in the case shown below, the 1 kg rock rides on a horizontal disk that rotates at constant speed 5m/s about its vertical axis. the radius of the disk is 1 meter. What is the magnitude of the friction?

Answer:

light refraction

Explanation:

Answer

I Think Its 150

Answer:

Explanation:

Step one:

given data

speed = 123m/s

radius of circle= 4330m

Step two:

We need to find the circumference of the circle, it represents the distance traveled

C=2πr

C= 2*3.142*4330

C= 27209.72m

Step three:

We know that velocity= distance/time

time= distance/velocity

time= 27209.72/123

time=221.2 seconds

in minute = 221.2/60

time= 3.7 min

Answer:

A) 2.650 km

Explanation:

The relationship between acceleration of gravity and gravitational constant is:

[tex]g = \frac{Gm}{R^2}[/tex] ---- (1)

Where

[tex]R = 6,400 km[/tex] -- Radius of the earth.

From the question, we understand that the gravitational field of the rocket is 50% of its original value.

This means that:

[tex]g_{rocket} = 50\% * g[/tex]

[tex]g_{rocket} = 0.50 * g[/tex]

[tex]g_{rocket} = 0.5g[/tex]

For the rocket, we have:

[tex]g_{rocket} = \frac{Gm}{r^2}[/tex]

Where r represent the distance between the rocket and the center of the earth.

Substitute 0.5g for g rocket

[tex]0.5g = \frac{Gm}{r^2}[/tex] --- (2)

Divide (1) by (2)

[tex]\frac{g}{0.5g} = \frac{Gm}{R^2}/\frac{Gm}{r^2}[/tex]

[tex]\frac{g}{0.5g} = \frac{Gm}{R^2}*\frac{r^2}{Gm}[/tex]

[tex]\frac{1}{0.5} = \frac{1}{R^2}*\frac{r^2}{1}[/tex]

[tex]2 = \frac{r^2}{R^2}[/tex]

Take square root of both sides

[tex]\sqrt 2 = \frac{r}{R}[/tex]

Make r the subject

[tex]r = R * \sqrt 2[/tex]

Substitute [tex]R = 6,400 km[/tex]

[tex]r = 6400km * \sqrt 2[/tex]

[tex]r = 6400km * 1.414[/tex]

[tex]r = 9 049.6\ km[/tex]

The distance (d) from the earth surface is calculated as thus;

[tex]d = r - R[/tex]

[tex]d = 9049.6\ km - 6400\ km[/tex]

[tex]d = 2649.6\ km[/tex]

[tex]d = 2650\ km[/tex] --- approximated

Answer:

Explanation:

The speed of the horse can be found by using the formula

[tex]v = \frac{p}{m} \\ [/tex]

p is the momentum

m is the mass

From the question we have

[tex]v = \frac{1200}{313} \\ = 3.83386..[/tex]

We have the final answer as

Hope this helps you

Answer:

Non-uniform velocity as the laser light beam has got reflected by the mirror

And as the light got reflected there is a change in velocity making it non-uniform velocity

Answer:

2008

Explanation:

2000+3+5======2008

Answer:

[tex]8\hat i-2\hat j-2\hat k[/tex]

Explanation:

Vectors in 3D

Given a vector

[tex]\vec P = P_x\hat i+P_y\hat j+P_z\hat k[/tex]

A vector [tex]\vec Q[/tex] parallel to [tex]\vec P[/tex] is:

[tex]\vec Q = k.\vec P[/tex]

Where k is any constant different from zero.

We are given the vectors:

[tex]\vec A = \hat i+4\hat j-2\hat k[/tex]

[tex]\vec B = 3\hat i-5\hat j+\hat k[/tex]

It's not specified what the 'resultant' is about, we'll assume it's the result of the sum of both vectors, thus:

[tex]\vec A +\vec B = \hat i+4\hat j-2\hat k + 3\hat i-5\hat j+\hat k[/tex]

Adding each component separately:

[tex]\vec A +\vec B = 4\hat i-\hat j-\hat k[/tex]

To find a vector parallel to the sum, we select k=2:

[tex]2(\vec A +\vec B )= 8\hat i-2\hat j-2\hat k[/tex]

Thus one vector parallel to the resultant of both vectors is:

[tex]\mathbf{8\hat i-2\hat j-2\hat k}[/tex]

Answer:

transition metals im sorry if this was too late

Answer:

Friction is when 2 solids move against each other. The cause of friction is adhesion, and surface roughness. Surface roughness is when a surface is rough enough that is causes friction against another surface. Adhesion is when 2 surfaces collide because of thier molecular force.

Answer:

1.92 m/s2

Explanation:

Answer:

44 grams- 55 grams through the whole day. Probably about 14.6 grams per meal.

Explanation:

Answer:

2 thumbs (ISSA Guide)

Explanation:

Answer:small differences in models can lead to large differences in complex systems

Explanation:   this is the  most accurate phrase  

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 60 × 2

We have the final answer as

Hope this helps you

Answer:

Pt 1: [tex]W=39J[/tex]

Pt 2: θ = [tex]19.7[/tex]

Explanation:

Part 1:

[tex]W=FS[/tex]

[tex]W=F_{_xs_x}+F{_ys_y}[/tex]

imagine the "i"and the "j" with the hat

[tex]W=(10i-1j)(4i+3j)[/tex]

[tex]W=(10*4)-(1*1)[/tex]

[tex]W=40-1[/tex]

[tex]W=39J[/tex]

Part 2:

[tex]|F|=\sqrt{10^2+(-1)^2}[/tex]

[tex]|F|=\sqrt{101}[/tex]

[tex]|S|=\sqrt{4^2+1^2}[/tex]

[tex]|S|=\sqrt{17}[/tex]

[tex]W=|F||S|cos[/tex]θ

[tex]39=(\sqrt{101})(\sqrt{17} )cos[/tex]θ

θ = [tex]19.7[/tex]

Hope it helps

Answer:

(1) R n = ( 1 − α ) R si − L ↑ + L ↓ where Rn is the net radiation (W m−2), Rsi is the solar radiation (W m−2), α is the soil surface albedo (α = 0–1

Explanation:

Answer:

Mike can travel 80 Km in 4 hours

Answer:

v_maria > 4.5 m/s

v_samantha > 3.8 m/s

Explanation:

Formula for centripetal acceleration is;

a_c = v²/r

Where;

v is speed

r is radius

For Maria;

r = 12 m

v = 4.5 m/s

Thus;

a_c = 4.5²/12

a_c = 1.6875 m/s²

For Samantha;

r = 6

v = 3.8 m/s

Thus;

a_c = 3.8²/6

a_c = 2.41 m/s²

We want to find how could each skater increase her centripetal acceleration without changing the size of her path.

From the centripetal acceleration formula, since the size of path can't be changed it means the radius can't be changed and so the only thing that can now increase the centripetal acceleration is when the speed increases.

Thus;

For Maria, she has to move with a faster speed. Thus: v_maria > 4.5 m/s

For Samantha, she also has to move with a faster speed. Thus; v_samantha > 3.8 m/s

Answer:

A

Explanation:

i think

Answer:25 N

Explanation:

in the case shown below, the 1 kg rock rides on a horizontal disk that rotates at constant speed 5m/s is 25N

Speed is the ratio of distance with respect to the time in which the distance was covered. Speed is a scalar quantity as it does not have magnitude only have direction

The formula of speed can be represented as s=d/t, Where, s is the speed in m.s-1, d is the distance traveled in m, t is the time taken in s

Uniform speed is defined when the object covers equal distance at equal time intervals, variable speed is defined as when the object covers a different distance at equal intervals of times.

Average speed is defined as the total distance travelled by an object to the total time taken by the object.

Instantaneous speed is defined as when the object is move with variable speed, then the speed at any instant of time is known as instantaneous speed.

For more details regarding speed, visit

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Answer:

The fundamental resonance frequency is 172 Hz.

Explanation:

Given;

velocity of sound, v = 344 m/s

total length of tube, Lt = 1 m = 100 cm

height of water, hw = 50 cm

length of air column, L = Lt - hw = 100 cm - 50 cm = 50 cm

For a tube open at the top (closed pipe), the fundamental wavelength is given as;

Node to anti-node (N ---- A) : L = λ / 4

λ = 4L

λ = 4 (50 cm)

λ = 200 cm = 2 m

The fundamental resonance frequency is given by;

[tex]f_0 = \frac{v}{\lambda}\\\\f_0 = \frac{344}{2}\\\\f_0 = 172 \ Hz\\\\[/tex]

Therefore, the fundamental resonance frequency is 172 Hz.

Answer:

Bobbie will need 12.7 seconds.

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes uniformly in time. If the speed changes from vo to vf in a time t, then the acceleration is:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The question states Bobbie is riding on a skateboard down a hill, starting from vo=26 m/s with an acceleration of a=6\ m/s^2 until his speed is 102 m/s. We are required to find the time needed to create that change of velocity.

Solving for t:

[tex]\displaystyle t=\frac{v_f-v_o}{a}[/tex]

[tex]\displaystyle t=\frac{102-26}{6}=\frac{76}{6}[/tex]

t = 12.7 s

Bobbie will need 12.7 seconds.

Answer:

The displacement is 6.4m

Explanation:

Step one:

given

we are told that Lucy runs 4 meters to the east,

then 5 meters south.

let the distance east be the displacement in the x-direction, and south be the y-direction

Step two:

The resultant of the x and y displacement is the magnitude of the total displacement z

applying Pythagoras theorem we have

z=√x^2+y^2

z=√4^2+5^2

z=√16+25

z=√41

z=6.4m

Answer:

The one with equal forces on both sides, D is your answer

Explanation:

A, 5 and 10 No

B 13 and 8 no

C 5 and 8 no

D 6 and 6 YES

Object 4 have steady speed. Object 4 have same force on both the sides of object. Same force is applied on both the sides.

Uniform or constant velocity describes a body's motion when there is no acceleration. A body's velocity is its rate of movement in a specific direction.

When running steadily, your exhaustion should be caused by the length of the run, not by your speed. A steady-state run pace, according to the McMillan Running website, is halfway between your current 30k and half-marathon pace. This speed should allow you to run for 25 to 75 minutes.

Therefore, Object 4 have steady speed. Object 4 have same force on both the sides of object. Same force is applied on both the sides.

To learn more about velocity, refer to the link:

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Increase of momentum of the collision will have the car in a unsettling position, creating an unsettling spot for it. Moreover increasing this would most likely take worse effect, it is better than increasing the time, which will only create the car faster. Let me show you what I mean...

Answer:

The value is [tex]KE = 259.6 \ J[/tex]

Explanation:

From the question we are told that

     The weight of the horizontal solid disk is  [tex]W = 805 \ N[/tex]

      The radius of the horizontal solid disk is  [tex]r = 1.58 \ m[/tex]

      The force applied by the child is  [tex]F = 49.5 \ N[/tex]

       The time considered is  [tex]t = 2.95 \ s[/tex]

Generally the mass of the  horizontal solid disk is mathematically represented as

          [tex]m_h = \frac{W}{ g}[/tex]

=>       [tex]m_h = \frac{805}{ 9.8 }[/tex]

=>       [tex]m_h = 82.14 \ N[/tex]

Generally the moment of inertia  of the horizontal solid disk is mathematically represented as  

         [tex]I = \frac{1}{2} * m * r^ 2[/tex]

=>      [tex]I = \frac{1}{2} * 82.14 * 1.58^ 2[/tex]  

=>      [tex]I = 102.5 \ kg \cdot m^2[/tex]

Generally the net torque experienced by the horizontal solid disk is mathematically represented as

           [tex]T = I * \alpha = F * r[/tex]

=>         [tex]\alpha = \frac{ F * r }{ I }[/tex]

=>         [tex]\alpha = \frac{ 49.5 * 1.58 }{ 102.53 }[/tex]

=>         [tex]\alpha = 0.7628[/tex]

Gnerally from kinematic equation we have that

         [tex]w = w_o + \alpha t[/tex]

Here  [tex]w_o[/tex] is the initial angular velocity velocity of the horizontal solid disk  which is  [tex]w_o = 0\ rad/s[/tex]

So

           [tex]w = 0 + 0.7628 * 2.95[/tex]

=>        [tex]w = 2.2503 \ rad/s[/tex]

Generally the kinetic energy is mathematically represented as

        [tex]KE = \frac{1}{2} * I * w^2[/tex]

=>      [tex]KE = \frac{1}{2} * 102.53 * 2.2503 ^2[/tex]

=>      [tex]KE = 259.6 \ J[/tex]

Split up the forces into components acting parallel to and perpendicular to the slope. See the attached picture for the reference axes.

The box stays on the surface of the plane, so that the net force acting perpendicular to it is 0, and the only acceleration is applied in the parallel direction.

Let m be the mass of the box, θ the angle the plane makes with the ground, and a the acceleration of the box. By Newton's second law, we have

• net parallel force

∑ Force (//) = W (//) - F = m a

(that is, the net force in the parallel direction is the sum of the parallel component of the weight W and the friction F which acts in the negative direction)

• net perpendicular force

∑ Force (⟂) = W (⟂) + N = 0

Notice that

W (//) = W sin(θ) … … … which is positive since it points down the plane

W (⟂) = -W cos(θ) … … … which is negative since it points opposite the normal force N

So the equations become

W sin(θ) - F = m a

-W cos(θ) + N = 0

Solving for a gives

a = (W sin(θ) - F ) / m

which is good enough if you know the magnitude of the friction force.

If you don't, you can write F in terms of the coefficient of kinetic friction between the box and plane, µ, as

F = µ N

so that

a = (W sin(θ) - µ N ) / m

and the normal force itself has a magnitude of

N = W cos(θ)

so that

a = (W sin(θ) - µ W cos(θ) ) / m

The weight W has magnitude m g, where g is the magnitude of the acceleration due to gravity, so

a = (m g sin(θ) - µ m g cos(θ) ) / m

a = g (sin(θ) - µ cos(θ))