x^2+12x-20/3x-5 = x^2+8x+12/2x+3
[tex] \frac{ {x}^{2} + 12x - 20}{3x - 5} = \frac{ {x}^{2} + 8x + 12}{2x + 3} [/tex]
Solution give;;;
Answers
Answer:
In attachment I have answered this problem.
![X^2+12x-20/3x-5 = X^2+8x+12/2x+3[tex] \frac{ {x}^{2} + 12x - 20}{3x - 5} = \frac{ {x}^{2} + 8x + 12}{2x](https://brainimage.s3.us-east-005.backblazeb2.com/answers/attachments/QIg6PJFut6p5lWD1RpwDe8l0Uq2ZDxXY.jpeg)
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Answer:
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