Mars is 7.83x10^10m [^10 is an exponent] from planet earth. The planet Earth is 5.98x10^24kg [^24 is an exponent] while Mars has a mass of 6.42x10^23kg [^23 is an exponent]. What is the gravitational attraction between the two planets? G=6.67×10^-11 (-11 is an exponent)
![Mars Is 7.83x10^10m [^10 Is An Exponent] From Planet Earth. The Planet Earth Is 5.98x10^24kg [^24 Is](https://brainimage.s3.us-east-005.backblazeb2.com/contents/attachments/zzl1b1xTCobWnhl88SMhQp8wjFrqLMYb.jpeg)
Answers
Answer:
Approximately [tex]4.18 \times 10^{16}\; \rm N[/tex].
Explanation:
Consider two objects of mass [tex]m_{1}[/tex] and [tex]m_{2}[/tex]. Let [tex]r[/tex] denote the distance between the center of mass of each object. Let [tex]G[/tex] denote the gravitational constant. ([tex]G \approx 6.67 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1}\cdot s^{-2}}[/tex].)
By Newton's Law of Universal Gravitation, the size of gravitational attraction between these two objects would be:
[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}}\end{aligned}[/tex].
In this question, [tex]m_{1} = 5.98\times 10^{24}\; {\rm kg}[/tex] and [tex]m_{2} = 6.24 \times 10^{23}\; {\rm kg}[/tex] are the mass of the two planets. The distance between the two planets is [tex]r = 7.83 \times 10^{10}\; \rm m[/tex] (approximately the same as the distance between the center of mass of planet Earth and the center of mass of Mars.)
Apply Newton's Law of Universal Gravitation to find the size of gravitational attraction between the two planets:
[tex]\begin{aligned}F &= \frac{G\, m_{1}\, m_{2}}{r^{2}} \\ &= \frac{1}{(7.83 \times 10^{10}\; {\rm m})^{2}} \\ &\quad \times (6.67 \times 10^{11}\; {\rm m^{3} \cdot kg^{-1} \cdot s^{-2}}) \\ &\quad \times (5.98 \times 10^{24}\; {\rm kg}) \\ &\quad \times (6.42 \times 10^{23}\; {\rm kg}) \\ &\approx 4.18 \times 10^{16}\; {\rm kg \cdot m \cdot s^{-2}} \end{aligned}[/tex].
Since [tex]1\; {\rm kg \cdot m \cdot s^{-2}} = 1\; {\rm N}[/tex], the size of gravitational attraction between the two planets would be approximately [tex]4.18 \times 10^{16}\; {\rm N}[/tex].
Related Questions
a 3 kg rock is falling from a rock ledge in the absence of air resistance how much force will the rock strikes the ground with
Answers
Answer:
papi sus
Explanation:
The expression below was formed by combining different gas laws. V is proportional to StartFraction n T over P EndFraction. Which law was used to determine the relationship between the volume and the number of moles in this equation? Boyle’s law Charles’s law Avogadro’s law Gay-Lussac’s law.
Answers
The relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
Avogadro's law:
It states that at constant temperature and pressure, gases with same volume has the same number of molecules.
For an ideal gas with with constant temperature and pressure, the volume of the gas is directly proportional to the amount or number of molecules.
Charle's law states that at constant pressure, volume (V) and temperature (T) are directly proportional.Boyle's law states that at constant temperature, the volume of gas is inversely proportional to the gas pressure.Gay-Lussac's law states that pressure (P) and absolute temperature (T) of the gas are directly proportional.Therefore, the relationship between the number of moles and the volume of gas is determined by the Avogadro's law in this equation.
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Answer:
Avogadro's law
Explanation:
A number line goes from 0 to 30. Closed circles are at 6 and 25. A line is drawn from point 6 to point 25. Ari is swimming a 25-meter race. After swimming 6 meters, she catches up to Amanda in a ratio of 7:3 from the 6-meter mark. At what meter mark does Ari catch up to Amanda? Round to the nearest tenth, if necessary. Ari catches up to Amanda at meters.
Answers
The position on the meter mark where Ari catches up with Amanda is 19.3 m.
The given parameters:
Range of the number line, = 0 to 30Position of the closed circles, = 6 and 25The ratio between the initial position and final position of Ari = 7:3The distance between 6 m mark and 25 m mark is calculated as follows;
[tex]d = 25 \ m - \ 6 \ m\\\\\d = 19 \ m[/tex]
The distance traveled by Ari before catching up with Amanda is calculated as follows;
total ratio = 7 + 3 = 10
[tex]distance = \frac{7}{10} \times 19 \ m\\\\distance = 13.3 \ m[/tex]
The position of Ari from the 6 m mark is calculated as follows;
[tex]position = 6 \ m \ + \ 13.3 \ m\\\\position = 19.3 \ m[/tex]
Thus, the position on the meter mark where Ari catches up with Amanda is 19.3 m.
Learn more about partition of line segments here: https://brainly.com/question/11764811
Answer:
The above answer is correct! The answer is 19.3 meters :)
Explanation:
adding a ss for proof!
hope this helps :D
can someone explain it please?
Answers
Answer:
The answer is 9.4 m/s
Explanation:
Because you add 5.0 + 4.5= 9.4
The mass of a car is 2000 lbs, and is traveling 100 mi/hr on the freeway, what is its momentum?
Answers
Answer:
momentum= 145999324.8(kg(m/s))
Explanation:
formula for momentum: p=mv
where p= momentum, m=mass, and v=velocity.
p=2000lbs(100mi/hr)
The standard unit for mass is kg
2000lbs=907.2kg
standard unit for velocity is meters/sec
100mi=160934meters.
907.2kg(160934m/s)=145999324.8
Which form can solutions come in?
liquid
gas
solid
all of the above
Answers
Answer:
liquid
Explanation:
leave a thanks if helped !
Kepler’s laws of planetary motion describe each of the three laws
Answers
Kepler's laws laid the foundation for the early study of astronomy.
Kepler was one of the earliest astronomers that contributed immensely to the study of the planets. The Kepler's laws of planetary motion are as follows;
The planets each travel along an ellipse with the sun at one focus.The line joining the sun and the planets sweeps out equal areas in equal time intervals.The square of the period of the revolution of the planets equals the cube of the planet's mean distance from the sun.Learn more about Kepler's laws; https://brainly.com/question/1017661
What is number 10 for this?
Answers
Answer:
The wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Given data in the question;
Speed of wave;
Frequency of wave;
wavelength;
To determine the wavelength of the radio wave, we use the expression for the relations between wavelength, frequency and speed.
Where is wavelength, f is frequency and c is the speed.
We substitute our given values into the equation
Therefore, the wavelength of WFNX’s radio waves with the given speed and frequency is 2.95m.
Explanation:
can someone explain it with steps?
A car was moving on a road at a constant speed of 15 m/s when suddenly the car driver saw some animal on the road at a distance of 21 m from the car, so he applied the brakes after a response time of 0.4 s and stopped before hitting the animal by 1 m. What was the deceleration of the car?
a-7.5 m/s^2
b-5.2 m/s^2
c-8.0 m/s^2
d-5.6 m/s^2
Answers
Answer:
Option C is the correct answer
Explanation:
Distance travelled by car during reaction time
[tex]=15\times0.4\\\\=6m[/tex]
The car stopped before hitting the animal by [tex]1 m[/tex]
Distance travelled during deceleration is [tex]21-6-1=14m[/tex]
Hence by [tex]v^2=u^2+2as[/tex]
We have
[tex]0^2=15^2+2 \cdot a \cdot 14\\\\a=\frac{-225}{28} \\\\=-8.03m/s^2[/tex]
Option C is the correct answer
Distance traveled during reaction time
15(0.4)=6mTotal distance
21-6-1=14m[tex]\\ \sf\longmapsto v^2-u^2=2as[/tex]
[tex]\\ \sf\longmapsto -(15)^2=2(14)a[/tex]
[tex]\\ \sf\longmapsto -225=28a[/tex]
[tex]\\ \sf\longmapsto a=-8.0m/s^2[/tex]
Use this table of a school bus during morning pickups to calculate its average speed between 0 h and 2.340 h.
Position (km) Time (h)
0.0 0.000
1.2 0.024
2.8 0.051
4.2 0.084
16.3 2.340
Answers
The average speed between 0 h and 2.340 h is 6.97 Km/h
Average speed is defined as the total distance travelled divided by the total time taken to cover the distance.
[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\ [/tex]
With the above formula, we can obtain the average speed between 0 h and 2.340 h as illustrated below:
Total time = 2.340 – 0 = 2.340 hTotal distance = 16.3 – 0 = 16.3 KmAverage speed =?[tex]Average \: speed = \frac{total \: distance}{total \: time} \\ \\Average \: speed = \frac{16.3}{2.340} \\ \\ Average \: speed = 6.97 \: Km/h \\ \\ [/tex]
Learn more about average speed: https://brainly.com/question/24884027
Answer:
6.983 km/hr
Explanation:
The average rate of change is (16.34 - 0.0)/(2.34 - 0.000) ≈ 6.983 km/hr
Mejor yo por favor
What is velocity? Explain.
Answers
Answer:
The velocity of an object is the rate of change of its position with respect to a frame of reference, and is a function of time. Velocity is equivalent to a specification of an object's speed and direction of motion (e.g. 60 km/h to the north).what is the most likely reason for the difference between how the compass works on earth and on the moon?
Answers
Answer: A compass taken to Earth's moon does not point in a specific direction on the moon. The moon does not have a strong magnetic field.
how to find velocity of center of mass before and after the collision
Answers
Hey there! I'll try to provide you with my best answer.
Answer: In a collision, the velocity change is always computed by subtracting the initial velocity value from the final velocity value. If an object is moving in one direction before a collision and rebounds or somehow changes direction, then its velocity after the collision has the opposite direction as before.
A moving coil meter has a resistance of 25 and indicate full scale deflection when a current of 4.0mA flows through it.How could this meter be converted to a millimeter having a full scale deflection for a current of 50 mA?
Answers
To find resistance(Rs)
Formula R
′
s=
lg−G
V
Calculations by formula
R
′
s=
(10×10
−3
−25
100
=10000−25
=9975
Ans- resistance by 9975Ω
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA.
Current sensitivity (S) is the ratio of full-scale deflection current to full-scale deflection voltage.
S = I(fsd) / V(fsd).
S = 4.0 / 25
S = 0.16 mA/Ω
Desired current sensitivity for 50 mA (S(new)) = 50 mA / V(fsd)
(S(new)) = 50 mA / V(fsd)
(S(new)) = 50 / 0.16
(S(new)) = 312.5 Ω
Add External Resistor:
Add an external resistor (R(ext)) in series with the meter. Calculate R(ext) as the difference between R(new) and the internal resistance of the meter
(R(internal) = 25 Ω:
R(ext) = R(new) - R(internal)
R(ext) = 312.5 Ω - 25 Ω
R(ext) = 287.5 Ω
By adding an external resistor of 287.5 Ω in series with the meter, the conversion of the moving coil meter to have a full-scale deflection for a current of 50 mA. This will achieve the desired result.
To know more about the external resistor:
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A 150 g sample of brass at 100 °C is placed in a Styrofoam cup of water containing 120 mL of water at 10 °C. No heat is lost to the cup or surroundings. What is the final temperature of the mixture? answer in celsius
Answers
Answer:
≈19.144°C.
Explanation:
all the details are in the attachment.
Note, that c₁, m₁, t₁ are the parameters of the sample of brass; c₂, m₂ and t₂ are the parameters of the sample of water.
P.S. change the provided design according Your requirements.
plssss helppppppppppp i need it
Answers
Answer:
D
Explanation:
I don't know how to explain it I just did it
By the way thxs for help on one of my problems
anything that has mass and occupies space is called
Answers
Answer:
Matter
Hope you could get an idea from here.
Doubt clarification - use comment section.
Depth perception is also known as ___________ vision.
Answers
Answer:
depth from optical expansion
Explanation:
A crate slides down a ramp that makes a 20∘ angle with the ground. To keep the crate moving at a steady speed, Paige pushes back on it with a 68 N horizontal force.
Part A
How much work does Paige do on the crate as it slides 3.0 m down the ramp?
Answers
Answer:
the answer is 69.7687j
Explanation:
W =F sin Φ
who made the first game
A William Shakespeare
B Horace Alexander
C Doris Twitchell Allen
D William higginbotham
Answers
Hope this helps
The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)
Answers
Answer:
Formula = D = m/v
Given value of D = 19.3 and m = 13g
19.3 = 13/v
V × 19.3 = 13
v = 13/19.3
v = 0.67
What will happen if the two plungers are pressed together firmly? Explain your answer.
Answers
Answer:
This air being forced out causing the air pressure inside to be much lower than that on the outside. As higher air pressure always pushes, it keeps the two plungers together.
Hope that helps. x
plssssss look at the picture i need it right hurry pls
Answers
Answer:
it is B
Explanation:
Answer:
CO and H20
Explanation:
Given that the mass of a liquid is 0.01kg and the volume of the liquid is 0.05m^3 . Calculate the density of the liquid
A) 2kg/m^3
B)0.2kg/m^3
C) 5kg/m^3
D) 0.5kg/m^3
Answers
Answer:
B.
Explanation:
Density = mass / volume
= 0.01/0.05
= 0.2 kg/m^3.
Which image shows an example of the electromagnetic force in action?
Answers
Answer:
Where are the images?
Explanation:
I can't help if there is no image(s) to this question.
bow long does it take earth to rotate once on its axis
Answers
Answer:
23 hours, 56 minutes
The time it takes Earth to rotate so the sun appears in the same position in the sky, known as a solar day, is 24 hours. However, the time it takes Earth to complete one full rotation on its axis with respect to distant stars is actually 23 hours 56 minutes 4.091 seconds, known as a sidereal day.
what are two variables that are always in every experiment?
Answers
the independent variable and the dependent variable.
how to prove the first linear motion
Answers
Answer:
Then solve for v as a function of t. This is the first equation of motion . It's written like a polynomial — a constant term (v0) followed by a first order term (at). Since the highest order is 1, it's more correct to call it a linear function.
Explanation:
Describe your acceleration if you ride your bike up a hill,then ride down the other side.
Answers
Answer:
first negative and then positve
Help it multiple-choice 16 and 17 only
Answers
Answer:
16. c
17. d
Explanation:
16. Newton’s third law states that a force will always have an opposite but equal force as a reaction, so every force comes as a pair of action-reaction forces. For example, if you push on a book, the book also pushes on you.
17. If 1cm represents 15N, then 5cm must represent 15N*5=75N.