Answer:
alright i responded
Explanation:
you didnt say i had to answer
Una curva de radio R = 75 [m] tiene un peralte hecho de tal forma que un auto andando a v1 = 35 [m/s] no derrape incluso con el piso congelado (sin roce). ¿Cuál es el coeficiente de roce estático mínimo necesario entre las ruedas y el pavimento para que, en un día seco y soleado, el auto no derrape cuando avanza a v2 = 118 [m/s]?
Answer:
053.
Explanation:
Given that the radius of curvature of the path, R = 75 m.
Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]
The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v on curved path having radiusR
Ris[tex]F_c = mv^2/R[/tex]
Gravitational force, [tex]F_g[/tex] = mg.
Let tha angle of superelevation is [tex]\theta.[/tex]
As the car does not skid even with zero friction, so
[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]
[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]
On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]
As [tex]v_2[/tex] = 118 m/s is greater than v_so the car tends to skid in upper direction and the frictional
force,f, will acts is downward direction.
As there is no skidding, so
[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]
[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]
where [tex]f= \mu N.[/tex]
[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]
Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.
[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]
From equation (ii)
[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]
[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]
[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]
[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]
=0.53
Hence, the minimum coefficient of friction is 0.53.
a motorcycle starts from rest covers 200 meter distance in 6 second calculate final velocity and acceleration
Explanation:
s = ut + 1/2 a t^2
200 = 0 * 6 + 1/2 * a * (6)^2
200 = 1/2 * a * 36
200 = 18 a
a = 200/18
a= 11.1m/sec^2
v = u + at
v = 0 + 11.1 * 6
v = 66.6m/s
hope it helps you
During a laboratory experiment, the temperature of the gas in a balloon is varied and the
volume of the balloon is measured.
A)
Which quantity is the independent variable?
B)
Which quantity is the dependent variable?
Which two elements have similar properties and 8 electrons in their outermost shells?
A. Chlorine and bromine
B. Calcium and strontium
C. Nitrogen and phosphorus
D. Argon and krypton
** THE ANSWER IS D **
Answer:
D
Explanation:
their octet is complete they don't react with any thing
Argon and krypton have similar properties, and they have a complete octet, which means that they do not react with anyone. Hence, option D is correct.
What are inert gases?The phrase "inert gas" is a bit misleading because, in some circumstances, these gases can really be reactive. As a result, these gases are typically referred to as noble gases in the context of chemistry and materials science.
The term "noble" has historically been used in chemistry (and earlier in alchemy) to characterize the resistance of some metals to chemical reaction, and the term "noble gas" denotes the same resistance.
Helium (He)Neon (Ne)Argon (Ar)Krypton (Kr)Xenon (Xe)Radon (Rn)These are the inert gases which are mentioned in the periodic table.
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if a truck goes 30 kilometers in 30 minutes what is the average speed
Answer:
60 km per hour
Explanation:
if you drive for 30 min and go 30km then if you drive for 60 min(1hr) then you would have driven 60km.
Answer:
60
Explanation:
hope this helps
the velocity of a car changes from 5 m/s to 20 m/s in 30 sec the acceleration?
Answer:
0.5m/s2
..............
A truck accelerates from 25 km/hr to 45 km/hr in 40 seconds. Calculate the average acceleration of the vehicle in m/s?.
Answer:
0.138889 m/s2
Explanation:
The average acceleration of the vehicle would be 0.139 meters/second².
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem a truck accelerates from 25 kilometers/hour to 45 kilometers/hour in 40 seconds.
Let us first convert the velocities from kilometers/hour to meters/seconds
25 kilometers/hour ⇒ 25×1000/3600
= 6.94 meters/seconds
45 kilometers/seconds = 45×1000/3600
= 12.5 meters/seconds
acceleration = change in the velocity/time
=(12.5 -6.94)/40
=0.139 meters/second²
Thus, the acceleration of the truck would be 0.139 meters/second²
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What is the voltage drop across the 10.0 Ω resistor?
Answer:
its 120 C
Explanation:
its 120 C
The voltage drop across the 10.0 Ω resistor is c)120V
What is voltage drop in a circuit ?Voltage drop is the decrease of electrical potential along the path of a current flowing in an electrical circuit.
since , all three resistors 10Ω , 20 Ω and 30Ω are in series combination
this implies that voltage drop across each resistor will be same as the total voltage drop in the circuit because in parallel combination voltage remain same in the circuit buy current get divided in each branch
hence , the voltage drop across the 10.0 Ω resistor = 120 V
correct answer c) 120 V
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Please help me out if you want brainliest !!!!! ASAP easy
Answer:
Road A = 8 meters Wet
Road B = 2 meters Muddy
Road C = 12 meters Dry
Explanation:
Question 13 (1 point)
The genetic material of an offspring of sexually reproducing organisms is best described as-
a
Ob
identical to that of the other offspring
a copy of the genetic material of the father.
a copy of The genetic material of the mother
genes from both parents, in unique combinations
ос
Od
The genetic material of an offspring of sexually reproducing organisms is best described as genes from both parents in unique combinations.
SEXUAL REPRODUCTION:
Sexual reproduction is a type of reproduction that involves two organisms (a male and a female). The male organism produces a gamete called SPERM while the female organism produces a gamete called EGG. The gametes are produced via a process called MEIOSIS. Meiosis is a process of cell division whereby genetically different daughter cells are produced. The genetic variation is attributed to a process called crossing over, which is the exchange of genetic material between non-sister chromatids of homologous chromosomes. At the end of the fertilization process between male sperm and female egg, the genetic material of the offspring will contain genes from both parents in unique combinations.Learn more at: https://brainly.com/question/11622266?referrer=searchResults
Please simplify and write the below paragraph.
The field lines due to a current in a
circular coil become straight and
perpendicular to the plane of the coil
at the centre. This is because at every
point of circular loop the concentric
circles representing the magnetic field
become larger and larger as we move
away from the wire.
Field lines become straight and perpendicular because every point of circular loop the concentric circles become larger and larger as we move away from the wire.
While the boys were playing baseball, one of the boys decides to kick his soccer ball high into the air. As the ball goes upward, which type of energy is increasing?
A.) Kinetic Energy
B.) Thermal Energy
C.) Potential Energy
D.) Mechanical Energy
PLZ HELP!!! the moon umbriel orbits uranus (mass = 8.68 x 10^25 kg) at a distance of 2.66 x 10^8 m. what is umbriels orbital speed? (In hours)
Answer:
99.48
Explanation:
99.48
state three ways of conserving energy
energy drinks
sitting
watching TV
Answer:
use natural lights
turn off electrical appliances..if not in use
check your wires every next Month
1. A ball is thrown straight up.if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand?
2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?
Answer:
1) The velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Explanation:
1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:
Position
[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]
[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)
Velocity
[tex]v = v_{o}-g\cdot t[/tex] (2)
Where:
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.
[tex]v[/tex] - Final velocity of the ball, measured in meters per second.
From (1), we get the time when the ball returns to the thrower's hand:
[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]
[tex]t = \frac{2\cdot v_{o}}{g}[/tex]
And then we apply this result in (2):
[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]
[tex]v = -v_{o}[/tex] (3)
Then, the velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:
[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)
If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:
[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]
The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
If a rock is dropped from the top of a tower at the front of it and takes 3.6 seconds to hit the ground. Calculate the final velocity of the penny in m/s. What is the height of the tower?
Answer:
35.28m/s; 63.50m
Explanation:
Given the following data;
Time, t = 3.6 secs
Since it's a free fall, acceleration due to gravity = 9.8m/s²
Initial velocity, u = 0
To find the final velocity, we would use the first equation of motion;
[tex] V = u + at[/tex]
Substituting into the equation, we have;
[tex] V = 0 + 9.8 * 3.6[/tex]
V = 35.28m/s
Therefore, the final velocity of the penny is 35.28m/s.
To find the height, we would use the second equation of motion;
[tex] S = ut + \frac {1}{2}at^{2}[/tex]
Substituting the values into the equation;
[tex] S = 0(3.6) + \frac {1}{2}*9.8*(3.6)^{2}[/tex]
[tex] S = 0 + 4.9*12.86[/tex]
[tex] S = 0.5 *36[/tex]
S = 63.50m
Therefore, the height of the tower is 63.50m.
Meteorites are of three kinds: stones, irons, and stony irons. Each
corresponds to a different part of planet formation. The stones resemble
pieces of planetary crust and mantle, the irons the planet cores, and the
stony irons the transitional area between core and mantle. In some stony
irons, translucent crystalline structures interpenetrate with opaque mantle
rock Collectors sometimes cut stony irons into thin slices and illuminate
them from one side for a gorgeous stained glass effect. Only one per cent
of all meteorites are stony irons. Five per cent are irons, and the remaining
ninety-four per cent are stones. The main function of the paragraph is to:
identify the three kinds of meteorites and provide information about each kind,
describe the chemical structure of the different types of rock found within the
meteorites classified as stones
explain why some meteorites contain both crystalline structures and opaque mantle
rock
list common ways collectors display pieces of meteorites.
Answer:
cookie
Explanation:
Which describes an interaction within the musculoskeletal system?
Answer:
The musculoskeletal system involves the complex interactions of muscles, bones, and connective tissues.
When a muscle contracts, a bone will move. When a bone contracts, a muscle will move. When a ligament contracts, a tendon will move.
Answer:
A. when a muscle contracts , a bone will move
Explanation
thats the correct answer to this question on edg2021 :)
b) A shopkeeper sold a watch for Rs 810 at 10% loss. How much did he pay to
buy the watch?
indir
Answer:
rs 900
Explanation:
the process is given
Which refers to the ratio of output work to input work of a machine expressed as a percent?
total work
wattage
efficiency
power
Answer: C.) Efficiency
Explanation: Edge 2020 good luck ^__^
An airplane is flying with velocity of 70km\hr in north east direction .The wind is blowing 30km\hr from north to south.What is the resultant displacement of the aeroplane in 4 h
Answer:
The resultant displacement of the airplane in 4 hours is 212.8 km.
Explanation:
The components of the airplane's velocity and wind's velocity are:
Airplane:
[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]
[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]
Wind:
[tex] v_{w_{x}} = 0 [/tex]
[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]
Now, to know the new velocity of the airplane we to find the result vector:
[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]
[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]
Now, the magnitude of the new speed of the airplane is:
[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]
Finally, after 4 hours the resultant displacement of the airplane is:
[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]
Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.
I hope it helps you!
Acceleration measures how much the ___________ of an object changes over time.
a) velocity
b) location
Answer: velocity
Explanation: v/t
A car is driving down the road at 35 m/s when the driver slams on the brakes. The car stops in a distance of 75 meters. The braking force necessary to do this is 9,800 Newtons. How much work do the brakes perform stopping the car?
Answer:
If the car is initially travelling at u m/s, then the stopping distance d m travelled by ... the speed of the car at the instant the brakes are applied. ... Common usage will force us to depart from this later in the notes. ... The history of these equations is not absolutely clear, but we do have some ... Newton (1642–1727) and Leibniz.
Explanation:
hope this helped
Definition of uniform speed
Answer:
Uniform Speed: A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. Variable Speed: A body is said to be moving with variable speed if it covers unequal distances in equal intervals of time.
Explanation:
I got it from google
Answer:
Speed is a measure of how fast an object is moving at a given instant of time. It is a scalar quantity. Its unit is m/s. For a body covering equal distances in equal time intervals, the speed is called uniform speed.
Explanation:
What are the ways of heat transfer?
Answer:
Conduction, Convection and Radiation
Explanation:
Hope this helps!
Identify the 3 types of energy transfer shown in the diagram.
Answer:
1.Conduction.
2.Convection.
3.Radiation.
Explanation:
I'm sure it's correct
Pitch describes how high or low a sound is. The pitch of a sound is most dependent upon the of the sound wave.
A.
amplitude
B.
rarefaction
C.
frequency
D.
wavelength
Answer:
The answer is C
Explanation:
A motorcyclist sees a branch in the road and hits the brakes, slowing down at -6.42 m/s. if it takes him 2.85 seconds to stop, what was his starting velocity?
Use the definition of average acceleration:
a = ∆v / t
If v is the starting speed, then ∆v = 0 - v, so solve for v :
-6.42 m/s² = (0 - v) / (2.85 s)
v = (6.42 m/s²) (2.85 s)
v ≈ 18.3 m/s
how can you show that pressure increases with the increase of force?
Answer:
...........................
What is the net force (including direction and magnitude) acting on the object on the above left?
Answer:
Explanation:
the net force on the right left is 25 N and is directed upward
the net force on the left one is zero because 200N force act upward and 200N force act downward so both cancel each other and net force is zero
i hope this will help you
The net force on the right left is 25 N and is directed upward.
The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
By looking at both figure we get idea of net force after calculation,
The net force on the right left is 25 N and is directed upward.
The net force on the left one is zero because 200 N force act upward and 200 N force act downward so both cancel each other and net force is zero.
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