Answer:
(a) 0.40
(b) 0.049
(c) [tex]\bar p\sim N(0.40,0.049^{2})[/tex]
(d) Explained below
Step-by-step explanation:
According to the Central limit theorem, if from an unknown population large samples of sizes n > 30, are selected and the sample proportion for each sample is computed then the sampling distribution of sample proportion follows a Normal distribution.
The mean of this sampling distribution of sample proportion is:
[tex]E(\bar p)=p[/tex]
The standard deviation of this sampling distribution of sample proportion is:
[tex]SE(\bar p)=\sqrt{\frac{p(1-p)}{n}}[/tex]
Given:
n = 100
p = 0.40
As n = 100 > 30 the Central limit theorem is applicable.
(a)
Compute the expected value of [tex]\bar p[/tex] as follows:
[tex]E(\bar p)=p=0.40[/tex]
The expected value of [tex]\bar p[/tex] is 0.40.
(b)
Compute the standard error of [tex]\bar p[/tex] as follows:
[tex]SE(\bar p)=\sqrt{\frac{p(1-p)}{n}}=\sqrt{\frac{0.40(1-0.40)}{100}}=0.049[/tex]
The standard error of [tex]\bar p[/tex] is 0.049.
(c)
The sampling distribution of [tex]\bar p[/tex] is:
[tex]\bar p\sim N(0.40,0.049^{2})[/tex]
(d)
The sampling distribution of p show that as the sample size is increasing the distribution is approximated by the normal distribution.
In 2001, a school population was 1696. By 2007 the population had grown to 2614.
1) How much did the population grow between the year 2001 and 2007?
students
2) How long did it take the population to grow from 1696 students to 2614 students?
years
3) What is the average population growth per year?
students/year
4) What was the population in the year 2000?
students
5) Find an equation for the population,
P
, of the school
t
years after 2000.
P
=
6) Using your equation, predict the population of the school in 2011.
students
Answer:
grew by 6
Step-by-step explanation:
write the number whose prime factorization is give: 2×2×2×7
Answer:
56
Step-by-step explanation:
Multiply it out 2×2×2×7 = 56
How do I solve for X?
Answer
50
Step-by-step explanation:
60 is supplementary to 120 so 60+70=130
and a triangle adds up to 180 so 180-130 would be 50
An oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day. For each additional well that is drilled, the average production per well decreases by 25 barrels per day.
Required:
How many additional wells should be drilled to obtain the maximum amount of oil per day?
Answer:
The additional wells for maximum amount of oil per day is 3 wells.
Step-by-step explanation:
Given;
initial number of wells, n = 6
total production, T = 1800
average production per well, = 1800/6 = 300 barrels per day
Let the additional well = y
total number of wells after optimization = 6 + y
new production per well = 300 - 25y
new total production = (6+y)(300-25y)
t = 1800 - 150y + 300y - 25y²
t = 1800 + 150y - 25y²
dt / dy = 150 -50y
for maximum value, dt/dy = 0
150 - 50y = 0
50y = 150
y = 150 / 50
y = 3
Therefore, the additional wells for maximum amount of oil per day is 3 wells.
33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.
Given that an oilfield contains 6 wells that produce a total of 1,800 barrels of oil per day, and for each additional well that is drilled, the average production per well decreases by 25 barrels per day, to determine how many additional wells should be drilled to to obtain the maximum amount of oil per day, the following calculation must be performed:
1800 x 6 = 10800 1200 x 30 = 36000 1000 x 38 = 38000 950 x 40 = 38000 900 x 42 = 37800 975 x 39 = 38025
Therefore, 33 additional wells should be drilled, reaching 39 wells, to obtain the maximum amount of oil per day.
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LUCILLE'S PENCIL POUCH WOULD HOLD 3/8
OF THE 48 PENCILS THAT SHE PURCHASED AT
THE BEGINNING OF THE NEW SCHOOL YEAR. How many pencils will fit in her pouch
HOW MANY PENCILS WILL FIT IN HER POUCH?
Answer:
The pouch would be able to hold 12.8 pencils :)
Step-by-step explanation:
because 3/8 is 37.5 and if you do that divided by 48 and add a decimal infront of the eight you will get your answer
Can someone help me with number 1 and 2
Describe the relationship between the point B (16, 24) and the point
B' (8, 12) in terms of dilations.
(x, y) → ()
Answer:
(x/2,(y/2)
Step-by-step explanation:
(16/2,24/2)
(8,12)
1. To rent a van, a moving company charges $30 plus $0.50 per mile. Write an equation
that represents the cost as a function of the number of miles. What does the slope
represent? Find the cost of the van for 150 miles.
Answer:
Step-by-step explanation:
which numerical pattern in nonlinear?
A. 3, 11, 19, 27,
B. 1, 3, 9, 27
C. 1, 4, 7, 10,
D. 2, 3, 4, 5
Answer:
I am going with B.1,3,9,27
Step-by-step explanation:
A,C and D the patterns are from addition ie. A +8, C+3 and D +1 but B it's ×3
Evaluate 12x−3y when x=−14 and y=3.
Answer:
-177
Step-by-step explanation:
12(-14) -3(3)
-168-9
-177
Answer:
-177
Step-by-step explanation:
Plug in -14 for x and 3 for y:
12(-14) - 3(3)
Note that when you multiply a positive and a negative number, your answer will be negative.
Multiply:
12 * -14 = -168
-3 * 3 = -9
Combine the terms:
-168 + (-9) = -168 - 9 = -177
-177 is your answer.
~
One package of blackberries costs $3. How many packages of blackberries can you buy for $15?
Answer:
5 packages
Step-by-step explanation:
One package of blackberries cost $3
Let x represent the number of packages that will cost $15
1 = $3
x= $15
3x= 15
Divide both sides by the coefficient of x which is 3
3x= 15/3
x= 5
Hence 5 packages of blackberries will cost $15
State whether the given pair of sets are equal, equivalent, both, or neither. {0,9}; {8, 1)
Answer:
Equivalent
Step-by-step explanation:
A set is a well defined collection of objects.
Two sets are said to be equal if they have the same elements.
Two sets are said to be equivalent if they have the same number of elements.
Given sets are [tex]\{0,9\}\,,\,\{8,1\}[/tex]
These sets are not equal as both the sets have different elements.
Order of both the sets is 2 (number of elements in both sets is 2)
So,
these two sets are equivalent.
Each picture shows how a mapping, f, maps elements of a domain onto a range.
Which mapping, f, is NOT a function?
Domain
Range
Domain
Range
-6
2.
5
6 00
4
7
7
1
9
8
Domain
Range
Domain
Range
5
4
2
→8
7
2
Answer:
Top left
Step-by-step explanation:
If an x value (domain) leads to more than one y-value (range), it is not a function. In other words, if each input value leads to only one output value, it is a function. It's still a function if the y-value leads to multiple x-values.
Find the slope of the line
graphed below.
Answer:
[tex]\frac{3}{5}[/tex] or 0.6
Step-by-step explanation:
This problem requires the slop formula which is [tex]\frac{y2-y1}{x2-x1}[/tex]
You start with the first point which is (-1,1). This will be x1 and y1.
The next point is (4,4). This will be x2 and y2.
You plug these values into your equation which gives you [tex]\frac{4-1}{4-(-1)}[/tex]
To solve, you evaluate, [tex]\frac{4-1}{4-(-1)}[/tex] = [tex]\frac{3}{5}[/tex] or 0.6
Multiply: -12y(y - 6) Enter the correct answer.
A worker at one farm is paid $486 for the week, plus $0.03 for every pound
of apples she picks. At another farm, a worker is paid $490 for the week, plus
$0.02 for every pound of apples. For how many pounds of apples are the workers
paid the same amount?
Answer:sorry this probably is t the most helpful but the closest i could get was 399 lbs. it’s is st$497.7 for one and $$497.8.
Step-by-step explanation:
The normal distribution An automobile battery manufacturer offers a 31/54 warranty on its batteries. The first number in the warranty code is the free-replacement period; the second number is the prorated-credit period. Under this warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charge to the consumer. If the battery fails after 31 months but within 54 months, the manufacturer provides a prorated credit toward the purchase of a new battery. The manufacturer assumes that x, the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months. Use the following Distributions tool to help you answer the questions that follow. (Hint: When you adjust the parameters of a distribution, you must reposition the vertical line (or lines) for the correct areas to be displayed.)
1. If the manufacturer's assumptions are correct, it would reed to replace _______ of its batteries free.
2. The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect. A standard deviation of ____ results in a 1.07% replacement rate.
3. Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?
Answer:
1) if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.
2) a standard deviation of 6.0843 results in a 1.07% replacement rate
3) using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit
Step-by-step explanation:
based on the given data;
x will represent the random variable such that the lifetime of its auto batteries, is normally distributed with a mean of 45 months and a standard deviation of 5.6 months
so
x → N( U = 45, ∝ = 5.6)
Under the warranty, if a battery fails within 31 months of purchase, the manufacturer replaces the battery at no charges to the consumer.
if the battery fails after 31 months but within 54 months, the manufacturer provides a prostrated credit towards the purchase of anew battery
1) If the manufacturer's assumptions are correct,
p(x < 3) = p( [x-u / ∝ ] < [ 31-45 / 5.6] )
= p( z < -2.5 )
using the standard normal table,
value of z = 0.0062 ≈ 0.62%
so if the manufacturer's assumptions are correct, it would reed to replace 0.62% of its batteries free.
2)
The company finds that it is replacing 1.07% of its batteries free of charge. It suspects that its assumption standard deviation of the life of its batteries is incorrect, so a standard deviation of ? results in a 1.07%
so lets say;
p ( x < 31 ) = ( 1.07%) = 0.0107
p ( [x-u / ∝ ] < [ 31-45 / ∝] ) = 0.0107
now from the standard table
-2.301 is 1.07%
so
( 31 - 45 / ∝ ) = -2.301
-14 / ∝ = -2.301
∝ = -14 / - 2.301
∝ = 6.0843
therefore a standard deviation of 6.0843 results in a 1.07% replacement rate
3)
Using the revised standard deviation for battery life, what percentage of the manufacturer's batteries don't free replacement but do qualify for the prorated credit?
p( 31 < x < 54 ) = p ( [31 - u / ∝ ] < [ x-u / ∝] < [ 54 - 45 / ∝] )
= p ( [31 - 45 / 6.0843 ] < [ x-u / ∝] < [ 54 - 45 / 6.0843] )
= p ( -2.301 < z < 1.4792 )
= p(Z < 1.5) - p(Z < -2.3)
= 0.9393 - 0.0108
= 0.919 ≈ 91.9%
therefore using the revised standard deviation for battery life, 91.9% of the manufacturer's batteries don't get free replacement but qualifies for the prorated credit
please help
Which values of k would cause this system of equations to have no solution? Check all that apply.
6x + 4y = 14,
3x + 2y = k
-2
5
7
10
21
Answer:
a , b , d , e
Step-by-step explanation:
Find the exponential function that satisfies the given conditions: initial value = 70, decreasing at a rate of 0.43% per week
Answer choices:
A) f(t) = 70 x 0.9957^t
B) f(t) = 70 x 1.43^t
C) f(t) = 0.43 x 0.3^t
D) f(t) = 70 x 1.0043^t
Answer:
a- just took the test
Step-by-step explanation:
find the number of terms in the arithmetic sequence
-7,-5.6,-4.2,-2.8,1.4,...,103.6
Answer:
80
Step-by-step explanation:
use the formula of arithmetic progression
6 ≤ -3x + 12
can somone solve this for me *correctly* ill give u brainlest only if ur right
Answer:
x ≤ 2
Step-by-step explanation:
-3x+12≥6
-3x≥6
3x≤6
x ≤ 2
Answer:
x ≤ 2 is the correct answer!
Step-by-step explanation:
Hope this helps!
please help me with this question
Answer:
2c^2
Step-by-step explanation:
c3-c1=c2
d2-d2=0
8/4=2
How to solve this without calculator?
sin-1(2/3)
Answer:-0.560
Step-by-step explanation:
The distance from a point to two is five units. The point could be located at
-7
-6
6
-3
NEXT QUESTION
O ASK FOR HELP
Answer:
The correct answer is -3
Step-by-step explanation:
attached is a number line to show diagrammatically how to count five units from the chosen point to point 2 on a number line.
Moving five units from -3 to 2 on a number line is given as follows:
-3 ⇒ -2 ⇒ -1 ⇒ 0 ⇒ 1 ⇒ 2
From the motion expression shown above, moving from -3 to 2 involves moving 5 units.
another way of determining the correct answer is to find the difference in interval between the two points as shown below:
Let the point be x
2 - x = 5 units
2 - 5 = x
∴ x = -3
Answer:
-3
Step-by-step explanation:
it was on quiz baby
a. Suppose a BMW dealer in Fullerton, CA is trying to calculate the probability of his car sale for next week. The dealer knows that the sale of car is normally distributed with mean 50 and variance 9. The variance 9 was calculated from the weekly car sale data of 20 weeks, as the population variance is not known to the dealer. What is the probability that the dealer will sell 51 or more cars next week? (Hint: use t distribution) (15)
Answer:
0.45576
Step-by-step explanation:
z = (x-μ)/σ, where
x is the raw score
μ is the population mean
σ is the population standard deviation.
Standard Deviation = √variance
Mean = 50
= √9
= 3
z = 51 - 50/3
= 0.11111
Probability value from Z-Table:
P(x<51) = 0.54424
P(x>51) = 1 - P(x<51)
= 1 - 0.54424
= 0.45576
The probability that the dealer will sell 51 or more cars is 0.45576
M/x =n-p, x for p ??
Answer:
the answer is A) X=m/n-p
Step-by-step explanation:
m/x=n-p
n-p=m/X
(n-p)×x=m
X=m/n-p
What is the goal of solving equations?
Answer:
The goal in solving an equation is to get the variable by itself on one side of the equation and a number on the other side of the equation. To isolate the variable, we must reverse the operations acting on the variable.
Step-by-step explanation:
The objective or equation would be to acquire the variables independently. A further explanation is provided below.
The objective is to address an expression by getting the component solely on a single side of this argument as well as a figure while on the other side of the same expression.Throughout the order to isolate variables, procedures that influence somewhat on variables have to be reversed. We achieve this by carrying out several halves of the expression the opposite of every process.
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Suppose that a tea company estimates that its monthly cost is C(c) = 500x² + 100x and its monthly revenue is R(2) = -0.6x3 + 700x2 – 400x + 300, where x is in thousands of boxes of tea sold. The profit is the difference between the revenue and the cost. What is the profit function, p(X)?
O A. P(x) = 0.6x3- 200x2 + 500x+ - 300
OB. P(x) = -0.6x3 + 1200x2 – 300x + 300
O C. P(x) = -0.6x3 + 200x2 – 500x + 300
D. P(xl = 0.6x3 + 200x2 – 500x + 300
Answer:
p(x) = 0.6x³ - 200x² + 500x- 300
Step-by-step explanation:
Given the cost function and revenue function as:
C(x) = 500x² + 100x
R(x) = -0.6x³ + 700x² – 400x + 300
To get the profit function:
p(x) = C(x) - R(x)
p(x) = 500x² + 100x -(-0.6x³ + 700x² – 400x + 300)
open the parenthesis
p(x) = 500x² + 100x + 0.6x³ - 700x² + 400x - 300
p(x) = + 0.6x³+500x² - 700x² + 100x+ 400x- 300
p(x) = 0.6x³ - 200x² + 500x- 300
Hence the profit function is expressed as p(x) = 0.6x³ - 200x² + 500x- 300
uestion 1:
Damon wants to sell his motorcycle that he paid $4,000 for 3 years ago. The motorcycle depreciated (decreased in value) at a constant rate each month over a 3-year period. If x represents the monthly depreciation amount, write an expression that shows how much Damon can sell his motorcycle for today.
Answer:
4,000 -x3
Step-by-step explanation:
x times 3 is equal to the decrease so therefore you take the decrease away form 4/oo
Answer:
3y-x=4,000
Step-by-step explanation:
Construct a table of values for the following functions using the integers from -4 to 4.
a. F(x)=6/x-2
b. r(x)=6x+12/x^-4
Step-by-step explanation:
Find the table attached
a) Given
F(x) = 6/x-2
When x = -4
F(-4) = 6/-4-2
F(-4) = 6/-6
F(-4) = -1
F(x) = 6/x-2
When x = -3
F(-3) = 6/-3-2
F(-3) = 6/-5
F(-3) = -1.2
F(x) = 6/x-2
When x = -2
F(-2) = 6/-2-2
F(-2) = 6/-4
F(-2) = -1.5
F(x) = 6/x-2
When x = -1
F(-1) = 6/-1-2
F(-1) = 6/-3
F(-1) = -2.0
F(x) = 6/x-2
When x = 0
F(0) = 6/0-2
F(0) = 6/-2
F(0) = -3
F(x) = 6/x-2
When x = 1
F(1) = 6/1-2
F(1) = 6/-1
F(1) = -6
F(x) = 6/x-2
When x = 2
F(2) = 6/2-2
F(2) = 6/0
F(2) = infty
F(x) = 6/x-2
When x = 3
F(3) = 6/3-2
F(3) = 6/1
F(3) = 6
F(x) = 6/x-2
When x = 4
F(4) = 6/4-2
F(4) = 6/2
F(4) = 3
b) Given
r(x)=6x+12/x^-4
When x = -4
r(-4) = 6(-4)+12/(-4)^-4
r(-4) = -24+12/(1/256)
r(-4) = -12(256)
r(-4) = -3072
When x = -3
r(-3) = 6(-3)+12/(-3)^-4
r(-3) = -18+12/(1/81)
r(-3) = -6(81)
r(-3) = -486
When x = -2
r(-2) = 6(-2)+12/(-2)^-4
r(-2) = -12+12/(1/16)
r(-2) = -0(16)
r(-2) = 0
When x = -1
r(-1) = 6(-1)+12/(-1)^-4
r(-1) = -6+12/(1)
r(-1) = -6+12
r(-1) = 6
When x = 0
r(0) = 6(0)+12/(0)^-4
r(0) = 0+12/0
r(0) = 12/0
r(0) = infty
When x = 1
r(1) = 6(1)+12/(1)^-4
r(1) = 6+12/1
r(1) = 18(1)
r(1) = 18
When x = 2
r(2) = 6(2)+12/(2)^-4
r(2) = 12+12/1/16
r(2) = 24(16)
r(2) = 384
When x = 3
r(3) = 6(3)+12/(3)^-4
r(3) = 18+12/1/81
r(3) = 30(81)
r(3) = 2430
When x = 4
r(4) = 6(4)+12/(4)^-4
r(4) = 24+12/1/256
r(4) = 36(256)
r(4) = 9216
We want to construct tables of values for the two given functions.
The tables are:
a)
[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]
b)
[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]
A table will be something like:
[tex]\left[\begin{array}{ccc}x&y\\-4&\\-3&\\-2&\\-1&\\0&\\1&\\2&\\3&\\4&\end{array}\right][/tex]
Where the values of x go from -4 to 4.
To complete the tables, we just need to evaluate the functions in each one of the x-values at the left, and the outcome will be placed at the right.
a) f(x) = 6/x - 2
Now we just need to evaluate the function in all the given points:
f(-4) = 6/(-4) - 2 = -3/2 - 4/2 = -7/2
f(-3) = 6/-3 - 2 = -4
f(-2) = 6/-2 - 2 = -5
f(-1) = 6/-1 - 2 = -8
f(0) is undefined, as we can't divide by zero, here we can write NaN (Not a number).
f(1) = 6/1 - 2 = 4
f(2) = 6/2 - 2 = 1
f(3) = 6/3 - 2 = 0
f(4) = 6/4 - 2 = -1/2
Now we put all of these in the correspondent place of the table:
[tex]\left[\begin{array}{ccc}x&y\\-4&-7/2\\-3&-4\\-2&-5\\-1&-8\\0&NaN\\1&4\\2&1\\3&0\\4&-1/2\end{array}\right][/tex]
b) We do the same thing, here we have:
r(x) = 6*x + 12/x^-4 = 6*x + 12*x^4
Now we evaluate this in the given values:
r(-4) = 6*(-4) + 12*(-4)^4 = 3,048
r(3) = 6*(-3) + 12*(-3)^4 = 954
r(-2) = 6*(-2) + 12*(-2)^4 = 180
r(-1) = 6*(-1) + 12*(-1)^4 = 6
r(0) = 6*0 + 120^4 = 0
r(1) = 6*1 + 12*1^4 = 18
r(2) = 6*2 + 12*2^4 = 204
r(3) = 6*3 + 12*3^4 = 990
r(4) = 6*4 + 12*4^4 = 3,096
Now we place these values in the correspondent place on the table:
[tex]\left[\begin{array}{ccc}x&y\\-4&3,048\\-3&954\\-2&180\\-1&6\\0&0\\1&18\\2&204\\3&990\\4&3,096\end{array}\right][/tex]
These are our two tables.
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