Answer:
Speed and velocity are related in much the same way that distance and displacement are related. Speed is a scalar and velocity is a vector.
Calculate the aceleration of a vehicle of 100 kg when applicates 400 N
Answer:
For this we applicate 2nd law of Newton:
F = ma
Replacing:
400 N = 100 kg * a
a = 400 N / 100 kg
a = 4 m/s²
The aceleration is 4 meters per second squared.
Answer:
....................
Explanation:
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pls help me with this
Answer:
A screw
Explanation:
help plz The sum of all chemical reactions that take place within an organism is known as ______________. *
Answer:
Metabolism
Explanation:
metabolism is the sum of all chemical reactions that take place within an organism
Answer:
Metabolism
Explanation:
what is the function of brushes in D.C motor
Answer:
to transfer the voltage
Explanation:
The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.
A meter stick is found to balance at the 49.7-cm mark when placed on a fulcrum. When a 41.5-gram mass is attached at the 28.5-cm mark, the fulcrum must be moved to the 39.2-cm mark for balance. What is the mass of the meter stick
Answer:
The value is [tex]M = 42.3 \ kg[/tex]
Explanation:
From the question we are told that
The first position of the fulcrum is x = 49.7 cm
The mass attached is [tex]m = 41.5 \ g[/tex]
The position of the attachment is [tex]x_1 = 28.5 \ cm[/tex]
The second position of the fulcrum is [tex]x_2 = 39.2 \ cm[/tex]
Generally the sum of clockwise torque = sum of anti - clockwise torque
So
[tex]CWT = m (x_2 - x_1)[/tex]
Here CWT stands for clockwise torque
[tex]ACWT = M ( x - x_2)[/tex]
So
[tex]m (x_2 - x_1) = M ( x - x_2)[/tex]
=> [tex]41.5 (39.2 - 28.5 ) = M ( 49.7 -39.2 )[/tex]
=> [tex]M = 42.3 \ kg[/tex]
the center of mass of a donut is located ?
a. in the hole
b. in material making up the donut
c. near the center of gravity
d. over a point of support
Answer:
A
Explanation:
where the hole is because it's a rigid object with uniform density.
Why do you think it is colder during the winter than the summer?
Answer:
As the earth travels around the sun during the year it maintains this tilt. Because of this tilt, in the summer we (north of the equator) are slanted more directly towards the sun so it's hotter. In the winter, we're slanted away so the sun's rays are less direct, making it colder.
A woman can lift barrels a vertical distance of 1 meter or can roll them up a 2-meter long ramp to the same elevation. If she uses the ramp, the applied force required is
Answer:
answer is 1/2 as much force required
what is the uses of space weather data?
Answer:
Space Weather Data
They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.
Explanation:
a 5.00 kg plane is speeding up on the ground with an applied force of 706 N. If the net force is 450 N, what would be the force due to air resistance
Answer:
The force due to air resistance is 256 N.
Explanation:
Given;
mass of the plane, m = 5 kg
applied force on the plane, Fa = 706 N
the net force on the plane, ∑F= 450 N
Let the force due to air resistance = Fr
The net force on the plane is given as;
Net force = applied force - force due to air resistance
∑F = Fa - Fr
Fr = Fa - ∑F
Fr = 706 - 450
Fr = 256 N.
Therefore, the force due to air resistance is 256 N.
at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C
Answer:
The volume of the gas becomes three times the initial volume.
Explanation:
Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.
So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.
The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.
As the pressure is constant, so [tex]P_1=P_2[/tex].
Let V_1 and V_2 be the initial and final volume respectively.
Assuming that the given gas is ideal gas.
So, applying the ideal gas equation
PV=nRT
where n is the number of moles of the gas and R is the universal gas constant.
For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]
and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]
Dividing the equation (i) by (ii), we have
[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]
As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then
[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]
As the pressure is not changing, so [tex]P_1=P_2[/tex], then
[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]
[tex]V_2=3V_1[/tex]
So, the volume of the gas becomes three times the initial volume.
Speed, Velocity, and Acceleration Escape Room.
Enter the correct 4 digit code (no spaces
Answer:1342
Explanation:
Calculate the displacement of the following components:
1 units North
2 units South
2 units North
2 units North
3 unit South
Answer:
zero displacement
its returnin to the starting point.
5 north 5 south
1. A book is at rest on a tabletop. Diagram the forces acting on the book.
The free-body diagram of the forces acting on a book resting on a table is shown in the figure.
When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.
So, the forces acting on a book resting on a tabletop are:
1. Weight of the book, W(downward)
2. Normal force (N) perpendicular to the surface in contact.
Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.
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A race car makes one lap around a track with a radius of 41 meters in 8 seconds. What is the velocity?
Answer:
31.21 m/s
Explanation:
radius=41m
time = 8 sec
circumference=2πr
from formula
circumference=2×22/7×41
=257.71m
now
velocity=total distance( circumference)/total time
=257.71/8
= 32.21m/s
The velocity of race car makes one lap around a track with a radius of 41 meters in 8 seconds is 32.19 m/s
What is velocity ?Velocity is "rate of change of displacement with respect to time".
i.e. v= dx/dt
it is also defined as displacement over time. i.e. v=Displacement/Time.
Velocity shows how much distance can be covered in unit time. It's SI unit is m/s. It is vector quantity ( having both direction as well as momentum). where displacement is distance from mean position.
Given,
Radius of the track r= 41m
time taken by car to complete one lap T = 8s
velocity v = ?
we know that ω = 2π÷T
ω = 2×3.14 ÷ 8
ω = 0.785 rad/s
v=rω
v= 41×0.785
v= 32.185 ≅32.19 m/s
Hence velocity of the car is 32.19 m/s
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I need help with the questions when it says what is the topic and rest
** 8. How many atoms of Carbon are in C2H40?
Answer:
2
Explanation:
A huge enormous gigantic number ... two in every molecule of the stuff !
a small balloon containing baking soda has a mass of 4 grams. A student adds 10 ml. of vinegar
to a 100 gram glass bottle. The student stretches the opening of the balloon over the mouth of
the bottle, mixing the baking soda and vinegar inside the bottle. Once the balloon is inflated, the
student finds the mass of the balloon, bottle, and their contents to be 116 grams. What was the
mass of the vinegar originally in the bottle
F.10g G.12g J.16g
Answer:
10 grams
Explanation:
I took a test with this question earlier.
A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a horizontal frictionless surface initially. When the ball is, again magically, released inside the shell, it sloshes around in the shell and eventually stops at the bottom of the shell. How far does the shell move from its initial contact point with the surface
Answer:
[tex]x =\frac{-R}{2}[/tex]
Explanation:
From the question we are told that mass
Thin layer radius [tex]= 2R[/tex]
Generally the expression for ths solution is given as
Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2
the center of mass will not move at initial state
Considering the center of mass of both bodies
[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]
[tex]x =\frac{-R}{2}[/tex]
Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]
The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
Given-
Radius of the ball is [tex]R[/tex].
the mass of the ball is [tex]m[/tex].
The mass of the thin shell is [tex]m[/tex].
The radius of the thin shell is [tex]2 R[/tex].
For the two bodies with mass [tex]m[/tex], the center of mass can be given as,
[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]
In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,
[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]
[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]
[tex]x_{cm} =x[/tex]
Distance for center of mass can also be given as,
[tex]x_{cm} =m\times o[/tex]
[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]
[tex]x_{cm} =\dfrac{-R}{2}[/tex]
Comparing both the values of the distance of center of mass we get,
[tex]x =\dfrac{-R}{2}[/tex]
Hence, The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
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PLZ HELP MEEEEEEE,;-;
Answer:
thxs for the points
Explanation:
because just started
will you help me please
Answer: True
Explanation: It's true because the definition of a Command economy states that it's an economy in which production, investment, prices, and incomes are determined CENTERALLY by a GOVERNMENT.Which of the following best describes reflection?
a. Reflection is when waves bend around an obstacle.
b. Reflection is when waves bounce off a surface.
c. Reflection is when waves bend.
Reflection is when waves bounce off a surface this because I did it in 7th grade was my favorite unit to learn in school.
What is Reflection?When two different media come together at an a wavefront might change direction so that it returns to the first medium, which is known as reflection.
The reflection of light, sound, and water waves are typical examples. According to the law of reflection, the angle at which the wave incident on the surface equals the angle at which it is reflected for specular reflection (such as at a mirror).
Reflection produces echoes in acoustics and is used in sonar. It is crucial to the study of seismic waves in geology. Surface waves in bodies of water are used to observe reflection.
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A ball has a mass of 0.1 kg and an initial velocity of 20 m/s. The ball is given an acceleration of 30 m/s2 for 5 s. What is the net force on the ball during acceleration?
Answer:
acceleration = v-u /t
30- 20/5
= 10/5 = 2m/sec²
Force = mass * acceleration
Force = 0.1 * 2
Force = 0.2 Newton
Answer:
I hope the above pic will help you
I will always help you understanding your assingments
have a great day #Captainpower:)
How much energy is required to raise the temperature of 5.0 g of silver from 298 K to
334 K?
Answer:
43.2J
Explanation:
Q = m × c × ∆T
Where:
Q = amount of energy
m = mass (grams)
c = specific heat capacity
∆T = change in temperature
Mass = 5.0g
Specific heat capacity of Silver (Ag) = 0.240 J/g°C
We need to convert the temperature from Kelvin (K) to °C
Initial temperature = 298 - 273 = 25°C
Final temperature = 334 - 273 = 61°C
Q = 5 × 0.240 × (61°C - 25°C)
Q = 1.2 × 36
Q = 43.2J
An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the airplane?
Answer:
You need to put the diagrams. repost and include the diagrams
PLEASE HELP ME!!!!!!!!!!!!
Answer:
It is either A or D I think it is A.
A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.
Calculate;
1)The work done by the effort
2)The efficiency of the system
3)The effort applied
Answer:
1) 4000Joules
2) 25%
3) 320N
Explanation:
A block and tackle consisting of 5 pulleys is used to raised a load of 400N through a height of 10m.If the work done against friction is 100j.
Calculate;
1)The work done by the effort
2)The efficiency of the system
3)The effort applied
1) Workdone by the effort is the work input = Load * distance moved by the Load
Workdone by the effort = 400 * 10
Workdone by the effort = 4000Joules
2) Efficiency = Work output/Work input * 100
Work output = work done against friction = 100 Joules
Efficiency = 100/4000 * 100
Efficiency = 10000/4000
Efficiency = 25%
Hence the Efficiency of the system is 25%
3) Using the efficiency formula:
efficiency = MA/VR * 100
Velocity ratio = 5
MA = Load/Effort
efficiency = (L/E)/5 * 100
25 = 400/E/5 * 100
25/100 = 400/5E
0.25 = 400/5E
0.25 * 5E = 400
1.25E = 400
E = 400/1.25
E = 320N
hence the effort applies is 320N
define light?it's types
Answer:
Light or visible light is electromagnetic radiation within the portion of the electromagnetic spectrum that can be perceived by the human eye. Visible light is usually defined as having wavelengths in the range of 400–700 nm, or 4.00 × 10⁻⁷ to 7.00 × 10⁻⁷ m, between the infrared and the ultraviolet.
Explanation:
This is one type of light.
Voltage has been described as similar to the water in the water pipes in your home. What other analogy can you think of that is similar to voltage?
A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.
Answer:
Explanation:
It is still using F = m*a -- just in a disguised form.
Givens
F = 900 N
vf = 360 m/s
vi = 0
t = 40 second
Formulas
a = (vf - vi)//t
F = m * a
Solution
a = (360 - 0)/ 40
a = 9
F = m * a
900 = m * 9
m = 900/9
m - 100 kg. Doesn't seem high enough.
Answer:
a= V- u/t
a= 360 - 0 /40 = 9 m/sec2
F = MA
900 = M * 9
M = 900/9
M= 100 kg