Which of the following gives the correct range for the graph?

A coordinate plane with a segment going from the point negative 5 comma negative 2 to 0 comma negative 1 and another segment going from the point 0 comma negative 1 to 2 comma 3.

a −5 ≤ x ≤ 2
b −5 ≤ y ≤ 2
c −2 ≤ x ≤ 3
d −2 ≤ y ≤ 3

If a normal distribution has mean of 57 and standard deviation as 20, then the z-score for x=50 is -0.35 .

In order to find the z-score for x=50, we can use the formula : z = (x-μ)/σ ;

Where x is = 50, "μ" is = mean of the distribution , and "σ" is = standard deviation of the distribution ;

In this case , x = 50 , mean(μ) = 57 and standard deviation(σ) = 20;

Substituting in the values,

We get,

⇒ z = (50-57)/20,

Simplifying, We get,

⇒ z = -0.35

So, the z-score for x=50 is -0.35.

Interpretation of the z-score is that :

The z-score represents the number of standard deviations that a given value (in this case, x=50) is from the mean of the distribution (μ=57).

A negative z-score means that the value is below mean. In this case, x=50 is 0.35 standard deviations below the mean of 57.

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The given question is incomplete, the complete question is

A normal distribution has mean of 57 and standard deviation as 20. Find and interpret the z-score for x=50.

A bisector in math is a line or a line segment that divides an angle or a line segment into two equal parts.

The bisector, also known as the perpendicular bisector, is a geometric concept in mathematics that is used to construct a line that is perpendicular to a given segment and passes through its midpoint. The bisector is an important tool in geometry and is used in a variety of applications, including constructing triangles, circles, and finding the circumcenter.

To construct the bisector of a segment, one must first locate the midpoint of the segment. This is done by dividing the length of the segment in half, using a straightedge to connect the two endpoints, and then drawing a perpendicular line through the midpoint. The resulting line is the bisector of the segment.

The bisector has several important properties. First, it is always perpendicular to the segment it bisects. This means that the angle between the bisector and the segment is always 90 degrees. Second, the bisector always passes through the midpoint of the segment. Finally, any point on the bisector is equidistant from the two endpoints of the segment. This means that the bisector can be used to construct other geometric objects that are equidistant from the endpoints of the segment, such as circles.

In summary, the bisector is a line that is perpendicular to a given segment and passes through its midpoint. It is an important tool in geometry and is used in a variety of applications, including constructing triangles, circles, and finding the circumcenter.

Note: This question is in Spanish. Here is the translation to English.

Bisector: the line by which a segment is divided into two parts perpendicularly.

Please explain this.

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The answer is 0.68.b) To find the probability that a randomly selected worker is married but not a college graduate, we need to subtract the probability that the person is married and a college graduate from the probability that the person is married.

The probability that a randomly selected worker is neither married nor a college graduate is the complement of the probability that they are either married or a college graduate. The equation for the complement is 1 - P(A).1 - (0.59 + 0.39 - 0.2)1 - (0.78 - 0.2)0.22. The answer is 0.68.b) To find the probability that a randomly selected worker is married but not a college graduate, we need to subtract the probability that the person is married and a college graduate from the probability that the person is married. The equation is P(A ∩ B) = P(A) × P(B|A).0.591 - 0.196 = 0.394.The answer is 0.394.c) To find the probability that a randomly selected worker is either married or a college graduate, we can use the formula P(A ∪ B) = P(A) + P(B) - P(A ∩ B).0.59 + 0.39 - 0.196 = 0.784.The answer is 0.784.

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5/6

The probability of rolling a sum greater than 12 or a sum that is an odd number after rolling two balanced and fair dice is 47/96.What is the probability of rolling a sum greater than 12 or a sum that is an odd number?The given information says that there are two balanced and fair dice. One is a six-sided die, and the other is an eight-sided die. We need to find the probability of rolling a sum greater than 12 or a sum that is an odd number after rolling the two dice.It's necessary to know the possible outcomes of the dice game when two dice are rolled. The 6-sided die has possible outcomes {1,2,3,4,5,6}, and the 8-sided die has possible outcomes {1,2,3,4,5,6,7,8}.The possible outcomes for each sum from 2 to 14 are shown below in the following table:The sum of the faces is odd if only one of the dice has an even number. In contrast, the sum of the faces is even if both dice have an even number. The red color represents the sum of the faces, which is an odd number, while the blue color represents the sum of the faces, which is an even number. Now we can easily calculate the total number of sums that are either greater than 12 or an odd number. It is important to note that the sum of 2 and 4 is even, and the sum of 13 and 14 is greater than 12. So the total number of sums that are either greater than 12 or an odd number is: 1 + 4 + 1 + 6 + 8 + 8 + 6 + 1 + 4 + 1 = 40It's also necessary to calculate the total number of possible outcomes when rolling two dice. The number of possible outcomes when rolling two dice is 6 x 8 = 48.We now have everything we need to find the probability of rolling a sum greater than 12 or a sum that is an odd number:Probability = Number of favorable outcomes / Total number of possible outcomes= 40/48 = 5/6Therefore, the probability of rolling a sum greater than 12 or a sum that is an odd number is 5/6.

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The square form of the given equation as per quadratic equation is: x²=7.

What is the quadratic equation?

A quadratic equation is an equation where the variable has the highest degree of 2.

Given equation:

⇒ [tex]3x^{2} -12 =9[/tex]

⇒ [tex]3x^{2} -12 -9=0[/tex]

⇒ [tex]3x^{2} -21 =0[/tex]

⇒ [tex]3x^{2} =21[/tex]

⇒  [tex]x^{2} =7[/tex]

Therefore, the square form of the given equation is x² = 7

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Suki spent a total of $17 on rides, food, and parking at the carnival.

The problem states that Suki took $20 to the carnival and spent some portion of it on rides, food, and parking. The first step is to figure out what fractions of her money she spent on each of these things.

The problem tells us that she spent one half of her money on rides, 1/4 of her money on food, and 1/10 of her money on parking. We can write this mathematically and use the multiplication :

Suki spent 1/2 x $20 = $10 on rides

Suki spent 1/4 x $20 = $5 on food

Suki spent 1/10 x $20 = $2 on parking

To find the total amount that Suki spent on rides, food, and parking combined, we simply add up these three amounts:

Total spent = $10 + $5 + $2 = $17

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The approximate angle is $\approx 135^{\circ}$, rounded to the nearest degree

\underset{v}{\rightarrow} - 3\underset{w}{\rightarrow} = (7 \cdot 4, 7 \cdot 2) - (3 \cdot 1, 3 \cdot -3) = (28, 12). The result in component form is (28, 12).

The exact magnitude of \underset{v}{\rightarrow} is $\sqrt{4^2 + 2^2} = \sqrt{20}$ and the exact magnitude of \underset{w}{\rightarrow} is $\sqrt{1^2 + (-3)^2} = \sqrt{10}$.

The dot product \underset{v}{\rightarrow}\cdot \underset{w}{\rightarrow} is (4 \cdot 1) + (2 \cdot -3) = -10.

proj_{\underset{w}{\rightarrow}}(\underset{v}{\rightarrow}) = (\frac{\underset{v}{\rightarrow}\cdot \underset{w}{\rightarrow}}{\Vert \underset{w}{\rightarrow} \Vert^2})\underset{w}{\rightarrow} = (\frac{-10}{10}) \cdot (1, -3) = (-1, 3).

proj_{\underset{v}{\rightarrow}}(\underset{w}{\rightarrow}) = (\frac{\underset{v}{\rightarrow}\cdot \underset{w}{\rightarrow}}{\Vert \underset{v}{\rightarrow} \Vert^2})\underset{v}{\rightarrow} = (\frac{-10}{20}) \cdot (4, 2) = (-2, -1). The results in component form are (-1, 3) and (-2, -1).

The angle between \underset{v}{\rightarrow} and \underset{w}{\rightarrow} can be found using the formula $\cos\theta = \frac{\underset{v}{\rightarrow}\cdot \underset{w}{\rightarrow}}{\Vert \underset{v}{\rightarrow} \Vert \cdot \Vert \underset{w}{\rightarrow} \Vert}$.

Plugging in the values, $\cos\theta = \frac{-10}{\sqrt{20}\cdot\sqrt{10}} = -\frac{1}{\sqrt{2}}$. The exact angle is $\arccos(-\frac{1}{\sqrt{2}})$. Using a calculator, the approximate angle is $\approx 135^{\circ}$, rounded to the nearest degree.

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After answering the presented question, we can conclude that As a equation result, the value of x is 34.

An equation is a mathematical statement that validates the equivalent of two expressions joined by the equal symbol '='. For instance, 2x - 5 = 13. 2x-5 and 13 are two examples of expressions. The character '=' connects the two expressions. An equation is a mathematical formula that has two algebras on each side of an assignment operator (=). It demonstrates the equivalency link between the left and middle formulas. L.H.S. = R.H.S. (left side = right side) in any formula.

We can see from the diagram that PQ is parallel to BC and that the line segments PQ and BC overlap at point O.

As a result, we have:

angle QPO stands for angle. 70° angle = ABC QOP stands for angle. ACB = 110°

angle AOB = angle - 180 ACB - ABC angle = 180 - 70 - 110 = 0

This indicates that points A, O, and B are collinear and that angle AOB is a straight angle, implying that angles AOP and POB are supplementary angles.

We may use this data to calculate the value of x:

AOP angle + POB angle = 180

(3x - 10) + (2x + 20) = 180

5x + 10 = 180

5x = 170

x = 34

As a result, the value of x is 34.

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The amount of copper that is contained in 120 pounds of brass is equal to 78 pounds.

Let the amount of copper be C.

Given the following data:

Quantity of brass = 120 pounds

Percentage of copper = 65%

To calculate the amount of cooper that is contained in 120 pounds of the brass:

In this exercise, you're required to determine how many pounds of copper can be found in 120 pounds of brass. Thus, we would solve for the percentage of copper contained in this type of brass.

[tex]Copper=\frac{65}{100}*120\\\\Copper, c=78 ponds.[/tex]

This is correct because 65% of 120 pounds is equal to 78 pounds. 65% can be expressed as a decimal (0.65) and multiplied by 120 pounds to find the number of pounds of copper contained in 120 pounds of the brass.

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Combination of red and yellow paint that follows the ratio of 3 parts yellow for every 2 parts red will make the shade of orange Lin needs.

Red  Yellow  

2   3

4   6

6   9

8   12

The formula for this specific shade of orange paint is 3 parts yellow for every 2 parts red. To calculate the amounts of red and yellow paint that can be used for different combinations we can use the following equation:

Yellow = 2 x Red/3

For the first combination of 2 parts red and 3 parts yellow, the equation can be written as:

Yellow = (2 x 2)/3

Simplified, that is 2/3, or 3 parts yellow.

For the second combination of 4 parts red and 6 parts yellow, the equation can be written as:

Yellow = (2 x 4)/3

Simplified, that is 4/3, or 6 parts yellow.

For the third combination of 6 parts red and 9 parts yellow, the equation can be written as:

Yellow = (2 x 6)/3

Simplified, that is 8/3, or 9 parts yellow.

For the fourth combination of 8 parts red and 12 parts yellow, the equation can be written as:

Yellow = (2 x 8)/3

Simplified, that is 16/3, or 12 parts yellow.

Therefore, any combination of red and yellow paint that follows the ratio of 3 parts yellow for every 2 parts red will make the shade of orange Lin needs.

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Shandra has cοllected apprοximately 93.67 grams οf the trace element.

The amοunt οf trace element refers tο the tοtal quantity οr mass οf a particular substance οr element that is present in a given sample οr substance. Tο find the amοunt οf trace elements, we can use the fοrmula:

       Amοunt οf trace element = cοncentratiοn × vοlume

where the cοncentratiοn is the amοunt οf the trace element per unit vοlume, and the vοlume is the tοtal vοlume οf the sample.

Here we have

A water sample shοws 0. 066 grams οf sοme trace element fοr every cubic centimeter οf water.

Shandra uses a cοntainer in the shape οf a right cylinder with a radius οf 5. 7 cm and a height οf 13. 9 cm tο cοllect a secοnd sample

As we knοw the vοlume οf a right cylinder, V = πr²h

Substituting the given values, we get:

V = π(5.7 cm)²(13.9 cm)

V = 1419.34 cm³

Since the cοncentratiοn οf the trace element is 0.066 g/cm³,

Find the number οf trace elements in the sample by multiplying the vοlume οf the sample by the cοncentratiοn:

Amοunt οf trace element = cοncentratiοn × vοlume

Amοunt οf trace element = 0.066 g/cm³ × 1419.34 cm³

Amοunt οf trace element = 93.67 g

Therefοre,

Shandra has cοllected apprοximately 93.67 grams οf the trace element.

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The rockets are at a height of 83.15 meters after 1.36 seconds. Rounded to the nearest hundred, this is 83 meters.

To find the moment when the rockets are at the same height, set f(x) = g(x) and solve for x:

-4.9x2 +50x = -4.9x2 +25x + 34

50x = 25x + 34

25x = 34

x = 1.36

Therefore, the rockets are at the same height after 1.36 seconds. To calculate the height, plug x = 1.36 into either function:

f(1.36) = -4.9(1.36)2 +50(1.36)

f(1.36) = -4.9(1.85) + 68

f(1.36) = 83.15 meters

Therefore, the rockets are at a height of 83.15 meters after 1.36 seconds. Rounded to the nearest hundred, this is 83 meters.

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Answer:

28

Step-by-step explanation:

4 cubed means 4 x 4 x 4, which is 64.

6 squared means 6 x 6, which is 36.

So,

4 cubed - 6 squared = 64 - 36 = 28.

On average, slightly more dogs attended the Level 2 class than the Level 1 class.The mean number of dogs attending the Level 1 class was 7.92, and the mean number of dogs attending the Level 2 class was 9.48.

The box plots provided show the results of Julia's two dog training classes. The Level 1 class helps dogs learn the basics, while the Level 2 class focuses on more advanced commands. From the box plots, we can see that the Level 1 class was attended more consistently than the Level 2 class, with the majority of classes having between 5 and 10 dogs attending. The Level 2 class, on the other hand, had more variability in attendance, with some classes having up to 18 dogs and other classes having as few as 3. The median number of dogs attending the Level 1 class was 8, while the median number of dogs attending the Level 2 class was 10. The mean number of dogs attending the Level 1 class was 7.92, and the mean number of dogs attending the Level 2 class was 9.48. This indicates that, on average, slightly more dogs attended the Level 2 class than the Level 1 class.

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We calculate the arc length to be 6.86 inches by rounding to the closest hundredth.

The distance between two places in a curve's section is known as the arc length of a circle. Any portion of a circle's circumference is an arc. The angle formed by the two line segments joining a point to an arc's endpoints at any given position is known as the arc's angle.

An arc with a radius of 18 inches and a centre angle of 22° can be calculated using the formula below:

Arc length = (central angle / 360°) × (2πr)

where r denotes the circle's radius.

Substituting the given values, we get:

Arc length = (22° / 360°) × (2π × 18 inches)

Arc length = (0.0611) × (2π × 18 inches)

Arc length ≈ 6.86 inches

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Landon would need to invest approximately $1,150 to reach a future value of $3,250 in 18 years with an interest rate of 6.6% compounded daily.

To determine how much Landon needs to invest, we can use the compound interest formula, which is:

A = P(1 + r/n)^(nt)

where A is the future value of the account, P is the principal amount (the amount Landon needs to invest), r is the interest rate (in decimal form), n is the number of times the interest is compounded per year, and t is the number of years.

In this case, the interest rate is 6.6% or 0.066, the account is compounded daily, so n = 365, and t = 18. We want to find the principal amount, P, that will result in a future value of $3,250.

Substituting these values into the formula, we get:

3,250 = P(1 + 0.066/365)^(365*18)

Simplifying the right-hand side of the equation, we get:

3,250 = P(1.000181)^6,570

Dividing both sides by (1.000181)^6,570, we get:

P = 3,250 / (1.000181)^6,570

Using a calculator, we can evaluate this expression to find that:

P ≈ $1,150.52

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Answer:

The box alone weighs 6 kg

Step-by-step explanation:

Let, weight of Apple be x, Oranges be y, Guavas be z nd box a.

A box of Apple weighs 270kg and 500g i.e270.5kg

a+x =270.5---(1)

A box of oranges weighs 192.5kg

a+y=192.5---(2)

A box of guavas weighs 245

a+z=245---(3)

Fruits together weigh 690 kg

x+y+z=690---(4)

Combining (1),(2),(3), we get

3a+x+y+z=708---(5)

From 4&5

3a+690=708

3a=18

a=6

So the box weighs 6 kg

Answer:

x = -10

Step-by-step explanation:

Note that it is a isosceles triangle. This means that the base angles (the angles that are not forged by the congruent sides) are congruent.

It is given that one of the angle measurements are 67°, meaning that ∠A would also be equal to 67. Set the equation:

m∠A = x + 77

67 = x + 77

Isolate the variable, x. Subtract 77 from both sides of the equation:

67 (-77) = x + 77 (-77)

x = 67 - 77

x = -10

x = -10 is your answer.

~

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As per the given equation, the beanbag will reach the ground after 1.5 seconds.

To find the time it takes for the beanbag to reach the ground, we need to set h equal to zero, since the beanbag will be on the ground when its height is zero. So we have the equation:

0 = −(2t − 3) − 8t(2t − 3)

We can simplify this equation by factoring out the common factor of (2t − 3):

0 = (2t − 3)(−1 − 8t)

Now we can use the Zero Product Property, which states that if the product of two factors is equal to zero, then at least one of the factors must be zero. So we can set each factor equal to zero and solve for t:

2t − 3 = 0 or −1 − 8t = 0

Solving the first equation for t, we get:

2t = 3

t = 3/2

Solving the second equation for t, we get:

−1 − 8t = 0

8t = −1

t = −1/8

However, we need to discard the negative value of t, because time cannot be negative. So the time it takes for the beanbag to reach the ground is t = 3/2 seconds or 1.5 seconds

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Answer:

[tex]\huge\boxed{\sf 10(9n + 8m)}[/tex]

Step-by-step explanation:

= 90n + 80 m

Common factor = 10

So, the expression becomes:

[tex]\rule[225]{225}{2}[/tex]

Answer: C

Step-by-step explanation: If you factor 10 out of 90n and 80m then you get 9n and 8m for each. to make the equation you get: 10(9n+8n)

Answer:

1.)

[tex]R = 8/17\\S = 15/17[/tex]

2.)

[tex]R = 5/13[/tex]

[tex]S=12/13[/tex]

Step-by-step explanation: sin represents the ratio between a side opposite to an angle and the hypotenuse. It is important to learn these ratios as they allow for you to solve for side lengths in a triangle and angles. We were in this case finding the ratios. A lowercase letter represents a side length opposite to the angle. So to find R we would just need to divide r by t. In the first example, it would just be 16/34 which simplifies to 8/17. Do the same thing for s, and it would be for 30/34 which simplifies to 15/17. Repeat the same steps and you should get 5/13 for R and 12/13 for S.

The area of the equilateral triangle with side length 2cm is approximately 1.73 cm².

An equilateral triangle with side length 2cm can be divided into two right triangles with hypotenuse equal to 2cm and the other two sides of length 1cm each.

We can then use the Pythagorean theorem to find the length of the height of the equilateral triangle, which is also the height of the right triangles.

Let h be the height of the equilateral triangle, then:

h² = 2² - 1²

h² = 3

h = √3

The area of the equilateral triangle can be found using the formula:

Area = (base × height) / 2

Since the equilateral triangle has three equal sides, the base is also equal to 2cm. Therefore, we have:

Area = ( 2 × √3 ) / 2

Area = √3

Rounding to the nearest hundredth, we get:

Area = 1.73 cm²

Therefore, the area of the equilateral triangle is  1.73 cm².

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We get the equation as : 5y + 70 = 395 if  the computer for 5 hours and charged her $70 for parts. The total was $395.

What is Algebraic expression ?

Algebraic expression can be defined as combination of variables and constants.

Let's use the variable "y" to represent the cost of labor per hour.

The technician worked on the computer for 5 hours, so the cost of labor would be 5y. Additionally, the technician charged $70 for parts. The total cost was $395. We can set up the following equation to represent the context:

5y + 70 = 395

This equation represents the total cost Sadie paid for the repair, which includes the cost of labor and parts.

Alternatively, we can use a tape diagram to represent the context. We can draw a rectangle and divide it into two parts, one representing the cost of labor and the other representing the cost of parts. The length of the labor part would be Five times the cost per hour (5y), and the length of the parts part would be $70.

]The length of the whole rectangle would represent the total cost ($395). We can label the unknown cost per hour as "y".

Therefore, we get the equation as : 5y + 70 = 395 if  the computer for 5 hours and charged her $70 for parts. The total was $395.

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The measure of the angle formed by the intersection of the River Line and the Northeast Line is equal to: C. 42°.

In Mathematics, a supplementary angle simply refers to two (2) angles or arc whose sum is equal to 180 degrees.

Additionally, the sum of all of the angles on a straight line is always equal to 180 degrees. In this scenario, we can logically deduce that the sum of the given angles are supplementary angles:

60° + (8x - 18)° + (3x + 6)° = 180°

60° + 8x - 18° + 3x + 6° = 180°

11x = 180° - (18° - 6° - 60°)

11x = 180° - 48°

11x = 132°

x = 132/11

x = 12

For the intersection of the River Line and the Northeast Line, we have:

R = (3x + 6)°

R = 3(12) + 6

R = 36 + 6

R = 42°.

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Complete Question:

What is the measure of the angle formed by the intersection of the River Line and the Northeast Line?

40

41

42

43

Answer: The ball is dropped from a height of 10 ft, so it first travels down 10 ft until it hits the ground. The distance traveled in this first part is 10 ft.

On the first bounce, the ball rebounds to one-fifth of its previous height, which is 2 ft (since 10/5 = 2). The ball then travels up 2 ft and back down 2 ft to the ground, for a total distance traveled of 10 + 2 + 2 = 14 ft.

On the second bounce, the ball rebounds to one-fifth of its previous height, which is 2/5 ft (since 2/5 x 2 = 4/5). The ball then travels up 4/5 ft and back down 4/5 ft to the ground, for a total distance traveled of 2/5 + 4/5 + 4/5 = 2 ft.

On the third bounce, the ball rebounds to one-fifth of its previous height, which is 4/25 ft (since 4/25 x 2/5 = 8/125). The ball then travels up 8/125 ft and back down 8/125 ft to the ground, for a total distance traveled of 4/25 + 8/125 + 8/125 = 0.32 ft (rounded to two decimal places).

The ball will continue to bounce, getting closer and closer to the ground with each bounce. We can calculate the total distance traveled by summing the distances traveled on each bounce:

10 + 14 + 2 + 0.32 + ...

To calculate the sum of this infinite series, we can use the formula for the sum of an infinite geometric series:

S = a / (1 - r)

where S is the sum, a is the first term, and r is the common ratio.

In this case, a = 10 (the distance traveled on the first drop), and r = 1/5 (the fraction by which the height decreases on each bounce). Plugging in these values, we get:

S = 10 / (1 - 1/5)

= 12.5

So the total distance traveled by the ball is 12.5 ft.

Step-by-step explanation:

Jacob's sample suggests that Garrett should expect approximately 80 percentage  of the students in the school to vote for him.

Jacob's sample of 30 students suggests that 24 of them will vote for Garrett, which is an 80% ratio. Applying this ratio to the entire school population, Garrett can reasonably expect that 80% of the students in the school will vote for him. This means that out of the total student population, Garrett can expect approximately 24/30, or 80%, of them to vote for him. This is a useful estimate for how many votes Garrett can expect to receive from the student body. It is important to note, however, that this is only an estimate and may not accurately reflect the actual number of students who will vote for Garrett. Factors such as student opinion or external influences may affect the actual voting results.

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The expected number of applicants who need to be interviewed in order to find the first one with advanced training is 8.

We can calculate this by using the formula for the geometric series. The formula for the geometric series is given by S = a1(1-rn)/1-r, where a1 is the first term in the series, r is the common ratio, and n is the number of terms. In this problem, a1 = 1 (since the probability of finding the first applicant with advanced training is 1/8), and r = 1/8 (since the probability of finding the next applicant with advanced training is 1/8). Thus, plugging these values into the formula yields S = 1(1-(1/8)^n)/1-(1/8) = 8. Therefore, the expected number of applicants who need to be interviewed in order to find the first one with advanced training is 8.

S = a1(1-rn)/1-r

S =[tex]1(1-(1/8)^n)/1-(1/8)[/tex]

S = 8

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We can predict that in 120 tries, we would expect to get heads and an odd number around 30 times. However, it is important to note that this is just a prediction and the actual number of times this occurs may vary due to chance.

When flipping a dime, there are two possible outcomes: heads or tails. Similarly, when rolling a die, there are six possible outcomes: 1, 2, 3, 4, 5, or 6. An odd number is any number that is not divisible by 2, so the odd numbers on a die are 1, 3, and 5.

The probability of flipping heads on a dime is 1/2, and the probability of rolling an odd number on a die is 3/6 or 1/2. To predict how many times you would flip heads and roll an odd number in 120 tries, we can use the multiplication rule of probability.

The multiplication rule of probability states that the probability of two independent events occurring together is the product of their individual probabilities. Since flipping a dime and rolling a die are independent events, we can multiply the probability of flipping heads and the probability of rolling an odd number to get the probability of both events occurring together.

So, the probability of flipping heads and rolling an odd number is:

P(heads and odd) = P(heads) x P(odd)

P(heads and odd) = (1/2) x (1/2)

P(heads and odd) = 1/4

We can estimate that in 120 trials, we should get heads about 30 times and an odd amount about the same. It is crucial to keep in mind that this is only a prediction and that there is a possibility that the actual frequency of occurrence will differ.

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If you add 5 to each data point in a set of data with a mean of 50 and a standard deviation of 10, the mean of the new set of data will become 55. The standard deviation of the new set of data will remain the same at 10.

The term standard deviation is frequently used in statistics to quantify the dispersion or spread of a set of data. The standard deviation is a measure of the amount of variation or dispersion of a set of data values from the mean. Standard deviation is denoted by the symbol s or σ (sigma).

The term mean or arithmetic mean is used in statistics to refer to the value that represents the central tendency of a data set. It is computed by dividing the sum of all data values into a data set by the total number of data points. The formula for computing the mean is given as:

mean = (sum of data values) / (total number of data points)

When you add 5 to each data point in a data set with a mean of 50, the sum of all data values in the data set will increase by (5 * n), where n is the total number of data points. Consequently, the new mean will be given as:

new mean = (sum of new data values) / (total number of data points)

⇒ [(sum of old data values) + (5 * n)] / n ⇒ (50n + 5n) / n ⇒ 55

When you add a constant value to each data point in a data set, the measure of central tendency, i.e., mean, median, and mode will also be shifted by the same constant value. This is because the sum of all data values in the data set increases by the product of the constant value and the total number of data points, n.

The measure of variability or spread, i.e., range, interquartile range, variance, and standard deviation, however, remains the same because it is independent of the location of the data values in the data set. Therefore, adding a constant value to every data point in a data set does not change the spread of the data set but shifts the measure of central tendency to a new value.

Hence, the mean of the new dataset will increase by 5, from 50 to 55, and the standard deviation of the new dataset will remain the same at 10.

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