PLEASE HELP QUICK WILL GIVE BRAINLIEST

Descent  = 10 feet

Time required = 2 1/2 minutes.

The rate of descent = (10 feet)/(2.5 mn) = 4 ft/min

In 6 minutes, the descent will be

(4 ft/min)*(6 min) = 24 ft

Answer:

(a) 4 feet/minute

(b) 24 feet

Step-by-step explanation:

9x - 2 = 5x + 54 because these angles are corresponding

9x - 5x = 54 + 2 add/subtract like terms

4x = 56 and this divided by 4

x = 14

9x - 2 + 10y + 6 = 180° because these two angles makes a straight line

9×14 - 2 + 10y + 6 = 180°

126 - 2 + 10y + 6 = 180° add like terms

130 + 10y = 180° subtract 130 from both sides

10y = 50 divide by 10

y = 10

Answer:

89

eighty-nine

Ants

Step-by-step explanation:

Answer:

i think its B

Step-by-step explanation:

Answer: 3

Step-by-step explanation:

Given data:

Area of smaller flower bed = 25/4

Area of bigger flower bed = 75/4.

Solution:

75/4 = 25/4

Divide both sides 5

15/4 = 5/4

= 15/4 / 5/4

= 15/4 / 4/5

= 3

Answer:

The larger flower bed has 3 square ft of space for every square foot of the smaller flower bed

Step-by-step explanation:

In other words in this question, we are asked to calculate how many of the smaller flower bed is contained in the larger one.

Mathematically, that would be 25/4 squares ft divided by 75/4 squared feet

Thus will be 75/4 divided by 25/4

Hence 75/4 * 4/25 = 3

Answer:

a) 0.2318

b) 0.2609

c) No it is not unusual for a broiler to weigh more than 1610 grams

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

Mean 1387 grams and standard deviation 192 grams. Use the TI-84 Plus calculator to answer the following.

(a) What proportion of broilers weigh between 1150 and 1308 grams?

For 1150 grams

z = 1150 - 1387/192

= -1.23438

Probability value from Z-Table:

P(x = 1150) = 0.10853

For 1308 grams

z = 1308 - 1387/192

= -0.41146

Probability value from Z-Table:

P(x = 1308) = 0.34037

Proportion of broilers weigh between 1150 and 1308 grams is:

P(x = 1308) - P(x = 1150)

0.34037 - 0.10853

= 0.23184

≈ 0.2318

(b) What is the probability that a randomly selected broiler weighs more than 1510 grams?

1510 - 1387/192

= 0.64063

Probabilty value from Z-Table:

P(x<1510) = 0.73912

P(x>1510) = 1 - P(x<1510) = 0.26088

≈ 0.2609

(c) Is it unusual for a broiler to weigh more than 1610 grams?

1610- 1387/192

= 1.16146

Probability value from Z-Table:

P(x<1610) = 0.87727

P(x>1610) = 1 - P(x<1610) = 0.12273

≈ 0.1227

No it is not unusual for a broiler to weigh more than 1610 grams

Answer:

B

Step-by-step explanation:

y2-y1/x2-x1

4-2/4-0

2/4=1/2

Answer: 1/2

Explanation: the equation is y = 1/2x + 2

Answer:

10

Step-by-step explanation:

Put the h+2 on the outside and 10h+20 on the inside

h+2 can go into 10h+20 ten times.

So the final answer is 10

Answer:

Yes

Step-by-step explanation:

The FIFO  method of process costing assumes that the opening work in process is the first group of units to be processed and completed during the current period. The opening work in progress is charged separately to completed production and the cost per unit is based only on the current period costs and the production for the current period. The closing work in process is assumed to come from the new units started during the period.

Complete Question

The  complete question is shown on the first uploaded image

Answer:

a

[tex]\^ p_1 =  0.8102 [/tex]

b

[tex]\^ p_2 =  0.6904 [/tex]

c

[tex]\^ p_3 =  0.3701 [/tex]

Step-by-step explanation:

From the question we are told that

   The sample size is  n  =  743

    The number that said social media makes them feel more connected  to what is going on in their friends' lives is  k =  602

   The number that said social  media helps them interact with a more diverse group of people is  y =  513

   The  number that said feel pressure to post content that will get a lot of likes and comments is  c  =  275

Generally a point estimate of the proportion of teens aged 13 to 17  who say social media makes them feel more connected to what is going on in their friends' lives is mathematically represented as

        [tex]\^ p_1 =  \frac{k}{n}[/tex]

=>      [tex]\^ p_1 =  \frac{602}{743 }[/tex]\

=>      [tex]\^ p_1 =  0.8102 [/tex]

Generally a point estimate of the proportion of teens aged 13 to 17  who say social media helps them interact with a more diverse group of people is mathematically represented as

        [tex]\^ p_2 =  \frac{k}{n}[/tex]

=>      [tex]\^ p_2 =  \frac{513}{743 }[/tex]\

=>      [tex]\^ p_2 =  0.6904 [/tex]

Generally a point estimate of the proportion of teens aged 13 to 17   who feel pressure to post content that will get a lot of likes and comments is mathematically represented as

        [tex]\^ p_3 =  \frac{k}{n}[/tex]

=>      [tex]\^ p_3 =  \frac{275}{743 }[/tex]

=>      [tex]\^ p_3 =  0.3701 [/tex]

The point estimate of the teens aged to who say social media makes them feel more connected is 0.8102.

The point estimate of the proportion of teens aged to who say social media makes them feel more connected to what is going on in their friends' lives will be:

= Number of teens / Sample size

= 602/743

=™0.8102

The point estimate of the proportion of teens aged to who say social media helps them interact with a more diverse group of people will be:

= 513/743

= 0.6904

The point estimate of the proportion of teens aged to who feel pressure to post content that will get a lot of likes and comments will be:

= 275/743

= 0.3701

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Answer:

3/5

Step-by-step explanation:

Answer:

Yup the answer is 3/5 :))

Step-by-step explanation:

Answer

I would say the 3rd one.

Step-by-step explanation:

I do not really remember this but I am in 8th grade math to (Algebra)

Answer:

62 degrees

Step-by-step explanation:

If 167 degrees is the whole angle measurement, then you take 167-105.

Answer:

the anwser is 24 please mark brianliest

Answer:

The answer is 24.

The probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.

Here,

Since the length of the pipes follows a uniform distribution on the interval [10 feet, 10.57 feet], the probability density function (PDF) for each pipe is:

f(x) = 1 / (10.57 - 10) = 1 / 0.57 ≈ 1.7544 for 10 ≤ x ≤ 10.57

Since the lengths of the pipes are independent, the joint probability density function (PDF) of X and Y is the product of their individual PDFs:

f(x, y) = f(x) * f(y) = 1.7544 * 1.7544 = 3.0805 for 10 ≤ x ≤ 10.57 and 10 ≤ y ≤ 10.57

Now, we want to find the probability that the second pipe (Y) is more than 0.11 feet longer than the first pipe (X).

Mathematically, we want to find P(Y > X + 0.11).

Let's set up the integral to calculate this probability:

P(Y > X + 0.11) = ∬[10 ≤ x ≤ 10.57] [y > x + 0.11] f(x, y) dx dy

We integrate with respect to x first and then with respect to y:

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] ∫[10 ≤ x ≤ y - 0.11] f(x, y) dx dy

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [∫[10 ≤ x ≤ y - 0.11] 3.0805 dx] dy

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (x)] from x = 10 to x = y - 0.11 dy

P(Y > X + 0.11) = ∫[10 ≤ y ≤ 10.57] [3.0805 * (y - (10 - 0.11))] dy

P(Y > X + 0.11) = 3.0805 * ∫[10 ≤ y ≤ 10.57] (y - 9.89) dy

P(Y > X + 0.11) = 3.0805 * [(y² / 2) - 9.89y] from y = 10 to y = 10.57

P(Y > X + 0.11) = 3.0805 * [((10.57)² / 2) - 9.89 * 10.57 - (((10)² / 2) - 9.89 * 10)]

P(Y > X + 0.11) = 3.0805 * [((111.7249 / 2) - 104.9135 - (50 / 2 - 98.9)]

P(Y > X + 0.11) = 3.0805 * [(55.86245 - 104.9135 + 49.9)]

P(Y > X + 0.11) = 3.0805 * [0.84895]

P(Y > X + 0.11) ≈ 2.6092

Therefore, the probability that the second pipe (with length Y) is more than 0.11 feet longer than the first pipe (with length X) is approximately 2.6092%.

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Answer:

The function written in python is as follows:

import random

def simulate():

    count = 0

    for i in range(1,51):

         num = random.randint(200,1000)

         if num == 781:

              count = count + 1

    print(count)

Step-by-step explanation:

This line imports the random library

import random

This line defines the function

def simulate():

This line initializes count to 0

    count = 0

This line iterates from 1 to 50

    for i in range(1,51):

This line generates random number between 200 and 999

         num = random.randint(200,1000)

This line checks if random number is 781

         if num == 781:

If yes, the count variable is incremented by 1

              count = count + 1

This line prints the number of times 781 is generated

    print(count)

Answer:

True

Step-by-step explanation:

True because if AC = BC, then the triangles are the same.

The side AC is congruent to the side BC the statement is true.

The Side-Angle-Side Congruence Theorem (SAS) defines two triangles to be congruent to each other if the included angle and two sides of one are congruent to the included angle and corresponding two sides of the other triangle.

In the given figure we can see that the ∠ACD ≅ ∠BCD and AB ⊥ CD mean that the line CD is dividing the line AB into two equal parts.

Therefore, the side AC is congruent to the side BC the statement is true.

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Answer:

c

Step-by-step explanation:

c/2-d

Answer:

[tex]\sqrt{26}[/tex]

Step-by-step explanation:

there are 11356.2 milliliters in 3 us gallons

Answer:

The answer is 20 and 200.

Step-by-step explanation:

Answer:

32/3

Step-by-step explanation:

Answer:

As a fraction: [tex]\mathbf{\dfrac{363}{2}}[/tex]

As a colon,  363:2

By using the word to; we have: 363 to 2

Step-by-step explanation:

A ratio is a comparison of two quantities. We can write a ratio as a fraction, using the word “to,” or using a colon.

A rate is a ratio that compares two different units, such as distance and time, or a ratio that compares two different things measured with the same unit, such as cups of water and litres of petrol.

We can use a ratio to compare the number of days regardless of employing any professional sports events each year with the total number of days in a year.

The ratio with which we can write, that compares days with games in a year with two days without them can be written in three ways.

Suppose there are 365 days in a year and it appears that two days in that year exist without a game.

i.e.

365 - 2(days without game) = 363 days with a game

Then:

As a fraction: [tex]\mathbf{\dfrac{363}{2}}[/tex]

As a colon,  363:2

By using the word to; we have: 363 to 2

Answer:

a to b        a:b         a/b

Ratio that compare days with games to days without them:

1- 363 to 2

2- 363 : 2

3- 363 / 2

Step-by-step explanation:

Ratio is a comparison of two or more numbers that indicates their sizes in relation to each other.

A ratio compares two quantities by division, with the dividend.

We can write a ratio to compare the number of days without any professional sports events each year with the total number of days in a year.

There are three ways to write a ratio to express the relationship between two quantities.

a to b        a:b         a/b

Ratio that compare days with games to days without them:

1- 363 to 2

2- 363 : 2

3- 363 / 2

These are the three ways to describe a ratio.

Answer:

24 miles in 1 hour

144 divded by 6 = 24

Hope this helps!  If so I would appricate brainliest

Answer:

Step-by-step explanation:

In order to solve this question we use ratio and proportion

From the question, for 6 hours John drove 144 miles

If 6 hours = 144 miles

Then one hour would be

[tex] \frac{144 \times 1}{6} = \frac{144}{6} \\ [/tex]

We have the final answer as

Answer: bsf google

Step-by-step explanation: go to google look it up and find the answer

Answer:

x-3

Step-by-step explanation:

It's x-3 because if you put 12-3 it will be 9 but if you add x+4 it will be 16

Complete Question

The complete question is shown on the first uploaded image

Answer:

a i

[tex]P(X  < 185 ) =  0.3085 [/tex]

a ii

[tex]P(X  > 195 ) =  0.3085 [/tex]

a iii

[tex]P(185 < X <  195 ) = 0.3829  [/tex]

b

[tex]x =  208.8[/tex]

Step-by-step explanation:

From the question we are told that  

   The mean is  [tex]\mu =  190[/tex]

   The standard deviation is  [tex]\sigma  =  10[/tex]

Generally the probability is  less than 185  is mathematically represented as

      [tex]P(X  < 185 ) =  P(\frac{X - \mu }{\sigma } < \frac{185 - 190 }{10 }   )[/tex]

Generally [tex]\frac{X - \mu }{\sigma } = Z (The  \ standardized \  value  \  \ of  \  X)[/tex]

=>   [tex]P(X  < 185 ) =  P(Z< -0.5)[/tex]

From the z-table the p value  of  (Z< -0.5) is

    [tex]P(Z< -0.5) = 0.3085[/tex]

So

    [tex]P(X  < 185 ) =  0.3085 [/tex]

Generally the probability is  less than 185  is mathematically represented as

      [tex]P(X > 195 ) =  P(\frac{X - \mu }{\sigma } > \frac{195 - 190 }{10 }   )[/tex]

=>   [tex]P(X  >  195 ) =  P(Z > 0.5)[/tex]

From the z-table the p value  of  (Z > 0.5) is

    [tex]P(Z > 0.5) = 0.3085[/tex]

So

    [tex]P(X  > 195 ) =  0.3085 [/tex]

Generally the probability is  less than 185  is mathematically represented as

      [tex]P(185 < X <  195 ) =  P( \frac{185 - 190 }{10 } <  \frac{X - \mu }{\sigma } <  \frac{195 - 190 }{10 } )[/tex]

=>   [tex]P(185 < X <  195 ) =  P(-0.5 < Z > 0.5)[/tex]

=>   [tex]P(185 < X <  195 ) = P(Z  <  0.5 ) -  P(Z <  -0.5) [/tex]

From the z-table the p value  (Z <  0.5) and  (Z <  -0.5) is  

    [tex]P(Z < 0.5) =  0.6915 [/tex]

and  

   [tex]P(Z < - 0.5) = 0.3085[/tex]

So

=>   [tex]P(185 < X <  195 ) = 0.6915 -  0.3085 [/tex]

=>   [tex]P(185 < X <  195 ) = 0.3829  [/tex]

Generally the level of cholesterol the 97th percentile represents  is mathematically evaluated as

    [tex]P(X < x ) =  0.97[/tex]

=> [tex]P(X < x ) = P(\frac{X - \mu}{\sigma }  <  \frac{x - 190}{10 }  ) = 0.97[/tex]

=>   [tex]P(X < x ) = P(Z <  \frac{x - 190}{10 }  ) = 0.97[/tex]

From the z-table  the z-score for  0.97  is  

      [tex]z-score =  1.88[/tex]

=>

  [tex]\frac{x - 190}{10 } =  1.88[/tex]

=>[tex]x =  208.8[/tex]