Work is done only when..... _ causes an object to _

(a) Your weight in Newtons is 560.7 N.

(b)  Your mass in kilograms is 57.12 kg.

(c) Your weight on the moon is 93.45 N.

a) To convert your weight from pounds to Newtons, we can use the conversion factor that 1 pound is equal to 4.45 Newtons.

Therefore, your weight in Newtons would be:

126 pounds x 4.45 Newtons/pound = 560.7 Newtons

b) To find your mass in kilograms, we can use the formula:

mass (kg) = weight (N) / acceleration due to gravity (m/s²)

The acceleration due to gravity on Earth is approximately 9.81 m/s². Therefore, your mass in kilograms would be:

mass (kg) = 560.7 N / 9.81 m/s² = 57.12 kg

c) The gravitational force between two objects depends on their masses and the distance between them. The gravitational force on the moon is about 1/6th the gravitational force on Earth.

Therefore, if you went to the moon, your weight would be about 1/6th of what it is on Earth.

Your weight on the moon would be:

126 pounds / 6 = 21 pounds

To convert this to Newtons, we can use the conversion factor:

1 pound = 4.45 Newtons

So your weight on the moon in Newtons would be:

21 pounds x 4.45 Newtons/pound = 93.45 Newtons

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The charge on the object is 8.01 x 10^-18 Coulombs.

Q = Ne

where Q is the charge, N is the number of excess or deficit electrons on the object, and e is the elementary charge, which is approximately 1.602 x 10^-19 Coulombs.

Q = 50 x 1.602 x 10^-19 C/electron

Q = 8.01 x 10^-18 C

A charge is a fundamental property of matter that describes the amount of electric energy that a particle possesses. It is a scalar quantity, meaning it has only magnitude and no direction. The charge can be either positive or negative and is measured in Coulombs (C).

Charged particles can interact with each other through electromagnetic force, which is one of the four fundamental forces of nature. Like charges repel each other while opposite charges attract. Electric fields are generated by charged particles, and the force they exert on other charged particles is proportional to the magnitude of their charges.

A charge is conserved in isolated systems, meaning that the total amount of charge in a closed system cannot be created or destroyed, but can only be transferred from one object to another.

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A sample of helium gas occupies 5 liters at 22°C and a gauge pressure of 200,000 pascals. The mass of the gas is 0.16 gm. It is calculated using ideal gas equation.

Define gauge pressure.

When compared to atmospheric pressure, gauge pressure is the pressure that is higher; it is positive for pressures over atmospheric pressure and negative for pressures below atmospheric pressure. Every fluid that is not contained experiences additional pressure due to the atmospheric pressure.

Gauge pressure, which is equal to the difference between absolute and atmospheric pressure and is zero-referenced against ambient air pressure, is the additional pressure in any system relative to atmospheric pressure. The absence of the negative sign serves to distinguish the negative pressure and is typically ignored.

The word "vacuum" can be given a value, and the gauge is referred to as a vacuum gauge. When internal pressure exceeds atmospheric pressure in a given area, the phrase gauge pressure is employed.

Using the formula:

PV = nRT

substituting the values and solving for n:

n = 0.04 moles

mass = 0.04 × 4 = 0.16g

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Answer: 180 Newtons.

Explanation:

The alternate form of Newton's second law states that force (F) is equal to mass (m) multiplied by acceleration (a):

F = m x a

In this problem, the mass of the runner (m) is 90 kg, and the acceleration (a) can be found by dividing the change in velocity (8 m/s) by the time interval (4 s):

a = (8 m/s) / (4 s) = 2 m/s^2

Substituting the values into the equation for force:

F = 90 kg x 2 m/s^2

F = 180 N

Therefore, the net force on the runner is 180 Newtons.

Answer:

it is located at the point directly above the focus

Answer:

D

Explanation:

Answer:

mass

Explanation:

The maximum pressure the rectangular block can exert on a surface when placed on one of its faces on a horizontal surface is 317.71 Pa.

The maximum pressure the rectangular block can exert on a surface occurs when it is placed on one of its smallest faces.

To calculate the maximum pressure, we need to find the weight of the block, which is equal to its mass multiplied by the acceleration due to gravity. The mass of the block can be calculated as follows:

mass = density x volume

The volume of the block is:

volume = length x width x height

volume = 6.0 cm x 8.0 cm x 12.0 cm

volume = 576 cm³

Converting to meters:

volume = 0.006 m x 0.008 m x 0.12 m

volume = 5.76 x 10^-5 m³

Therefore, the mass of the block is:

mass = density x volume

mass = 2700 kg/m³ x 5.76 x 10^-5 m³

mass = 0.1555 kg

The weight of the block is:

weight = mass x acceleration due to gravity

weight = 0.1555 kg x 9.81 m/s²

weight = 1.526 N

When the block is placed on one of its smallest faces, the area of contact with the surface is:

area = length x width

area = 6.0 cm x 8.0 cm

area = 48 cm²

Converting to meters:

area = 0.06 m x 0.08 m

area = 0.0048 m²

Therefore, the maximum pressure the block can exert on the surface is:

pressure = weight / area

pressure = 1.526 N / 0.0048 m²

pressure = 317.71 Pa

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A: The gravity between Earth and the spaceship decreases, B: Gravity obeys the inverse square law, C:   d=2; m=2; m=2,   d=1; m=1; m=2,   d=1; m=1;   m=1,   d=2; m=1; m=2,   d=2; m=1; m=1.

According to Newton's inverse square law, the force of gravity acting between any two objects is inversely equal to the square of the distance between their centres. Altering the separation distance (d) results in a modification in the force of gravity acting between the objects.

The third law of planetary motion, which states that "the square of the time taken for a planet to orbit the sun is directly proportional to the cube of the semi-major axis of the orbit," is where Newton actually got the idea for his inverse square law.

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The correct answer for all questions are: a), b) & c) will be acceleration due to gravity g=9.8 m/s^2, d) 0 m/s, e) 7.644 m/s, f) 2.977 m

A) The acceleration of the ball while it is moving upward is the acceleration due to gravity, which is 9.8 m/s2 in the downward direction.

B) The acceleration of the ball while it is moving downward is also the acceleration due to gravity, which is 9.8 m/s2 in the downward direction.

C) The acceleration of the ball while it is at its maximum height is still the acceleration due to gravity, which is 9.8 m/s2 in the downward direction.

D) The velocity of the ball when it reaches its maximum height is 0 m/s, because it has stopped moving upward and is about to start moving downward.

E) The initial velocity of the ball can be found using the equation v = v0 + at, where v is the final velocity, v0 is the initial velocity, a is the acceleration, and t is the time.

Since the ball is caught at the same height it was released, the final velocity is equal to the initial velocity, but in the opposite direction. Therefore, v = -v0. Plugging in the values for a (9.8 m/s2) and t (1.56 s), we get:

-v0 = v0 + (9.8 m/s2)(1.56 s)

Solving for v0, we get:

v0 = (9.8 m/s2)(1.56 s)/2

v0 = 7.644 m/s

The initial velocity of the ball is 7.644 m/s in the upward direction.

F) The maximum height that the ball reaches can be found using the equation h = v0t + (1/2)at2, where h is the height, v0 is the initial velocity, t is the time, and a is the acceleration.

Plugging in the values for v0 (7.644 m/s), t (1.56 s/2 = 0.78 s), and a (9.8 m/s2), we get:

h = (7.644 m/s)(0.78 s) + (1/2)(9.8 m/s2)(0.78 s)2

h = 2.977 m

The maximum height that the ball reaches is 2.977 m.

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The total angular momentum of the two-disk system after the smaller disk is dropped on the larger disk is [tex]\omega _2 = (I_1\times \omega _1) / (I_1 + m_2 \times r^2)[/tex].

The total angular momentum of the two-disk system after the smaller disk is dropped on the larger one will depend on the initial angular momenta of the two disks and any changes that occur when they collide.

Assuming the system is isolated, the total angular momentum before and after the collision must be conserved. Before the collision, we can assume that the smaller disk has an initial angular momentum of zero since it is not rotating, and the larger disk has an initial angular momentum given by:

[tex]L_1 = I_1 \times \omega_1[/tex]

where [tex]I_1[/tex] is the moment of inertia of the larger disk and ω₁ is its initial angular velocity.

When the smaller disk is dropped onto the larger one, there will be a transfer of angular momentum from the smaller disk to the larger one. The final angular velocity of the combined system will depend on the moment of inertia of the combined system, which can be approximated as:

[tex]I_2  I_1 + m_2 \times r^2[/tex]

Where m_2 is the mass of the smaller disk and r is the distance from the center of the larger disk to the point where the smaller disk makes contact. We assume that the collision is elastic and that no external forces act on the system, so angular momentum is conserved:

[tex]L_1 = L_2[/tex]

[tex]I_1 \times \omega _1 = (I_1 + m_2 \times r^2) \times \omega _2[/tex]

Solving for ω₂, we get:

[tex]\omega _2 = (I_1\times \omega _1) / (I_1 + m_2 \times r^2)[/tex]

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The weight is 1372 N

The weight of an object on Earth can be calculated by using the following formula:

Weight = Mass x Acceleration due to Gravity

Where:

Weight is measured in Newtons (N)

Mass is measured in kilograms (kg)

Acceleration due to Gravity is a constant value

Weight = mass * acceleration due to gravity

Weight = 140 Kg * 9.8

= 1372 N

To calculate the weight of an object on Earth, you need to know its mass.

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The voltage available to operate an overvoltage relay 59G when connected across the grounding resistor is 54 V. The multiple of pickup if 59G minimum operating value is 5.4 V is 10.

An overvoltage relay is a type of protective relay that is used to detect overvoltage conditions on an electrical network. The purpose of this relay is to detect if the voltage on the network exceeds a certain level, which could result in damage to equipment or electrical systems connected to the network. The overvoltage relay is connected to the electrical network in such a way that it monitors the voltage level on the network and is capable of tripping a circuit breaker or other protective device if the voltage level exceeds a preset value.

The voltage available to operate an overvoltage relay 59G when connected across the grounding resistor is 54 V. This is because the grounding resistor limits the voltage to a maximum of 54 volts. If the voltage level on the network.

The multiple of pickup if 59G minimum operating value is 5.4 V is 10. This means that the overvoltage relay will trip if the voltage on the network exceeds 54 volts. If the voltage level on the network is between 5.4 volts and 54 volts, the overvoltage relay will not trip, since the voltage is below the pickup level. However, if the voltage level on the network exceeds 54 volts, the overvoltage relay will trip and disconnect the circuit.

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Answer:

We can use conservation of momentum to solve for the unknown mass of the second box. The total momentum before the collision is equal to the total momentum after the collision.

Before collision:

p = m1v1 = (7 kg)(6 m/s) = 42 kg m/s

After collision:

p = m1v1 + m2v2 = (7 kg)(2 m/s) + m(2 m/s)

Setting the two expressions for momentum equal to each other, we can solve for m2:

42 kg m/s = (7 kg)(2 m/s) + m(2 m/s)

42 kg m/s = 14 kg m/s + 2m kg m/s

28 kg m/s = 2m kg m/s

m = 14 kg

Therefore, the mass of the second box is 14 kg

Here are at least five forces that people may exert from the moment they wake up in the morning to the time they go to sleep:

Gravitational force: This force is exerted on our bodies from the moment we wake up in the morning, keeping us grounded to the surface of the earth. Muscular force: As we move and perform daily activities, our muscles exert force to lift, carry, push, or pull objects. Frictional force: This force is exerted when we walk or run, helping us grip the ground and move forward. Air resistance force: As we move through the air, our bodies and clothing experience air resistance, which can affect our movement and speed. Electrical force: Our nervous system relies on electrical signals to communicate with our muscles and organs, which help us perform various actions throughout the day. These forces may vary depending on the activities a person engages in throughout their day, but they all play a role in the functioning of our bodies and the world around us.

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To calculate the magnitude of the gravitational force exerted by Venus on a 65 kg human standing on the surface of Venus, we use Newton's Law of Universal Gravitation and it will be 6.3 x 10-6 N

This states that the gravitational force (F) between two masses (m1 and m2) separated by a distance (r) is given by the equation:

F = G * (m1 * m2) / r2

Where G is the gravitational constant, which is 6.67 x 10-11 Nm2/kg2. Using this equation and the given values, we have:

F = 6.67 x 10-11 * (4.9 x 1024 * 65) / (6.1 x 106)2

F = 3.3 x 105 N

To calculate the magnitude of the gravitational force exerted by the human on Venus, we use the same equation as before, but with the masses of the human and Venus reversed. This gives:

F = 6.67 x 10-11 * (65 * 4.9 x 1024) / (6.1 x 106)2

F = 4.0 x 10-6 N

For comparison, the approximate magnitude of the gravitational force of the human on a similar human who is standing 3.5 meters away can be calculated using the same equation. The masses of both humans are the same, so we have:

F = 6.67 x 10-11 * (65 * 65) / (3.5)2

F = 6.3 x 10-6 N

To calculate the gravitational force in both cases, we had to make the following approximations or simplifying assumptions:

Treat the humans as though they were points or uniform-density spheres.

Ignore the effects of the Sun, which alters the gravitational force that one object exerts on another

And Treat Venus as though it were spherically symmetric.

We also had to use the same gravitational constant in (a) and (b) despite its dependence on the size of the masses.

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The speed of the bob in a simple pendulum changes every time from A to B. So, its motion can't be a uniform motion. Therefore, the motion of the bob in a simple pendulum is a non-uniform motion.

A simple pendulum is a weight (or bob) suspended from a string or rod, which is free to swing back and forth under the influence of gravity. It is an idealized model used to study the behavior of more complex pendulum systems and has been studied extensively in physics due to its simplicity and ubiquity in everyday life.

The motion of a simple pendulum can be described by a number of variables, including the length of the string, the mass of the bob, the angle at which the pendulum is released, and the amplitude and period of the pendulum's oscillations.

In the absence of friction, the motion of a simple pendulum is governed by the laws of conservation of energy and conservation of momentum.

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Answer:

D: The Moon's orbit is tilted compared

to Earth's orbit, so Earth is not in the

Moon's shadow most months.

D, invisible is not a way light can be transmitted.

Light can be transmitted through a medium such as air, water, glass, or a vacuum. When light is transmitted, it passes through the medium without being absorbed or reflected, allowing it to be seen on the other side of the medium. Transmission of light can occur in a straight line or can be refracted or diffracted, depending on the properties of the medium it is passing through.

Light can be absorbed by a material, which means that the energy of the light is transferred to the material. When this happens, the material may become excited, and the energy can cause a change in the material, such as heating it up, causing it to emit light, or causing a chemical reaction.

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Answer: The wavelength

Explanation:

The speed of a wave is calculated as the product of the frequency times the wavelength.

Hope this helps!!! :)

Part A: The electric potential V at a point on the disk's axis a distance x from the center of the disk is given by:

V = σ/2ε₀ × [tex](R^{2}/(x^{2} +R^{2} )^{1/2})[/tex]

Part B: After calculating for −∂V/∂x we get:

-∂V/∂x = σR²x/2ε₀[tex](x^{2}+R^{2})^{3/2}[/tex]

Part A:

The disc can be split into a number of thin, concentric rings in order to compute the electric potential V at a point on its axis that is located x distance from the disk's centre.

Each ring's potential is determined by:

[tex]V_{ring}[/tex] = 1/4πε₀ × ([tex]Q_{ring}[/tex] /  [tex](x^{2} +R^{2} )^{1/2}[/tex])

where

[tex]Q_{ring}[/tex] is the charge of the ring and

ε₀ is the permittivity of free space.

Since

the disk has uniform surface charge density σ, the charge on each ring is given by:

[tex]Q_{ring}[/tex] = σ × 2πr × dr

where

r is the radius of the ring and

dr is its thickness.

By substituting [tex]Q_{ring}[/tex] into the expression for [tex]V_{ring}[/tex], we get:

[tex]V_{ring}[/tex] = 1/4πε₀ × (σ × 2πr × dr / [tex](x^{2} +R^{2} )^{1/2}[/tex])

By integrating across all the rings, it is possible to get the total potential V at any point along the axis of the disc:

V = ∫V_ring

V = ∫(1/4πε₀ × (σ x 2πr × dr / [tex](x^{2} +R^{2} )^{1/2}[/tex])

V = σ/2ε₀ × ∫(r / [tex](x^{2} +R^{2} )^{1/2}[/tex]) dr from 0 to R

By evaluating the integral and simplifying, we get:

V = σ/2ε₀ × [[tex](R^{2}/(x^{2} +R^{2} )^{1/2})[/tex] - [tex](0/(x^2+0^2)^{1/2})[/tex]]

V = σ/2ε₀ × [tex](R^{2}/(x^{2} +R^{2} )^{1/2})[/tex]

Therefore, the electric potential V at a point on the disk's axis a distance x from the center of the disk is given by:

V = σ/2ε₀ × [tex](R^{2}/(x^{2} +R^{2} )^{1/2})[/tex]

Part B:

To find the value of −∂V/∂x,

The derivative of the equation for V with regard to x must be taken:

∂V/∂x = -σR²x/2ε₀[tex](x^{2}+R^{2})^{3/2}[/tex]

Hence, the expression for −∂V/∂x is:

-∂V/∂x = σR²x/2ε₀[tex](x^{2}+R^{2})^{3/2}[/tex]

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The calculation for the quantity for 1.5 V is simple: 1.5V = 1.5 x 1 = 1.5. The formula for this calculation is V = Voltage x 1, where V is the quantity. The calculation for 1.5V is shown below:

1.5V = 1.5 x 1 = 1.5, By multiplying 1.5 with 1, we get 1.5. This is the calculation for 1.5V.

To understand the calculation of 1.5V better, it is important to first understand the basic unit of electricity - volts. Volts measure the force of electricity in a circuit. It is the amount of electricity that flows through the circuit and is measured in terms of voltage. The higher the voltage, the more electricity is available in the circuit.

To calculate the quantity of electricity for 1.5V, we need to multiply 1.5 with 1. This is the calculation for 1.5V. By multiplying 1.5 with 1, we get 1.5, which is the quantity of electricity for 1.5V.

In conclusion, the calculation for the quantity of electricity for 1.5V is 1.5 x 1 = 1.5. This calculation can be represented using the formula V = Voltage x 1, where V is the quantity.

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Answer:

1st is hydropower

2nd is fossil fuels

Answer:

[tex]a = - \frac{5}{4} \: m{s}^{ - 2}[/tex]

Explanation:

a = acceleration (m/s²)

v = final velocity (m/s) = 0

u = initial velocity (m/s) = 5

t = time (s) = 4

[tex]a = \frac{v - u}{t} \\ a = \frac{(0 - 5)}{4} \\ a = - \frac{5}{4} [/tex]

The set of atoms must also be founding the equations products so that the equation models the law of conservation of mass is option (A) 1 S and 4 O

The law of conservation of mass is a fundamental principle in chemistry that states that the mass of the reactants in a chemical reaction must be equal to the mass of the products. This principle is based on the fact that atoms cannot be created or destroyed in a chemical reaction, and therefore, the number of atoms of each element on both sides of the equation must be the same.

In order to balance a chemical equation and satisfy the law of conservation of mass, it is necessary to adjust the coefficients of the reactants and products to ensure that the number of atoms of each element is equal on both sides of the equation.

Therefore, the correct option is (A) 1 S and 4 O

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The canyon is approximately 258 meters wide.

The speed of sound in air depends on the temperature, and we can use the formula:

v = 331.4 + 0.6T

where;

The speed of sound is:

v = 331.4 + 0.6(27.0)

v = 343.8 m/s

Let's call the distance to one wall "d". When the man fires the shot, the sound travels to the wall, reflects, and returns to the man.

The total distance traveled is 2d. The time it takes for the sound to travel this distance is:

t = 2d/v

Similarly, for the other wall, the total distance traveled is 2(D - d)

where;

The time it takes for the sound to travel this distance is:

t + 1.00 = 2(D - d)/v

We can solve these equations for d and D:

d = vt/2

D = (v/2)(t + 1.00)

Substituting in the values we have:

d = (343.8 m/s)(1.50 s)/2 = 257.85 m

D = (343.8 m/s/2)(1.50 s + 1.00 s) = 515.70 m

Therefore, the width of the canyon is:

D - d = 515.70 m - 257.85 m = 257.85 m

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At 900 rpm, a fan spins. angular speed of the any point on a fan blade and tangential speed of a blade's tip if there is a 20 cm gap between the centre and the tip. 9.4 rads and 18.8 m/s.

Correct option is, C.

A amount or angle rotated (and angular displacement) by a rotating body in a given length of time is known as the angular velocity of the body. The symbol for it is omega (). The formula for angular velocity is rad/s = dtd. Radian per second serves as its SI unit.

The product of a moment of inertia (I) as well as the angular velocity () of the an object in rotation is the angular momentum. A vector quantity is angular momentum. Kg. m2 is the SI unit for angular momentum.

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the answer to the question is pitch

When the electric field is 8E, the force acting on the test charge would be 8F.

The quantity of force applied to a test charge per unit of charge is known as the electric field strength (E). (q). As a result, E = F / q. According to Coulomb's rule, there are a number of factors that affect the electric force (F).

In line with the formula:

Force (F)=Charge x Electric Field

We can use this knowledge to determine the charge on the test charge if it experiences a force of 2F where the electric field is 2E:

2F = q × 2E

q = 2F / 2E

q = F / E

The force acting on the test charge where the electric field is 8E can now be determined using the charge number mentioned above:

Force (F') = Charge (q) x Electric Field (E')

F' = q × E'

F' = (F / E) × 8E

F' = 8F.

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