The electric field inside the non-conductor sphere would be different. For a non-conductor sphere, the charge is distributed uniformly throughout the sphere, rather than being concentrated on the surface as in a conductor.
The electric field outside a uniformly charged solid sphere (conductor or non-conductor) is given by:
E = kQ/R^2
where k is the Coulomb constant, Q is the total charge on the sphere, and R is the radius of the sphere.
For the given solid metal sphere with a radius of 2.00 m and a total charge of -4.20 μC, we have:
E = (9.0 × 10^9 N·m^2/C^2) × (-4.20 × 10^-6 C) / (2.00 m)^2
E ≈ -9.86 N/C
The electric field is negative, which indicates that the direction of the electric field is inward, toward the center of the sphere.
For a solid non-conductor sphere that is uniformly charged throughout, the electric field outside the sphere can still be calculated using the same formula. The total charge Q on the sphere and the radius R of the sphere would be the same as for the metal sphere. Therefore, the magnitude of the electric field outside the solid non-conductor sphere would be the same as for the metal sphere:
E = kQ/R^2
E = (9.0 × 10^9 N·m^2/C^2) × (-4.20 × 10^-6 C) / (2.00 m)^2
E ≈ -9.86 N/C
However, the electric field inside the non-conductor sphere would be different. For a non-conductor sphere, the charge is distributed uniformly throughout the sphere, rather than being concentrated on the surface as in a conductor. Therefore, the electric field inside the non-conductor sphere would be zero. This is because the electric field due to one element of charge is cancelled by the electric field due to an opposite element of charge located on the opposite side of the sphere.
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Solve it fast pleaseeee.
1. The horizontal component of the force on the box, given that at force of 18 N was applied at angle of 34° to the horizontal is 15 N
2. The vertical component of the force on the box is 10 N
1. How do I determine the horizontal component of force?From the question given above, the following data were obtained:
Force applied (F) = 18 NewtonsAngle (θ) = 34 °Horizontal component of force (Fx) =?The horizontal component of the force can be obtained as illustrated below:
Horizontal component of force (Fx) = F × Cosθ
Horizontal component of force (Fx) = 18 × Cos 34
Horizontal component of force (Fx) = 15 N
2. How do I determine the vertical component of force?From the question given above, the following data were obtained:
Force applied (F) = 18 NewtonsAngle (θ) = 34 °Vertical component of force (Fy) =?The vertical component of the force can be obtained as illustrated below
Vertical component of force (Fy) = u × Sine θ
Vertical component of force (Fy) = 18 × Sine 34
Vertical component of force (Fy) = 10 N
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Tres participantes en un concurso de TV están colocados en el centro
de un campo plano grande. A cada uno se le proporciona una regla
graduada de un metro, un compás, una calculadora, una pala
y (en diferente orden para cada concursante) los siguientes tres desplazamientos:
A: 72. 4 m, 32. 0° al este del norte
B: 57. 3 m, 36. 0° al sur del oeste
C: 17. 8 m al sur
Los tres desplazamientos llevan al punto donde están enterradas las
llaves de un Porsche nuevo. Dos concursantes comienzan a medir de inmediato; sin embargo, el ganador calcula
primero a donde debe ir. Con tres cifras
significativas exprese la resultante
Para encontrar el punto donde están enterradas las llaves del Porsche nuevo, debemos sumar los tres desplazamientos dados en el problema.
Primero, el desplazamiento de A tiene una magnitud de 72.4 m y una dirección de 32.0° al este del norte. Usando trigonometría, podemos descomponer este desplazamiento en sus componentes vertical y horizontal: Componente vertical = 72.4 m sin(32.0°) ≈ 38.9 m hacia el norte. Componente horizontal = 72.4 m cos(32.0°) ≈ 61.5 m hacia el este. Por lo tanto, el desplazamiento de A se puede representar como un vector de 61.5 m hacia el este y 38.9 m hacia el norte. Segundo, el desplazamiento de B tiene una magnitud de 57.3 m y una dirección de 36.0° al sur del oeste. De manera similar, podemos descomponer este desplazamiento en sus componentes vertical y horizontal: Componente vertical = 57.3 m sin(36.0°) ≈ 34.4 m hacia el sur. Componente horizontal = 57.3 m cos(36.0°) ≈ 46.0 m hacia el oeste. Por lo tanto, el desplazamiento de B se puede representar como un vector de 46.0 m hacia el oeste y 34.4 m hacia el sur. Finalmente, el desplazamiento de C tiene una magnitud de 17.8 m hacia el sur. Este desplazamiento solo tiene una componente vertical. Ahora, podemos sumar los tres vectores de desplazamiento para obtener la resultante. Podemos hacer esto sumando las componentes horizontal y vertical por separado: Componente horizontal total = 61.5 m - 46.0 m = 15.5 m hacia el este
Componente vertical total = 38.9 m - 34.4 m - 17.8 m = -13.3 m hacia el norte. La magnitud de la resultante se puede encontrar usando el teorema de Pitágoras: |magnitud resultante| = sqrt((15.5 m)^2 + (-13.3 m)^2) ≈ 20.2 m. Por lo tanto, el concursante ganador debería ir en una dirección de aproximadamente 29.7° al este del norte para encontrar las llaves del Porsche nuevo.
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Añadir mayor cantidad de gas a un tanque, la presión interna aumentará debido a que al incrementar el número de partículas,
Translation-Adding more gas to a tank, the internal pressure will increase because by increasing the number of particles?
Adding more gas to a tank, the internal pressure will increase because by increasing the number of particles increases collision between particles.
The frequency of collisions between gas particles and the container walls determines the gas pressure. The number of collisions and consequently the pressure will rise if we fill the container with more gas particles.
The Avogadro Principle (V N) states the frequency of collisions with the container walls must increase as the number of gas particles increases. The pressure of the gas then rises as a result of this. Pressure rises as the number of gas molecules rises while the volume of the container stays the same. Gas pressure rises as container volume decreases. The pressure rises as the temperature of a gas inside a rigid container rises.
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how does changing the direction of the applied force change the amount of the force that is doing work?
The component of the force acting in the direction of an object's motion determines how much force is doing work on that object. The "parallel component" of the force is referred to as this.
Applied forceA force that is applied perpendicular to an object's motion has no effect since it does not add to the object's kinetic energy.
It follows that the force exerted on the item will increase if the applied force's direction is adjusted to make it more parallel to the direction of motion.
The amount of force accomplishing work will decrease, on the other hand, if the direction of the applied force becomes increasingly perpendicular to the direction of motion.
Take the movement of a box across a rough surface as an illustration.
Only a fraction of the force will be parallel to the surface of the force delivered at a 45-degree angle to the surface, contributing to the motion of the box.
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If a planet had twice the earth's radius, but only one-third its mass, the acceleration due to gravity at its surface would be
The acceleration due to gravity at the surface of the planet would be one-twelfth (1/12) of the acceleration due to gravity at the surface of the Earth.
The acceleration due to gravity at the surface of a planet is given by the formula:
g = G * M / R^2
Where:
g is the acceleration due to gravity
G is the gravitational constant
M is the mass of the planet
R is the radius of the planet
we are given that the planet has twice the Earth's radius (2R) and one-third of its mass (1/3M).
now, the acceleration due to gravity at the surface of the planet would be:
g = G * (1/3M) / (2R)^2
= G * (1/3M) / 4R^2
= (1/12) * (G * M / R^2)
= (1/12) * gEarth
where gEarth is the acceleration due to gravity at the surface of the Earth.
Hence, the acceleration due to gravity at the surface of the planet would be one-twelfth (1/12) of the acceleration due to gravity at the surface of the Earth.
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One design feature to ensure that the thermometer measured the desired range of temperature
Answer:
tube (sufficiently) long / not too short.
suppose all the people of the earth go to the north pole and, on a signal, all jump straight up. estimate the recoil speed of the earth. the mass of the earth is 6 1024 kg, and there are about 6 billion people (6 109). take the average mass of a person to be 72 kg and the distance the average person's center of mass rises after leaving the ground to be 0.2 m.
Answer:
m g H = 1/2 m v^2 conservation of energy
v = (2 g H)^1/2 = (2 * 9.8 * .2)^1/2 = 1.98 m/s (call it 2 m/s)
Total momentum of people
N m v = 6E9 * 72 * 2 = 8.6E11 kg m/s momentum of people
M V = N m v to get recoil speed of people (conservation momentum)
V = N m v / M = 8.6E11 / 6.0E24 = 1.4E-13
The speed of the earth would be less than 1/trillionth m/s
The estimated recoil speed of the earth is -1.44 x 10-14 m/s.
First, we need to calculate the total mass of all the people jumping on the earth's surface. This can be done by multiplying the average mass of a person by the total number of people:
Mass of all people = (72 kg)(6 x 109) = 4.32 x 1011 kg
Next, we need to calculate the total momentum of all the people jumping. This can be done by multiplying the total mass of all the people by the distance they jump:
Momentum of all people = (4.32 x 1011 kg)(0.2 m) = 8.64 x 1010 kg m/s
Now, we can use the law of conservation of momentum to find the recoil speed of the earth.
This law states that the total momentum before an event is equal to the total momentum after an event. Therefore, the momentum of the earth before the jump is equal to the negative of the momentum of all the people after the jump:
Momentum of earth = -Momentum of all people = -8.64 x 1010 kg m/s
Finally, we can use the formula for momentum (p = mv) to find the recoil speed of the earth:
v = p/m = (-8.64 x 1010 kg m/s)/(6 x 1024 kg) = -1.44 x 10-14 m/s
Therefore, the estimated recoil speed of the earth is -1.44 x 10-14 m/s.
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Calculate the work W done from x = 5 m to x = 10 m by the one-dimensional force depicted in the graph
The work W done from x = 5 m to x = 10 m by the one-dimensional force depicted in the graph is 250 J
What is the work done by the force?The work done by the force is the product of the force and distance traveled.
The product of the force and distance traveled is the sum of the area of the two triangles that are formed from x = 5 to x = 10
The area of the first triangle = 1/2 * 100 * 1
The area of the first triangle = 50 J
The area of the second triangle = 1/2 * √(100² + 1²) * 4
The area of the second triangle = 0.5 * √10001 * 4
The area of the second triangle = 200 J
Therefore, the work done = 200 + 50 J
Work done = 250 J
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Which two statements about earth's oceanic and continental crust are true? A. Oceanic crust is thicker than continental crust. B. Oceanic crust is denser that continental crust. C. Continental crust is darker in color than oceanic crust. D. Continental crust is older than oceanic crust. PLEASE HELPPPPPP I GIVE LOT OF POINTS I NEED THIS
The oceanic crust is not thicker than the continental crust. The thickness of the continental crust is typically 30 km, compared to the oceanic crust's average thickness of 7 km.
Is the continental crust thicker than the oceanic crust on Earth?There are two different types of crust that cover the Earth: continental and oceanic. The continental crust is typically up to 25 miles thick, whereas the thinner oceanic crust is typically a little over four miles thick.
Is it accurate to say that the crust on land is thicker than that on the ocean?The thickness of the continental crust is normally 40 km (25 miles), whereas the thickness of the oceanic crust is only 6 km (4 miles). Different densities of lithospheric rock's impact can be seen in
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Catching a wave a 77 kg suffer starts with a speed of 1. 3 m/s
The amount of non-conservative work done on the sofa is 3833.83 Joules .
The total work done by the wave is expressed as;
Workdone = Potential energy + Kinetic energy
Workdone = mgh + 1/2mv²
m is the mass = 77kg
g is the acceleration due to gravity = 9.8m/s²
v is the velocity = 8.2m/s
h is the height = 1.65m
Substitute into the formula;
Workdone = 77(9.8) (1.65) + 1/2(77)8.2²
Workdone = 1245.09 + 2588.74
Workdone = 3833.83 Joules
It is a scalar quantity that depends on both the mass and velocity of an object. The formula for calculating kinetic energy is KE = 0.5 * m * v^2, where KE is the kinetic energy, m is the mass of the object, and v is its velocity.
When an object is in motion, it possesses kinetic energy because it has the ability to do work on other objects when it interacts with them. For example, a moving ball has the potential to do work when it collides with another ball, causing it to move and potentially change its direction or speed.
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when there is zero voltage across an ideal photocell, the amount of current that flows from the photocell is:
When there is zero voltage across an ideal photocell, the amount of current that flows from the photocell is zero.
What is a photocell? A photocell is a transducer that converts light energy into electrical energy. It is also known as a photoresistor or light-dependent resistor (LDR). It is a sensor that detects light and converts it into electricity.
A photocell is a component that senses light levels and reacts to them. It is a semiconductor device that has an electrical resistance that changes depending on the amount of light it receives.
The amount of light received by a photocell is proportional to the current generated. As the light intensity decreases, the resistance of the cell increases.
The current through the circuit and the voltage across the circuit decrease when the resistance of the cell increases.The current that flows from an ideal photocell when there is zero voltage across it is zero.
The photocell produces a current proportional to the amount of light it receives. As a result, the ideal photocell has zero current when there is zero voltage across it. The photoelectric effect is responsible for the current generated by a photocell.
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assume the electric field e in some region is uniform: it is the same at all points specificallv. e has a magnitude of 5 v/m and points the x direction. what can vou then sav about the behavior of the electric potential a) in the y direction and b) in the y direction? exolain vour answers
Electric potential in y direction (a) will be constant and in x direction (b) will decrease as you move in direction of the electric field.
The electric field E in a region is uniform if it is the same at all points. Specifically, if E has a magnitude of 5 V/m and points in the x direction, then we can say the following about the behavior of the electric potential:
a) In the y direction, the electric potential will be constant. This is because the electric field is perpendicular to the y direction, and therefore does not affect the electric potential in that direction.
b) In the x direction, the electric potential will decrease as you move in the direction of the electric field.
This is because the electric field is parallel to the x direction, and therefore affects the electric potential in that direction. Specifically, the electric potential will decrease by 5 V for every meter you move in the x direction.
To summarize, the electric potential will be constant in the y direction, and will decrease in the x direction as you move in the direction of the electric field. This is due to the fact that the electric field is uniform and points in the x direction.
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A snowboarder on a slope starts from rest and reaches a speed of 2. 1 m/s after 8. 6 s
The magnitude of accelration is 0.23 m/s^2 and the distance is 8.7 m
final speed , v = 2 m/s
time taken , t = 8.6 s
a)
Let the magnitude of accelartion be a
v = u + a * t
2 = 0 + a * 8.6
solving for a
a = 0.23 m/s^2
b)
The distance travelled in this time , s = v^2 /2a
s = 2^2 /( 2 * 0.23) m
s = 8.7 m
Magnitude refers to the size or extent of something, and it is often used in physics and mathematics to describe the strength or intensity of a physical quantity or phenomenon. Magnitude can be measured using various units, depending on the type of quantity being measured.
For example, in physics, the magnitude of a force is the strength or intensity of the force, and it is typically measured in units such as newtons (N) or pounds-force (lbf). The magnitude of a vector quantity, such as velocity or acceleration, is the length of the vector and is measured in units such as meters per second (m/s) or meters per second squared (m/s^2).
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Complete Question: -
A snowboarder on a slope starts from rest and reaches a speed of 2.0 m/s after 8.6 s.
(a) What is the magnitude of the snowboarder's average acceleration?
_____ m/s2
(b) How far does the snowboarder travel in this time?
_____ m
Convert this decimal into its fractional
form simplified completely.
0.350
Answer:
7/20
Explanation:
0.35 as a fraction =35/100
35/100 can b divided by 5 so =7/20
0.350 simplified as a fraction is 7/20
Answer:
7/20
Explanation:
The switch in a series RL circuit with a resistance of 6. 2 Ω , inductance of 3. 5 H, and
voltage of 38. 2 V is closed at t = 0. 3 s. What is the maximum current in the circuit?
Answer in units of A
The maximum current in the circuit is 17.46 A.
To find the maximum current in the circuit, we need to find the time at which the current reaches its maximum value. This occurs when the derivative of the current with respect to time is zero:
di/dt = (V/L) e^(-Rt/L) = 0
Solving for t, we get:
t = (L/R) ln(V/I)
where I is the maximum current.
Substituting the given values, we get:
t = (3.5/6.2) ln(38.2/I) = 0.3
Solving for I, we get:
I = 17.46 A
Inductance is a property of an electrical circuit that describes the ability of a component to store energy in a magnetic field. It is measured in henries (H) and is denoted by the letter L. Inductors are components that are specifically designed to have high inductance.
If the current is changing, then the magnetic field also changes, and this change induces a voltage in nearby conductors. This is known as electromagnetic induction, and it is the basis for many important electrical devices, including transformers and electric motors. The inductance of a component depends on several factors, including the number of turns in the coil, the size of the coil, and the material from which the coil is made.
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Dolphins don't have gills, they have lungs. To take in air, they have blowholes located on top of
their heads. This location gives it an advantage. What is the advantage of having a blowhole on TOP
of its head?
The advantage of having a blowhole on top of a dolphin's head is that it allows them to breathe while swimming without having to break the surface of the water, which is crucial for their survival.
Dolphins are aquatic mammals and need to breathe air to survive. The location of their blowhole on the top of their head allows them to take in air without having to break the surface of the water, which is critical for their survival in the wild. When a dolphin needs to breathe, it can simply surface and quickly exhale and inhale through its blowhole.
This enables them to maintain a constant speed while swimming, and also helps them avoid detection from predators or prey that may be lurking at the surface. In addition, having a blowhole on top of their head allows them to quickly clear their airways of water and mucus, which can be useful for diving and hunting.
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does a 50kg box or a 10kg box need more net force in order to move with the same acceleration
To move with the same acceleration as the 10kg box, the 50kg box needs higher net force.
What is the equation for net force?The term "net force" refers to the combined effects of all the forces exerted on a moving body, including gravitational, frictional, and normal forces. FNet equals Fa, Fg, Ff, and FN.
Newton's Second Law of Motion states that
A mass-proportional force is needed to accelerate an item.
The following formula determines the net force necessary to move an item at a given acceleration:
net force = mass x acceleration
The 50kg box and the 10kg box both accelerate at the same rate, but the 50kg box's net force need is more than the 10kg box's because of its heavier mass.
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A family is building a new dog house for a pet that needs ruff-ly 60 cubic feet. Find the best dimensions for the dog house, explain your reasoning and show your work
The dog home would measure 5 feet long, 4 feet wide, and 3 feet high (height) or 4 feet (length) x 5 feet (width) x 3 feet (height).
To find the best dimensions for a dog house with a volume of approximately 60 cubic feet, we need to consider several factors such as the size of the dog, the available space for the dog house, and the materials available for construction.
Assuming that the dog is of average size, we can start by considering the shape of the dog house. A rectangular prism is a common shape for a dog house, so we can begin with that shape.
Let's define the dimensions of the dog house as length (L), width (W), and height (H). We can express the volume of the dog house as:
Volume = L x W x H
Given that the volume of the dog house is approximately 60 cubic feet, we can try different combinations of the dimensions to find the best one. One way to do this is to keep one dimension constant and vary the others.
For example, if we keep the length and width constant at 4 feet and 5 feet, respectively, we can find the height by solving the equation:
60 = 4 x 5 x H
H = 3 feet
Therefore, the dimensions of the dog house would be 4 feet (length) x 5 feet (width) x 3 feet (height).
Alternatively, we could keep the length and height constant at 5 feet and 3 feet, respectively, and vary the width:
60 = 5 x W x 3
W = 4 feet
Therefore, the dimensions of the dog house would be 5 feet (length) x 4 feet (width) x 3 feet (height).
Both options result in a volume of approximately 60 cubic feet and provide a comfortable space for the dog. The choice between them would depend on the available space for the dog house and the materials that are available for construction.
Finding the best dimensions for a dog house requires consideration of various factors, such as the size of the dog and the available materials. By experimenting with different combinations of dimensions, we can find the optimal size and shape that provide enough space and comfort for the pet.
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A uniform stick has length l. The moment of inertia about the center of the stick is io. A particle of mass m is attached to one end of the stick. The moment of inertia of the combined system about the center of the stick is
A uniform stick has length l, The combined moment of inertia with mass M at one end of the rod is I₀ + M(L² ÷ 4).
The stick is I₀. The particle is MR² about the point of rotation but R = 1/2 the stick length so for the particle,
I = M × (L ÷ 2)²
I = M × L² × (1 ÷ 2)²
I = (1/4) × M × L²
Therefore, The total I is the sum of the separate is I₀ + (1/4) M L².
Then the combined moment of inertia with mass M at one end of the rod is:
I₀ = (mL²) ÷ 12
I = (mL²) ÷ 12 + M(L ÷ 2)²
I = I₀ + M(L ÷ 2)²
I = I₀ + M(L² ÷ 4)
Therefore, the combined moment of inertia with mass M at one end of the rod is I₀ + M(L² ÷ 4).
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Predict click reset and select cardboard this blocks all light in some of the hot are based on your hypothesis. How will this affect popping time explain? will give brainliest
This lets most of the light through but still blocks some hot air. It will take a long time to pop.
A hypothesis is an educated guess or tentative explanation that serves as a starting point for scientific investigation. It is a statement that suggests a possible relationship between two or more variables that can be tested through research.
A hypothesis should be based on existing knowledge and should be testable through empirical evidence. It should also be falsifiable, meaning that it should be possible to prove it wrong through experimentation or observation. In the scientific method, a hypothesis is usually formulated after conducting a literature review and making observations about the phenomena being studied. Once the hypothesis is established, the researcher can design experiments or collect data to test the hypothesis.
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Why is it a good laboratory skill to make multiple trials and average them?
Making multiple trials and averaging them is a good laboratory skill for several reasons such as, it reduces random error, increases precisions, increases accuracy and confidence in the result.
Why should multiple trials necessary as a good laboratory skill?Why multiple trials necessary as a good laboratory skill is that Random errors can occur in any laboratory experiment due to small variations in measurement or other factors that are beyond the experimenter's control. By conducting multiple trials and averaging the results, these random errors are minimized, since they will be averaged out across the different trials.
Also by averaging multiple trials, the overall precision of the measurement is increased. This is because averaging reduces the effect of outliers or other anomalous results that may occur in individual trials
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Consider a simple, ideal Rankine cycle modified with reheating. For constant mass flow rate, what is the affect on:
(a) pump power input,
(b) turbine power output,
(c) heat input required,
(d) waste heat rejected,
(e) thermal efficiency, and
(f) steam quality at the turbine exit
(a) Increasing the reheat in a simple, ideal Rankine cycle with a constant mass flow rate will result in an increase in pump power input. (b) Increasing the reheat in a simple, ideal Rankine cycle with a constant mass flow rate will result in a decrease in turbine power output.
(c) Heat input required increases due to the addition of reheat stages.
(d) Waste heat rejected increases due to the additional heat input required for reheating.
(e) Thermal efficiency slightly decreases due to the lower steam temperature after reheating.
(f) Steam quality at the turbine exit decreases slightly due to the lower steam temperature after reheating.
The Rankine cycle or Rankine Vapor Cycle is the process widely used by power plants such as coal-fired power plants or nuclear reactors. In this mechanism, a fuel is used to produce heat within a boiler, converting water into steam which then expands through a turbine producing useful work.
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An object has a potential energy of 19,000 J at a height of 2.75 m. What is the objects mass?
Answer:m = 0.7
Explanation:
Answer:
m = 705 kg
Explanation:
PE = m * g * h
m = PE / (g * h)
m = 19,000 (J) kg m/s² / (9.8 m/s² * 2.75 m)
m = 19,000 / (9.8 * 2.75 )
m = 19000 / 26.95
m = 705.009276438 kg
chatGPT
i have to teach (as a student) HOW A STEAM ENGIN WORKS
TELL ME ALL THE RESEARCH TOPICS FOR IT PLS
The steam engine moves a piston back and forth inside a cylinder using the force created by the pressure of the steam. A connecting rod and crank can convert this pushing force into a rotational force for wo
Why aren't steam engines used anymore?Because electric and diesel locomotives are faster, more effective, and simpler to operate, steam locomotives are no longer utilized to transport people or goods. The locomotives that are still in operation are historical artifacts from the 1800s that serve as a great reminder of how far we've come.
In what way do steam engines generate heat?Simply explained, steam engines generate heat energy by boiling water and producing steam using fire and coal (chemical energy). This heat energy is then used to push the cylinder and piston, which in turn moves the wheels (kinetic).
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According to eq. 6. 134, the x-velocity in fully developed laminar flow between parallel plates is given by u = 1 2μ ( ∂p ∂x) (y2 − h2) the y-velocity is υ = 0. Determine the volumetric strain rate, the vorticity, and the rate of angular deformation. What is the shear stress at the plate surface?
The volumetric strain rate is zero, the vorticity is -1/2μ (∂p/∂x) y, the rate of angular deformation is 1/2μ (∂p/∂x) y, and the shear stress at the plate surface is -1/2 (∂p/∂x) [tex]h^2[/tex].
Given:
x-velocity: u = 1/2μ (∂p/∂x) ([tex]y^2 - h^2[/tex])
y-velocity: υ = 0 (no variation in y-direction)
where,
μ = dynamic viscosity
p = pressure
x, y = coordinates
h = distance between the plates
To determine the volumetric strain rate, we can start by considering the continuity equation for incompressible flow, which states that the product of velocity and cross-sectional area is constant:
u × (h-y) = Q/A
where A is the cross-sectional area and Q is the volumetric flow rate.
Taking the derivative of both sides with respect to time and simplifying, we get:
dQ/dt = -u × dA/dy
Since the y-velocity is zero, we have dA/dy = 0, so:
dQ/dt = 0
This means that the volumetric flow rate is constant and there is no change in volume with time. Therefore, the volumetric strain rate is zero.
The velocity vector's curl is used to define the vorticity.
ω = ∇ x v
where ∇ is the del operator. For two-dimensional flow, the vorticity is a scalar and can be expressed as:
ω = (∂υ/∂x) - (∂u/∂y)
Substituting the given values for u and υ, we get
ω = 0 - (∂/∂y)[1/2μ (∂p/∂x) ([tex]y^2 - h^2[/tex])]
Simplifying and integrating with respect to y, we get:
ω = -1/2μ (∂p/∂x) y
The formula for angular deformation rate is:
D = (∂u/∂y + ∂υ/∂x) = ∂u/∂y
Substituting the given value for u, we get:
D = (∂/∂y)[1/2μ (∂p/∂x) [tex](y^2 - h^2)[/tex]]
Simplifying and integrating with respect to y, we get:
D = 1/2μ (∂p/∂x) y
To find the shear stress at the plate surface, we can use the following relation:
τ = μ (∂u/∂y)|y=h
Substituting the given value for u, we get:
τ = μ (∂/∂y)[1/2μ (∂p/∂x) ([tex]y^2 - h^2[/tex])]|y=h
Simplifying, we get:
τ = -1/2 (∂p/∂x) [tex]h^2[/tex]
Therefore, the volumetric strain rate is zero, the vorticity is -1/2μ (∂p/∂x) y, the rate of angular deformation is 1/2μ (∂p/∂x) y, and the shear stress at the plate surface is -1/2 (∂p/∂x) [tex]h^2[/tex].
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Solve fasttt pleasee
The labels for vectors A, B, and C ought to be determined by their magnitudes and directions. It is essential to keep track of their angles in relation to the +x axis.
(2) Look for Ay, Ay, B, B, C, and C:We need to use trigonometry to figure out the y and x-components of each vector in order to find Ay, Ay, B., B, C, and C. The magnitude of the vector is divided by the cosine of its angle with the +x-axis to get the y-component, and the magnitude of the vector is divided by the sine of its angle with the +x-axis to get the x-component.
(3) Determine the total force:The Pythagorean theorem can be used to determine the net force. We really want to add the x and y-parts of the vectors to acquire the resultant vector. The Pythagorean theorem can then be used to determine the magnitude of the net force.
In conclusion, we can use the Pythagorean theorem to determine the net force and trigonometry to determine the components of each vector.
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if a force of 50 newton stretches a wire from 20m to 20.01m what is the amount of force required to stretch the same material from 20m to 20.05m
250N is the amount of force required to stretch the same material from 20m to 20.05m
What is a force in science?A force is an effect in physics that causes the motion of a mass object to alter its velocity (e.g., moving from a state of rest), i.e., to accelerate. It can be a shove or a draw, with magnitude and direction always present, rendering it a vector quantity. It is measured in newtons (N) and is denoted by the sign F. (formerly P).
Newton's second law, in its initial version, says that the total force operating on an object is equivalent to the rate at which its momentum varies with time.
Original length = 20m
first new length = 20.01m
first increase in length = 20.01m - 20m = 0.01m
Second new length = 20.05m
second increase in length = 20.05 - 20m = 0.05m
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Full Question: If a force of 50N stretches a wire from 20m to 20.01m, what is the amount of force required to stretch the same material from 20m to 20.05m?
A. 250N
B. 200N
C. 100N
D. 50N
Estimate the terminal speed of a wooden sphere (density 0. 830 g/cm3) falling through air, if its radius is 8. 50 cm and its drag coefficient is 0. 500. (The density of air is 1. 20 kg/m3. )
The estimated terminal speed of the wooden sphere falling through air is approximately 8.68 m/s.
To estimate the terminal speed of the wooden sphere falling through air, we can use the following equation:
[tex]V_{terminal}[/tex] = [tex](2mg) / (p_{air} \times Cd \times A \times v^2)[/tex]
Where:
[tex]V_{terminal}[/tex] is the terminal velocity (m/s)
m is the mass of the sphere (kg)
g is the acceleration due to gravity (9.81 m/[tex]s^2[/tex])
[tex]p_{air}[/tex] is the density of air (1.20 kg/[tex]m^3[/tex])
[tex]C_d[/tex] is the drag coefficient (0.500)
A is the cross-sectional area of the sphere ([tex]m^2[/tex])
v is the velocity of the sphere relative to the air (m/s)
First, we need to calculate the mass of the sphere:
[tex]m = (4/3) \times \pi \times r^3 \times p[/tex]
where:
r is the radius of the sphere (m)
ρ is the density of the sphere (kg/[tex]m^3[/tex])
Substituting the given values, we get:
[tex]m = (4/3) \times \pi \times (0.0850 m)^3 \times 830 kg/m^3\\m = 0.980 kg[/tex]
Next, we need to calculate the cross-sectional area of the sphere:
[tex]A = \pi \times r^2\\A = \pi \times (0.0850 m)^2\\A = 0.0228 m^2[/tex]
Now, we can substitute the values into the equation for terminal velocity and solve for [tex]V_{terminal}[/tex] :
[tex]V_{terminal}[/tex] = [tex](2mg) / (p_{air} \times Cd \times A \times v^2)[/tex]
[tex]V_{terminal}[/tex] =[tex](2 \times 0.980 kg \times 9.81 m/s^2) / (1.20 kg/m^3 \times 0.500 \times 0.0228 m^2 \times v^2)[/tex]
[tex]V_{terminal}[/tex] = 8.68 m/s
Therefore, the estimated terminal speed of the wooden sphere falling through air is approximately 8.68 m/s.
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Difference between Magma and Lava ? (Please note that this question is based on grade 4 question )
Answer: The difference between lava and magma is if they have breached the surface yet. If the molten rock is still inside the earth, it is considered magma. once the volcano or opening erupts and the molten rock is on the surface, it is lava.
a horizontal rope is tied to a 50 kg box on frictionless ice. what is the tension in the rope if: a. the box is at rest? b. the box moves at a steady 5.0 m/s? c. the box has vx
A- The tension of the rope is 490.5N, when box is at rest , B- when box moves 5m/s tension is 500N, C- when the box has vx tension is 10Vx² N..
a)The tension in the rope when the box is at rest is equal to the weight of the box. Thus, the tension in the rope would be 50 kg x 9.81 m/s= 490.5 N.
b)When the box is moving at a steady 5.0 m/s, we need to use the equation of motion to find the tension in the rope. The equation of motion for a steady velocity is: F= ma+maF=2m(F=2m) (Since acceleration is zero)F=2(50kg)(0m/s²+5m/s²)F= 500N
c)When the box has a velocity component in the x-direction (Vx), the tension in the rope can be calculated as follows: F=ma+maF=2m(F=2m) (Since acceleration is zero)F=2(50kg)(Vx²/10m/s²)F= 10Vx² NThe tension in the rope when the box has a velocity component in the x-direction (Vx) is F = 10Vx² N.
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