A rectangle with a length of x+5 has a perimeter of 4x+ 14. What is the width of the rectangle?

What i put before is wrong sorrI

Length of the rectangle (l) = x + 5

Perimeter of the rectangle = 4x + 14

Formula of perimeter of the rectangle = 2(length + width)

Let the width of the rectangle be 'w'. So,

[tex] \rm \longrightarrow 2(l + w) = 4x + 14 \\ \\ \rm \longrightarrow 2(x + 5 + w) = 4x + 14 \\ \\ \rm \longrightarrow \dfrac{2(x + 5 + w)}{2} = \dfrac{4x + 14}{2} \\ \\ \rm \longrightarrow x + 5 + w = 2x + 7 \\ \\ \rm \longrightarrow x + 5 + w - (x + 5) = 2x + 7 - (x + 5) \\ \\ \rm \longrightarrow x - x + 5 - 5 + w = 2x - x + 7 - 5 \\ \\ \rm \longrightarrow w = x + 2[/tex]

[tex] \therefore [/tex] Width of the rectangle (w) = x + 2

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ty!

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