I can’t figure it this problem out please help me

The total cost of materials for one candle is $2 and she pays $40 for the booth for the day.

Therefore, the total cost for making and selling one candle is $2 + $12 + $40 = $54

To cover all her expenses, Leila must sell enough candles to make $54 from each candle.

She must sell 54/$12 = 4.5 candles

Therefore, Leila needs to sell at least 5 candles to cover all her expenses.

At that point, her sales and expenses will be 5 candles x $12/candle = $60

Therefore, Leila's sales and expenses will be $60 at that point.

Answer: 3 + y = 24

Step-by-step explanation: Hello!

If she rode 3 miles one day and y miles the other 6 days of the week, and in total that adds up to 24 miles, that means the equation should be addition.

3 miles + y miles = 24 miles
Monday, other 6 days, total seven days

The equation should be:
3 + y = 24

The sampling used in this situation is Stratified sampling
In the question, students are selected from subgroups of Sophomore, Junior, and Senior classes.

We are told that 49, 34, and 48 students are selected from the Sophomore, Junior, and Senior classes with 496, 348, and 481 students respectively.

This means that the sample numbers of 49, 34 and 48 students were selected in proportion to the subgroup sizes of 496, 348, and 481 students respectively.

Thus, due to the fact that subgroups were selected & that sample number of students were also selected in proportion to their respective subgroup sizes.

This is, therefore, a stratified sampling.

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Q: 49, 34, and 48 students are selected from the Sophomore, Junior, and Senior classes with 496, 348, and 481 students respectively. Identify which type of sampling is used and why?

The linear equation for the cost of lemonades is 1.50*x+6 where x=5 i.e. A   and he spends $54.75 in total.

What is a linear equation ?

A linear equation is an equation in which the highest power of the variable is always 1. It is also known as a one-degree equation. The standard form of a linear equation in one variable is of the form

Ax + B = 0

e.g. x-10=0. Here, x is a variable, A is a coefficient and B is constant.

The standard form of a linear equation in two variables is of the form

Ax + By = C

e.g. 2x-4y=10. Here, x and y are variables, A and B are coefficients and C is a constant.

Now,

Cost of lemonade=$1.5, number of lemonades=5

Cost of hamburger=$8.25, number of hamburgers=5

Tip=$6

Hence,

        Total cost=5*1.5+5*8.25+6

          Total cost =$54.75

Cost of lemonades only = 5*1.5+6

In type of linear equation  1.50*x+6 where x=5

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Approximation of decimals is a mathematical technique for finding or measuring approximations and minimizing the number of decimal places.

A fractional representation of a real number that comes close to representing it. Any real number a can be represented by an endless number of decimal fractions.

The number of decimal places in a decimal number is the number of digits following the decimal point. A mathematical method for locating or measuring approximations and reducing the number of decimal places is known as approximation of decimals.

Any comparison that is close but not accurate to another entity is called an approximation. By rounding, one can get a good idea of a number. By rounding the values in a computation before performing the operations, a calculation can be approximated.

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The temperature of city A is 4°C.

The temperature of city B is 4°C.

An equation is a mathematical statement that is made up of two expressions connected by an equal sign.

Example:

2x + 4= 6 is an equation.

We have,

5x = 8 + 3y  ______(1)

x − 2y = −4 _______(2)

Where x is the temperature of city A and y is the temperature of city B.

Now,

From (2),

x = -4 + 2y

Substitution in (1).

5 (-4 + 2y) = 8 + 3y

-20 + 10y = 8 + 3y

-20 - 8 = 3y - 10y

-28 = -7y

y = 4

Now,

x = -4 + 2y

x= -4 + 2 x 4

x = -4 + 8

x = 4

Thus,

The temperature of both city A and city B is 4°C.

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The constants a and b can be found by ensuring the function is continuous and that the limits at each point match. This can be done by setting the values of a and b so that the function and its derivative are equal at each point.

To find the constants a and b for the given piece-wise cubic function, we must consider the definition of continuity and limits. Firstly, for the function to be continuous, the function and its derivative must be equal at each point. Thus, we need to set the values of a and b so that the function and its derivative are equal at the points x=1, x=2 and x=3. We can use this to create a system of equations to solve for a and b. Once we have determined the values of a and b, we can then check that the limits at each point match. This can be done by computing the left and right hand limits at each point, and ensuring they are equal. If the limits are equal, then the function is continuous and the constants a and b are correct.

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The measures of the angles are Z = 146 degrees, X and W = 34 degrees and B = 119 degrees

Question 4

From the question, we have

<Y = 146 degrees

Because the lines XY and WZ are equal, it means that

<Z = 146

So, we have

X = W = (180 - 146)

Evaluate

X = W = 34

Question 6

Here, we have

Sum of the angles = 180 degrees

This gives

9x + 2 + 5x - 4 = 180

Evaluate the like terms

14x = 182

Divide by 14

x = 13

So, we have

B = 9 * 13 + 2

B = 119 degrees

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The equation of the line that is parallel to x + y = 4 and passes through (2, 3) is expressed as: y = -x + 5.

Two lines are parallel if and only if their slopes are equal. The equation of the line x + y = 4 is in slope-intercept form (y = mx + b), where m is the slope. The slope of this line is m = -1, as the coefficient of x is -1.

An equation of a line that is parallel to the line x + y = 4 and passes through the point (2, 3) can be written in the form y = mx + b, where m = -1.

Substituting the point (2,3) and the slope -1 into the point-slope form of a line gives:

y - 3 = -1(x - 2)

Expanding the right hand side gives:

y - 3 = -x + 2

And rearranging the equation gives the final form of the equation of the line:

y = -x + 5

So, the equation of the line that passes through the point (2, 3) and is parallel to the line x + y = 4 is y = -x + 5.

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Length of malcom's story is 418lines, the operation used to solve this problem is; lines of zac story+ extra lines of malcom story.

Usually, simplification involves proceeding with the pending operations in the expression. Like, 5 + 2 is an expression whose simplified form can be obtained by doing the pending addition, which results in 7 as its simplified form. Simplification usually involves making the expression simple and easy to use later.

Given;

Number of lines in zac story=273

Number of lines in malcom story= 273+145

Now.

Total number of lines in malcom story

=273+145

=418

Therefore, the answer after simplification will be 418

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Answer:

x = -2

y = -5

Step-by-step explanation:

5x - y = -5

3x - 6y = 24

First, multiply the first equation by -6

-30x + 6y = 30

3x - 6y = 24

-27x = 54

x = -2

Now, put in -2 for x and solve for y

5(-2) - y = -5

-10 - y = -5

-y = 5

y = -5

Let's Check

5(-2) -(-5) = -5

-10 + 5 = -5

-5 = -5

So, x = -2   y = -5  is the correct answer.

The sample has 3.33% of defective bulbs so, B. The shipment will not be replaced.

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, If a shipment has at least 5% defective light bulbs, it will be replaced.

Now, A sample of 60 light bulbs has 2 that are defective.

Therefore, The percentage of defective bulbs is,

= (2/60)×100%.

= (1/30)×100%.

= 3.33%, So, the shipment will not be replaced.

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Answer:

(pr²)

given,

p=3 r=3

(3 X 3²)

(3 X 9)

27

The frequency table is added below

From the question, we have the following parameters that can be used in our computation:

7 9 6 8 7 6 8 6 9 5 7 7

6 8 9 8 8 6 4 8

When represented on a frequency table, we have

Class limits Class boundaries Frequency

2.5 - 3.5            3.0 - 4.0         0

3.5 - 4.5            4.0 - 5.0              1

4.5 - 5.5             5.0 - 6.0            1

5.5 - 6.5             6.0 - 7.0       5

6.5 - 7.5              7.0 - 8.0          4

7.5 - 8.5              8.0 - 9.0           6

8.5 - 9.5             9.0 - 10.0            3

Total        20

The class boundary is calculated as

class boundary = Class limits ± 0.5

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The answer is x4 – 6x2 – 27 = 0 and this is a quadratic equation in the polynomials .

This is a quartic equation because the highest degree is 4

In the second option, we have 3x⁴ = 2x, this is also another quartic equation.

In the third equation, we have 2(x + 5)⁴ + 2x² + 5 = 0, this is a quartic equation because the highest degree is 4

In the fourth equation, 6(2x + 4)² = (2x + 4) + 2

This is a quadratic equation because the highest degree is 2

In the fifth equation, we have 6x⁴ = -x² + 5 which is also another quartic equation

An algebraic equation of the second degree in x is a quadratic equation. The quadratic equation is written as ax2 + bx + c = 0, where x is the variable, a and b are the coefficients, and c is the constant term. First, there must be a term other than zero in the coefficient of x2 (a 0) for an equation to be a quadratic equation. The x2 term is written first when constructing a quadratic equation in standard form, then the x term, and finally the constant term. The numerical values of a, b, and c are typically expressed as integral values rather than fractions or decimals.

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The measure of other two angles in the given quadrilateral are 10° and 25°.

A quadrilateral is a polygon with four sides four angles and four vertices. Whenever we name a quadrilateral, we need to keep in mind the order of the vertices.

Given that, two angles of a quadrilateral measure 130° and 195°.

The other two angles are in a ratio of 2:5.

So, the other two angles are 2x and 5x

Now, 130°+195°+2x+5x=360°

325°+7x=360°

7x=360°-325°

7x=35°

x=5

So, 2x=10° and 5x=25°

Therefore, the measure of other two angles in the given quadrilateral are 10° and 25°.

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Arithmetic mean deals will middle number while geometric mean deals with typical value

From the question, we have

Arithmetic mean and Geometric mean

The arithmetic mean is the sum of a set of numbers divided by the number of items in the set, and is often used to find the "middle" value of a dataset.

On the other hand, the geometric mean is the nth root of the product of a set of numbers and is often used to find the "typical" value of a dataset when dealing with quantities that can increase or decrease exponentially.

The above definitions imply that the difference between the arithmetic mean and geometric mean can be significant when dealing with sets of numbers that have large variations in values.

In general, the geometric mean will be less than or equal to the arithmetic mean.

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The numeric value of the greatest sum that can be obtained by Greg is given as follows:

1173.

When two n digit numbers are added, the numbers in the equivalent positions are added with each other, that is, starting from the end of the number to the begining.

For example, 21 + 32:

Hence the sum is of 54.

Hence the greatest sum would be obtained as follows:

Hence the sum would be given as follows:

642 + 531 = 1173.

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Answer:

a)  Domain:  (-∞, 10)

b)  k⁻¹(8) = 6

c)  CBD

d)  Range:  (-∞, 7)

e)  k⁻¹(0) = 4

f)  x = -5

Step-by-step explanation:

The domain of the inverse of a function is the same as the range of the original function.  

Therefore, the domain of the inverse function is:

The inverse of a function is its reflection in the line y = x.

Therefore, given that function k(6) = 8 then:

The inverse of a function is its reflection in the line y = x.

We cannot find k⁻¹(-9) since we have not been given the value of x when k(x) = -9.

The range of the inverse of a function is the same as the domain of the original function.  

Therefore, the range of the inverse function is:

The inverse of a function is its reflection in the line y = x.

Therefore, given that function k(4) = 0 then:

The zero of the inverse function is the y-intercept of the original function.  Therefore, given that k(0) = -5 then:

Therefore, x = -5 is a zero of k⁻¹(x).

We have to find solutions for the given differential equation when

y = 0,  y = 1/(k-x) and y(a) = b using ordinary differential equations.

We have dy / dx = y^2

a. let's define the given y = 1/(k-x)

derive the above equation with respect to x :

                                  dy / dx = y' = 1/(k-x)^2

So this is the general solution.

b) We would want a singular solution that is not included in the general form. Here we could use y = 0

dy / dx = 0 = 0^2

so,this is a trivial singular solution.

c) If we have y(a) = b,

then, y = 1(k-a) = b

To find the value of k we use the other condition: y'(^2) = 4 x y(2)

           1/(k-a)^2 = 4 x  1/(k-a)

              k - 2 = 1/4

              therefore, k = 9/4

hence we got, y = 1/(9/4 - a) = b

So the points (a, b) are of the form: (a, 1/(9/4 - a))

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The complete question is :

Find a general solution of the differential equation dy/dx=y2

b. Find a singular solution that is not included in the general solution.

c. Inspect a sketch of typical solution curves to determine the points (a,b) for which the initial value problem (y′)2=4y,y(a)=b

Answer:

it is easy to add all the numbers up then you will get 77 then tell me how many number should you add to get to 100 it is easy trust me

Step-by-step explanation:

The graph that represents an exponential decay function is the second graph.

For you to determine which of the graphs represents an exponential decay, we will need to check the curve that passes through or lies on the x-axis.

we can draw a graph by putting the value of x and we are getting the value of y in this way we get the coordinates of a point

From both figures, we can see that the curve of the second graph almost lies on the x-axis as it curves downwards. This makes it an exponential decay function.

Hence the graph that represents an exponential decay function is the second graph.

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complete question is

Which description matches the function represented by this graph?

A. exponential growth

B. linear growth

C. linear decay

D. exponential decay

Answer:

B or 2

Step-by-step explanation:

The answer above is correct.

Answer:

1.7320508075689

The amount of the principal investment is, $1200. So option A is correct

Simple interest is an amount which is calculated for a certain period of time and for a certain rate, in simple interest calculation there are three factors which we consider: principal amount(P), rate(R) and time(T).

Every time we calculate simple interest the principal values will be the same unlike compound interest.

Formula;    Simple Interest(I) =  P × R × T/100

A = P(1 + RT)

Given that,

A = $1422

R =  3.7%

T =  5 year

P  = ?

After 5 year total amount

1422 = P ( 1 + 0.037 × 5)

P  =   1422/( 1 + 0.037 × 5)

   =    1422/1.185

P  =    1200

Hence, the principal amount is $1200

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there exists an integer that is greater than 5 and whose square is smaller than 40, express as a mathematical quantifiers ∃x∈ℤ: x > 5 ∧ x² < 40

1.  Start by writing down the equation: x² < 40

2.  Take the square root of both sides of the equation to isolate the variable x: √x² < √40

3.  Simplify both sides of the equation: x < √40

4.  Check that the result makes sense: x < 6.3

5.  Take the integer part of the result: x < 6

6.  Since the requirement is that x is greater than 5, the answer is x = 6.

We start by writing the equation x² < 40 and then take the square root of both sides to get x < √40. We check that the result is reasonable and then take the integer part of the result to get x < 6. Since the requirement is that x is greater than 5, the answer is x = 6. To confirm, we can calculate that x² = 36 which is smaller than 40, and indeed, 6 is greater than 5. Therefore, the integer that is greater than 5 and whose square is smaller than 40 is 6. This can be expressed mathematically as ∃x∈ℤ: x > 5 ∧ x² < 40 which translates to: There exists an integer x such that x is greater than 5 and the square of x is smaller than 40.

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Based on the steps for solving the equation, a true statement include the following: A. there are infinitely many solutions to the equation.

In Mathematics, no solution is sometimes referred to as zero solution, and an equation is said to have no solution when the left hand side and right hand side of the equation are not the same or equal.

In Mathematics, an equation is said to have an infinitely many solution when the left hand side and right hand side of the equation are the same or equal:

3x - 9x + 1 = 2(-3x + 1) - 1

-6x + 1 = -6x + 2 - 1

-6x + 1 = -6x + 1

When x = 1, we have:

-6(1) + 1 = -6(1) + 1

-5 = -5.

When x = 2, we have:

-6(2) + 1 = -6(2) + 1

-11 = -11.

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The equation of the exponential function is y = 0.2⋅2^x

The steps for this process are as follows:

Step 1: Set up the equation.

The equation of an exponential function has the form y = a⋅b^x

where a and b are constants and b is greater than 0 and not equal to 1.

Step 2: Find the constants.

We can use the given points to find the constants in the equation. For example, when x = 0, y = 0.2.

So we can set 0.2 = a⋅b^0.

This means that a = 0.2 and b^0 = 1,

so b = 1.

Step 3: Write the equation.

Substituting a = 0.2 and b = 1 into the equation gives us y = 0.2⋅2^x.

This is the equation of the exponential function represented by the table.

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Applying the linear pair definition, m<KGH = 60°.

In geometry, a linear pair is a pair of adjacent angles that are supplementary, meaning that their measures add up to 180 degrees. The two angles must be adjacent, meaning that they share a common side or vertex, and they must be linear, meaning that they are formed by two intersecting lines.

Therefore:

m<FGK + m<KGH = 180

Substitute

120 + m<KGH = 180

m<KGH = 180 - 120

m<KGH = 60°

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