A submarine is exploring the Pacific Ocean. At 502.5 feet below sea level, the water temperature is 63 1/4 °F. The submarine dives down 115 feet deeper, and the water temperature drops by 2 1/5 °F. What were the elevation and the water temperature after the submarine dove? Assume that sea level is at 0 feet of elevation.

Write an expression to represent the submarine’s elevation after its final dive. Then simplify the expression to find its elevation.

Answer:

-502.5 - 115 = - 617.5

63 1/4 - 2 1/5 =  

63 - 2 = 61

1/4 - 1/5 = 5/20 - 4/20 = 1/20

so 63 1/4 - 2 1/5 = 61 1/20

after the sub dove, elevation level is - 617.5 and temp is 61 1/20 F

Step-by-step explanation:

The elevation is 617.5 feet deep and the temperature is [tex]61\dfrac{1}{20}[/tex] F.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

The expression for the elevation is,

E = -502.5 - 115

E  = - 617.5 feet

The temperature at this elevation is calculated as:-

⇒ 63 ( 1/4 )- 2( 1/5 )

⇒ 63 - 2 = 61

⇒ 1/4 - 1/5

⇒ 5/20 - 4/20

⇒ 1/20

T = 63 (1/4) - 2 ( 1/5 )

T = 61 ( 1/20 ) F

Therefore, the elevation is 617.5 feet deep and the temperature is [tex]61\dfrac{1}{20}[/tex] F.

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