PLEASEEEE

Calculate the mechanical advantage of a ramp if the box you are trying to move has a mass of 10 kilograms, the
board is 15 feet long and the height of the ramp is 5 feet.

Answers

Answer 1

Answer:

add answer +5 so so so so so

Answer 2

Answer:

3 trust me

Explanation:


Related Questions

A gas cylinder holds 0.10 mol of O2 at 150 C and a pressure of 3.0 atm. The gas expands adiabatically until the pressure is halved
Part A
What is the final volume?
Part B
What is the final temperature?

Answers

Answer:

V2 = 1.899*10^-3 m^3

T2 = 347.125 K

Explanation:

Using gas law, we know that

PV = nRT,

Where

V1 = 0.00115743 m^3.

gamma = 1.4

Now, when we solve for final volume, V2 we get

V2 = V1/((P2/P1)^(1/gamma))

V2 = 1.899*10^-3 m^3

Using the same law and method, when we try to solve for the temperature, we find that the final temperature, T2 is

T2 = T1*((V1/V2)^(gamma-1))

T2 = 347.125 K

The final volume is 1.899*10^-3 m^3

And, the final temperature is 347.125 K

Gas law:

here we used gas law,

we know that

PV = nRT,

Here

V1 = 0.00115743 m^3.

gamma = 1.4

Now final volume is

V2 = V1/((P2/P1)^(1/gamma))

V2 = 1.899*10^-3 m^3

Now the final temperature is

T2 = T1*((V1/V2)^(gamma-1))

T2 = 347.125 K

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An astronaut stands on the surface of an asteroid. The astronaut then jumps such that the astronaut is no longer in contact with the surface. The astronaut falls back down to the surface after a short time interval. Which of the following forces CANNOT be neglected when analyzing the motion of the astronaut?

Answers

Asteroids are known through the help of artificial gravity, to have small gravity. The forces that cannot be neglected when analyzing the motion of the astronaut is that the gravitational force between the astronaut and the asteroid.

The gravitational force between two objects is said to be inversely proportional to the distance between them when squared. Therefore, when an individual halve the distance then the force increases by four times.

Unbalanced forces are simply known to be brought about due to a change in motion, speed, and/or direction. If two forces act in the same direction on an object, the net force is said to be equal to the sum of the two forces.

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20 pts.





Which of the following statements is true?
O Electromagnets use electrlcity and magnets.
O Magnetic fields are strongest around the poles of a magnet.
O The south pole of a magnet will repel the south pole of another magnet.
O all of the above

Answers

Answer:

all are true so d is right

Explanation:

Electromagnets use electrlcity and magnets is true.

Magnetic fields are strongest around the poles of a magnet is true.

The south pole of a magnet will repel the south pole of another magnet is true

and since all of them is true the answer is d all of the above

two spheres A and B are projected off the edge of a 1.0 m high table with the same horizontal velocity . sphere A has a mass of 20.g and sphere B has a mass of 10.g.
     If both spheres leave the edge of the table at the same instant, sphere A will land
a.    at some time after sphere B.
b.    at the same time as sphere B.
c.    at some time before sphere B.
d.    There is not enough information to decide.​

Answers

A would land before since its heavier


Through what angle in degrees does a 33 rpm record turn in 0.32 s?
63°
35°
46°
74°

Answers

Answer:

1 rev = 2(pi) rad  pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.

Calculation of the angle:Since we know that

1 rev = 2(pi) rad

So here  pi(rad) = 180 degrees

Now for 33 rpm it should be like

=  33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s

= 63.36 degrees

= 63 degrees

hence, The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.

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A 1.2-kg object moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 6.0 m/s in the opposite direction. If the object is in contact with the wall for 2.0 ms, what is the magnitude of the average force on the object by the wall?
a. 9.8 kN.
b. 8.4 kN.
c. 7.7 kN.
d. 9.1 kN.
e. 1.2 kN.

Answers

Given that,

Mass of the object, m = 1.2 kg

Initial speed of the object, u = 8 m/s

Final speed of the object, v = -6 m/s (in opposite direction)

Time, t = 2 ms

To find,

The average force on the object by the wall.

Solution,

Let F be the force. Using Newton's second law of motion,

F = ma, a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1.2\times ((-6)-8)}{2\times 10^{-3}}\\\\=8400\ N[/tex]

or

F = 8.4 N

So, the magnitude of average force in the object by the wall is 8.4 N.

Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.

Answers

Answer:

The current is 11 Amperes

Explanation:

Electric Current

The electric current is defined as a stream of charged particles that move through a conductive path.

The current intensity can be calculated as:

[tex]\displaystyle I=\frac{Q}{t}[/tex]

Where:

Q = Electric charge

t   = Time taken by the charge to move through the conductor

The current intensity is often measured in Amperes.

The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:

[tex]\displaystyle I=\frac{55}{5}[/tex]

I = 11 Amp

The current is 11 Amperes

1+1=?




FIRST ONE TO ANSWER GETS BRAINLIEST!

Answers

Answer:

Thx for points merry Christmas answer 2

Explanation:

Answer:2

Explanation:

What would be the magnitude of a star with a temperature of 25,000 located on
the main sequence?

Answers

Answer:

hvkhvkhvkvlhvgjvgv

Explanation:

The speed of sound in air is 10 times faster than the speed of a wave on a certain string. The density of the string is 0.002kg/m. The tension in the string is __________.

Answers

Answer:

The tension on the string is 2.353 N.

Explanation:

Given;

the speed of sound in air, v₀ = 343 m/s

then, the speed of sound on the string, v = 343 / 10 = 34.3 m/s

mass per unit length, m/l = μ = 0.002 kg/m

The speed of sound on the string is given as;

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu[/tex]

where;

T is the tension on the string

T = (34.3)²(0.002)

T = 2.353 N

Therefore, the tension on the string is 2.353 N.

g A communication system operating at a power of 510 W produces electromagnetic radiation with a wavelength of 10.5 cm . Calculate the number of photons produced by the system per minute.

Answers

Answer:

The value is  [tex]N = 2.69 *10^{26} \ photons[/tex]

Explanation:

From the question we are told that

    The power is  [tex]P = 510 \ W[/tex]  

    The wavelength is  [tex]\lambda = 10.5 \ cm = 0.105 \ m[/tex]

   

Gnerally the number of photon produced is mathematically represented as

             [tex]N = \frac{P * \lambda }{ h * c }[/tex]

Here  [tex]h[/tex] is the Planck's constant with a value   [tex]h = 6.62607015 * 10^{-34} J \cdot s[/tex]

          c is the speed of light with value  [tex]c = 3.0*10^{8 } \ m/s[/tex]

So  

             [tex]N = \frac{ 510 * 0.105 }{ 6.62607015 * 10^{-34} * 3.0 *10^{8} }[/tex]

=>          [tex]N = 2.69 *10^{26} \ photons[/tex]

PHYSICS! HELP ME PLEASE ASAP!

1.) If an ambulance passes you while you're walking your dog, a change in pitch is ____?
A.) not perceived by either the pedestrian or you
B.) perceived by the you
C.) perceived by the driver

2.) In the star wars movies, the soundtrack is very important. musicians and sound technicians spend weeks perfecting the noise of the light sabers, lasers, tie fighters and explosions. in real life, there would be no sound at all in space. Why?
A.) mechanical waves require a medium to travel
B.) sound is an electromagnetic wave
C.) mechanical waves do not require a medium to travel
D.) sound is a product of vibration

3.) what is a compression?
A.) region of zero pressure in a medium caused by a wave passing
B.)region of a high altitude in a medium caused by a passing wave
C.) region of a high pressure in a medium cause by a passing wave
D.) region of low pressure in a medium caused by a passing wave

Answers

Answer:

1B, 2B and 3C hope this helps

Explanation:

When an element ejects an alpha particle, the mass number of that element

A.reduce by 4.

B.remains unchanged.

C.increase by 1.

D. reduce by 1.

Answers

Answer:

A.reduce by 4.

Explanation:

In Chemistry, an alpha particle which is typically a helium nucleus has an atomic mass (number of nucleons) of four (4). Therefore, the ejection of an alpha particle by any chemical element simply means that, the mass number of that particular chemical element would be reduced by four (4).

Basically, this process is referred to as an alpha decay and can be defined as a radioactive disintegration of a chemical element that causes it to emit an alpha particle and as a result reducing its mass number by four (4).

Hence, when an element ejects an alpha particle, the mass number of that element reduces by 4.



A popular ride at an amusment park lifts
customers up to a height of 50 m and then
drops them threw a displacement of 50 m
before slowing them to a stop. How fast
are the customers going at the 50 m
mark?

Answers

Answer:

[tex]31.32\ m/s[/tex]

Explanation:

[tex]We\ are\ given\ that:\\Height\ to\ which\ there're\ lifted=50m\\Displacement\ during\ the\ descent=50m\\Now,\\In\ order\ to\ find\ the\ velocity\ of\ the\ customers\ at\ 50\ m,\\We\ can\ use\ the\ Third\ Equation\ Of\ Motion,\ which is:\\2as=v^2-u^2\\As\ we\ know\ that,\\Acceleration\ due\ to\ gravity=9.81\ m/s^2\ or\ roughly\ 10\ m/s^2\\Displacement=50\ m\\Initial\ velocity=0\ m/s^2\\ [As\ they\ stop\ when\ they\ reach\ the\ maximum\ height\ of\ 50\ m\\ and\ begin\ their\ descent][/tex]

[tex]By\ reconstructing\ the\ Third\ Equation\ Of\ Motion,\ we\ have:\\2gs=v^2\\Hence,\\v^2=2*9.81*50 \\v^2=981\ m^2/s^2 \\v=\sqrt{981\ m^2/s^2} \\v=31.32\ m/s[/tex]

A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.

Determine the magnitude of the distance the object traveled and the magnitude and direction of the displacement.

Answers

Answer:

The answer is 8m N

Explanation:

When a tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward. then the distance traveled by it is 82 m and the displacement covered by it is 26 m in a southward direction

What is displacement?

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.

Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.

Thus, when a tennis ball travels 16 meters to the north, 22 meters to the south, 12 meters to the north, and 32 meters to the south. then it has a covered distance of  82 meters and has covered 26 meters of displacement in a southerly direction.

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A spring of spring constant 25 N/m is hung vertically and a 0.300 kg mass is attached to one end, causing a displacement of the end of the spring of _____ m.
a. 0.01
b. 0.12
c. 0.77
d. all of the above

Answers

Answer:

The displacement of the spring is 0.12 m.

Explanation:

Given;

spring constant, k = 25 N/m

mass attached to the spring, m = 0.300 kg

displacement of the spring, x = ?

Apply Hook's law, weight of the mass attached (applied force) is directly proportional to the extension of the spring.

F = kx

mg = kx

0.3 x 9.8 = 25x

2.94 = 25x

x = 2.94 / 25

x = 0.12 m

Therefore, the displacement of the spring is 0.12 m.

A force of 64 N gives an object an acceleration of 23.53 m/s^2. What is the mass of the object?
A-2.00 kg
B-1505 kg
C-2.72 kg
D-736 kg

Answers

D is the right answer for this I think

Which structures are found in the middle ear? Check all that apply.

A. hammer
B. anvil
C. ear canal
D. cochlea
E. ear drum
F. stirrup

Answers

Answer:

E, A, B, F

Explanation:

The Middle Ear contains:

eardrum.

cavity (also called the tympanic cavity)

ossicles (3 tiny bones that are attached) malleus (or hammer) - long handle attached to the eardrum. incus (or anvil) - the bridge bone between the malleus and the stapes. stapes (or stirrup) - the footplate; the smallest bone in the body.

Answer: rawr

Explanation:

hammer

anvil

ear drum

stirrup

Match the scienntist with their accomplishment / discoveries

Answers

Answer:

newton - motion, gravity

kepler - orbital paths

brahe - the sun goes around the earth

Explanation:

im not sure about brahe but its the only one that makes sense

What electromagnetic wave is a is a TV remtoe

Answers

Answer:

infared radiation

Explanation:

what is mean by combination reaction ?​​

Answers

[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

A tsunami, an ocean wave generated by an earthquake, propagates along the open ocean at 700 km/hr and has a wavelength of 750 km. What is the frequency of the waves in such a tsunami?A. 6.8 HzB. 0.93 HzC. 0.00026 HzD. 1.1 HzE. 0.15 Hz

Answers

Answer:

C) 0.00026 Hz

Explanation:

In any wave, there exists a fixed relationship between the speed v, the frequency f and the wavelength λ, as follows:

       [tex]v = \lambda * f (1)[/tex]

Replacing by the givens in (1), and solving for f, we get:

       [tex]f = \frac{v}{\lambda} = \frac{700km/hr}{750 km} = 0.93 1/hr (2)[/tex]

Converting the units to Hz (1/sec), we get:

       [tex]f = 0.93 \frac{1}{hr} *\frac{1 hr}{3600sec} = 2.6e-4 = 0.00026 Hz (2)[/tex]

The answer C. is the right one.

What is the condition required of the phase difference (in radians) between two waves with the same wavelength if these waves interfere constructively?
a. (2m +1)π where m= 0, +1, +2, etc.
b. mπ where m = 0, +1, +2, etc.
c. 2mπ where m = 0, +1, +2, etc.
d. (m+1)π where m = 0, +1, +2, etc.

Answers

Answer:

c.

Explanation:

In order to two waves with the same wavelength can interfere constructively, their crests and valleys must coincide in space, so the phase difference must be equal to an integer number of wavelengths, i.e. m *(2 π rad), where m= 0, +1, +2, etc.This is equal to the stated by the answer c) , so c) it's the right answer.

Help me please,

A ball is thrown straight up in the air. What is the velocity and acceleration at the top of the path?

A) v 0m/s, = 0m/s/s

B) v = 0m/s, a 10m/s/s

C) v = 10m/s, a 10m/s/s

D) v = 10m/s, a = 0m/s/s

E) None of the above

Answers

Option B

Explanation:

no distance was given only the acceleration due to the fact that it went up (10m/s/s)

s0 it is

0 m/s and 10m/s/s (option B)

*
If a rock falls for 3 seconds off of a bridge, how far will the rock fall?
-30 m
-45m
-60m
-75m

Answers

It will fall for about 45m

A police officer standing at the side of the road uses a radar emitting frequency of 24.15 GHz. A car is going away from the officer at a speed of 50mph. What will be the difference in frequency of the beam reflected by the car received back by the radar?
a. 4.0 kHz (lower frequency)
b. 1.8 kHz (higher frequency)
c. 4.0 kHz (higher frequency)
d. 1.8 kHz (lower frequency)

Answers

Answer:

The correct answer is  C

Explanation:

  From the question we are told that  

       The frequency of the radar is [tex]f = 24.15 \ GHz = 24.15 *10^{9} \ Hz[/tex]

         The speed of the car is [tex]v = 50 mph = \frac{50}{2.237} = 22.35 \ m/s[/tex]

Generally the difference frequency reflected by the car and the frequency which the radar receives back is mathematically represented as

        [tex]\Delta f = \frac{f * 2 * v }{ c }[/tex]

Here  c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

=>    [tex]\Delta f= \frac{2 * 24.15 *10^{9} * 22.35}{ 3.0*10^{8}}[/tex]      

=>    [tex]\Delta f = 4000 \ Hz[/tex]

=>     [tex]\Delta f = 4.0 \ kHz[/tex]  

Given that the value is positive then it a higher frequency

       

true or false The most extreme tides occur during a new
moon and full moon.

Answers

Answer:

true

Explanation:

Suppose a uniform solid sphere of mass M and radius R rolls without slipping down an inclined plane starting from rest. The linear velocity of the sphere at the bottom of the incline depends on?

Answers

Answer:

None of the mass or the radius of the sphere

Explanation:

When a uniform solid sphere of any given mass, say M and any given radius, say R, rolls without slipping downwards an inclined plane that starts from rest. The linear velocity of the sphere at about the bottom of the inclined happens not to depend on either of its mass or that of the radius of its sphere.

Define conductor and insulator, including how the resistance is different in the two, and give at least one example of each.

Answers

Answer:

Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.

Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.

Example of conductor is copper

Example of insulator is plastic

A disk rotates at a constant angular velocity of 30 degrees per second. Consider a point on the edge of the disk. Through how many degrees has it rotated after 3 seconds?

Answers

Answer:

The disk covers a rotation of 90º after 3 seconds.

Explanation:

Since the disk rotates at constant angular speed, we can determine the change in angular position ([tex]\Delta \theta[/tex]), measured in sexagesimal degrees, by the following kinematic formula:

[tex]\Delta \theta = \omega\cdot \Delta t[/tex] (1)

Where:

[tex]\omega[/tex] - Angular velocity, measured in sexagesimal degrees per second.

[tex]\Delta t[/tex] - Time, measured in seconds.

If we know that [tex]\omega= 30\,\frac{\circ}{s}[/tex] and [tex]\Delta t = 3\,s[/tex], then the change in angular position is:

[tex]\Delta \theta = \left(30\,\frac{\circ}{s} \right)\cdot (3\,s)[/tex]

[tex]\Delta \theta = 90^{\circ}[/tex]

The disk covers a rotation of 90º after 3 seconds.

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