The probability that the next patient arrives during the following 20 minutes is approximately 0.776.
(a) The probability that exactly 7 patients will arrive during a 90-minute period can be found by using the Poisson distribution formula.Poisson distribution formula:P(X = x) = (e-λ * λx) / x!Where: λ is the average number of events per unit of time or space, x is the number of occurrences, e is the exponential constant equal to 2.71828.x! means x factorial that is x(x − 1)(x − 2)⋯(2)(1).Here, λ = 9/60 = 0.15 (since there are 9 arrivals in one hour, there would be 9/60 arrivals in 1 minute)We are to find the probability of exactly 7 patients arriving in 90 minutes.The time period is 90/60 = 1.5 hours. Hence, λ = 0.15 × 1.5 = 0.225P(X = 7) = (e-λ * λ7) / 7! = (e-0.225 * 0.2257) / 7! = 0.085 ≈ 0.09Therefore, the probability that exactly 7 patients will arrive during a 90 minutes period is approximately 0.09(b) We can calculate the probability of at least 30 minutes passing until the next patient arrives by using the cumulative distribution function (CDF) of the exponential distribution.Exponential distribution formula:f(x) = λe-λxwhere λ is the rate parameter, x is the time period, and e is the exponential constant equal to 2.71828.The mean waiting time between two successive arrivals is 60/9 = 6.67 minutes.Hence, λ = 1/6.67 = 0.15The probability of at least 30 minutes passing until the next patient arrives can be calculated as follows:P(X > 0.5) = 1 - P(X ≤ 0.5) = 1 - (1 - e-λx) = e-λx = e-0.15×0.5 ≈ 0.776Therefore, the probability that at least 30 minutes will pass until the next patient arrives is approximately 0.776.(c) The probability that the next patient arrives during the following 20 minutes can be calculated as follows:P(X > 1) = 1 - P(X ≤ 1) = 1 - (1 - e-λx) = e-λx = e-0.15×1/3 ≈ 0.776Therefore, the probability that the next patient arrives during the following 20 minutes is approximately 0.776.
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I need help with this demon!
The percentage of of the shaded region is 74.8%
What is area of a circle?A circle is simply a round shape that has no corners or line segments. It is a closed curve shape in geometry. The enclosed body of a circle is called the circumference.
The space enclosed by the boundary of a plane figure is called its area. The area of a figure is the number of unit squares that cover the surface of a closed figure. Area is measured in squared units.
The area of a circle is expressed as :
πr²
The area of the shaded part = area of big circle - area of small circle
= 3.14(8.01²-4.02²)
= 3.14(64.16-16.16)
= 3.14( 48)
= 150.72in²
area of the big circle = 3.14 × 64.16 = 201.46
therefore the percentage of the shaded region of the point = 150.72/201.46 × 100
= 74.8% ( nearest tenth)
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I need help solving this problem
By speed fοrmula, light frοm the star takes abοut 1.3 x 10⁹secοnds tο reach Earth.
What is speed?Speed is defined as the distance travelled by an οbject in a given amοunt οf time. Speed is a scalar quantity, meaning that it has magnitude but nο directiοn.
Mathematically, speed is calculated as fοllοws:
speed = distance/time
Where "distance" is the distance travelled by the οbject, and "time" is the time it takes fοr the οbject tο travel that distance.
We can use the fοrmula:
time = distance/speed
where distance is the distance frοm the star tο Earth, and speed is the speed οf light.
Putting the values, we get:
time = (3.9 x 10¹⁴ km) / (3.0 x 10⁵km/s)
Simplifying, we can divide the distances and divide the pοwers οf ten:
time = 1.3 x 10⁹ s
Therefοre, light frοm the star takes abοut 1.3 x 10⁹secοnds tο reach Earth.
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The percent of carbon-14 remaining in a fossil can be found using the exponential expression (1/2)^t/5730 where t represents the age of the fossil in years. Rewrite the percent as an exponential expression with a base of 2
The percent of carbon remaining after 30642 years if, the half-life of carbon is 5730 years would be 3.1%
Total time is given: 30642 years
Half-Life of carbon-14 : 5730 years
After 1 half-life of the carbon-14 remaining carbon: 1/2
After 2 half-lives the carbon-14 remaining carbon : 1/4
After 3 half-lives the carbon-14 remaining carbon : 1/8
...
...
After n half-lives the carbon-14 remaining carbon : (1/2)^n
Number of half-lives in 30642 years: 30642 / 5730 ≈ 5 approx.
Amount of carbon remaining after 5 half-lives: 1/32
1/32 ≈ 0.031 = 3.1%
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25 Cards are drawn from a standard deck of 52 cards, what is the
probability of getting 2 kings?
The probability of getting 2 kings out of 25 cards is approximately 0.044 or 4.4%.
Drawing cards from a standard deck of 52 cards is a random process, and the probability of getting 2 kings out of 25 cards depends on the total number of possible outcomes.
There are 4 kings in a deck of 52 cards,
So, The probability of drawing a king on the first draw = 4/52.
Since the deck is not replaced,
The probability of drawing another king on the second draw = 3/51.
Therefore,
The probability of getting 2 kings out of 25 cards can be calculated by combining these two probabilities.
The probability of drawing 2 kings = [tex](4/52) * (3/51) * (25C2)[/tex]
Where,
25C2 = The number of ways to select 2 cards out of 25.
After calculating this expression, the probability of getting 2 kings out of 25 cards is approximately 0.044 or 4.4%.
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A Brick hits a window smashing it, which force is larger
The force exerted by the brick on the window is equal in magnitude but
opposite in direction to the force exerted by the window on the brick.
When a brick hits a window and smashes it, there are two forces
involved: the force exerted by the brick on the window and the force
exerted by the window on the brick.
According to Newton's third law of motion, for every action, there is an
equal and opposite reaction.
The magnitude of the forces involved depends on several factors,
including the mass of the brick, its velocity, the angle of incidence, and
the strength of the window. The force exerted by the brick on the
window will be the impact force, which is the force applied over a short
period of time during the collision.
The impact force will depend on the momentum of the brick, which is
the product of its mass and velocity.
It's not possible to say which force is larger because the two forces are
equal in magnitude but opposite in direction, according to Newton's third
law of motion.
The strength of the window will also play a role, as a stronger window
will be able to resist a higher impact force before breaking.
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Factorise ax-a+x-1 By grouping terms in pairs
The factorized terms of the given expression ax - a + x - 1 by grouping the terms in pairs is given by (x - 1)(a + 1) .
Expression is equal to,
ax - a + x - 1
To factorize the expression ax-a+x-1 by grouping terms in pairs.
First group the first two terms and the last two terms together we get,
⇒ ax - a + x - 1 = ( ax - a ) + ( x - 1 )
Now factor out the common factor of 'a' from the first group.
And the common factor of '1' from the second group we get,
⇒ ax - a + x - 1 = a(x - 1) + 1(x - 1)
Both the groups have a common factor of (x - 1).
Take out common factor we have,
⇒ ax - a + x - 1 = (x - 1)(a + 1)
Therefore, the factorized expression is equal to,
ax - a + x - 1 = (x - 1)(a + 1)
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If the y intercept is 4, the x coordinate is 4 and the y coordinate is 12, what is the gradient
the slope goes by several names
• average rate of change
• rate of change
• deltaY over deltaX
• Δy over Δx
• rise over run
• gradient
• constant of proportionality
however, is the same cat wearing different costumes.
[tex]\stackrel{ y-intercept }{(\stackrel{x_1}{0}~,~\stackrel{y_1}{4})}\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{12}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{12}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{4}-\underset{x_1}{0}}} \implies \cfrac{ 8 }{ 4 } \implies 2[/tex]
Evaluate the function f(x) = 4x-6 at the given values of the independent variable and simplify
In general, to evaluate the function f(x) at a specific value of x, we substitute that value into the expression for f(x) and simplify.
What is function?In mathematics, a function is a relation between two sets, where for every element in the first set (called the domain), there is exactly one element in the second set (called the range) that the function maps to. In simpler terms, a function is a rule that assigns each input value from the domain to exactly one output value in the range. Functions are usually represented by a formula or equation that describes the relationship between the input and output values. For example, the function f(x) = 2x + 1 maps every input value of x to an output value that is twice the input value plus 1.
Here,
To evaluate the function f(x) = 4x - 6, we substitute the given values of the independent variable into the expression for f(x) and simplify.
For example:
f(0) = 4(0) - 6 = -6
f(1) = 4(1) - 6 = -2
f(2) = 4(2) - 6 = 2
f(-1) = 4(-1) - 6 = -10
f(3a) = 4(3a) - 6 = 12a - 6
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A home-improvement store sold wind chimes for $30 each. A customer signed up for a free membership card and received a 5% discount off the price. Sales tax of 8% was applied after the discount. What was the final price of the wind chime?
sale price=$30
discount price=0.05
Taking it $30*0.05=600$
after applying 0.08
600*0.08=48$
, so 48$ is the final price of the wind chime.
The demand on Samsung TVs at X-store for the past 3 years is given in this table in units/season: Year 1 Year 2 Year 3 Average indices Forecast
Spring 1500 1650 1550
Summer 1000 900 850
Fall 500 600 550
Winter 200 150 220
The annual forecast for year 4 is 3710TVs. Use seasonality indexing to forecast the values of the 4th year (units/season),
The forecasted demand for Samsung TVs at X-store for the 4th year using seasonality indexing are as follows:
Spring: 5800 TVsSummer: 3373 TVsFall: 2031 TVsWinter: 693 TVsWhat is the use of seasonality indexing in forecasting?A seasonal index is a tool that compares a specific season during a cycle to the average season during that cycle. By deseasonalizing data, we can predict or approximate future data values by removing seasonal fluctuations or patterns in the data.
To use seasonality indexing to forecast the values of the 4th year, we first need to calculate the average indices for each season:
Average index for Spring:
= (1500 + 1650 + 1550) / 3
= 1567
Average index for Summer:
= (1000 + 900 + 850) / 3
= 917
Average index for Fall:
= (500 + 600 + 550) / 3
= 550
Average index for Winter:
= (200 + 150 + 220) / 3
= 190
Next, we need to calculate the seasonality index for each season by dividing the average index by 100:
Seasonality index for Spring = 1567 / 100 = 15.67
Seasonality index for Summer = 917 / 100 = 9.17
Seasonality index for Fall = 550 / 100 = 5.50
Seasonality index for Winter = 190 / 100 = 1.90
To forecast the demand for the 4th year, we can use the following formula "Seasonality index x Average demand for the season".
For Spring, the Forecasted demand for Spring in year 4:
= 15.67 x (3710/4)
= 5800.175
≈ 5800 TVs
For Summer, the Forecasted demand for Summer in year 4:
= 9.17 x (3710/4)
= 3372.925
≈ 3373 TVs
For Fall, the Forecasted demand for Fall in year 4:
= 5.50 x (3710/4)
= 2031.25
≈ 2031 TVs
For Winter, the Forecasted demand for Winter in year 4:
= 1.90 x (3710/4)
= 692.75
≈ 693 TVs
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A hose fills a 3-gallon bucket in 9 seconds. At this rate, how long will it take to fill a bucket that is 67% larger than the 3-gallon bucket? Round to the nearest second.
It took 15.03 seconds to fill the 67% larger than the 3-gallon bucket
Calculating the time required to fill the bucket:
To solve this problem, use the concept of proportionality to calculate the time required. Use the concept of percentage increase to find the volume of the larger bucket, which was 67% larger than the 3-gallon bucket.
Here we have
A hose fills a 3-gallon bucket in 9 seconds.
The volume of the bucket which is 167% more than 3 gallons
= 167% of 3 gallons = [167/100] × 3 = 5.01 gallons
It took 9 seconds to fill 3 gallons
The time required to fill 5.01 gallons = 9/3 × [5.01]
= 15.03 seconds
Therefore,
It took 15.03 seconds to fill the 67% larger than the 3-gallon bucket
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To raise money for charity, Monica and her friends start the Pampered Pooch Pet Wash. The first day they are open, they forget to put up posters and only raise a little money. The next day, they hang posters all over the neighborhood and raise $55.50. In all, Monica and her friends raise $65.50 on the first two days they are open. Which equation can you use to find the amount of money a Monica and her friends raise on the first day?
55.50a = 65.50
a + 55.50 =65.50
a - 65.50 = 55.50
a - 55.50 =65.50
Answer:
Step-by-step explanation:
[tex]a[/tex] is the amount earned on the first day.
She earnt $[tex]$a[/tex] dollar on day 1, $55.50 on day 2, and $65.50 total in the 2 days.
So we get
[tex]a+55.50=65.50[/tex]
An article suggests the uniform distribution on the interval (6.5, 21) as a model for depth (cm) of the bioturbation layer in sediment in a certain region. (a) What are the mean and variance of depth? (Round your variance to two decimal places.) mean variance (b) What is the cdf of depth? F(x) = {0 x < 6.5 6.5 lessthanorequalto x < 21 1 21 lessthanorequalto x (c) What is the probability that observed depth is at most 10? (Round your answer to four decimal places.) What is the probability that observed depth is between 10 and 15? (Round your answer to four decimal places.) (d) What is the probability that the observed depth is within 1 standard deviation of the mean value? (Round your answer to four decimal places.) What is the probability that the observed depth is within 2 standard deviations of the mean value?
Answer : a ) Variance = (21 - 6.5)^2/12 = 13.7708, b) 1, 21 <= x, c) Probability = 0.5862, D) Probability = 0.8552
The uniform distribution on the interval (6.5, 21) can be represented as U(6.5, 21).
(a) The mean and variance of a uniform distribution can be calculated using the following formulas:
Mean = (a + b)/2
Variance = (b - a)^2/12
where a and b are the lower and upper bounds of the distribution, respectively.
For the given distribution, a = 6.5 and b = 21.
Therefore, the mean and variance of depth are:
Mean = (6.5 + 21)/2 = 13.75
Variance = (21 - 6.5)^2/12 = 13.7708
(b) The cdf of a uniform distribution can be calculated using the following formula:
F(x) = (x - a)/(b - a)
For the given distribution, F(x) = (x - 6.5)/(21 - 6.5) for 6.5 <= x < 21.
Therefore, the cdf of depth is:
F(x) = {
0, x < 6.5
(x - 6.5)/14.5, 6.5 <= x < 21
1, 21 <= x
(c) The probability that observed depth is at most 10 can be calculated using the cdf:
P(X <= 10) = F(10) = (10 - 6.5)/14.5 = 0.2414
The probability that observed depth is between 10 and 15 can be calculated using the cdf:
P(10 <= X <= 15) = F(15) - F(10) = (15 - 6.5)/14.5 - (10 - 6.5)/14.5 = 0.5862
(d) The standard deviation of a uniform distribution can be calculated using the following formula:
Standard deviation = sqrt(Variance)
For the given distribution, the standard deviation is:
Standard deviation = sqrt(13.7708) = 3.7118
The probability that the observed depth is within 1 standard deviation of the mean value can be calculated using the cdf:
P(13.75 - 3.7118 <= X <= 13.75 + 3.7118) = F(13.75 + 3.7118) - F(13.75 - 3.7118) = (13.75 + 3.7118 - 6.5)/14.5 - (13.75 - 3.7118 - 6.5)/14.5 = 0.5118
The probability that the observed depth is within 2 standard deviations of the mean value can be calculated using the cdf:
P(13.75 - 2*3.7118 <= X <= 13.75 + 2*3.7118) = F(13.75 + 2*3.7118) - F(13.75 - 2*3.7118) = (13.75 + 2*3.7118 - 6.5)/14.5 - (13.75 - 2*3.7118 - 6.5)/14.5 = 0.8552
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whats 2 + 2n is it 4n or 4 or something diffrent?
Answer:
it depends
Step-by-step explanation:
it depends on the value of n
for instance if n was = to 7 then
2+2n = 2+2(7) = 2+14 = 16
Answer: 2+2n
Step-by-step explanation:
The expression 2 + 2n can be simplified as follows:
2 + 2n = 2(1 + n)
So the expression 2 + 2n is equivalent to 2 times the quantity 1 plus n, or simply 2(1 + n). It cannot be simplified any further unless there is additional information or context provided.
The issues surrounding the levels and structure of executive compensation have gained added prominence in the wake of the financial crisis that erupted in the fall of 2008. Based on the 2006 compensation data obtained from the Securities and Exchange Commission (SEC) website, it was determined that the mean and the standard deviation of compensation for the 524 highest paid CEOs in publicly traded U. S. Companies are $10. 82 million and $10. 25 million, respectively. An analyst randomly chooses 46 CEO compensations from 2006 for analysis. Calculate the expected value of the sample mean. The sample mean is ______________ million dollars
Based on the information provided in the question, The expected value of the sample mean is approximately 497.92 million dollars.
To calculate the expected value of the sample mean, first calculate the mean of the population ($10.82 million) and then multiply it by the sample size (46).
Mean of Population * Sample Size = Expected Value of Sample Mean
$10.82 million * 46 = $497.92 million
Expected Value of Sample Mean = $497.92 million
A sample mean is a statistical measurement that shows the mean value of the data in a sample. It is determined by summing all of the values in the sample and dividing the total by the number of observations.
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The base of the pennant measures 3 inches and the height of the pennant measures 5 inches if austin is covering the pennant with paint how much of the surface will be covered?
Austin needs to cover 15 square inches of surface area with paint in order to finish the task.
The area of the pennant is the length times the width, which is 3 inches times 5 inches. This gives us 15 square inches of surface area to be covered. To calculate the amount of paint needed, we first need to calculate the area of the pennant. The formula for area is area = length x width. Plugging in the measurements for the base and height of the pennant, we get 15 square inches of surface area. This means that Austin needs to cover 15 square inches of surface area with paint in order to finish the task.
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After spending 60 percent of his money , Joseph has a re 600. How much did he have in the beginning?
After spending 60% of his money Joseph has rs. 600., He has 1500 in the beginning.
A value or ratio that may be stated as a fraction of 100 is referred to as a percentage in mathematics. If we need to calculate a percentage of a number, we should divide it by its entirety and then multiply it by 100. The proportion, therefore, refers to a component per hundred. Per 100 is what the word percent means. The letter "%" stands for it.
Let the total amount be x
He spent 60% of his money
So, Money spent = 60% x=0.6x
Remaining amount = x- 0.6 x = 0.4x
We are given that Now he has Rs.600
[tex]0.4x=600\\\\x=\frac{600}{0.4}\\\\x=1500[/tex]
Hence He has Rs.1500 at the beginning
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7th grade teacher decided to have her students take the same survey. She could found that 7 students or 35% of her students, prefer rock music. How many students are in this class
7. what is the value of X in the proportion [tex]\frac{6x+1}{7}[/tex]=[tex]\frac{18x-2}{14}[/tex]
8. john, alana, and jesus are sharing a bag of candy in the extended ratio 2:3:4. if there are 63 candies in the bag, then how many will alana get?
9. which of the following are equivalent to the ratio (2x-6) : (6x-4) ?
Step-by-step explanation:
7. Cross multiply
14( 6x +1) = 7( 18x - 2)
Open the brackets
84x +14 = 126x - 14
Subract 84x from both sides
14 = 42x - 14
Add 14 to both sides
28 = 42x
Divide both sides by 42
X = 28/42
Write in simplest form
X=2/3
8. Add all the ratio 2+3+4= 9
Alana is ratio 3
3/9 x 63 candy = 21 candy
9. 3ab : 27ab
Divide both sides by 3, you have 1ab: 9ab
Divide both sides by ab, you have 1: 9
A car hire company charged rs. C a day together with an additional rs. C per mile work out the total charge for hiring a car for 50 days and travelling 2500 miles during that time
The fixed charge for a taxi ride is Rs. 5 and the charge per km is Rs. 7.
Given that the charge for a 12 km ride is Rs. 89 and for a 20 km ride is Rs. 145, we can form two equations in terms of the fixed charge (c) and the charge per km (x).
Solving these equations, we get c = 5 and x = 7. Therefore, the fixed charge for a taxi ride is Rs. 5 and the charge per km is Rs. 7. To find the charge for a 30 km ride, we can substitute these values in the formula
c + 7x, which gives us 5 + 7x30 = Rs. 215.
89 = c + 12x ---------------(1)
145 = c + 20x -------------(2)
Solving equations 1 and 2, we get,
8x = 56
x = 7.
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Complete Question:
The car hire charges in a city comprised of a fixed charge together with the charge for the distance covered. For a journey of 12 km, the charge paid is Rs 89 and for a journey of 20 km, the charge paid is Rs 145. What will a person have to pay for traveling a distance of 30 km?
Choose the expression that is equivalent to a fraction with four raised to the negative third power in the numerator and the quantity three raised to the negative second power times four squared end quantity in the denominator and the entire fraction is cubed
Answer: go look on yt there’s a good video on this one
Step-by-step explanation:
five college students with the flu return to an isolated campus of 2500 students. assume the rate at which the virus spreads is proportional to both the number of students infected and the number of students not infected.
According to proportionality, the virus will spread at a rate of 12475 students per day.
If five college students with the flu return to an isolated campus of 2500 students, and the rate at which the virus spreads is proportional to both the number of students infected and the number of students not infected, then we can use the following formula to find the rate of spread:
Rate of spread = (number of students infected) x (number of students not infected)
In this case, the number of students infected is 5 and the number of students not infected is 2500 - 5 = 2495. So, the rate of spread is:
Rate of spread = 5 x 2495 = 12475
This means that the virus will spread at a rate of 12475 students per day, assuming that the rate of spread is proportional to both the number of students infected and the number of students not infected.
It is important to note that this is a simplified model and does not take into account other factors that may affect the rate of spread, such as the effectiveness of quarantine measures or the individual immune systems of the students. However, it does give us an idea of how quickly the flu can spread in a population of 2500 students.
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Two radar stations have been positioned 6 miles apart at points A and B. Point D is located exactly 3 miles from point A. A plane is flying overhead at point C such that the radar stations and the plane are all equidistant. What should be the vertical distance from the plane to point D? Round the answer to the nearest tenth of a mile. miles
Therefore, DM = 0, which means that the plane is directly above point D. Pythagorean theorem The vertical distance from the plane to point D is simply the altitude of the plane.
what is Pythagorean theorem?The Pythagorean Theorem is the fundamental Euclidean geometry relationship between the three sides of a right triangle. According to this rule, the area of a square with the hypotenuse side equals the sum of the areas of squares with the other two sides.
drawing a diagram
A ------ 3 miles ------ D ----- x miles ------ C
| |
| |
6 miles 6 miles
| |
| |
B -----------------------------------------------
[tex]AC^2 = AD^2 + DC^2\\BC^2 = BD^2 + DC^2\\AD^2 + DC^2 = BD^2 + DC^2\\AD^2 = BD^2[/tex]
So, the plane must be directly above the midpoint of AB. Let's call this point M:
A ------ 3 miles ------ D ----- x miles ------ C
| |
| |
6 miles 3 miles 6 miles
| |
| |
B -----------------------------------------------
|
|
M
Now, let's use Pythagoras' theorem again to find the distance from the plane to point D:
[tex]DM^2 = AD^2 - AM^2\\DM^2 = AD^2 - 3^2\\DM^2 = 3^2 - 3^2\\DM^2 = 0[/tex]
Therefore, DM = 0, which means that the plane is directly above point D. The vertical distance from the plane to point D is simply the altitude of the plane.
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find the area of the shaded region of the given circle
diameter = 14cm
[tex]radius \: = \frac{d}{2} = \frac{14}{2} \\ = 7cm[/tex]
Area of circle ( A1 ) = [tex]\pi {r}^{2} [/tex]
[tex] = \frac{22}{7} \times 7 \times 7 \\ [/tex]
[tex] = 154 {cm}^{2} [/tex]
Area of Square ( A2 ) = l²
= ( 14 )²
= 196cm²
Area of shaded region = A2 - A1
= 196 - 154
= 42cm²
....Thank you !! :)
Which of the following could be the measure of the angle below?
On a coordinate plane, a horizontal straight line is on the x-axis from negative 4 to positive 4.
–180°
–120°
140°
510°
Answer:
-180
Step-by-step explanation:
The measure of the angle on the attached figure is
There are two ways to measuring it
1. Counterclockwise: In this the sign is positive
So,
We can write
180°,
180°+360° = 540°,
180° + 2(360°) =180°+720° =900°,
2. Clockwise: In this, the sign is negative
So,
We can write
-180°,
-180° - 360° = -540°,
-180° - 2(360°) = -180° - 720° = -900°
the correct option is A.
What is the equation of the line that passes through the point (-3, 4) and has a
slope of 2/3?
Answer:
y = 2/3x + 6
Step-by-step explanation:
The equation is y = mx + b
m = the slope
b = y-intercept
We know
m = 2/3
Y-intercept is located at (0, 6)
So, our equation is y = 2/3x + 6
Option #1: point-slope form: y - y1 = m ( x - x1 )
y - 4 = 2/3 ( x - (-3) ) or y - 4 = 2/3 ( x + 3 )
Option #2: slope-intercept form: y = mx + b
Take the point-slope and solve for y:
y - 4 = 2/3 ( x + 3 )
y - 4 = 2/3 x + 2
y = 2/3 x + 6
Una varilla de plata mide 48 cm a 13°C. ¿Cuál es su longitud si se calienta hasta 500°C? (α=〖2x10〗^(-5) 〖°C〗^(-1)) ayuda se entrega a las 12 del medio dia
The length of the silver rod when heated to 500°C is approximately 48.47 cm.
To solve this problem, we can use the formula:
L₂ = L₁ (1 + αΔT)
where L₁ is the original length of the rod at temperature T₁, L₂ is the new length of the rod at temperature T₂, α is the coefficient of linear expansion of the material, and ΔT = T₂ - T₁ is the change in temperature.
We are given that the original length of the silver rod is L₁ = 48 cm at temperature T₁ = 13°C. The coefficient of linear expansion for silver is α = 2x10^(-5) °C^(-1). The change in temperature is ΔT = 500°C - 13°C = 487°C.
Substituting these values into the formula, we get:
L₂ = 48 cm (1 + 2x10^(-5) °C^(-1) x 487°C)
= 48 cm (1 + 0.00974)
= 48 cm (1.00974)
= 48.47 cm
Therefore, the length of the silver rod is approximately 48.47 cm.
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_____The given question is incorrect, the correct question is given below:
A silver rod measures 48 cm at 13°C. What is its length when heated to 500°C? (α=2x10^(-5) °C^(-1)).
use differentials to approximate the change in cost corresponding to an increase in sales (or production) of one unit. then compare this with the actual change in cost. (round your answers to two decimal places.)Function x-Value C = 0.075x^2 + 6x + 7 X = 10x-valuex = 10
The approximate change in cost corresponding to an increase in sales of one unit is 8.50. and actual change in cost is 8.25.
To answer this question, we need to use differentials to approximate the change in cost corresponding to an increase in sales (or production) of one unit. To do this, we need to calculate the derivative of the given cost function C = 0.075x^2 + 6x + 7.
The derivative of this function is dC/dx = 0.15x + 6. We can now use this derivative to approximate the change in cost when x is increased by one unit. This is given by dC/dx = 0.15(10) + 6 = 8.5.
To compare this with the actual change in cost, we can calculate the change in cost when x is increased from 10 to 11. This is given by C(11) - C(10) = (0.075x^2 + 6x + 7) | 11 - (0.075x^2 + 6x + 7) | 10 = 0.075(121) + 66 + 7 - 0.075(100) - 60 - 7 = 8.25.
Therefore, the approximate change in cost when x is increased by one unit (calculated by differentials) is 8.50 and the actual change in cost is 8.25. This shows that the approximate change in cost calculated by differentials is an accurate estimation of the actual change in cost.
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Consider a population of size N = 14,600 with a mean of μ = 156 and standard deviation of a = 23.
Compute the following z-values for sampling distributions of with given sarkple size. Round solutions to
two decimal places, if necessary.
The z-values of the sampling distributions are;
z = 2.27z = -2.09z = -2.2z = -3.33What is a sampling distribution?A sampling distribution is a probability distribution obtained through the repeated sampling of a specified population.
The z-value for a sampling distribution can be obtained using the formula;
[tex]z = \frac{\bar{x} -\mu}{\frac{\sigma}{\sqrt{N} } }[/tex]
Where;
[tex]\bar{x}[/tex] = The sample mean
μ = The population mean = 156
σ = The population standard deviation = 23
N = The sample size
The z-values for the sampling distributions are therefore;
1) The number of observations selected from the population, is 76, and the sample mean is; [tex]\bar{x}[/tex] = 162, we get the following z-value.
When, N = 76 and [tex]\bar{x}[/tex] = 162
[tex]z = \frac{162-156}{\frac{23}{\sqrt{76} } } \approx 2.27[/tex]2) The selected observations is 92, and the sample mean is; [tex]\bar{x}[/tex] = 151, we get the following z-value.
When, N = 92 and [tex]\bar{x}[/tex] = 151
[tex]z = \frac{151-156}{\frac{23}{\sqrt{92} } } \approx -2.09[/tex]3) The number in the random sample, N = 102 and the sample mean is; [tex]\bar{x}[/tex] = 151, we get;
When, N = 102 and [tex]\bar{x}[/tex] = 151
[tex]z = \frac{151-156}{\frac{23}{\sqrt{102} } } \approx -2.2[/tex]4) The number of observations in the random sample, N = 120 and the sample mean is; [tex]\bar{x}[/tex] = 149, we get;
When, N = 120 and [tex]\bar{x}[/tex] = 149
[tex]z = \frac{149-156}{\frac{23}{\sqrt{120} } } \approx -3.33[/tex]Learn more on the z-values of a sampling distribution here: https://brainly.com/question/14263321
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Automobile Depreciation For a random sample of 20 automobile models, we record the value of the model as a new car and the value after the car has been purchased and driven 10 miles. 1 The difference between these two is a measure of the depreciation on the car just by driving it off the lot. Depreciation values from our sample of 20 automobile models can be found in the dataset CarDepreciation. Click here for the dataset associated with this question. Click here to access StatKey. Round your answers to the nearest integer. (a) Find the mean and standard deviation of the Depreciation amounts in CarDepreciation. Mean
The mean Depreciation of automobile for a random sample of 20 automobile models is 6626.
To find the mean of the Depreciation amounts in Car Depreciation, we can use the following formula:
mean = (sum of all values) / (number of values)
The resulting value of 6626 indicates the average depreciation amount in dollars of the 20 automobile models in the sample of standard deviation.
In statistics, the mean is a measure of central tendency that represents the average value of a dataset. It is calculated by adding up all the values in the dataset and then dividing the sum by the number of values.
The mean is commonly used as a measure of the "typical" value in a dataset and is often used to compare the values of different datasets or to track changes in a single dataset over time.
Automobile Depreciation For a random sample of 20 automobile models, we record the value of the model as a new car and the value after the car has been purchased and driven 10 miles. 1 The difference between these two is a measure of the depreciation on the car just by driving it off the lot.
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