You use a rope 2.00 m long to swing a 10 kg weight around your head. The tension in the rope is 20 N. In half a revolution how much work in J is done by the rope on the weight

The extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

The given parameters;

The radius of the circular path when spring is stretched is calculated as;

R = l₁ + x

R = 0.201 + 0.0176

R = 0.2186 m

The spring constant is calculated as follows;

[tex]F = ma\\\\Kx = \frac{mv^2}{R} \\\\K = \frac{mv^2}{Rx} \\\\K = \frac{(3.41)^2 m}{0.2186 \times 0.0176} \\\\K = 3,022.4 m \ N/m[/tex]

The extension of the spring when the ball is allowed to hang straight down, motionless;

[tex]F = mg\\\\Kx=mg\\\\x = \frac{mg}{K} \\\\x = \frac{9.8 m}{3022.4 m} \\\\x = 0.0032 \ m[/tex]

Thus, the extension of the spring when the ball is allowed to hang straight down, motionless is 0.0032 m.

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The two conditions are:

1) Application of-force on the body.

2) Displacement of the body in the direction of force.

Hope this helps!

Answer:14

Explanation:cuz

Answer:

T = C / R      t = time, C =constant of proportionality, R = rate

180 min = C / 400 gal/min      

C = 72000 gal      to empty tank

T = 72000 gal / 600 gal/min = 120 min = 2 hrs

Answer:

A rogue wave estimated at 18.3 meters (60 feet) in the Gulf Stream off of Charleston, South Carolina. At the time, surface winds were light at 15 knots.

Explanation:

Rogue, freak, or killer waves have been part of marine folklore for centuries, but have only been accepted as real by scientists over the past few decades.

Rogues, called 'extreme storm waves' by scientists, are those waves which are greater than twice the size of surrounding waves, are very unpredictable, and often come unexpectedly from directions other than prevailing wind and waves.

Most reports of extreme storm waves say they look like "walls of water." They are often steep-sided with unusually deep troughs.

Since these waves are uncommon, measurements and analysis of this phenomenon is extremely rare. Exactly how and when rogue waves form is still under investigation, but there are several known causes:

Constructive interference. Extreme waves often form because swells, while traveling across the ocean, do so at different speeds and directions. As these swells pass through one another, their crests, troughs, and lengths sometimes coincide and reinforce each other. This process can form unusually large, towering waves that quickly disappear. If the swells are travelling in the same direction, these mountainous waves may last for several minutes before subsiding.

Focusing of wave energy. When waves formed by a storm develop in a water current against the normal wave direction, an interaction can take place which results in a shortening of the wave frequency. This can cause the waves to dynamically join together, forming very big 'rogue' waves. The currents where these are sometimes seen are the Gulf Stream and Agulhas current. Extreme waves developed in this fashion tend to be longer lived.

Hope this helps, have a nice day/night! :D

On January 1st, 1995, the first accurate measurement of a rogue wave took place. It was captured by a laser detector on Statoil's Draupner oil drilling rig, which is situated 100 miles off the Norwegian coast.

Although rogue, freak, or killer waves have been mentioned in maritime legend for many years, scientists have only recently acknowledged their existence.

Scientists refer to these waves as "rogues," or "severe storm waves," since they are more than twice as large as the waves around them, very unpredictable, and frequently arrive from directions other than the prevailing wind and waves.

Extreme storm waves are typically described as looking like "walls of water" in reports. Frequently, they have steep sides and exceptionally deep valleys.

Measurements and analyses of this phenomenon are extremely rare because these waves are not common.

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It will be

[tex] {m/s}^{2} [/tex]

I am just explaining with the units only, because you want to know the accurate unit.

[tex] \frac{m/s}{s} \\ = \frac{m}{s} \times \frac{1}{s} \\ = \frac{m}{s \times s} \\ = \frac{m}{ {s}^{2} } \\ = {m/s}^{2} [/tex]

Hope you understood.

Do comment if you have any query.

Answer:

combine them all

6 m

Explanation:

Answer:

IF SHE BREATHS SHES A T.H.OT

Explanation:

Pls dont hate me its meme k ,_.

Answer:

Explanation:

The gravitational force = G * m1 * m2 / r^2

That means as the distance increases, r get's bigger and m1 and m2 don't change, the force decreases. Read that sentence carefully. In physics, it is very important to know what goes up and goes down means and especially why.

Answer:

Solar eclipses occur when the Moon passes between Earth and the Sun, leaving a moving region of shadow on Earth's surface. Lunar eclipses occur when Earth passes between the Sun and the Moon, casting a shadow on the Moon. This is an annular eclipse.

(credits to "britannica")

Explanation:

Answer:

well your substitution method is correct but make sure to double check the original formula

This was kinda hard thinking it might be that the new force is going to 4 times bigger than the original one.

Answer:

Explanation:

The current is the same through components connected in series. If you want to measure the current in a component, the ammeter must be placed in series.

__

The voltage is the same at the terminals of components connected in parallel. If you want to measure the voltage across a component, the voltmeter must be connected across the component, that is, in parallel with it.

[tex]\huge \mathbb \pink{ANSWER:}[/tex]

To measure the current through and the voltage across a resistor in a circuit, you should place the ammeter in series with the resistor and the voltmeter in parallel with the resistor.

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Answer:

A. longer days and more direst sunlight

Explanation:

In the Northern Hemisphere, June 21 has longer days and more direct sunlight than December 21, so option A is correct.

Essentially, it alludes to a person's half-divisions. The Earth can be split up into many equal divisions. Latitudinal or longitudinal divisions may be used. Based on a hypothetical equator line, it can be either the northern or Southern Hemisphere, and based on the prime meridian, it can be either the eastern or western hemisphere. When viewed from a latitudinal perspective, the Northern and Southern Hemispheres are essentially hemispheres of the Earth.

The Northern Hemisphere is the region of the Earth that lies above the equator, which is an imaginary line. This hemisphere includes anything that is above this 0° line. It is the half of the planet that has the most people on the planet and more land than water.

The summer solstice falls on June 21 in the Northern Hemisphere and the winter solstice falls on June 21 in the Southern Hemisphere. The solstices are reversed around December 21 and winter officially starts in the Northern Hemisphere.

Therefore, in the Northern Hemisphere, June 21 has longer days and more direct sunlight than December 21.

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Answer:

Increase 9 times

Explanation:

[tex] \huge \bf༆ Answer ༄[/tex]

The given terms in the question are : -

We have been given the task to find out time (t)

The formula that can be used to find time is : -

[tex] \sf \: I = \dfrac{ Q}{t}{} [/tex]

Rearrange the formula,

[tex] \sf \: t = \dfrac { Q}{I }[/tex]

Solve for time (t)

[tex]꧁ \: \large \frak{Eternal \: Being } \: ꧂[/tex]

Answer:

A lever is a simple machine in the subject "S.T.E.M"

Explanation:

Levers use the following forces in order to be used: push or pull.

examples are crow bars,shovels, brooms and ect.

Answer:

speed and acceleration

Explanation:

speed is a scalar quantity

acceleration is a vector quantity

Explanation:

weight =0.454 × 9.8=4.4492N

Answer:

4.45 n sorry if I am wrong

Answer:

Heat is given off by Fire.

Explanation:

Answer:

I believe 0 to V sorry if im wrong

Explanation:

Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

force = mass × acceleration

From the question

mass = 2.5 kg

acceleration = 3.0 m/s²

We have

force = 2.5 × 3.0 = 7.5

We have the final answer as

Hope this helps you

Answer:

Δ-727 or -7.27x10²kJ

Explanation:

ΔV=q-w

(q)= -622

(w)= -105

(both negative because it indicate loss of energy)

ΔV= -622+(-105)

ΔV= -727 kJ

The change in internal energy of the system when it released a heat of 622 kJ and does a work of 105 kJ on the surroundings is -727 kJ.

Internal energy is all the energy contained in an object.

To calculate the change in internal energy of the system, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the change in internal energy of the system when it released a heat of 622 kJ and does a work of 105 kJ on the surroundings is -727 kJ.

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Answer:

V =  1.25E-7 cubic meter

Answer:

Oh its fine i am not in college but its still fine

Explanation:

Answer:

m V1 = (m + M) V2 conservation of momentum

T = time to fall 2 m

2 = 9.8 / 2 T^2    initial vertical velocity zero

T^2 = 4/9.8       T = .639 sec

Sx = V2 * .639 sec     distance traveled horizontally

V2 = 4 /.639 = 6.26 m/sec

V1 = (m + M) / m * 6.26 m/sec       from first equation

V1 = (600 + 10) / 10 * 6.26 m/s = 382 m/s

There seems to be some confusion on units

Note that 382 m/s is a reasonable answer for speed of bullet

1100 ft/sec is reasonable for a .22 cal bullet

1100 ft/sec / 3.28 ft/m = 335 m/sec

Hi there!

We can begin by using the derived kinematic equation:

[tex]t = \sqrt{\frac{2h}{g}[/tex]

Plug in the given values and let g = 9.8 m/s²:

[tex]t = \sqrt{\frac{2(20)}{g}} = \boxed{2.02 s}[/tex]

Now, we can solve for its final velocity using the equation:

[tex]v_f = v_i + at[/tex]

It is dropped from rest, so vi = 0 m/s.

[tex]v_f = at[/tex]

[tex]v_f = 9.8(2.02) = \boxed{19.796 m/s}[/tex]

Answer:

a. The ball would reach the ground in approximately [tex]2.02\; \rm s[/tex].

b. The velocity of the ball right before landing would be approximately [tex]19.8\; \rm m\cdot s^{-1}[/tex].

(Assumptions: the ball was dropped with no initial velocity; air resistance on the ball is negligible; [tex]g = 9.81\; \rm m\cdot s^{-2}[/tex].)

Explanation:

Under these assumptions, the acceleration of this ball would be constantly [tex]a = g = 9.81\; \rm m\cdot s^{-2}[/tex] (same as the gravitational field strength) during the descent.

Displacement of the ball: [tex]x = 20.0\; \rm m[/tex].

Initial velocity of the ball: [tex]v_{0} = 0\; \rm m\cdot s^{-1}[/tex].

Let [tex]t[/tex] denote the duration of this descent.

The SUVAT equation [tex]x = (1/2)\, a\, t^{2} + v_{0}\, t[/tex] relates the known quantities [tex]a[/tex], [tex]x[/tex], and [tex]v_{0}[/tex] to the unknown [tex]t[/tex].

Substitute the known quantities into this equation and solve to find the value of [tex]t\![/tex]:

[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2} + 0\; {\rm m \cdot s^{-1}} \times t[/tex].

[tex]\displaystyle 20.0\; {\rm m} = \frac{1}{2}\times 9.81\; {\rm m\cdot s^{-2}} \times t^{2}[/tex].

[tex]\displaystyle t^{2} = \frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}[/tex].

Since [tex]t > 0[/tex]:

[tex]\begin{aligned}t &= \sqrt{\frac{20.0\; \rm m}{(1/2) \times 9.81\; \rm m\cdot s^{-2}}} \\ &\approx 2.01928\; \rm s\\ &\approx 2.02\; \rm s \\ & (\text{Rounded to 2 sig. fig.})\end{aligned}[/tex].

Since the acceleration of this ball is constant, the velocity of the ball right before landing would be:

[tex]\begin{aligned}v_{1} &= a\, t \\ &\approx 9.81\; \rm m\cdot s^{-2} \times 2.01928\; \rm s \\ &\approx 19.8\; \rm m \cdot s^{-1} \end{aligned}[/tex].

The number of heaters that can safely be operated in the circuit is 5 heaters.

From the question given above, the following data were obtained:

Power of heater = 300 W

Voltage (V) = 110 V

Current (I) = 15 A

Voltage (V) = 110 V

Current (I) = 15 A

P = IV

P = 15 × 110

Thus, the power that can be drawn from the circuit is 1650 W

Power of heater = 300 W

Power of Circuit = 1650 W

[tex]Number \: of \: heaters \: = \frac{power \: of \: circuit}{power \: of \: heater} \\ \\ = \frac{1650}{300} \\ \\ = 5.5[/tex]

From the calculation made above, the number of heaters that can be operated safely in the circuit is 5 heaters.

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