Millie Moo the cow can produce 14
gallons of milk in 3 days. How many gallons
of milk does Millie produce each day?
Round to the nearest hundredth if
necessary.

Answer:

False

Step-by-step explanation:

For the one on the left I got 234 and the one on the right I got 248

Answer:

not sure what you need but I would be happy to help

Answer:

There is something wrong with the question because you cannot earn more interest during a year than the principal if you earn only 9% or 11%. You would have to earn more than 100%, so I will do this calculation based on $17,170 (not $171,700) earned in interest per year.

let S = amount received from short term note, and L = amount received from long term note

0.11S + 0.09L = 17170

S + L = 170000

S = 170000 - L

0.11 (170000 - L) + 0.09L = 17170

18700 - 0.11L + 0.09L = 17170

1530 - 0.02L = 0

1530 = 0.02L

L = 1530 / 0.02 = $76,500

S = 170000 - 76500 = $93,500

Answer:

3 over 100

Step-by-step explanation:

Answer:

-8z +724 + 5y +2c

Step-by-step explanation:

Combine like terms

Answer:

x = 9°

y = 119°

Step-by-step explanation:

Given,

y° = 61°+58° { the exterior angle formed by producing the side of triangle is equal to two non-adjacent angle}

or, y° = 119°

therefore, y° = 119°

Now,

52°+y°+x° = 180°{the sum of angle if triangle is 180°}

or, 52°+119°+x°= 180°

or, 171°+x° = 180°

or, x° = 180°-171°

or, x° = 9°

therefore, x° = 9°

Answer:

-15, -9, -3, 3

Step-by-step explanation:

First One:

y =3(-4)-3 is -15

Second:

y= 3(-2)-3 is -9

Third:

y= 3(0)-3 is -3

Last One:

y= 3(2)-3 is 3

Answer:

3 : 1

Step-by-step explanation:

The biggest circle has a radius of 20 cm

So that means, its area will be,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi * 20^{2}[/tex]

A = [tex]\pi * 400[/tex]

=> A = 400[tex]\pi[/tex]

We do not need to solve this because it is nit required

Then, one small circle has an area of,

Area = [tex]\pi r^{2}[/tex]

Area = [tex]\pi *5^{2}[/tex]

Area = [tex]\pi *25[/tex]

=> Area = 25[tex]\pi[/tex]

As there are 4 circles in, we get that the area covered by the small squares,

=> [tex]25\pi * 4[/tex]

=> [tex]100\pi[/tex]

So, the amount shaded = 100/400 (We can omit the [tex]\pi[/tex] at this stage because we are finding out a ratio)

=> 1/4

So, there is 1 cut region and the remaining is the uncut region,

As we need to find uncut to cut, the ratio will be,

=> remaining : 1

=> 3 : 1

If my answer helped, kindly mark me as the brainliest!!

Thanks!!

Answer:

z=2

Step-by-step explanation:

Just solve

1 + z = 3 (minus 1 on both sides)

z = 2

Plug in

3=(2+1)

3 = 3

Answer:

1/4 - 1/3i

Step-by-step explanation:

(4+3i)(-i) / 12i(-i)

= 3 - 4i / 12

Answer:

that what

Step-by-step explanation:

Answer:

10%

Step-by-step explanation:

(a) What percentage of meals had less than 10 grams of fat?

(b) Round your answer to the nearest tenth of a percent.

To find the percentage of meals with less than 10 grams of fat, count the number of meals with less than 10 grams of fat and divide by the total number of meals; multiply this figure by a hundred.

(A) Total number of meals = 550

Number of meals having less than 10 grams of fat = 77

Percentage of meals having less than 10 grams of fat = 77/550 × 100

= 0.14 × 100 = 14%

(B) Rounding the answer to the nearest tenth of a percent means approximating it to the nearest multiple of 10 that is not more than 100 (where 100 here represents a full cent or 'percent').

The multiples of 10 that are close to 14 are 10 and 20. The closest being 10, your answer becomes 10%

Given:

A basketball player made 55 baskets in a season.

20% of these baskets were three-point shots.

To find:

The number of three-point shots.

Solution:

We have,

Total number of baskets = 55

Number of three-point shots = 20% of total baskets

Now,

[tex]\text{Number of three-point shots}=\dfrac{20}{100}\times 55[/tex]

[tex]\text{Number of three-point shots}=\dfrac{1}{5}\times 55[/tex]

[tex]\text{Number of three-point shots}=11[/tex]

Therefore, the number of three-point shots did made by the player is 11.

Answer:

The answer is c. 5 5/8.

Step-by-step explanation:

Its c because your supposed to multiply them. When you multiply them you get 5 5/8. Hope this helped,have a great day!

Answer:

The correct answer is D. 37.975.

Step-by-step explanation:

Answer:

4/5

Step-by-step explanation:

Answer:

The number of printers for type A = x = 80 printers

The number of printers for type B = y = 60 printers

Step-by-step explanation:

Let the number of printers for type A = x

Let the number of printers for type B = y

You can order no more than 140 printers this month

x + y ≤ 140

x + y = 140

x = 140 - y

Profit for type A = $25

Profit for type B = $11

You need to make at least $2660 profit

25x + 11y ≥ 2660

25x + 11y = 2660

Substitute 140 - y = x

25(140 - y ) + 11y = 2660

3500 - 25y + 11y = 2660

3500 - 2660 = 25y - 11y

840 = 14y

y = 840/14

y = 60 printers

x = 140 - y

x = 140 - 60

x = 80 printers

To minimize cost :

The number of printers for type A = x = 80 printers

The number of printers for type B = y = 60 printers

Answer:

Cash it at the issuing bank (this is the bank name that is pre-printed on the check)

Cash a check at a retailer that cashes checks (discount department store, grocery stores, etc.)

Cash the check at a check-cashing store.

Deposit at an ATM onto a pre-paid card account or checkless debit card account.

Step-by-step explanation:

Answer:

Amscot?

Step-by-step explanation:

Answer:

a) 15.866%

b) Middle 95% = 350 ml to 750 ml

c) 0.3829

d) Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml

Step-by-step explanation:

We solve using z score formula

z-score is is z = (x-μ)/σ, where x is the raw score, μ is the population mean, and σ is the population standard deviation.

The distribution of bladder volume in men is approximately Normal with mean 550 ml and standard deviation 100 ml.

Required:

a. What percent of men have a bladder volume smaller than 450 ml?

z = 450 - 550/100

= -1

P-value from Z-Table:

P(x<450) = 0.15866

Convert to percentage

0.15866 × 100

= 15.866%

b. Between what volumes do the middle 95% of men’s bladders fall?

Middle 95% falls between 2 standard deviation of the mean

μ ± 2σ

μ - 2σ

550 - 2(100)

= 550 - 200

= 350 ml

μ + 2σ

= 550 + 2(100)

= 550 + 200

= 750 ml

Middle 95% = 350 ml to 750 ml

c. What proportion of male bladders are between 500 and 600 ml?

For 500ml

z = 500 - 550/100

= -0.5

Probability value from Z-Table:

P(x = 500) = 0.30854

For 600ml

z = 600 - 550/100

= 0.5

Probabilty value from Z-Table:

P(x = 600) = 0.69146

Proportion of male bladders are between 500 and 600 ml

P(x = 600) - P(x = 500)

0.69146 - 0.30854

= 0.38292

≈ 0.3829

d. What volumes do the middle 90% of men’s bladder fall?

The z score for middle 90% + / – 1.645

Hence,

1.645 = x - 550/100

1.645 × 100 = x - 550

164.5 + 550 = x

x = 714.5 ml

-1.645 = x - 550/100

-1.645 × 100 = x - 550

- 164.5 + 550 = x

x = 385.5ml

Middle 90% of men’s bladder fall = 385.5ml to 714.5 ml

Answer:

20°

Step-by-step explanation:

Step 1:

x + 40° = 3x       Vertical ∠'s

Step 2:

40° = 2x      Subtract x on both sides

Step 3:

x = 40° ÷ 2     Divide

Answer:

x = 20°

Hope This Helps :)

Answer:

i am pretty sure it would be 8

Step-by-step explanation:

when it rounds to 2 but also rounds to 100, 8 would be the best bet.

Answer:

A) The height of the trapezoid is 6.5 centimeters.

B) We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex].  [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex]

C) The length of the other base of the trapezoid is 20 centimeters.

D) We can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. [tex]b = \frac{A}{h}[/tex]

Step-by-step explanation:

A) The formula for the area of a trapezoid is:

[tex]A = \frac{1}{2}\cdot h \cdot (b_{1}+b_{2})[/tex] (Eq. 1)

Where:

[tex]h[/tex] - Height of the trapezoid, measured in centimeters.

[tex]b_{1}[/tex], [tex]b_{2}[/tex] - Lengths fo the bases, measured in centimeters.

[tex]A[/tex] - Area of the trapezoid, measured in square centimeters.

We proceed to clear the height of the trapezoid:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.

3) [tex]2\cdot A\cdot (b_{1}+b_{2})^{-1} = (2\cdot 2^{-1})\cdot h\cdot [(b_{1}+b_{2})\cdot (b_{1}+b_{2})^{-1}][/tex] Compatibility with multiplication/Commutative and associative properties.

4) [tex]h = \frac{2\cdot A}{b_{1}+b_{2}}[/tex] Existence of multiplicative inverse/Modulative property/Definition of division/Result

If we know that [tex]A = 91\,cm^{2}[/tex], [tex]b_{1} = 16\,cm[/tex] and [tex]b_{2} = 12\,cm[/tex], then height of the trapezoid is:

[tex]h = \frac{2\cdot (91\,cm^{2})}{16\,cm+12\,cm}[/tex]

[tex]h = 6.5\,cm[/tex]

The height of the trapezoid is 6.5 centimeters.

B) We should follow this procedure to solve the formula for [tex]b_{1}[/tex]:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]A = 2^{-1}\cdot h \cdot (b_{1}+b_{2})[/tex] Definition of division.

3) [tex]2\cdot A \cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot (b_{1}+b_{2})[/tex] Compatibility with multiplication/Commutative and associative properties.

4) [tex]2\cdot A \cdot h^{-1} = b_{1}+b_{2}[/tex] Existence of multiplicative inverse/Modulative property

5) [tex]\frac{2\cdot A}{h} +(-b_{2}) = [b_{2}+(-b_{2})] +b_{1}[/tex] Definition of division/Compatibility with addition/Commutative and associative properties

6) [tex]b_{1} = \frac{2\cdot A}{h}-b_{2}[/tex] Existence of additive inverse/Definition of subtraction/Modulative property/Result.

We used an algebraic approach to to solve the formula for [tex]b_{1}[/tex].

C) We can use the result found in B) to determine the length of the remaining base of the trapezoid: ([tex]A= 215\,cm^{2}[/tex], [tex]h = 8.6\,cm[/tex] and [tex]b_{2} = 30\,cm[/tex])

[tex]b_{1} = \frac{2\cdot (215\,cm^{2})}{8.6\,cm} - 30\,cm[/tex]

[tex]b_{1} = 20\,cm[/tex]

The length of the other base of the trapezoid is 20 centimeters.

D) Yes, we can find their lengths as both have the same length and number of variable is reduced to one, from [tex]b_{1}[/tex] and [tex]b_{2}[/tex] to [tex]b[/tex]. Now we present the procedure to clear [tex]b[/tex] below:

1) [tex]A = \frac{1}{2} \cdot h \cdot (b_{1}+b_{2})[/tex] Given.

2) [tex]b_{1} = b_{2}[/tex] Given.

3) [tex]A = \frac{1}{2}\cdot h \cdot (2\cdot b)[/tex] 2) in 1)

4) [tex]A = 2^{-1}\cdot h\cdot (2\cdot b)[/tex] Definition of division.

5) [tex]A\cdot h^{-1} = (2\cdot 2^{-1})\cdot (h\cdot h^{-1})\cdot b[/tex] Commutative and associative properties/Compatibility with multiplication.

6) [tex]b = A \cdot h^{-1}[/tex] Existence of multiplicative inverse/Modulative property.

7) [tex]b = \frac{A}{h}[/tex] Definition of division/Result.

Answer:

Step-by-step explanation:

The maximum profit will be found in the vertex of the parabola, which is what your equation is. You could do this by completing the square, but it is way easier to just solve for h and k using the following formulas:

[tex]h=\frac{-b}{2a}[/tex] for the x coordinate of the vertex, and

[tex]k=c-\frac{b^2}{4a}[/tex] for the y coordinate of the vertex.

x will be the selling price of each widget and y will be the profit. Usually, x is the number of the items sold, but I'm going off your info here for what the vertex means in the context of this problem.

Our variables for the quadratic are as follows:

a = -10

b = 600

c = -3588. Therefore,

[tex]h=\frac{-600}{2(-10)}=30[/tex] so the cost of each widget is $30. Now for the profit:

[tex]k=-3588-(\frac{(600)^2}{4(-10)})[/tex] This one is worth the simplification step by step:

[tex]k=-3588-(\frac{360000}{-40})[/tex] and

k = -3588 - (-9000) and

k = -3588 + 9000 so

k = 5412

That means that the profit made by selling the widgets at $30 apiece is $5412.

Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].

What is the maximum profit?

Maximum profit, or profit maximisation, is the process of finding the right price for your products or services to produce the best profit.

Here given that,

A company sells widgets. The amount of profit, [tex]y[/tex], made by the company, is related to the selling price of each widget, [tex]x[/tex], by the given equation.

As the maximum profit found in the vertex of the parabola,

Here, [tex]x[/tex] will be the selling price of each widget and [tex]y[/tex] will be the profit.

The number of items sold is [tex]x[/tex].

So, the quadratic equation is:-

[tex]a = -10b = 600c = -3588.[/tex]

Therefore, so the cost of each widget is $[tex]30[/tex].

For the profit:-

[tex]k = -3588 - (-9000) andk = -3588 + 9000 sok = 5412[/tex]

Hence,the profit made by selling the widgets at $[tex]30[/tex] apiece is $[tex]5412[/tex].

To know more about the maximum profit

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Answer:

2 2/3 or 8/3

Step-by-step explanation:

Formula for each side = 2/3 x 2/3

2/3 x 2/3 = 4/9

6 sides

4/9 x 6 or 4/9 + 4/9 + 4/9 + 4/9 + 4/9 + 4/9

=2 2/3 or 8/3

Answer:

2 2/3

Is the answer

Answer:

8 quarts

Step-by-step explanation:

no explanation needed this should be correct.

Answer:

You're right!

Step-by-step explanation:

Answer:

Were you right?

Step-by-step explanation: