = 1.0 L + 0.5 L + 0.5 L + 1.5 L = 3.5 L

Total moles of sulfuric acid = (1.0 L x 0.40 M / 1000) + (0.5 L x 0.40 M / 1000) + (0.5 L x 0.20 M / 1000) + (1.5 L x 0 / 1000) = 0.5 mol

Final concentration before adding more sulfuric acid = 0.5 mol / 3.5 L = 0.14 M

When 2.0 L of 0.1 M sulfuric acid are added:

Total volume = 3.5 L + 2.0 L = 5.5 L

Total moles of sulfuric acid = 0.5 mol + (2.0 L x 0.1 M / 1000) = 0.7 mol

Final concentration = 0.7 mol / 5.5 L = 0.13 M

Therefore, the final molar concentration of the solution is 0.13 M.

In a perfect world, your calorimeter will not exchange any heat with its contents. In this perfect world, if hot water loses 75 calories when cool metal pieces are poured in, how many calories do the metal pieces gain?​

Answers

Answer:

In a perfect world, where the calorimeter does not exchange any heat with its contents, the amount of heat lost by the hot water will be equal to the amount of heat gained by the cool metal pieces. This is due to the principle of conservation of energy, which states that energy cannot be created or destroyed, only transferred from one form to another. Therefore, the number of calories gained by the metal pieces will be equal to the number of calories lost by the hot water, which is 75 calories.

Explanation:

In summary, according to the principle of conservation of energy, in a perfect world where a calorimeter does not exchange any heat with its contents, the number of calories gained by the cool metal pieces will be equal to the number of calories lost by the hot water, which is 75 calories.

write down the formulas and predict the products. Name and balance the equation iron(ii) bromide + Barium Chloride

Answers

The formula for iron(II) bromide is FeBr2, while the formula for barium chloride is BaCl2. The products of the reaction are barium bromide (BaBr2) and iron(II) chloride (FeCl2).

What is Balanced Equation ?

A balanced chemical equation is a symbolic representation of a chemical reaction that shows the relative numbers of reactant and product molecules or ions involved. In a balanced equation, the number of atoms of each element must be the same on both the reactant and product sides, in order to obey the law of conservation of mass.

The balanced chemical equation for the reaction between iron(II) bromide and barium chloride is:

FeBr2 + BaCl2 → BaBr2 + FeCl2

In this reaction, the iron(II) ion (Fe2+) in iron(II) bromide (FeBr2) is replaced by the barium ion (Ba2+) from barium chloride (BaCl2), forming barium bromide (BaBr2) and iron(II) chloride (FeCl2). The balanced equation shows that two bromide ions (Br-) and two chloride ions (Cl-) are involved in the reaction, which ensures that the equation is balanced in terms of both mass and charge.

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The vapor pressure of mercury at 25 degrees Celsius is 1.85 mmHg . Calculate the vapor pressure in atm and torr . Round each of your answers to 3 significant digits.

Answers

The vapor pressure of mercury at 25°C is 1.85 torr. To convert the vapor pressure of mercury from mmHg to atm, we can use the conversion factor 1 atm = 760 mmHg:

Why does vapour pressure exist?

A liquid's molecules enter the gaseous phase when heated because they have enough kinetic energy to overcome the forces holding them in the liquid. By doing this, they produce a population of molecules in the vapour phase above the liquid, which leads to the creation of a pressure—the liquid's vapour pressure.

1.85  mmHg x (1 atm / 760 mmHg) = 0.00243 atm (rounded to 3 significant digits)

Therefore, the vapor pressure of mercury at 25°C is 0.00243 atm.

To convert the vapor pressure of mercury from mmHg to torr, we can simply use the definition that 1 torr = 1 mmHg:

1.85 mmHg = 1.85 torr (rounded to 3 significant digits)

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Why is capturing quality data and the use of analytics critical for the fire and emergency services?

Answers

Capturing quality data and using analytics are critical for the fire and emergency services to improve situational awareness, enhance resource management, improve incident management, and develop better planning and prevention strategies.

What is fire?

Fire is a chemical reaction that occurs when a fuel (such as wood, paper, or gasoline) combines with oxygen in the air, producing heat and light. The reaction is exothermic, meaning it releases energy in the form of heat and light. Fire requires three elements to exist: fuel, oxygen, and heat. These elements are often referred to as the "fire triangle."

Capturing quality data and using analytics are critical for the fire and emergency services for several reasons:

Improved situational awareness: Fire and emergency services need accurate, up-to-date information to make informed decisions and respond effectively to emergencies.

Enhanced resource management: Fire and emergency services often operate under tight budget constraints and need to make the most of their resources.

Improved incident management: The ability to capture and analyze data in real-time can help fire and emergency services manage incidents more effectively.

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Study each picture that depicts the involvement of a particular gland in the endocrine system. Write down the name of the endocrine gland and explain its effect, according to its function.

Answers

The thyroid gland produces and secretes two hormones, thyroxine (T4) and triiodothyronine (T3), which are involved in regulating the body's metabolism.

What is thyroid gland?

The thyroid gland is regulated by the pituitary gland, which secretes thyroid-stimulating hormone (TSH). When TSH binds to receptors on the thyroid gland, it stimulates the production and secretion of T4 and T3. These hormones play an important role in the growth and development of the body's tissues and organs, including the brain, heart, and muscles.

What is hyperthyroidism?

If there is an overproduction of thyroid hormones, it can lead to hyperthyroidism, which can cause symptoms such as weight loss, nervousness, and rapid heartbeat. On the other hand, an underproduction of thyroid hormones can lead to hypothyroidism, which can cause symptoms such as fatigue, weight gain, and cold intolerance.

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A 15.0 g sample of potassium chlorate is decomposed, according to the following balanced equation:

2 KClO3(s) ----> 2 KCl(s) + 3 O2(g)

Part A) Assuming complete decomposition, calculate the volume of O2 (in L) collected at 27°C and 756 torr pressure.

Part B) If the oxygen gas in the reaction above is collected over water, it will be saturated with water vapor. Will you need to adjust the pressure of 756 torr?

Answers

We can use the ideal gas law to solve for the volume of oxygen gas produced:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant (0.08206 L atm/mol K), and T is the temperature in Kelvin.

First, we need to calculate the number of moles of oxygen gas produced from the given mass of potassium chlorate. We can use the molar mass of KClO3 (122.55 g/mol) and the stoichiometry of the balanced equation:

15.0 g KClO3 x (1 mol KClO3/122.55 g KClO3) x (3 mol O2/2 mol KClO3) = 0.184 mol O2

Now we can solve for the volume of oxygen gas at 756 torr (convert to atm) and 27°C (convert to Kelvin):

P = 756 torr = 0.996 atm

T = 27°C + 273.15 = 300.15 K

n = 0.184 mol

R = 0.08206 L atm/mol K

V = nRT/P = (0.184 mol)(0.08206 L atm/mol K)(300.15 K)/(0.996 atm) = 4.76 L

Therefore, the volume of O2 collected at 27°C and 756 torr pressure is 4.76 L.

Part B:

If the oxygen gas is collected over water, it will be saturated with water vapor. This means that the total pressure in the container will be the sum of the pressure of the oxygen gas and the pressure of the water vapor. The pressure of the water vapor can be calculated using the vapor pressure of water at the given temperature.

At 27°C, the vapor pressure of water is 26.7 torr. Therefore, the total pressure in the container will be:

P total = P oxygen gas + P water vapor = 756 torr + 26.7 torr = 782.7 torr

Since the problem provided the pressure in torr, we need to convert to atm before using the ideal gas law. Therefore, we need to adjust the pressure to:

P = 782.7 torr x (1 atm/760 torr) = 1.03 atm

We can then use the same equation as in part A to calculate the volume of oxygen gas:

V = nRT/P = (0.184 mol)(0.08206 L atm/mol K)(300.15 K)/(1.03 atm) = 4.32 L

Therefore, if the oxygen gas is collected over water, the volume of oxygen gas produced would be 4.32 L instead of 4.76 L (as in part A).

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Predicting the units of the solution to a basic quantitative... A student sets up the following equation to solve a problem in solution stoichiometry. (The ? stands for a number the student is going to calculate.) Enter the units of the student's answer. (0.22L)×(1 mL/10‐³ L)×(1.57g/mL)/(61.04 g/mol) = ?​

Answers

Answer:

(0.22 L) × (1 mL/10^-3 L) × (1.57 g/mL) / (61.04 g/mol) = ?

First, let's simplify the units:

(0.22 L) × (1000 mL/1 L) × (1.57 g/mL) / (61.04 g/mol) = ?

(0.22 L) × (1570 g/mol) / (61.04 g/mol) = ?

Now we can cancel out the units of g/mol:

(0.22 L) × (1570/61.04) = ?

(0.22 L) × 25.73 = ?

5.66 L·g

Therefore, the units of the student's answer are L·g.

what is the product of the reaction of 2,2-dichloro-3-methylbutane with water. how does this product react with OH-

Answers

The reaction of 2,2-dichloro-3-methylbutane with water results in the formation of 3-methyl-2-butanol, which can react with OH- in a nucleophilic substitution reaction to form 3-methyl-2-butyl alcohol and water.

The reaction can be represented by the following equation:

2,2-dichloro-3-methylbutane + H2O → 3-methyl-2-butanol + H+ + Cl-

The reaction of 2,2-dichloro-3-methylbutane with water can result in the formation of an alcohol and a hydrogen ion. The product of this reaction is 3-methyl-2-butanol.

The reaction can be represented by the following equation:

2,2-dichloro-3-methylbutane + H2O → 3-methyl-2-butanol + H+ + Cl-

In this reaction, one of the chlorine atoms from 2,2-dichloro-3-methylbutane is replaced by a hydroxyl group (-OH) from water, resulting in the formation of an alcohol group (-OH) in the product, 3-methyl-2-butanol. The other chlorine atom remains as an ion, Cl-.

The product, 3-methyl-2-butanol, can react with OH- in a nucleophilic substitution reaction. In this reaction, the hydroxide ion (OH-) acts as a nucleophile and attacks the carbon atom that is attached to the leaving group (the -OH group) in the 3-methyl-2-butanol molecule. The leaving group then departs with its pair of electrons, forming a new bond with the nucleophile (OH-). The result is the formation of a new alcohol molecule.

The reaction can be represented by the following equation:

3-methyl-2-butanol + OH- → 3-methyl-2-butyl alcohol + H2O

In this reaction, the -OH group of 3-methyl-2-butanol is replaced by the hydroxide ion (OH-) to form 3-methyl-2-butyl alcohol, and a water molecule is formed as a byproduct.

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What does volume measure?
A. The space a substance takes up
B. The amount of energy in a substance
C. The phase of matter of a substance
D. The amount of matter (particles) in a substance

Answers

Volume is the measure of the space a substance takes up, hence the correct option is A.

Various types of measurements

Nominal, ordinal, interval, and ratio measurements are the four main types of measurement.

An object or event's attributes are quantified through measurement so that they can be compared to those of other things or events. In other words, measurement is the process of comparing a physical quantity to a fundamental reference quantity of the same kind to determine how big or small it is.

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C₂H5OH + 302 → 2CO₂ + 3H₂O AH-1367kJ/mol
How many grams of carbon dioxide are produced when 370. kJ of energy are used in the following reaction?

Answers

We can start by using the given enthalpy change and the balanced equation to calculate the amount of moles of carbon dioxide produced:

1 mol of C2H5OH produces 2 mol of CO2

-1367 kJ/mol is released when 1 mol of C2H5OH is combusted

370 kJ of energy are used in the reaction

Now we can use a proportion to find the number of moles of C2H5OH that produce 370 kJ of energy:

-1367 kJ/mol / 1 mol of C2H5OH = -x kJ / (2 mol of CO2)

Solving for x gives:

x = (370 kJ) (1 mol of C2H5OH) / (-1367 kJ/mol) (2 mol of CO2)

x = 0.1355 mol of CO2

Finally, we can use the molar mass of CO2 (44.01 g/mol) to find the mass of CO2 produced:

mass of CO2 = number of moles of CO2 * molar mass of CO2

mass of CO2 = 0.1355 mol * 44.01 g/mol = 5.96 g of CO2

Therefore, when 370 kJ of energy are used in the reaction, 5.96 g of carbon dioxide are produced.

Cl2 + 2NaBr → 2NaCl + Br2


How many moles of bromine gas, are produced by the reaction of chlorine gas and of 5.2 moles of sodium bromide, NaBr?

Answers

Answer:

1 mole of Cl2 reacts with 2 moles of NaBr to produce 1 mole of Br2.

So, to calculate the number of moles of Br2 produced, we first need to find the number of moles of Cl2 required to react with 5.2 moles of NaBr. Since the stoichiometric ratio of Cl2 to NaBr is 1:2, we need half as many moles of Cl2 as moles of NaBr:

Number of moles of Cl2 = 5.2 moles NaBr / 2 = 2.6 moles Cl2

Now we can use the stoichiometric ratio between Cl2 and Br2 to calculate the number of moles of Br2 produced:

1 mole Cl2 produces 1 mole Br2

Therefore, 2.6 moles Cl2 will produce 2.6 moles Br2.

Explanation:

Chemistry Help!
1. Imagine that you are dissolving a red Gatorade mix in water.
a. What is the solute?
b. What is the solvent?
c. What is the solution?
d. What could you do to increase the molarity of the Gatorade in the water?

Answers

Answer:

a. The solute is the substance that is being dissolved, in this case, the red Gatorade mix.

b. The solvent is the substance in which the solute is being dissolved, in this case, water.

c. The solution is the resulting homogeneous mixture of the solute (red Gatorade mix) and the solvent (water).

d. To increase the molarity of the Gatorade in the water, you could add more Gatorade mix to the water while keeping the volume of the solution constant. Alternatively, you could decrease the volume of water while keeping the amount of Gatorade mix constant, which would increase the concentration of Gatorade in the solution.

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Consider a solution that is 1.4×10−2 M in Ba2+ and 1.9×10−2 M in Ca2+. What minimum concentration of Na2SO4 is required to cause the precipitation of the cation that precipitates first? Express your answer using two significant figures.

Answers

Tο determine which catiοn will precipitate first, we need tο cοmpare the sοlubility prοducts (Ksp) οf their respective sulfates. The catiοn with the smaller Ksp value will precipitate first. The Ksp values fοr BaSO₄ and CaSO₄ are:

Ksp(BaSO₄) = 1.1 × 10⁻¹⁰

Ksp(CaSO₄) = 2.4 × 10⁻⁵

What is a catiοn?

A catiοn is an iοn with a pοsitive charge that is fοrmed by the lοss οf οne οr mοre electrοns frοm a neutral atοm. Catiοns are fοrmed when atοms lοse electrοns tο achieve a mοre stable electrοn cοnfiguratiοn, typically by becοming isοelectrοnic with a nearby nοble gas.

Since the Ksp value fοr BaSO4 is smaller, it will precipitate first. Tο calculate the minimum cοncentratiοn οf Na₂SO₄ required tο precipitate all οf the Ba2+ iοns, we need tο use the sοlubility prοduct expressiοn fοr BaSO₄:

BaSO₄(s) ⇌ Ba2+(aq) + SO₄₂-(aq)

Ksp = [Ba2+][SO₄₂-]

Since all οf the Ba2+ iοns will be precipitated, the cοncentratiοn οf Ba2+ will be zerο οnce precipitatiοn is cοmplete. Thus, the Ksp expressiοn simplifies tο:

Ksp = [SO₄₂-]²

Sοlving fοr [SO₄₂-], we get:

[SO₄₂-] = sqrt(Ksp) = sqrt(1.1 × 10⁻¹⁰) = 1.05 × 10⁻⁵ M

This means that the cοncentratiοn οf Na₂SO₄ needs tο be at least 1.05 × 10⁻⁵M tο prοvide enοugh SO₄₂- iοns tο precipitate all οf the Ba₂+ iοns. We rοund this tο twο significant figures, giving a final answer οf 1.1 × 10⁻⁵ M Na₂SO₄.

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