Answer:
The velocity of the droplet right before it hits the ground is 40.08 m/s.
Explanation:
To determine the velocity of the droplet right before it hits the ground,
From one of the equations of kinematic for free fall motions,
v = u + gt
Where v is the final velocity
u is the initial velocity
g is acceleration due to gravity (take g = 9.8 m/s²)
and t is time
For the question, v is the velocity of the droplet right before it hits the ground.
u = 0 m/s (Since the molten lead was dropped from rest)
Therefore,
v = gt
First, we will determine the time t
Also, from one of the equations of kinematic for free fall motions,
h = ut + 1/2(gt²)
u = 0 m/s
From the question, the molten lead was dropped from the top of the 82.15 m tall tower, therefore
h = 82.15
Hence,
82.15 = 0×t + 1/2 (9.8 × t²)
82.15 = 1/2 (9.8 × t²)
82.15 = 4.9 t²
t² = 82.15/4.9
∴ t = 4.09 secs
Now, for the velocity v, of the droplet right before it hits the ground,
Recall
v = gt
Then,
v = 9.8 × 4.09
v = 40.08 m/s
Hence, the velocity of the droplet right before it hits the ground is 40.08 m/s.
Use the principle of superposition (Equation 1.3) to predict the electric field at the point 0.5 meters to the right and 1.5 meters above the 5 nC charge. Express your result both in terms of x and y components, and then in terms of total magnitude and direction.
Answer:
Explanation:
The x component of electric field Ex = k Q / R²
= 9 x 10⁹ x 5 x 10⁻⁹ / .5²
= 180 N .
The y component of electric field Ey = k Q / R²
The y component of electric field Ey
= 9 x 10⁹ x 5 x 10⁻⁹ / 1.5²
= 20 N
Total field = [tex]\sqrt{180^2+20^2}[/tex]
= 181.1 N .
Angle with x axis = Tanθ = Ey / Ex = 20 / 180 = .111
= 6.33⁰
Birdman is flying horizontally at a
speed of 17 m/s and a height of 78
m. Birdman releases a turd directly
above the start of the field. How far
from the start of the field should the
robot hold the bucket to catch the
turd?
Answer:
68 m
Explanation:
Given that the horizontal velocity of the birdman = 17 m/s and
the height, h= 78 m.
The gravitational force is acting in the downward direction, so it will not change the horizontal speed.
The horizontal speed will remains be constant and will be equal to the initial horizontal speed of the turd.
Initially, the turd was also flying horizontally with the birdman, so the initial velocity of the turd is the same as the horizontal velocity of the birdman, i.e In the horizontal direction, [tex]u_0=17[/tex] m/s.
In the vertical direction, u = 0,
The distance to be traveled, in the direction of application of force, is equals to the height of the turd, i.e
s= 78 m
Let t be the time taken to cover a distance of 78 m.
Now, applying the equation of motion in the vertical direction,
[tex]s=ut+\frac 12 at^2[/tex]
where u is the initial velocity and a is the acceleration due to gravity in the direction of displacement,s.
Here, [tex]a=g=9.81 m/s^2[/tex], so
[tex]78=0\times t +\frac 12 (9.81)t^2[/tex]
[tex]\Rightarrow t^2=(78\times2)/9.81[/tex]
[tex]\Rightarrow t = 4[/tex] seconds.
Hence, the time taken to reach the ground is 4 seconds.
As the horizontal speed, [tex]u_0=17[/tex] m/s, is constant throughout the journey, so
the horizontal distance covered by turd
[tex]= u\times t[/tex]
[tex]= 17 \times 4 = 68[/tex] m.
So, the distance of landing from the start of the field is 68 m as the birdman releases a turd directly above the start of the field.
Hence, the robot must hold the bucket at a distance of 68 m from the start of the field.
Please help A.S.A.P
What would you expect to see on intrusive igneous rocks compared to extrusive igneous rocks?
Answer:
Intrusive igneous rocks cool from magma slowly because they are buried beneath the surface, so they have large crystals. Extrusive igneous rocks cool from lava rapidly because they form at the surface, so they have small crystals. Texture reflects how an igneous rock formed
Explanation:
A distance of 2.5 meters separates two similar balls of mass 0.70 kg each. Calculate the force of gravity between the two balls.
Answer:
2
Explanation:
PLEASE HELP ME FAST!
Which of these sentences best illustrates visualization using a sequence of events? A. The earthquake sent out a shock waves in all directions. The sea surface is disturbed also. Big waves are formed. These waves travel fast across the sea. They are dangerous and can kill. B. Then, all of a sudden, a strong earthquake strikes off the coast of Alaska, deep down on the seafloor. After this, the seafloor moves up and down. Next the walls and floors of the house is suddenly start to shake. C. Both A and B. D. Neither A or B.
Answer:
Explanation:
C. Both A and B I guess
Answer:
its b
Then, all of a sudden, a strong earthquake strikes off the coast of Alaska, deep down on the sea floor. After this, the sea floor moves up and down. Next, walls and floors of the houses suddenly start to shake.
Explanation:
mark me brainleist please!
also i really hope this helps and have a really good day
-TA
how does the initial velocity affect the final velocity
Answer:
Initial velocity is independent of the slope of the graph; that is, the acceleration. An object thrown downward still accelerates after release at the same rate as an object that is dropped.
Miguel added 150 grams of baking soda to a liter of water at 20 °C. No matter how long he keeps stirring the solution, he can’t get all of the baking soda to dissolve. Explain why.
Answer:
See the answer below
Explanation:
This is because, at 20 °C, the solution has become saturated with the baking soda.
The solubility of a substance is the maximum amount of that substance that will dissolve in a particular solvent at a given temperature. The solubility of a substance generally increases with an increase in temperature.
At 20 °C temperature, the maximum amount of baking soda that can dissolve in a liter of water has been exceeded by Miguel. Hence, no matter how hard he tries to stir the solution, the excess baking soda will not dissolve.
The reason he can’t get all of the baking soda to dissolve is; because at 20 °C, the solution has become saturated with the baking soda.
What is a saturated solution?For us to say a substance is soluble, it means that the maximum amount of that substance will dissolve in a particular solvent at a given temperature. Thus, the solubility of a substance is said increase with a corresponding increase in temperature.
From the question, at 20 °C temperature, miguel has exceeded the maximum amount of baking soda that can dissolve in a liter of water. Therefore, no matter how hard he tries to stir the solution, it will not dissolve due to the excess soda.
Read more about saturated solution at; https://brainly.com/question/4529762
A ball is thrown vertically upward with an initial velocity of 29.4 m/s². What is the maximum height reached by the ball? How long is the ball in the air? What is the final velocity of the ball before it goes back to its original position?
Answer:
Most likely it will reach 29.4 up in the air before coming back down.
Explanation:
The force of the ball will be the same on how high it will go.
NEED HELP ASAP!!!
If 100 newtons of force are applied over a distance of 50 meters for 5 seconds, how much power is used
2,500 watts
1,000 joules
10 watts
1,000 watts
Answer:
2,500 watts
Explanation:
I got this answer right on a test. I hope it works for you to.
Answer:
2500 wats
Explanation:
How plants are in the
Solora System
Answer:
there was 9 but pluto got kicked out of the solar System so 8
3- The velocity-time graph below shows the motion of a
ball in free fall. What is the acceleration of the ball from
0.5 to 0.7 seconds? Show your work:
Answer:
The acceleration of the ball from 0.5 to 0.7 seconds is 10 m/s²
Explanation:
The data from the given velocity-time graph are as follows;
Velocity (meters per second) [tex]{}[/tex] Time (seconds)
0 [tex]{}[/tex] 0.4
0.5 [tex]{}[/tex] 0.45
1. [tex]{}[/tex] 0.5
1.5 [tex]{}[/tex] 0.55
2.2 [tex]{}[/tex] 0.6
2.5 [tex]{}[/tex] 0.65
3.0 [tex]{}[/tex] 0.7
3.5 [tex]{}[/tex] 0.75
4.0 [tex]{}[/tex] 0.8
4.5 [tex]{}[/tex] 0.85
Therefore, the average acceleration of the ball from 0.7 to 0.7 seconds is given as follows;
Acceleration = (Change in velocity)/(Related change in time)
Acceleration = (3.0 - 1)m/s/(0.7 - 0.5)s = 2/0.2 m/s² = 10 m/s²
The acceleration of the ball from 0.5 to 0.7 seconds = 10 m/s².
One particle has a charge of 4.2 x 10-9 C, while another particle has a charge
of 1.10 x 10-9 C. If the two particles are separated by 0.005 m, what is the
electromagnetic force between them? The equation for Coulomb's law is
Fe = k992, and the constant, k, equals 9.00 x 109 Nm2/C2.
A. 8.31 x 10-6N
B. 1.66 x 10-5 N
C. 1.85 10-13 N
D. 1.66 10-3 N
Answer:
D
Explanation:
Answer:
The forces between the charges is [tex]1.66*10^{-3} N[/tex]
Explanation:
Data given:
First charge [tex]q_{1} =4.2*10^{-9} C[/tex]
Another charge [tex]q_{2} =1.1*10^{-9} C[/tex]
Distance (r)= (0.005)m
Force(F)=?
It is based on Electrostatic force between two charges i.e. defined by Coulomb's law.
What is electrostatic force?The force acting between two static charges, is called electrostatic force.
What is Coulomb's law?The force acting between two charges is
(a) directly proportional to the product of charges F ∝ [tex]q_{1} q_{2}[/tex]
(b) inversely proportional to the square of the separation. F ∝ [tex]\frac{1}{r^{2} }[/tex]
From above;
[tex]F=k.\frac{q_{1} q_{2} }{r^{2} }[/tex]
On putting values: -
[tex]F=1.66*10^{-3} N[/tex]
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A container of rocks is brought back from the Moon's surface where the acceleration due to gravity is 162 meters per second if the total mass of the container of rocks is 650 kilograms, what is its weight on
Earth's surface
Answer:
6318 N
Explanation:
From the question given above, the following data were obtained:
Acceleration due to gravity of the moon (gₘ) = 1.62 m/s²
Mass (m) of container = 650 kg
Weight (W) of container on the earth =.?
Next, we shall determine the acceleration due to gravity of the earth. This can be obtained as follow:
Acceleration due to gravity of the moon (gₘ) = 1.62 m/s²
Acceleration due to gravity of the earth (gₑ) =.?
gₘ = 1/6 × gₑ
1.62 = 1/6 × gₑ
1.62 = gₑ /6
Cross multiply
gₑ = 1.62 × 6
gₑ = 9.72 m/s²
Finally, we shall determine the weight of the container on the earth as follow:
Mass (m) of container = 650 kg
Acceleration due to gravity of the earth (gₑ) = 9.72 m/s²
Weight (W) of container on the earth =.?
W = m × gₑ
W = 650 × 9.72
W = 6318 N
Therefore, the weight of the container on earth is 6318 N
what does acceleRation measure
Answer:
Speed and distance traveled
Explanation:
1 point
An Arizona solar power plant is able to produce 24 megawatts, which
serves 6,000 homes. How many watts per home?
40 W
О
400 W
4,000 W
40,000 W
Which is better sunlight or moonlight
Answer:
moonnn
Explanation:
HELP HELP, this should be pretty easy
Where does all of earth’s atmosphere energy come from
Answer:The atmosphere directly absorbs about 23% of incoming sunlight, and the remaining energy is transferred from the Earth's surface by evaporation (25%), convection (5%), and thermal infrared radiation (a net of 5-6%).Jan
Explanation:
None
PLEASE HELP!! ILL MARK BRAINLYEST!!!
A chemical change occurs when a substance changes phase.
True
False
Answer:
False
Explanation:
A rescue pilot wishes to drop a package of emergency supplies so that it lands as close as possible to a target. If the plane travels with a velocity of 18 m/s and is flying 225 m above the target, how far away (horizontally) from the target must the rescue pilot drop the package?
Answer:
x = 121.86 m
Explanation:
It is given that,
The vertical velocity of a plane, [tex]v_x=18\ m/s[/tex]
It is flying above the target, h = 225 m
First we will find the time taken by the plane to reach the ground. It can be calculated using the second equation of motion as follow :
[tex]h=ut+\dfrac{1}{2}at^2[/tex]
Here, u = 0 and a = g
[tex]h=\dfrac{1}{2}gt^2\\\\t=\sqrt{\dfrac{2h}{g}} \\\\t=\sqrt{\dfrac{2\times 225}{9.81}} \\\\t=6.77\ s[/tex]
Let x is the horizontal distance from the target. It can be calculated as follows :
[tex]x=v_xt\\\\x=18\times 6.77\\\\x=121.86\ m[/tex]
So, the rescue pilot drop the package at a distance of 121.86 m from the target.
Clouds in our atmosphere cause us to see the different phases of the moon.
True
False
Answer:
False
Explanation:
:)
Answer:
The answer is false
Explanation:
The clouds have nothing to do with the changes in the phases of the moon but, rather the postioning of the sun and the moon regarding revolution and the spinning of the earth on it axis.
I hope this helps you good luck and have a good day.
George weighs 200 lb. what is his weight in Newtons (think metric, ha ha 1 kg=2.2 lb)
Answer:
889.644 newton
Explanation:
multiply the pound value by 4.448
A volcano erupts, and a chunk of hot magma is launched horizontally with a speed of 208\,\dfrac{\text m}{\text s}208 s m 208, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction from a height of 94\,\text m94m94, start text, m, end text. We can ignore air resistance.
Answer:
a. 42.92 m/s b 4.4 s c. 915.2 m
Explanation:
Here is the complete question
A volcano erupts, and a chunk of hot magma is launched horizontally with a speed of 208 m/s, from a height of 94 m. We can ignore air resistance.
What is the vertical velocity of the magma when it hits the ground?
Solution
a. Using v² = u² - 2gy since it is motion under gravity, where u = initial vertical velocity = 0 m/s, g = acceleration due to gravity = -9.8 m/s² and y = height = 94 m.
Substituting these values into the equation, we have
v² = u² - 2gy
v² = 0² - 2 × (-9.8 m/s²) × 94 m
v² = 1842.4 m²/s²
v = √1842.4 m²/s²
v = 42.92 m/s
b. We also find the time it takes to drop from the height of 94 m from
y = ut - 1/2gt² , u = 0
So, t = √(2y/g)
= √(2 × 94 m ÷ 9.8 m/s²)
= √19.184 s²
= 4.4 s
c. The horizontal distance the chunk of hot magma covers is thus x = Vt where v = horizontal velocity = 208 m/s
x = 208 m/s × 4.4 s = 915.2 m
Answer:
that's wrong its 911
Explanation:
trust me
A ball is thrown straight up from the ground. Where will the ball have its lowest velocity
Explanation:
i think it will be on the ground
The temperature of a 5.0 kg block increases by 3 degrees C when 2,000 J of thermal energy are added to the block. What is the specific heat of the block? _____________
Help. Please! I really need help. It’s timed, and I’m loosing points.
Answer:
I think balanced
Explanation:
because there is a 2 on each arrow
Answer I'm thinking balanced as well
Explanation:
8. Approximately how many hours a day are spent in school and doing homework?
A. 7 hours
B. 8.5 hours
C. 9 hours
D. 8 hours
Answer:
There would be 9 b/c there is so many hours of school and the homework depends on how old you are so i am pretty sure it is C.
Explanation:
A 1 kg object is located at a distance of 1.0 x 103 m from the center of a larger
object whose mass is 2.0 x 1020 kg.
a. What is the size of the force acting on the smaller object?
The force = 1.334 x 10⁴ N
Further explanationGravity is a force that arises because of the attraction between objects with mass.
The magnitude of this attraction is proportional to the mass of the object.
The greater the mass of the object, the greater the gravitational force
Relationships can both be stated in
Newton's Gravity Law:
[tex]\rm F=G.\dfrac{m_1.m_2}{r^2}[/tex]
with F = gravitational force, N
G = gravitational constant, 6.67 x 10⁻¹¹ Nm²/kg²
m1, m2 = mass of object, kg
r = distance between two objects. m
m₁= 1 kg
m₂=2 x 10²⁰ kg
r = 1 x 10³ m
The force acting on the smaller object=The force acting on the larger object(Newton's Third Law)
[tex]\tt F=6.67\times 10^{-11}\dfrac{1\times 2.10^{20}}{(1\times 10^3)^2}\\\\F=1.334\times 10^4~N[/tex]
A tennis racket strikes a tennis ball with a force of 100 N. With what force
does the ball strike the racket? *
Answer:
-100N
Explanation:
Newton's third law of motion states that to every force exerted on one body, there is an equal and opposite force. This means that if object A exerts an ACTION force on B, there is a force called REACTION FORCE, which is equal and opposite, exerted on A by B.
The action and reaction forces are equal in size/magnitude but opposite in direction. In this case where a tennis racket strikes a tennis ball with a force (action force) of 100N, the ball will strike the racket with a reaction force of -100N.
F(RB) = -F(BR)
PLEASE HELP!!
A player punts a football at an angle of 30 degrees. The football has an initial
velocity of 20.0 m/s. Find the y-component of the ball's velocity.
17.3 m/s
O 10.0 m/s
O 30.0 m/s
0 25.1 m/s
Answer:
The y-component of the ball's velocity is 10 m/s
The second choice 10.0 m/s is correct
Explanation:
Projectile Motion
It's the type of motion that experiences an object that is projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.
Being vo the magnitude of the initial velocity and θ the angle it makes with the horizontal, the components of the initial velocity are calculated as follows:
[tex]v_{ox}=v_o.\cos\theta[/tex]
[tex]v_{oy}=v_o.\sin\theta[/tex]
Since the football is kicked at vo=20 m/s and an angle of θ=30°:
[tex]v_{oy}=20.\sin 30^\circ[/tex]
[tex]v_{oy}=20*0.5=10[/tex]
The y-component of the ball's velocity is 10 m/s
The second choice 10.0 m/s is correct
How long will it take an airplane at rest that
accelerates uniformly at 2.5 m/s to reach a ground
velocity of 70 m/s that is required for takeoff
Answer:
28 seconds.
Explanation:
Apply the first equation of motion as;
v=u +at where;
v= final velocity of the plane = 70m/s
u=initial velocity of the plane= 0m/s -----it was at rest
a= acceleration uniform =2.5 m/s²
t= time required for takeoff = ?
Substitute values in the equation as;
v= u + at
70 = 0 + 2.5*t
70 = 2.5t
70/2.5 = 2.5/2.5t
28 = t
Time required for takeoff is 28 seconds.