Chemistry High School

You have a stock solution of HNO3 with a concentration of 4.5 x 10^-4 M. However, you need 275 ml of a 2.50 x 10^-5 M solution. How much of the stock solution will you need?

Answers

Answer 1

Answer:

15.28 mL

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M₁) = 4.5x10¯⁴ M

Volume of diluted solution (V₂) = 275 mL

Molarity of diluted solution (M₂) = 2.5×10¯⁵ M

Volume of stock solution (V₁) needed =.?

The volume of the stock solution needed can be obtained by using the dilution formula as illustrated below:

M₁V₁ = M₂V₂

4.5x10¯⁴ × V₁ = 2.5×10¯⁵ × 275

4.5x10¯⁴ × V₁ = 0.006875

Divide both side by 4.5x10¯⁴

V₁ = 0.006875 / 4.5x10¯⁴

V₁ = 15.28 mL

Therefore, the volume of the stock solution needed is 15.28 mL

Related Questions

A student is drinking a cup of hot chocolate as they sit by a campfire on a chilly evening. They know that the cup of hot chocolate transfers thermal energy to the surrounding air. The heated air over their cup of hot chocolate expands and rises and is replaced by cooler, denser air.
This method of energy transfer is —

Answers

Answer:

This method of energy transfer is

Explanation:

Answer:

radiation

Explanation:

radiation is when an existing heat source spreads heat to its surroundings

Someone please answer this...

Answers

Answer:

5446.8 J

Explanation:

From the question given above, the following data were obtained:

Mass (M) = 50 g

Initial temperature (T₁) = 70 °C

Final temperature (T₂) = 192.4 °C

Specific heat capacity (C) = 0.89 J/gºC

Heat (Q) required =?

Next, we shall determine the change in the temperature. This can be obtained as follow:

Initial temperature (T₁) = 70 °C

Final temperature (T₂) = 192.4 °C

Change in temperature (ΔT) =?

ΔT = T₂ – T₁

ΔT = 192.4 – 70

ΔT = 122.4 °C

Finally, we shall determine the heat required to heat up the block of aluminum as follow:

Mass (M) = 50 g

Specific heat capacity (C) = 0.89 J/gºC

Change in temperature (ΔT) = 122.4 °C

Heat (Q) required =?

Q = MCΔT

Q = 50 × 0.89 × 122.4

Q = 5446.8 J

Thus, the heat required to heat up the block of aluminum is 5446.8 J

what water has 97% of water

Answers

Answer:

ocean

Explanation:

because its easy

The answer would be Ocean

Give two limitations of law of Constant Composition

Answers

Answer:

1.The law does not hold true if the different isotopes of the element are involved in making chemical compound.

2.The law is not applicable when elements combine in the same ratio but different compounds are formed.

The photo shows wires made of pure copper, an element
What would the smallest piece of copper be?
A. Copper atom
B. Mixture of different kinds of metallic elements
C. Copper molecule
D. Compound containing two or more elements

Answers

Answer:

Explanation:

I hope its right. I'm pretty sure.

Answer:

Explanation:

Copper Atom

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