Answer:
Explanation:The information that would be most likely needed to make the calculation of the gravitational force between an asteroid and a planet other than Earth are:
The mass of the asteroid (A)
The mass of the planet (C)
The distance between the asteroid and the planet (E)
The constant G-6.67 x 10^-11 Nm²/kg (G)
Therefore, the options that apply are A, C, E, and G.
Find I1, V1, and V2 for the circuit shown in Fig. 4
From the given circuit, the value of I1 = -4 Amp, V1 = -4 V, and the V2 = 4V. Ohm's law has three different variations that are related to voltage, current, and resistance. The relationship between the voltage across the terminals and the resistor's resistance determines the current for a constant flow of current.
What is the tenet of Ohm's law?According to Ohm's law, the voltage across a conductor determines how much current flows through it. For many materials, including metals, this is true so long as the temperature (as well as other physical parameters) stay constant.
What does "nodal analysis" mean?Any electrical network may be solved using nodal analysis, which is what it is called. the formula used to determine how much voltage is shared across circuit nodes. Since the node voltages are with respect to the ground, this method is also referred to as the node-voltage method.
Applying KCL,
I1 = -1 -3
I1 = -4 A
Applying concept of super-node,
V2 = 4V
[tex]\frac{4-V1}{2} -1-3=0[/tex]
[tex]2-\frac{V1}{2} =4[/tex]
[tex]\frac{-V1}{2} =4-2[/tex]
[tex]V1=-4V[/tex]
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Use the work energy theorem to rank the final kinetic energy of a ball based on the initial kinetic energy Ki, the magnitude of a constant force F on the ball, the displacement of the ball, d and the angle, theta between the displacement of the ball and the net force on the ball. Rank from greatest kinetic energy (1) to least kinetic energy (4).
1. ki= 150 J, F= 10 N, d=15 m, theta= 90 degrees
2. Ki= 300 J, F= 200 N, d= 1.5 m, theta= 180 degrees
3. ki= 200 J, F= 25 N, d= 4 m, theta= 0 degreee
4. ki= 450 J, F= 15 N, d= 30 m, theta= 150 degrees
4.
Answer:
150 J
-300 J
300 J
256.8 J
Explanation:
Use the following equation: W = ΔK = Kf - Ki
Calculations below:
Ki = 150 J, F = 10 N, d = 15 m, θ = 90°
The work done on the ball is:
W = Fd cos θ = 10 × 15 × cos 90° = 0 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 150 + 0 = 150 J
Ki = 300 J, F = 200 N, d = 1.5 m, θ = 180°
The work done on the ball is:
W = Fd cos θ = 200 × 1.5 × cos 180° = -600 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 300 - 600 = -300 J
Ki = 200 J, F = 25 N, d = 4 m, θ = 0°
The work done on the ball is:
W = Fd cos θ = 25 × 4 × cos 0° = 100 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 200 + 100 = 300 J
Ki = 450 J, F = 15 N, d = 30 m, θ = 150°
The work done on the ball is:
W = Fd cos θ = 15 × 30 × cos 150° = -193.2 J
Therefore, the final kinetic energy is:
Kf = Ki + W = 450 - 193.2 = 256.8 J
The Hertzsprung-Russell diagram shown is divided into four sections.
C Section 3
n
Luminosity (Lsun)
Cortion A
10%
10⁰
10²
10-2
104
Hertzsprung-Russell Diagram
400 200 100
55
Temperature (x10² K)
Which section of the diagram includes the coolest, brightest stars?
A Section 1
B
Section 2
75
45
●
30
The section of the diagram that includes the coolest, brightest stars is A, Section 1.
How is the Hertzsprung-Russell diagram described?On the Hertzsprung-Russell diagram, the vertical axis represents luminosity, which is the total amount of energy emitted by a star per unit time. The luminosity is measured in units of solar luminosity, which is the amount of energy emitted by the Sun per unit time.
The section that includes the coolest, brightest stars is Section 1. This is because in this section, the stars have a low temperature (around 3,000-4,000 K) and a high luminosity (around 1,000-10,000 times that of the Sun). These stars are called red giants, and they are nearing the end of their lives. As they run out of fuel, their outer layers expand and cool, making them appear red and bright.
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004 (part 1 of 2) 10.0 points
In a 95 s interval, 216 hailstones strike a glass
2
window of area 1.156 m² at an angle 67 to the
window surface. Each hailstone has a mass of
5 g and speed of 13.5 m/s.
If the collisions are elastic, find the average
force on the window.
Answer in units of N.
005 (part 2 of 2) 10.0 points
Find the pressure on the window.
Answer in units of N/m².
Average force F = 97.52 N acting on window surface.
Pressure on the window: P = 84.39 N/m²
Explain about the elastic collision?An elastic collision is one in which the system does not experience a net loss of kinetic energy as a result of the collision. In elastic collisions, momentum as well as kinetic energy are both conserved. An example of an elastic collision is when two balls collide at a pool table.Average force F:
F = mg sinФ
Put the values:
F = 0.05*9.81* sin 67°
F = 0.45 N
Number of hailstones = 216
Average force F = 0.45* 216 = 97.52 N
Pressure on the window:
Pressure = Average force / area
P = 97.52 / 1.156
P = 84.39 N/m²
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which one defines force?
Answer:
a
Explanation:
a push or a pull that occurs when an object interacts with another object or field.
pls mrk me brainliest
On a hot summer day, a young girl swings on a rope above the local swimming hole. When she lets go of the rope her initial velocity is 2.25m/s at an angle of 35º above the horizontal. If she is in flight for 1.20s, how high above the water was she when she let go of the rope?
When she let go of the rope, her height above the water would be 3.20 meters.
Kinematic motionWe can use the equations of motion to solve this problem. Let's assume that the girl's initial height above the water is h, and that the acceleration due to gravity is -9.81 m/s^2 (negative because it is directed downward). Then we have:
Initial horizontal velocity (vx) = 2.25 cos(35º) = 1.84 m/s
Initial vertical velocity (vy) = 2.25 sin(35º) = 1.30 m/s
During the 1.20 s of flight, the girl's vertical motion can be described by the following equation:
h + vy*t + (1/2)gt^2 = 0
where t is the time of flight and g is the acceleration due to gravity. Substituting the known values, we get:
h + (1.30 m/s)(1.20 s) + (1/2)(-9.81 m/s^2)*(1.20 s)^2 = 0
Simplifying and solving for h, we get:
h = -1/2*(-9.81 m/s^2)(1.20 s)^2 - (1.30 m/s)(1.20 s) = 3.20 m
Therefore, the girl was 3.20 meters above the water when she let go of the rope.
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A rocket at rest on the ground with initial mass 20,000 kg, 80% of which is fuel, burns 200kg/s as it flies
directly upwards. The exhaust gas exits the rocket at a relative speed of 1.80 km/s. Find (a) the thrust of
the rocket, (b) how long it takes to exhaust its fuel, and (c) the rocket’s speed at the end of its engine burn.
Assume g is constant and neglect air resistance.
For Part A I got: 360,000 Newtons, Part B: 20 Seconds, Part C 205.658 m/s
Are my answers correct?
To check your answers, we can use the following equations:
(a) Thrust = (mass flow rate of exhaust gas) * (exhaust velocity of gas) + (initial mass of rocket) * (acceleration due to gravity)
(b) Time to exhaust fuel = (0.8 * initial mass of rocket) / (mass flow rate of exhaust gas)
(c) Final velocity of rocket = (exhaust velocity of gas) * ln(initial mass of rocket / final mass of rocket)
Using the given values:
Mass flow rate of exhaust gas = 200 kg/s
Exhaust velocity of gas = 1.80 km/s = 1800 m/s
Initial mass of rocket = 20,000 kg
Acceleration due to gravity = 9.81 m/s^2
Final mass of rocket = 0.2 * initial mass of rocket = 4,000 kg
(a) Thrust = (200 kg/s) * (1800 m/s) + (20,000 kg) * (9.81 m/s^2) = 360,000 N
Your answer for part (a) is correct.
(b) Time to exhaust fuel = (0.8 * 20,000 kg) / (200 kg/s) = 800 s = 20 minutes
Your answer for part (b) is incorrect. The correct answer is 800 seconds or 20 minutes, not 20 seconds.
(c) Final velocity of rocket = (1800 m/s) * ln(20,000 kg / 4,000 kg) = 205.66 m/s
Your answer for part (c) is correct.
5. What is the area of this figure? Please show your work.
20 in.
7 in
6. What is the area of this figure? Please show your
10 ft
8 ft
6 ft
work.
Answer:
The area of the figure 7 in the area of 6 ft
A car is moving along a road at 13.0 m/s with an engine that exerts a force of 1,775.0 N on the car to balance the drag and friction so that the car maintains a constant speed. What is the power output of the engine?
Answer:
The power output of the engine can be calculated using the formula:
Power = Force x Velocity
where force is the net force acting on the car, and velocity is the speed of the car. In this case, the net force is equal to the force exerted by the engine, which is 1,775.0 N, since the car is moving at a constant speed and there is no acceleration. The velocity of the car is 13.0 m/s. Thus, the power output of the engine can be calculated as:
Power = 1,775.0 N x 13.0 m/s = 23,075 W
Therefore, the power output of the engine is 23,075 watts.
Two identical billiard balls are rolling toward each other at the same speed. What will be true after they collide head–on?
They will both stop rolling immediately after the collision.
One ball will stop rolling as the other bounces backward at a slower speed.
They will both bounce back at a faster speed after the collision.
They will both bounce back at the same speed they had before the collision.
Answer:
After the head-on collision, both identical billiard balls will bounce back at the same speed they had before the collision. This is because of the conservation of momentum, which states that the total momentum of a closed system remains constant if no external forces act on it. In this case, the two billiard balls are a closed system, and their total momentum before the collision is equal and opposite to their total momentum after the collision. Therefore, they will both bounce back with the same speed they had before the collision.
Explanation:
A 7g bullet is fired into a 345g block that is initially at rest at the edge of a frictionless table of height 1.9m. The bullet remains in the block and after impact the block lands 2m from the bottom of the table. Find the initial speed of the bullet. The acceleration due to gravity is 9.8m/s^2. Answer in units of m/s
Answer:
≈ 192.7 m/s
Explanation:
Let's start by finding the velocity of the block just before it hits the ground. We can use the conservation of energy:
The initial potential energy of the block is mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the table.The final kinetic energy of the block is (1/2)mv^2, where v is the velocity of the block just before it hits the ground.Conservation of energy tells us that these two energies are equal:
mgh = (1/2)mv^2
Solving for v, we get:
v = sqrt(2gh)
Plugging in the given values, we get:
v = sqrt(2 * 9.8 m/s^2 * 1.9 m) = 6.06 m/s
Now, let's use conservation of momentum to find the initial speed of the bullet. We know that the total momentum of the system (bullet + block) is conserved before and after the collision. Before the collision, the momentum is:
p = mb * vb
where mb is the mass of the block and vb is its initial velocity, which is 0 since it is at rest.
After the collision, the bullet and block move together with a common velocity v. The total momentum is:
p = (mb + m) * v
where m is the mass of the bullet. Since momentum is conserved:
mb * vb = (mb + m) * v
Solving for vb, we get:
vb = (mb + m) * v / mb
Plugging in the given values, we get:
vb = (345 g + 7 g) / 7 g * 6.06 m/s = 192.7 m/s
Therefore, the initial speed of the bullet was approximately 192.7 m/s.
if 100g of iron at 100°c is dropped into 390g of water at 20°c what will the final temperature be?
I need guidance in this one
The clay ball that could stick to the door would be more effective when you want to shut the door from a distance be throwing a n object.
Will a rubber ball or a clay ball do better at helping you shut a door when thrown at the door?The effective way to shut the door could be through the use of the clay ball that could stick to the door and push it to the place where it could jam rather than the rubber ball that would bound back.
The best way to shut a door is to use the door handle or knob to pull the door towards you and guide it into the door frame until it clicks shut.
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Which type of wave interaction allows us to hear sounds around corners and under doors?
A. Diffraction
B.Absorption
C.refraction
D.reflection
Answer: Diffraction
Explanation: It is diffraction, because due to diffraction, sound waves bend on the corner as their size is of the order of wavelength of sound waves.
I need this tomorrow 50 points
Answer: NUMBER - 275.5 N
Explanation:
If the train set uses stronger magnets, will the distance between these train cars increase or decrease? Explain your answer.
The distance between the train cars will decrease, as stronger magnets will create a greater attractive force between them. This will cause the cars to be pulled closer together.
What is stronger magnet?The strength of a magnet depends on the type of magnet and the material it is made from. Generally, the strongest magnets are neodymium magnets, also known as rare earth magnets. These are made from a combination of neodymium, iron, and boron and can produce magnetic fields up to 1.4 teslas, or 14,000 gauss. Samarium cobalt magnets are also powerful, producing fields up to 1.4 teslas. Other types of magnets, such as ceramic and Alnico magnets, generally produce magnetic fields of around 0.5 teslas or 5,000 gauss.
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Help me please I’m begging
The total resistance is 3 ohm
The current is 1.5 A
What is the total resistance of the circuit?To calculate the total resistance of a circuit, you need to determine the equivalent resistance of all the resistors in the circuit. The equivalent resistance is the single resistance value that could replace all the individual resistors and produce the same overall resistance.
1) This is a parallel circuit thus;
1/RT = 1/6 + 1/6
RT = 3 ohm
2) This is a series circuit thus;
RT = 4 + 6 = 10 ohm
Current = 15V/10 ohm
= 1.5 A
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An 12.000 milligram particle is sliding across a friction-less one-dimensional path at 55.000 m/s and collides with a 68.000 milligram particle moving at -48.000 m/s in a perfectly inelastic collision. What are the velocities of the particles after the collision?
answer with correct units
Answer:
-3525.000 m/s
Explanation:
In a perfectly inelastic collision, the two particles stick together and move with a common velocity after the collision. We can use the conservation of momentum to solve for this common velocity.
The initial momentum of the system is:
p_initial = m1 * v1 + m2 * v2
= (12.000 mg)(55.000 m/s) + (68.000 mg)(-48.000 m/s)
= -282.000 kg·m/s
Here, we convert the masses to kilograms to match the units of velocity.
Since the particles stick together after the collision, their masses add up:
m_final = m1 + m2
= 12.000 mg + 68.000 mg
= 80.000 mg
= 0.080 g
Now, we can use the conservation of momentum to find the final velocity:
p_final = m_final * v_final
where p_final = p_initial and m_final = 0.080 g.
Therefore:
v_final = p_final / m_final
= -282.000 kg·m/s / 0.080 g
= -3525.000 m/s
helpme please help me ples
It is female (XO).A karyotype can be used to diagnose a chromosomal disorder by examining the number and arrangement of a person's chromosomes.
What is chromosomes ?Chromosomes are thread-like structures located in the nucleus of cells that carry genetic information in the form of genes. They are composed of DNA and proteins and are responsible for directing the development and functioning of cells. In humans, chromosomes come in pairs of 23, with one copy of each pair inherited from each parent.
For example, Down Syndrome is caused by an extra chromosome 21, Klinefelter Syndrome is caused by an extra X chromosome in males (XXY), and Turner Syndrome is caused by a single X chromosome in females (XO).
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Compare the patterns of iron filings to the spiral arms in Interacting galaxies.
The primary locations for the birth of new stars are in galaxies' spiral arms. The proportion of the galaxy that can participate in star formation increases as more gas and dust become available.
What distinguishes the numerous varieties of spiral galaxies?We refer to some spiral galaxies as "barred spirals" because the centre bulge seems extended, like a bar. The spiral arms of the galaxy seem to emerge from the ends of the bar in barred spirals. Elliptical galaxies are round or oval in shape, as their name implies, and have a rather uniform distribution of stars.
The four spiral arms are what?The Norma and Cygnus arm, Sagittarius, Scutum-Crux, and Perseus arms are the four principal spiral arms of the Milky Way.
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Explain why a football accelerates
faster than a soccer ball when the
same amount of force is applied?
Answer: Answer is below <3 (The underlined part is the answer)
Explanation: The reason why an object with a smaller mass has a larger acceleration than an object with a larger mass if the same force acts on each is because the acceleration of an object depends on its mass as well as the force exerted on it, and if the mass is smaller than the other object than it is faster.
The reason why a football accelerates faster than a soccer ball when the same amount of force is applied is because of the difference in their masses. The acceleration of an object is directly proportional to the force applied to it and inversely proportional to its mass. This means that the smaller the mass of an object, the greater the acceleration it experiences when the same amount of force is applied to it.
A football is typically smaller and lighter than a soccer ball, so when the same amount of force is applied to both balls, the football experiences a greater acceleration due to its lower mass. This is consistent with Newton's second law of motion, which states that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass.
Additionally, the surface area and shape of the balls can also affect their acceleration. A football is typically more aerodynamic with a pointed shape that reduces air resistance, allowing it to move through the air more easily and accelerate faster. In contrast, a soccer ball has a more spherical shape that can create more air resistance, slowing down its acceleration.
Therefore, the mass, shape, and surface area of the ball are all factors that can affect its acceleration when a force is applied.
Use the table to answer the question.
Wave Wavelength (meters) Frequency (hertz)
W 5 200
X 3 300
The table shows information about two waves. Based on the given information, which conclusion can be made?
O Wave W has a faster speed.
O Wave W has a greater amplitude.
O Wave X has a greater amplitude.
O Wave X has a faster speed.
We can see from the table that we have in the question that Wave W has a faster speed.
What is the relationship of wavelength and frequency?Wavelength and frequency are two fundamental properties of waves, including electromagnetic waves and sound waves. The relationship between wavelength and frequency can be described by the following equation:
c = λν
where c is the speed of light (or speed of sound), λ is the wavelength, and ν is the frequency.
According to this equation, the wavelength and frequency are inversely proportional to each other.
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The wave in the liquid travels towards the surface at an angle. Fig 9.2 shows the centres of the compressions of the sound wave in liquid. Some compressions shown have reached the liquid-air boundary. The parts of these compressions in the air are not shown on Fig 9.2 These waves are also reflected at the boundary. Draw on the diagram the reflected wavefronts.
The reflected sound wavefronts at the given boundary are waves that have bounced off a surface and changed direction.
The reflected sound wavefront is shown in the attachment.
What are reflected wavefronts?A reflected wavefront is a wavefront that has bounced off a surface and changed direction. When a wave, such as a light wave or sound wave, encounters a surface, some of the wave energy is reflected back in the opposite direction.
An example of reflected sound wavefronts in water can be seen in underwater sonar imaging.
In sonar imaging, a sound wave is emitted from a source and travels through the water. When the sound wave encounters an object, some of the wave energy is reflected back toward the source.
Reflected wavefronts play an important role in many areas of science and engineering, such as optics, acoustics, and electromagnetism. They are used to model the behavior of waves in complex systems and to design and optimize devices such as mirrors, lenses, and antennas.
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A rock group is playing in a bar. Sound
emerging from the door spreads uniformly in
all directions. The intensity level of the music
is 32.2 dB at a distance of 4.99 m from the
door.
At what distance is the music just barely
audible to a person with a normal threshold
of hearing? Disregard absorption.
Answer in units of m.
Answer:
5292.64 m
Explanation:
At the moment when a shot putter releases a 5.00kg shot, the shot is 3.00m above the ground and traveling at 15.0m/s. It reaches a maximum height of 14.5m above the ground and then falls to the ground. If air resistance is negligible, what was the potential energy of the shot as it left the hand relative to the ground?
The potential energy of the shot as it left the hand relative to the ground would be -524 J.
Potential energy calculationAt the moment the shot putter releases the shot, the total energy of the system is:
E = KE + PE
where KE is the kinetic energy of the shot and PE is its potential energy relative to the ground. We can assume that the kinetic energy is entirely due to the motion of the shot in the horizontal direction, so we can write:
KE = (1/2)mv^2
where m is the mass of the shot, and v is its horizontal velocity. Substituting the known values, we get:
KE = (1/2)(5.00 kg)(15.0 m/s)^2 = 1125 J
At the maximum height of 14.5 m, the shot has zero kinetic energy, so all its energy is potential energy:
PE = mgh
where g is the acceleration due to gravity and h is the height above the ground. Substituting the known values, we get:
PE = (5.00 kg)(9.81 m/s^2)(14.5 m - 3.00 m) = 601 J
Therefore, the potential energy of the shot as it left the hand relative to the ground was:
PE = E - KE = 601 J - 1125 J = -524 J
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Sort the following items from most to least inertia.
Answer: In order of most inertia to least.
car stopped
motorcycle driving
dog laying
large hot coffee
small mouse
Explanation:
Honestly, I'm not 100% sure about this, but inertia is the want to remain the way it currently is, So the larger the object, the more inertia it should have. So I basically arranged the things by size, I think the moving and not is a red herring to throw you off. Also given that the dog laying in the middle option makes sense because a dog would be in the middle of the size options.
Physics problem in the photo that I have no clue how to answer, please, and thank you!
The resistive force of friction (Fr) divided by the normal or perpendicular force (N) pushing the objects together yields the coefficient of friction (fr), which is a numerical value. It is expressed by the equation: fr = Fr/N.
What is the coefficient of friction μ?coefficient of friction, ratio of the frictional force opposing the motion of two surfaces in contact to the normal force pushing the two surfaces together.
Typically, it is represented by the Greek letter mu (). In terms of math, is equal to F/N, where F stands for frictional force and N for normal force. The things creating friction will determine the coefficient of friction. The value is often between 0 and 1, although it can also be higher. A number of 0 indicates that there is absolutely no friction between the items; superfluidity makes this feasible.
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Full Question ;
A concrete highway curve of radius 80.0 m is banked at a 18.0 degrees angle.
What is the maximum speed with which a 1100 kg rubber-tired car can take this curve without sliding? (Take the static coefficient of friction of rubber on concrete to be 1.0.)
1. Find the displacement of a
farmer who walked 80.0 m
[0°] and then 60.0 m [335°].
it of
The farmer had a displacement of 133.4 m at an angle of -15.5° after moving 80.0 m [0°] and then 60.0 m [335°].
To find the displacement of the farmer who walked 80.0 m [0°] and then 60.0 m [335°], we need to use vector addition. First, we need to convert the distances and angles into their respective x and y components. The x component of the first displacement is 80.0 m (cos 0°) = 80.0 m, and the y component is 80.0 m (sin 0°) = 0 m. Similarly, the x component of the second displacement is 60.0 m (cos 335°) = 49.5 m, and the y component is 60.0 m (sin 335°) = -35.1 m (negative because it is in the fourth quadrant).
Next, we add the x and y components separately to find the resultant x and y components.
Resultant x component
= 80.0 m + 49.5 m
= 129.5 m
Resultant y component
= 0 m - 35.1 m
= -35.1 m
Now, we can use the Pythagorean theorem to find the magnitude of the resultant displacement:
|displacement| = √(129.5 m)² + (-35.1 m)²
= 133.4 m
Lastly, we can use inverse tangent to find the direction of the displacement:
θ = a tan (-35.1 m / 129.5 m) = -15.5°
Therefore, the displacement of the farmer who walked 80.0 m [0°] and then 60.0 m [335°] is 133.4 m at an angle of -15.5°.
Finding displacement through vector addition is a common problem in physics and is an important concept in understanding motion. By breaking down distances and angles into their respective x and y components, we can add them together to find the resultant displacement.
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A scientist makes a model of Earth's water by drawing 100 drops of water, all the same size. How many of the 100 drops represent ocean water?
A.3
B.50
C.75
D.97
Answer:
D
Explanation:
If the water represents the oceans water then you'd would need to calculate how much of earth is water (96.5)
A machine has velocity ratio 6 and is 80% efficient. what effort would be needed to lift a load of 300N with the aid of this machine?
The effort needed to lift the load of 300 N, given that the velocity ratio is 6 and the machine has an efficiency of 80% is 62.5 N
How do i determine the effort needed to lift the load?First, we shall determine the mechanical advantage of the machine. Details below:
Velocity ratio (VR) = 6Efficiency = 80%Mechanical advantage (MA) = ?Efficiency = MA / VR
80% = MA / 6
Cross multiply
MA = 80% × 6
MA = 4.8
Finally, we shall determine the effort of the machine. Details below:
Mechanical advantage (MA) = 4.8Load (L) = 300 NEffort (E) = ?Mechanical advantage (MA) = Load (L) / Effort (E)
4.8 = 300 / Effort
Cross multiply
4.8 × Effort = 300
Divide both sides by 4.8
Efoort = 300 / 4.8
Effort = 62.5 N
Thus, we can conclude that the effort of the machine is 62.5 N
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