Movie Mania requires customers to pay a sign-up fee of $20, and charges $4.00 to rent a DVD. Hurricane Video is free to join, but DVDs cost $6.00 to rent. Write and solve an equation to find the number of DVDs you would have to rent in order for both stores to charge the same. Explain what your variable represents.Movie Mania requires customers to pay a sign-up fee of $20, and charges $4.00 to rent a DVD. Hurricane Video is free to join, but DVDs cost $6.00 to rent. Write and solve an equation to find the number of DVDs you would have to rent in order for both stores to charge the same. Explain what your variable represents.

Answer: x=7

Step-by-step explanation:

Answer:

I believe it would be $2 per bag normally.

Step-by-step explination:

If you take $2 and subtract $.50 it is $1.50. Take that multiplied by the number of bags he bought (4), would mean he spent $6 at Wal-mart.

Now $2 subtracted my the sale of $1, is $1 per bag. If he bought 6 bags at Kroger, 1 multiplied by 6, would equal 6. Meaning he spent $6 at both stores if the price was $2.

Answer:

I believe the slope of the line passing through the points is x= -3

Answer:D

Step-by-step explanation:

$120.65 is the new price of the coat.

In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.

here, we have,

A department store purchases a coat for $95

To sell the coat to customers, the price is increased by 27%

So, the new price of the coat = $95+ $95*27%

                                                 =$120.65

Hence, $120.65 is the new price of the coat.

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MARK AS BRAINLIST

Step-by-step explanation:

L = 6t+5

H = √t

A = L*H

= (6t+5) *√t = 6t√t + 5√t

A'(t) = 6t * 1/2*√t + √t * 6 + 5/2*√t

= 6t/2√t + 6√t + 5/2√t

Expression for the rate of change of the area with respect to time will be,

A' = [tex]9t^{\frac{1}{2}}+\frac{5}{2}t^{-\frac{1}{2}}[/tex] cm per second

It's given in the question,

      (6t + 5) cm

       [tex]\sqrt{t}[/tex] cm

Area of the rectangle is given by,

Area = Length × Height

A = (6t + 5)(√t)

A = [tex]6t^{\frac{3}{2}}+5t^\frac{1}{2}[/tex]

Now find the derivative of area (A) with respect to time (t).

[tex]\frac{dA}{dt}=\frac{d}{dt}(6t^{\frac{3}{2}}+5t^\frac{1}{2})[/tex]

A' = [tex](6\times \frac{3}{2})t^\frac{1}{2}+\frac{5}{2} t^{-\frac{1}{2}}[/tex]

A' = [tex]9t^{\frac{1}{2}}+\frac{5}{2}t^{-\frac{1}{2}}[/tex]

     Therefore, expression for the rate of change of the area will be,

A' = [tex]9t^{\frac{1}{2}}+\frac{5}{2}t^{-\frac{1}{2}}[/tex]

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Answer:

44 i believe

Step-by-step explanation:

Equations: 60x + 3000 = 3,000, 600 + 150y = 3000

X: 20

Y: 10

You should solve for x & y

Q1: 0, it's already filled up to the max of 3000 pounds.

Q2: 16, 60 times 10 is 600. 3000-600 = 2400. 2400/150 = 16

I hope this helped, ask if you need more help :)

Answer:

=12n3+17n+16

i hope this helps :)

Answer:

It's A.

Step-by-step explanation:

Answer:

10 inches

Step-by-step explanation:

1,000 / 100 = 10

The answer is definatly NOT D. I think that the answer is A.

The design that should  give Shanika what she wants is the radius of 90 cm.

Since The table has a radius of 40 centimeters and height of 60 centimeters. She wants the tablecloth to hang an even 10 centimeters above ground.

So, the radius is

= 40 + 60 - 10

= 90 cm

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Answer:

7

Step-by-step explanation:

one bag of candy for every three people

12 ÷ 4 = 3

21 ÷ 7 = 3

Answer:

7  

Step-by-step explanation:

Apply proportions:

People/bag of candy

[tex]\frac{12}{4}[/tex]

For 21 people

[tex]\frac{21}{x}[/tex]

Equal both expressions

[tex]\frac{12}{4} =\frac{21}{x}[/tex]

Solve for x:

[tex]x=21\frac{12}{4} \\x= \frac{21}{3} \\x=7[/tex]

You should purchase 7 bags of candy

Answer:

that answer is b

Step-by-step explanation:

hope this helps

The area of square ABCD would be; 64 unit sq.

The shortest distance (length of the straight line segment's length connecting both given points) between points ( p,q) and (x,y) is:

D = √[(x-p)² + (y-q)²]    units.

Given that Square ABCD has vertices; A(-4.5, 4), B(3.5, 4),C(3.5, -4), and D(-4.5, -4).

To find the distance from two of the vertices of the square. The distance formula is as follows;

√[(x-p)² + (y-q)²]  

A(-4.5, 4), B(3.5, 4),

D = √[(x-p)² + (y-q)²]  

D = √(3.5-(-4.5))² +(4 -(4))²

D = √(3.5-(-4.5))² +(4 -(4))²

D = √(64 + 0)

D = 8

Therefore, the side of the square is 8 units.

The area of the square = side x side

= 8 x 8

= 64 unit sq.

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Answer:

if u get it pls tell me

Step-by-step explanation:

Answer:

y = -1/6x-3

hope this helps

Answer:

x+6y+18=0

Step-by-step explanation:

we have to use (y-y1)=m(x-x1)

now,(x1,y1)=(6,-4),m=-1/6

so, (y+4)=-1/6(x-6)

or,6y+24=-x+6

or,x+6y+24-6=0

x+6y+18=0 is the required equation.

Answer: Tiffany got 45 questions right! Hope this helped.

Step-by-step explanation:

Answer:

line A is steeper.

Line A´s slope is 1, while line d´s slope is 2/5

Answer:

yes they are equivalent

Answer:

pls help

Step-by-step explanation:

Answer:

1. yes

2. no

3. yes

4. yes

5. yes

Step-by-step explanation:

All triangles have 3 angle measurements that add up to 180

I did these all mentally so do double check :)

Answer:1.20/5

Step-by-step explanation:

Answer:

9/10 or in decimal form 0.9

Step-by-step explanation:

Answer:

t≈ 8

Step-by-step explanation:

\text{Compounded Monthly:}

Compounded Monthly:

A=P\left(1+\frac{r}{n}\right)^{nt}

A=P(1+  

n

r

​  

)  

nt

Compound interest formula

A=109700\hspace{35px}P=97000\hspace{35px}r=0.016\hspace{35px}n=12

A=109700P=97000r=0.016n=12

Given values

109700=

109700=

\,\,97000\left(1+\frac{0.016}{12}\right)^{12t}

97000(1+  

12

0.016

​  

)  

12t

Plug in values

109700=

109700=

\,\,97000(1.0013333)^{12t}

97000(1.0013333)  

12t

Simplify

\frac{109700}{97000}=

97000

109700

​  

=

\,\,\frac{97000(1.0013333)^{12t}}{97000}

97000

97000(1.0013333)  

12t

​  

Divide by 97000

1.1309278=

1.1309278=

\,\,1.0013333^{12t}

1.0013333  

12t

\log\left(1.1309278\right)=

log(1.1309278)=

\,\,\log\left(1.0013333^{\color{blue}{12t}}\right)

log(1.0013333  

12t

)

Take the log of both sides

\log\left(1.1309278\right)=

log(1.1309278)=

\,\,\color{blue}{12t}\log\left(1.0013333\right)

12tlog(1.0013333)

Bring exponent to the front

\frac{\log\left(1.1309278\right)}{\log\left(1.0013333\right)}=

log(1.0013333)

log(1.1309278)

​  

=

\,\,\frac{12t\log\left(1.0013333\right)}{\log\left(1.0013333\right)}

log(1.0013333)

12tlog(1.0013333)

​  

Divide both sides by log(1.0013333)

92.3402971=

92.3402971=

\,\,12t

12t

Use calculator

\frac{92.3402971}{12}=

12

92.3402971

​  

=

\,\,\frac{12t}{12}

12

12t

​  

Divide by 12

7.6950248=

7.6950248=

\,\,t

t

Answer:

x = 6

Step-by-step explanation:

5 times x is 5x, 5 times 9 is 45; 5x+49-4; 49 minus 4 is 45; 5x+45 = 75; now minus 45 from each side so it would now be 5x = 30; now divide; 30/5 = 6.

Answer:

1. A

2. D

3. A

4. A

Step-by-step explanation:

Question 1:

Switch sides:

5(5 + 4v) > 105

Divide both sides by 5:

5(5 + 4v) / 5 > 105/5

Simplify:

5 + 4v > 21

Subtract 5 from both sides:

5 + 4v - 5 > 21 - 5

Simplify:

4v > 16

Divide both sides by 4:

4v/4 > 16/4

Simplify:

v>4

Question 2:

Expand:

5m - 3m - 6 < 24 - 3m

Add similar elements:

2m - 6 < 24 - 3m

Add 6 to both sides:

2m - 6 + 6 < 24 - 3m + 6

Simplify:

2m < -3m +30

Add 3m to both sides and simplify:

5m < 30

Divide both sides by 5:

5m/5 < 30/5

Simplify:

m<6

Question 3:

Expand:

18x + 12 ≤ -39 + x

Subtract 12 from both sides and simplify:

18x ≤ x - 51

Subtract x from both sides and simplify:

17x ≤ -51

Divide both sides by 17 and simplify:

x ≤ -3

Question 4:

Add similar elements:

-3m + 5m = 2m

Expand and simplify:

2m ≥ -12m

Add 12m to both sides and simplify:

14m ≥ 0

Divide both sides by 14 and simplify:

m ≥ 0

Four years ago average age of A , B & C was 25 years.

A's present age

Let the ages of A , B , C be A , B , C years.

We know that,

Average = Sum of observations/Number of observations.

Here,

Sum of observations = A - 4 + B - 4 + C - 4 = (A + B + C - 12) years.

Number of observations = 3.

So, (A + B + C - 12)/3 = 25

⟹ A + B + C - 12 = 3 * 25

⟹ A + B + C = 75 + 12

⟹ A + B + C = 87 -- equation (1)

Also given that,

Average age of B & C before 5 years was 20 years.

⟹ (B - 5 + C - 5)/2 = 20

⟹ B + C - 10 = 2 * 20

⟹ B + C = 40 + 10

⟹ B + C = 50 -- equation (2)

Subtract equation (2) from equation (1).

⟹ A + B + C - (B + C) = 87 - 50

⟹ A + B + C - B - C = 37

⟹ A = 37 years

∴ A's present age is 37 years.

I hope it will help you.

Regards.

Answer:

→ md - 2nd + 3md = 2 * [ a + (n - 1)d ]

→ 4md - 2nd = 2 * [ a + (n - 1)d ]

→ 2(2md - nd) = 2 * (a + nd - d)

→ 2md - nd - a + d = nd

→ 2md - nd - (md - 2nd) + d = nd

[ From equation (1) ]

→ 2md - nd - md + 2nd + d = nd

→ md + nd + d = nd

→ (m + n + 1)d = n * d

→ (m + n + 1) = n

Step-by-step explanation:

Answer:

46. -22

47. -22

48. 8

Answer:

46) -22

47) -22

48)  8

49) -8

50) -4

51)  4

Step-by-step explanation:

Answer:

Answer: 7.93

Estimate: 8

Answer: 7.93, or to the nearest tenths, 7.9