Write the balanced net ionic equation for the reaction of aqueous sodium sulfate with aqueous lead(II) nitrate. Include phases.

net ionic equation:

Answers

Answer 1

Answer:

SO₄²⁻ (aq) + Pb²⁺ (aq) → PbSO₄ (s)

General Formulas and Concepts:

Solubility Rules

Explanation:

Step 1: RxN

Na₂SO₄ (aq) + Pb(NO₃)₂ (aq) → PbSO₄ (s) + NaNO₃ (aq)

Step 2: Balance RxN

Na₂SO₄ (aq) + Pb(NO₃)₂ (aq) → PbSO₄ (s) + 2NaNO₃ (aq)

Step 3: Ionic Equations

Total Ionic Equation:

2Na⁺ (aq) + SO₄²⁻ (aq) + Pb²⁺ (aq) + 2NO₃⁻ → PbSO₄ (s) + 2Na⁺ (aq) + 2NO₃⁻ (aq)

Cancel out spectator ions.

Net Ionic Equation:

SO₄²⁻ (aq) + Pb²⁺ (aq) → PbSO₄ (s)


Related Questions

very
Which of the
following mineral
characteristics are
associated with
gold?
A. it is a compound
B. it is made of many elements
C. it is man made
D. it is a solid

Answers

Answer:

D,B

Explanation:

there are 79 elements in gold

HEEEELLLPPPP PLEASE I WILL MARK BRAINLIEST

Answers

try going to the google app. i don’t know how long it will take for someone to answer this right so you could do that. just make sure when u scan it, that it’s on homework.

Consider the following equilibrium.
NH3(aq) + H2O(l) equilibrium reaction arrow NH4+(aq) + OH −(aq)
What will happen to the equilibrium constant if the concentration of OH − increases through the addition of a small amount of NaOH(aq)?

Answers

Answer:

It will remain the same

Explanation:

The equilibrium constant of the reaction will remain the same if the concentration of the OH is increased.

Changes in concentration values of any of the reactant does not affect the value of the equilibrium constant.

The equilibrium constant is a constant at a given temperature. It is temperature dependent. Since we have no change in temperature, therefore, the equilibrium constant will not change.

The equilibrium constant if the concentration of OH − increases through the addition of a small amount of NaOH(aq) is :

- Remains same.

Equilibrium Reaction

The equilibrium constant of the response will stay the same in case the concentration of the OH is increased.

Changes in concentration values of any of the reactant does not influence the esteem of the equilibrium constant.

The equilibrium constant may be a consistent at a given temperature.

It is temperature dependent. Since we have no alter in temperature.

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The half life of radium-226 is 1600 years.

a. After how many half-lives would 25% of the radium-226 remain.
b. Write a function m(t) that models the mass remaining after years.
c. How much of the sample will remain after 3000 years?
d. After how long will only 15 mg of the sample remain?

Answers

Answer:

Explanation:

a )

half life = 1600 years

50% in 1600 years

25% in next 1600 years

so 25% in total of 3200 years .

b )

disintegration constant = .693 / half life

= .693 / 1600

λ= 4.33 x 10⁻⁴ year⁻¹

m(t) = [tex]m_0e^{-\lambda t }[/tex]

m₀ is initial mass , λ =  4.33 x 10⁻⁴ year⁻¹

c )

m(t) after 3000 years , t = 3000

m(t) = [tex]m_0e^{-4.33\times10^{-4 }\times 3000 }[/tex]

= [tex]m_0e^{-1.3}[/tex]

= .2725 m₀

percentage of mass remaining = 27.25 %

25% radium-226 remain after 3200 years. 6.82 mg of sample remains after 3000 years. 15 mg of the sample will stay long about 1179. 19 years.

Half life of radium-226 = 1600 years

What is half-life?

half-life, in radioactivity, the interval of time required for one-half of the atomic nuclei of a radioactive sample to decay.

Calculation of each part can be done as

a )

half-life = 1600 years

50% in 1600 years

25% in next 1600 years

so 25% in total of 3200 years .

b )

Let decay function is

[tex]m(t) = m_o e^{-kt} \ \ \ \ \ ...(i)\\[/tex]

where k is decay constant

At half life,

[tex]m(t) = \frac{m_o}{2},t= 1600\ years\\So,\ \frac{m_o}{2} = m_oe^{-k1600}\\\frac{1}{2} = e^{-k1600}\\[/tex]

applying log on both sides

[tex]ln \frac{1}{2} = lne^{-1600k}\\-0.693147 = -1600 k \\k =\frac {0.693147}{1600}\\k = 4.332\times10^{-4}\\[/tex]

substitute the value of k in equation (i)

[tex]m(t) = m_oe^{-4.332\times10^{-4t}}\\m(t) = 25e^{-0.0004332t}[/tex]

c) when t = 3000 years

[tex]m(t) = 25e^{-0.0004332t}[/tex]

[tex]m(3000) = 25e^{-0.0004332\times3000}[/tex]

remain sample after 3000 years = 6.82 mg

d) when m(t) = 15 mg

[tex]15 = 25e^{-0.0004332t}\\e^{-0.0004332 t} = \frac{15}{25}\\applying\ log\ on\ both\ side\\ln \ e^{-0.0004332t}=ln(\frac{15}{25)}\\-0.0004332t = -0.510825\\t=\frac{0.510825}{0.0004332}\\t= 1179.19 \ years[/tex]

Hence, this is the required answer.

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What is the pH value of distilled water?

Answers

Answer:

7

Explanation:

The ph level should be 7, but because it absorbs carbon dioxide from the atmosphere it’s actually slightly acidic with a pH of 5.8

A geologist studies rocks. Which of Earth's spheres would a geologist be most interested in?​

Answers

Answer:

Lithosphere

Explanation:

Answer:

ether the crust or lithosphere

Explanation:

Europium orbital diagram

Answers

What are you talking about there’s no question

The Venmo diagram compares protons with electrons. Which shared property belongs in the region marked B?

Answers

Protons and Electrons have one thing in common is electrically charged.
Answer D

How many mL (to the nearest mL) of 0.140-M KF solution should be added to 400. mL of 0.212-M HF to prepare a pH

Answers

Answer:

205mL of 0.140M KF solution

Explanation:

pH = 2.70 solution.

It is possible to obtain the pH of the buffer of HF-KF using the H-H equation:

pH = pKa + log [KF] / [HF]

Where pH is desire pH = 2.70

pKa is pKa of HF = 3.17

[KF] could be taken as moles of KF

And [HF] moles of HF: 400.0mL = 0.4L * (0.212mol/L) = 0.0848 moles of HF

Replacing:

2.70 = 3.17 + log [KF] / [0.0848 moles HF]

-0.47 = log [KF] / [0.0848 moles HF]

0.3388 = [KF] / [0.0848 moles HF]

[KF] = 0.02873 moles of KF must be added.

In mL using concentration of KF (0.140M):

0.02873 moles KF * (1L / 0.140 mol) = 0.205L =

205mL of 0.140M KF solution

Which statement accurate describes plate tectonics?

Answers

Answer:

the lithosphere is broken into sections called plates.

Answer:

The lithosphere is broken into sections called plates.

Explanation:

edge2020

what do y'all girls find attractive on a guy?

Answers

Answer:

alot of things

Explanation:

A binding protein binds to a ligand L with a Kd of 400 nM. What is the concentration of ligand when Y is (a) 0.25, (b) 0.6, (c) 0.95?

Answers: (a) 133.33nm (b) 600nm (c) 7,600nm

Answers above are correct. Please show all steps, really trying to understand.

Answers

Answer:

(a) 133.33nm

(b) 600nm

(c) 7,600nm

Explanation:

The concentration of Y can be determined by using the formula:

[tex]Y = \dfrac{[L]}{k_d+[L]}[/tex]

where;

[L] = concentration of the binding ligand.

kd = 400 nm

Thus:

When Y = 0.25; we get :

[tex]0.25 = \dfrac{[L]}{400+[L]}[/tex]

0.25 (400 + [L]) = [L]

100 + 0.25[L] = [L]

100 = [L] - 0.25 [L]

100 = 0.75 [L]

[L] = 100/0.75

[L] = 133.33 nm

At, Y = 0.6

[tex]0.6 = \dfrac{[L]}{400+[L]}[/tex]

0.6 (400 + [L]) = [L]

240 + 0.6[L] = [L]

240 = [L] - 0.6 [L]

240 = 0.4 [L]

[L] = 240/0.4

[L] = 600 nm

At, Y = 0.95

[tex]0.95 = \dfrac{[L]}{400+[L]}[/tex]

0.95 (400 + [L]) = [L]

380 + 0.95[L] = [L]

380 = [L] - 0.95 [L]

380 = 0.05 [L]

[L] = 380/0.05

[L] = 7600 nm

When sodium atoms (Na) and chlorine atoms (CI) join to make

Answers

Answer: Potassium and fluorine

Explanation:

The two rows form bonds the easiest

Answer: #1

Explanation:

Please help. Will give brainliest.

Answers

Answer:

B.

Explanation:

i think its B

Which element is the most similar to calcium ca

Answers

Answer:

strontium

Explanation:

Answer:

Strontium

Explanation:

This is a earth metal, calcium is a reactive metal that forms a dark oxide nitride layer when exposed to air.

which of the following is an example of
a physical property?

Answers

Answer:

physical property is property that you can touch, smell as it is bumpy it smells like eggs.

Explanation:

YW

Answer:

Physical properties include: appearance, texture, color, odor, melting point, boiling point, density, solubility, polarity, and many others.

Explanation:

pls help!!

The number that represents a neutral pH is ________.​

Answers

Answer:

7

Explanation:

7 is the number that represents a neutral pH

Question 1 (1 point)
A chemical reaction is when substances are changed into other substances.

True or False

Answers

the answer to that is: F A L SE

. Calculate the pH, pOH, Ka, Kb, pKa, and pKb for a 0.082M solution of triethylamine?

Answers

Answer:

pH = 4.40

Explanation:

Calculate the number of C atoms in 0.716 mole of C?

Answers

Answer:

The answer is 4.31 × 10²³ C atoms

Explanation:

The number of C atoms can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 0.716 × 6.02 × 10²³

We have the final answer as

4.31 × 10²³ C atoms

Hope this helps you

In an aqueous solution, a 0.100 M solution of glucose is prepared with a total volume of 0.150 Liters. If the molar mass of glucose is 180.16 g/mol how many grams must the solution contain?

Answers

Answer:

2.70 g of glucose.

Explanation:

The following data were obtained from the question:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Next, we shall determine the number of mole of glucose in the solution. This can be obtained as follow:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Mole glucose =?

Molarity = mole /Volume

0.1 = Mole of glucose /0.15

Cross multiply

Mole of glucose = 0.1 × 0.15

Mole of glucose = 0.015 mole

Finally, we shall determine the mass of glucose in the solution as follow:

Mole of glucose = 0.015 mole

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Mole = mass /molar mass

0.015 = mass of glucose /180.16

Cross multiply

Mass of glucose = 0.015 × 180.16

Mass of glucose = 2.70 g

Therefore, the solution contains 2.70 g of glucose.

The grams that the solution must contain is :

- 2.70 g of glucose.

Mole Concept

Given:

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molar mass of glucose = 180.16 g/mole

Molarity of the glucose solution = 0.1 M

Volume of solution = 0.15 L

Molarity = mole /Volume

0.1 = Mole of glucose /0.15

Mole of glucose = 0.1 × 0.15

Mole of glucose = 0.015 mole

Mole of glucose = 0.015 mole

Molar mass of glucose = 180.16 g/mol

Mass of glucose =.?

Mole = mass /molar mass

0.015 = mass of glucose /180.16

Mass of glucose = 0.015 × 180.16

Mass of glucose = 2.70 g

The solution contains 2.70 g of glucose.

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Calculate the mass percentage of NaClNaCl in a solution containing 1.50 gg of NaClNaCl in 50.0 gg of water.

Answers

Answer:

%m/m = 2.9 %

Explanation:

The mass percentage (m/m %) of a solution is calculated as follows:

m/m % = mass of solute/ mass of solution x 100

The solution is composed by : solute + solvent. In this case, the solute is NaCl and the solvent is water. We have:

mass of solute = 1.50 g

mass of solvent = 50.0 g

mass of solution = mass of solute + mass of solvent = 1.50 g = 50.0 g = 51.5 g

Thus, the mass percentage of NaCl in the solution is :

% m/m = (1.50 g)/(51.5 g) x 100 = 2.91 % ≅ 2.9 %

i need help ):

soo.. help me ! please (:

Answers

23 Sandwiches

Slices of cheese

6 slices of bread

0 slices of cheese

I think this is right.
Hope this helps :)

Answer:

23 Sandwiches

6 slices of bread

0 slices of cheese

Explanation:

brainliest pls:)

Please help I beg you

Answers

Answer:

is highly respect is correct I promise!

8. Which object has molecules that are moving? water in a cup that is not moving, or water in the ocean
PLEASE HELP ASAP!!!

Answers

Answer:

Water in the ocean

Explanation:

The water in the ocean is always moving so all the molecules are was well

11) Nitrogen oxides undergo many interesting reactions in the environment and in industry. Given the following information, calculate H for the overall equation:
2 NO2(g) + 1/2 O2(g) N2O5(s).
N2O5(s) 2 NO(g) + 3/2 O2(g), deltaH = 223.7 kJ

NO2(g) NO(g) + 1/2 O2(g), delataH = 57.1 kJ

delataH = ______kJ

12))))Write all coefficients, even if they are fractions or 1.)
(a) (Apply fractions as needed.)
______ _____(s) + ______ ______ (g) 5 NaCl(s)
(b) (Use the lowest possible coefficients.)
_______ _____ (s) + ______ _____(g) _____CaCl2(s)
(c) (Apply fractions as needed.)
_____ _____(g) _____O3(g)
(d) (Apply fractions as needed.)
______Mg(s) + _____ ______(s) + _____ ____(g) _____Mg3(PO4)2(s)

Answers

Answer:

one more time

Explanation:

shpuld i go

0.954 mol bromine is added to 1 L reaction vessel that contains 1.22 mole of hydrogen and 1 mole of HBr at 1500K. What is the partial pressure of hydrogen, bromine and HBr at equilibrium?

Answers

Answer:

Partial pressure of H₂ →  149.9 atm

Partial pressure of Br₂ → 117.2 atm

Partial pressure of HBr → 112.8 atm

Explanation:

The problem can be solved by the Ideal Gases Law.

In a mixture of gases we know that the sum of partial pressures values the total pressure in the vessel. And the total pressure in the vessel is generated by the total moles which are presennt.

Total moles = 0.954 moles + 1.22 moles + 1 mol = 3.174 moles

Let's apply the Law to determine the total pressure.

P . 1 L = 3.174 moles . 0.082 . 1500 K

P = 390.4 atm

Now we apply the mole fraction concept

Mole fraction (1) →  moles of gas / total moles

Mole fraction (2) → partial pressure of gas / total pressure

In conclussion 1 = 2

Partial pressure of H₂ →  (1.22 / 3.174) . 390.4 atm = 149.9 atm

Partial pressure of Br₂ → (0.954 / 3.174) . 390.4 atm = 117.2 atm

Partial pressure of HBr → (1 / 3.174) . 390.4 atm = 112.8 atm

Suppose that you are a scientist who studies climate changes. While examining the rings of tree trunks, you notice several very large tree rings. What can you conclude about the climate during those years?

Answers

Answer:

The climate was wet and cold

Explanation:

Answer:

The large tree rings allow you to conclude that the climate was either very warm or wet during those growing seasons, because greater than normal growth occurred.

Explanation: It is the edge sample response

How does the number of atoms or molecules in a system affect its thermal energy?
A. A system with fewer atoms and molecules has more thermal energy.
B. A system with more atoms and molecules has more thermal energy.
C. The number of atoms or molecules does not affect the thermal energy of a system.
D. Thermal energy increases as the atoms and molecules in a system move more.

Answers

Answer:

D. Thermal energy increases as the atoms and molecules in a system move more.

Explanation:

Thermal energy is a form of kinetic energy possessed by molecules of a system. The measure of this kinetic energy in an atom is called heat.

The average kinetic energy of a system is the temperature.

According to the kinetic theory, the more the particles move, the more their thermal energy. Thermal energy is often predicated on the velocity of the particles of the medium.

Mineral reaction to stress​

Answers

Answer:

Tenacity describes the reaction of a mineral to stress such as crushing, bending, breaking, or tearing. ... The majority of all minerals are brittle. An example is Quartz. (Minerals that are not brittle may be referred to as Nonbrittle minerals.)

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