If a gas turned into a solid without going through the liquid state and how do you reverse it?
Answer:
put it in a volcano
Explanation:
Question /
Which object is shown below?
A. Convex mirror
B. Convex lens
C. Concave lens
D. Concave mirror
SLIDNAT
which process of the method a neutral object obtains an. electrical charge
4
What happens because the Earth's orbit
is NOT a perfect circle?
Help Resources
A. We are always the exact same distance away from the
Sun throughout the entire year.
B. At certain timesh during the year, we are closer to the Sun
than at other times.
C. The shape of Earth's orbit does not affect the distance
from the Sun.
which is an example of a scientist using a mathematical model to describe the weather?
A. The scientist finds an equation that predicts how long a rainstorm will last.
B. The scientist says that a lightning bolt is like a long snake.
C. The scientist uses cotton balls to represent clouds, and grass to represent the ground.
D. The scientist thinks of a cloud as a giant ball of cotton candy.
(its A)
Answer:
The scientist finds an equation that predicts how long the rainstrom will last.
Explanation:
I just answered it :)
PLEASE HELPPPPPP <333
Answer:
Explanation:
The answer is c. I am very sure
Answer:
i think its b
Explanation:
im not very sure
The gauge pressure in your car tires is 3.00 ✕ 10^5 N/m2 at a temperature of 35.0°C when you drive it onto a ship in Los Angeles to be sent to Alaska. What is their gauge pressure (in atm) later, when their temperature has dropped to
−42.0°C?
Assume the tires have not gained or lost any air.
Explanation:
Using the ideal gas equation, which I presume you are since you didn't specify using any other EOS, we have PV=nRT. Solving for what changes, i.e. pressure(P) and temperature(T), we have P/T=nR/V. Now, we can set up a relationship between the two pressures and temperatures and solve for what's necessary.
So, we have:
P1/T1=P2/T2
Solving for P2, we have:
P2=(P1*T2)/T1
NOTE: We MUST convert our temperatures to kelvin, otherwise you will end up with a NEGATIVE AND INCORRECT pressure!
Plugging in our values of P1=3.00x10^5 N/m^2, T1 of 308.15K, and T2 of 235.15K. Now we are free to evaluate:
P2=[(3.00x10*5 N/m^2)(235.15K)]/[308.15K]
P2=228930.7156 N/m^2
Or, to the appropriate amount of significant figures: 2.29x10^5 N/m^2
Which makes sense intuitively, as things tend to deflate slightly when the temperature drops!
Hope this helps!
Mark as brainlist...
I WILL REPORT YOU IF YOU ANSWER WITH LINK!!! WILL GIVE BRAINLIEST
You have two identical bowling balls that are 1.00 m apart as measured from their centers. There is an attractive force of gravity between them due to their mass. When a net charge of +0.40 nC is placed on each bowling ball, the force exerted by the electrostatic forces exactly balances the force of gravity on the bowling balls resulting in a net charge of zero. The formula for the electrostatic force is similar to the formula for the gravitational force. There is a constant that is multiplied by the magnitude of each of the two charges and divided by the square of the distance between them. What two conclusions can you draw from this information?
CHOOSE 2 ANSWERS
Answer:
I think is is
Explanation:
B and C why because i have a gut feeling
The sun appears to move across the sky each day. What time of day will the shadow be shortest?
A. Sunrise
B. Noon
C. Sunset
D. Midnight
PLEASE HELP ME IN THE QUESTION ALSO! because I didn't understand
Answer:
3.69 m/s²
Explanation:
weight = mass × Acceleration of gravity
479.96 = 129.72 × Acceleration of gravity
Acceleration of gravity = 479.96/129.72 = 3.69 m/s²
Which sentence best explains the law of conservation of mass as applied to
chemical reactions?
A. The amount of mass changes only slightly during a chemical
reaction.
B. The volumes of the reactants and products are equal during a
chemical reaction.
C. The types of atoms can change during a chemical reaction, but
their masses cannot.
D. In a chemical reaction, the total mass of the reactants equals the
total mass of the products.
Answer:
A. The amount of mass changes only slightly during a chemical
reaction.
5. What is the period of a vertical mass-spring system that has an amplitude of
71.3 cm and maximum speed of 7.02 m/s? The spring constant is 12.07 N/m.
The period of the vertical mass-spring is 0.64 s.
The given parameters:Amplitude of the spring, A = 71.3 cm Maximum speed of the spring, V = 7.02 m/sSpring constant, k = 12.07 N/mThe angular speed of the vertical mass-spring is calculated as follows;
[tex]V_{max} = A \omega\\\\\omega = \frac{V_{max}}{A} \\\\\omega = \frac{7.02}{0.713} \\\\\omega = 9.85 \ rad/s[/tex]
The period of the vertical mass-spring is calculated as follows;
[tex]f = \frac{\omega }{2\pi} \\\\T = \frac{1}{f} \\\\T = \frac{2 \pi}{\omega } \\\\T = \frac{2\pi }{9.85} \\\\T = 0.64 \ s[/tex]
Thus, the period of the vertical mass-spring is 0.64 s.
Learn more about period of oscillation here: https://brainly.com/question/20070798
What does the outer part of the disk turn into?
1) Planets and Moons
2) Interstellar Cloud
3) Planetary Nebula
4) It gets sucked into the star
Answer:
what does the outer part of the disk turn into
Explanation:
4) it gets sucked into the star
An electron moves through a region of crossed electric and magnetic fields. The electric field E = 3059 V/m and is directed straight down. The magnetic field B = 1.14 T and is directed to the left. For what velocity v of the electron into the paper will the electric force exactly cancel the magnetic force?
Answer:
v = 2683.33 m/s
Explanation:
The magnetic force and the electric force on the electron must be the same, in order for them to cancel each other:
[tex]Electric\ Force = Magnetic\ Force\\Eq = qvBSin\theta \\\\v = \frac{E}{BSin\theta}[/tex]
where,
v = velcoity of electron = ?
E = Electric Field = 3059 V/m
B = Magnetic Field = 1.14 T
θ = Angle between velocity and magnetic field = 90°
Therefore,
[tex]v = \frac{3059\ V/m}{(1.14\ T)Sin90^o}[/tex]
v = 2683.33 m/s
Particles q1 = -53.0 uc, q2 = +105 uc, and
q3 = -88.0 uc are in a line. Particles qı and q2 are
separated by 0.50 m and particles q2 and q3 are
separated by 0.95 m. What is the net force on
particle qı?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-53.0 μC
-88.0 C
+105 με
+92
91
93
K 0.50 m
0.95 m
Enter
no
Answer:
[tex]-180.38\ \text{N}[/tex]
Explanation:
[tex]q_1=-53\ \mu\text{C}[/tex]
[tex]q_2=105\ \mu\text{C}[/tex]
[tex]q_3=-88\ \mu\text{C}[/tex]
r = Distance between the charges
[tex]r_{12}=0.5\ \text{m}[/tex]
[tex]r_{23}=0.95\ \text{m}[/tex]
[tex]r_{13}=1.45\ \text{m}[/tex]
k = Coulomb constant = [tex]9\times 10^9\ \text{Nm}^2/\text{C}^2[/tex]
Net force is given by
[tex]F=F_{12}+F_{13}\\\Rightarrow F=\dfrac{kq_1q_2}{r_{12}^2}+\dfrac{kq_1q_3}{r_{13}^2}\\\Rightarrow F=kq_1(\dfrac{q_2}{r_{12}^2}+\dfrac{q_3}{r_{13}^2})\\\Rightarrow F=9\times 10^9\times (-53\times 10^{-6})(\dfrac{105\times 10^{-6}}{0.5^2}+\dfrac{-88\times 10^{-6}}{1.45^2})\\\Rightarrow F=-180.38\ \text{N}[/tex]
The force on the particle [tex]q_1[/tex] is [tex]-180.38\ \text{N}[/tex].
Answer:
The answer sir would be 180.38
Explanation:
Put in 180.38 trust
A helicopter carrying Dr. Evil takes off with a constant upward acceleration of 7.0 m/s2m/s2. Secret agent Austin Powers jumps on just as the helicopter lifts off the ground. After the two men struggle for 11.0 ss, Powers shuts off the engine and steps out of the helicopter. Assume that the helicopter is in free fall after its engine is shut off, and ignore the effects of air resistance. Part A What is the maximum height above ground reached by the helicopter
Answer:
[tex]H_t= 725.8[/tex]
Explanation:
From the question we are told that:
Acceleration of Dr Evil [tex]a=7.0m/s^2[/tex]
Struggle time [tex]t=11s[/tex]
Generally the Newton's equation for Height traveled is mathematically given by
[tex]s = ut +\frac{1}{2} at2[/tex]
[tex]s = 7*121/2[/tex]
[tex]s= 423.25[/tex]
Generally the Newton's equation for Velocity at given time is mathematically given by
[tex]v= u+at \\ v= 0+7*11[/tex]
[tex]v= 77 m/s[/tex]
Generally the Newton's equation for Total Height [tex]H_t[/tex] is mathematically given by
[tex]v^2= u2+2as\\ v^2=772+2x(-9.8)s \\ s = 5929/19.6[/tex]
[tex]s=302.5m[/tex]
Therefore the total height is given as
[tex]H_t=423.3+302.5[/tex]
[tex]H_t= 725.8[/tex]
HELP!!!!
A student did an experiment to determine the
specific heat capacity of an unknown metal.
She heated 1.00 x 10- kg of the metal to 225°C
and quickly placed it in an insulated container
(negligible specific heat capacity) that contained
0.0900 kg of water at a temperature of 18.0°C.
What is the final temperature of the water if the
specific heat capacity of the metal is
2.11 x 102 J/kg.°C?
Answer:
T₂ = 16.83°C
Explanation:
Applying the law of conservation of energy principle here in this situation we get the following equation:
[tex]Energy\ Lost\ by\ Metal = Energy\ Gaine\ by\ Water\\m_{metal}C_{metal}(T_2-T_{1metal}) = m_{w}C_{w}(T_2-T_{1w})[/tex]
where,
T₂ = Final Temperature of Water = Final Temperature of Metal = ?
C_metal = Specififc Heat Capacity of the metal = 2.11 x 10² J/lg.°C
T_1metal = Initial Temperature of Metal = 225°C
m_metal = mass of metal = 1 x 10⁻²[tex](0.01\ kg)(211\ J/kg.^oC)(T_2-225^oC) = (0.09\ kg)(4184\ J/kg.^oC)(T_2-18^oC)\\2.11 T_2 - 474.75 = 376.56T_2 - 6778.08\\374.45T_2 = 6303.33\\[/tex] kg (exponent assumed due to missing info in question)
C_w = Specififc Heat Capacity of the water = 4184 J/lg.°C
T_1w = Initial Temperature of water = 18°C
m_w = mass of water = 0.09 kg
Therefore,
[tex](0.01\ kg)(211\ J/kg.^oC)(T_2-225^oC)=(0.09\ kg)(4184\ J/kg.^oC)(T_2-18^oC)\\\\2.11 - 474.75T_2 = 376.56 - 6778.08T_2\\[/tex]
T₂ = 16.83°C
Question below in photo!! Please answer! Will mark BRAINLIEST! ⬇⬇⬇⬇⬇⬇⬇
its wave length
its wave lenght because how its measure
A small wooden block with mass 0.750 kg is suspended from the lower end of a light cord that is 1.40 m long. The block is initially at rest. A bullet with mass 0.0100 kg is fired at the block with a horizontal velocity v0. The bullet strikes the block and becomes embedded in it. After the collision the combined object swings on the end of the cord. When the block has risen a vertical height of 0.800 m, the tension in the cord is 5.00 N.
Required:
What was the initial speed v0 of the bullet?
Answer:
The initial speed of the bullet will be:
[tex]v_{ib}=331.36\: m/s[/tex]
Explanation:
Using the momentum conservation:
[tex]p_{i}=p_{f}[/tex]
[tex]m_{b}v_{ib}=Mv[/tex] (1)
Where:
M is the mass of the black plus the mass of the bulletv(ib) is the initial velocity of the bulletv is the velocity of the block with the bullet inside.Using the conservation of energy:
[tex]\frac{1}{2}Mv^{2}=\frac{1}{2}Mv_{2}^{2}+Mgh [/tex] (2)
Where v(2) is the speed of the system at 0.8 m of vertical height.
Using the forces acting on the system we can find v(2).
The forces can be equal to the centripetal force:
[tex]T-Mg*sin(\alpha)=M\frac{v_{2}^{2}}{L}[/tex]
α is the angle of T with respect to the horizontal, here α = 25.4°
So, v(2) will be:
[tex]T-Mg*sin(\alpha)=M\frac{v_{2}^{2}}{L}[/tex]
[tex]\frac{L}{M}(T-Mg*sin(\alpha))=v_{2}^{2}[/tex]
[tex]\frac{1.4}{0.76}(5-0.76*9.81*sin(25.4))=v_{2}^{2}[/tex]
[tex]v_{2}=1.82 \: m/s[/tex]
Using this value on equation (2) we will find v.
[tex]v^{2}=v_{2}^{2}+2gh [/tex]
[tex]v^{2}=1.82^{2}+2(9.81)(0.8) [/tex]
[tex]v=4.36\: m/s [/tex]
And finally using equation (1) we can find the initial speed of the bullet.
[tex]m_{b}v_{ib}=Mv[/tex]
[tex]0.01*v_{ib}=0.76*4.36[/tex]
[tex]v_{ib}=331.36\: m/s[/tex]
I hope it helps you!
For an adiabatic process, the change in T is determined by the change in V. In this problem you will compute the contributions to S from the V and T terms separately, then add them up to find the total entropy change for an adiabatic process. Argon gas, initially at pressure 100 kPa and temperature 300 K, is allowed to expand adiabatically from 0.01 m3 to 0.026 m3 while doing work on a piston.
This question is incomplete, the complete question is;
The entropy of an ?-ideal gas changes in the following way as a function of temperature and volume:
ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex]) + ∝nRln(T[tex]_f[/tex]/T[tex]_i[/tex])
For an adiabatic process, the change in T is determined by the change in V. In this problem you will compute the contributions to S from the V and T terms separately, then add them up to find the total entropy change for an adiabatic process.
Argon gas, initially at pressure 100 kPa and temperature 300 K, is allowed to expand adiabatically from 0.01 m³ to 0.026 m³ while doing work on a piston.
1) What is the change in entropy due to the volume change alone, ignoring any effects of changing internal energy? ΔS = ? J/K
2) For this adiabatic expansion, what is the final temperature? T[tex]_f[/tex] = ? K
Answer:
1) the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.
2) the final temperature is 158.66 K
Explanation:
Given the data in the question;
ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex]) + ∝nRln(T[tex]_f[/tex]/T[tex]_i[/tex])
P[tex]_i[/tex] = 100 kPa = 100000 Pa
V[tex]_i[/tex] = 0.01 m³
V[tex]_f[/tex] = 0.026 m³
T[tex]_i[/tex] = 300 K
1) the change in entropy due to the volume change alone
from the question; ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex]) + ∝nRln(T[tex]_f[/tex]/T[tex]_i[/tex])
so change in entropy due to the volume change alone is;
ΔS = nRln(V[tex]_f[/tex]/V[tex]_i[/tex])
we know that, from ideal gas law; PV = nRT
so, nR = P[tex]_i[/tex]V[tex]_i[/tex]/T[tex]_i[/tex] ---- let this be equation 1
∴ ΔS = P[tex]_i[/tex]V[tex]_i[/tex]/T[tex]_i[/tex] × ln(V[tex]_f[/tex]/V[tex]_i[/tex])
we substitute
ΔS = [( 100000 Pa × 0.01 m³) / 300 K ] × ln(0.026m³ / 0.01m³ )
ΔS = 3.185 J/K
Therefore, the change in entropy due to the volume change alone, ignoring any effects of changing internal energy is 3.185 J/K.
2) Final temperature
we know that, in an adiabatic expansion;
[tex]PV^Y[/tex] = K
where Y = 5/3
so
[tex]P_i[/tex][tex]V_i^{(5/3)[/tex] = [tex]P_f[/tex][tex]V_f^{(5/3)[/tex]
[tex]P_f[/tex] = [tex]P_i[/tex][tex]( \frac{V_i}{V_f})^{(5/3)[/tex]
we substitute
[tex]P_f[/tex] = ( 100000 Pa) [tex]( \frac{0.01 m^3}{0.026 m^3})^{(5/3)[/tex]
[tex]P_f[/tex] = 20341.255 Pa
Also from ideal gas law;
PV = nRT
T = PV / nR
so
T[tex]_f[/tex] = P[tex]_f[/tex]V[tex]_f[/tex] / nR
but from equation 1; nR = PV/T
so
T[tex]_f[/tex] = (P[tex]_f[/tex]V[tex]_f[/tex]) / (P[tex]_i[/tex]V[tex]_i[/tex]/T[tex]_i[/tex] )
T[tex]_f[/tex] = ( P[tex]_f[/tex]V[tex]_f[/tex]T[tex]_i[/tex] / P[tex]_i[/tex]V[tex]_i[/tex] )
we substitute
T[tex]_f[/tex] = ( 20341.255 Pa × 0.026 m³ × 300 K) / 100000 Pa × 0.01 m³ )
T[tex]_f[/tex] = 158.66 K
Therefore, the final temperature is 158.66 K
Types of RM radiation that make up the electromagnetic spectrum are microwaves, infrared light, ultraviolet light, X-rays, and gamma rays.
True
False
Answer:
True
Explanation:
The electromagnetic spectrum can be regarded as term that give description of range of light that are in existence, and this range from radio waves up to gamma rays. It can be explained as
range of frequencies that electromagnetic radiation takes with thier respective wavelengths as well as photon energies
The Types of electromagnetic radiation that make up the electromagnetic spectrum are
✓ microwaves
✓ infrared light
✓ ultraviolet light
✓X-rays,
✓gamma rays.
When you are high up in the air you
have
greater potential energy
less potential energy
Answer:
Its Greater potential energy because the air is high up and that makes high energy power
Explanation:
write formula of Plank's constant ,angular momentum, impulse ,stress,Young s modulus.
Answer:
E = hf. Plank's constant
L=mvr Angular momentum
F • t = m • Δ v. Implulse
: σ = F/A Stress
Explanation:
for youngs modulus its in the pictuure
Helppp pls yes or no question
Answer:
yes, should be
Explanation:
This is a hard yes or no question becuase the amplitudes are the same height but in different beating orders.
Answer:
They appear to be about the same height, so the answer is true.
Explanation:
6. Applying Explain how scientists see what early galaxies looked like..
Answer: The younger elliptical and lenticular galaxies had results similar to spiral galaxies like the Milky Way. The researchers found that the older galaxies have a larger fraction of low-mass stars than their younger counterparts.
Explanation:
The ratio of the elements in a binary ionic compound are based on the element's ________________.
Answer:oxidation number
Explanation:
i just took quiz;)
The ratio of the elements in a binary ionic compound are based on the element's oxidation number.
What is Oxidation number?Oxidation number can be generally described as the number which is allocated to the chemical elements in a chemical combination of different compounds. The oxidation number of an element is basically the number or count of electrons that atoms in a molecule can share, lose or gain while they are forming chemical bonds with the other atoms of a different element or atom.
The oxidation state, or oxidation number is the hypothetical charge which is present on an atom if all of the bonds in an atom to different atoms were fully ionic in nature. Oxidation state describes the degree of oxidation of an atom in a chemical compound or molecule. The oxidation state may be positive, negative or zero depending upon the loss or gain of electrons.
Learn more about Oxidation number here:
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A disk of radius 25 cm spinning at a rate of 30 rpm slows to a stop over 3 seconds. What is the angular acceleration? B. How many radians did the disk turn while stopping ? C. how many revolutions?
Answer:
A. α = - 1.047 rad/s²
B. θ = 14.1 rad
C. θ = 2.24 rev
Explanation:
A.
We can use the first equation of motion to find the acceleration:
[tex]\omega_f = \omega_i + \alpha t[/tex]
where,
ωf = final angular speed = 0 rad/s
ωi = initial angular speed = (30 rpm)(2π rad/1 rev)(1 min/60 s) = 3.14 rad/s
t = time = 3 s
α = angular acceleration = ?
Therefore,
[tex]0\ rad/s = 3.14\ rad/s + \alpha(3\ s)[/tex]
α = - 1.047 rad/s²
B.
We can use the second equation of motion to find the angular distance:
[tex]\theta = \omega_it +\frac{1}{2}\alpha t^2\\\theta = (3.14\ rad/s)(3\ s) + \frac{1}{2}(1.04\ rad/s^2)(3)^2[/tex]
θ = 14.1 rad
C.
θ = (14.1 rad)(1 rev/2π rad)
θ = 2.24 rev
A 1.00 x 109 kg object is raised vertically at a
constant velocity of 4.00 m/s by a crane. What
is the power output of the crane?
Answer:
P = 3.92 10¹⁰ W
Explanation:
The power is data by the expression
P = W / t
the work of a force is
W = F. y
the bold ones represent vectors. In this case the displacement is vertical upwards and the vertical forces upwards, therefore the angle is zero and the cos 0 = 1
W = F y
we substitute
P = F y / t
P = F v
as the body rises at constant speed the acceleration is zero and from the equilibrium condition
F -W = 0
F = mg
we substitute
P = m g v
let's calculate
P 1.00 10⁹ 9.8 4
P = 3.92 10¹⁰ W
form
bonds with each other.
There are many kinds of mixtures. Some mixtures are
chunky like a mixture of peanuts and raisins. These
mixtures are called
I
mixtures.
Answer:
Homogeneous mixtures
Explanation:
I think so because homogeneous means mixed mixtures
The Image shows a magnetic field around the poles of a magnet. Identify the areas where the magnetic force is the strongest.
N
Answer:
strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.
Explanation:
The lines of magnetic force are drawn so that the density of lines is proportional to the intensity of the magnetic field.
Therefore, the sections where the magnetic field is strongest are at the points of the north pole and the south pole, specifically between the red box and the letter of each pole.