Which of the following can be used to find the measure of angle C, angle D, and ankle E?

A-Pythagorean Theorem

B-Triangle Sum Theorem

C-Isosceles Triangle Theorem

D-AAA Postulate Theorem

Answer:

Step-by-step explanation:

250 for place  4 for books each.

If they charge 14 per person, 4 of that goes for the books and 10 will be applied to the rental fee.

250/10= 25 people to break even. Any people beyond that  is a profit of 10.00 since the other 4 will still go to the books.

Answer:

20x^2 - 107x - 10.

Step-by-step explanation:

8x - 108x - 10 - (9x^2 + 7x -29x^2)

simplifying:

-100x - 10 - (7x - 20x^2)

20x^2-100x - 7x - 10

20x^2 - 107x - 10

Answer:

−9x

2

+x−8

Step-by-step explanation:

Answer:

-1/2

Step-by-step explanation:

It’s y2 - y1 over x2-x1

- 2 - 3

— - -—-

6 - (-4)

= -5/10

= -1/2

Answer: 1/2

Step-by-step explanation:

Answer:

1/6

Step-by-step explanation:

You're welcome :)

Answer:

undefined

Step-by-step explanation:

Horizontal lines have no slope. The line on the graph is vertical, so we can't really tell what slope it is. But there isn't any run and only rise, therefore the slope is "undefined."

Answer:108 degrees

Step-by-step explanation:

Answer:

Scalene triangle

Step-by-step explanation:

24+48= 72

180-72=108

All three angles are different meaning that the triangle must be a scalene triangle.

Answer:

Please find attached, the required drawing of quadrilateral ABCD and the dilation of quadrilateral ABCD scaled down by a scale factor of 1/3

Step-by-step explanation:

The coordinates of the quadrilateral ABCD are;

A(0, 6), B(6, 6), C(9, 0), D(0, 0)

From the dilation by a scale factor of 1/3, using D as the center of dilation, we have from the attached drawing, the following coordinates of the quadrilateral EFGH as E(0, 2), F(2, 2), G(3, 0) H(0, 0) which is the quadrilateral ABCD scaled down by 1/3

It's B!!!           ik cuz i ggogled it lol

Answer:

I think the answer is B. $92

Step-by-step explanation:

$80 time (115 on calculator will give you 9200

Answer:

-3

Step-by-step explanation:

since it is a gap of 6 the first one gave ...so 3-6=-3

Step-by-step explanation:

subtraction if that wut u askim

Answer:

518

Step-by-step explanation:

P = 2

Q = 8

p3 + 64q

Multiply "p" (which is 2) with 3

Multiply "q" (which is 8) with 8

Add the two numbers you get

And you have you answer

I hope this helps. :)

Answer:

its red okay? i hop help

Answer:3:1. Yellow

Step-by-step explanation:

Answer:

The perimeter of the new TV is approximately  95.32 inches

Step-by-step explanation:

The diagonal dimension of the original TV = 32 inches

The perimeter of the original TV = 87.16 inches

The diagonal dimension of the new TV = 70 inches

The perimeter of the new TV = 87.16 inches

For the original TV, we have;

Let w be the width of the original TV and l be the length of the original TV, we have;

2·w + 2·l = 87.16

√(w² + l²) = 32

Therefore, we have;

32² = w² + l²

w = (87.16 - 2·l)/2

w = 43.58 - l

32² = l² + (43.58 - l)²

l² + (43.58 - l)² - 32² = 0

l² + 43.58² - 2 × 43.85 × l + l² - 32² = 0

2·l² - 87.16·l + 875.2164 = 0

By the quadratic formula, we have;

l = (87.16 ± √((-87.16)² - 4×2 × 875.2164))/(2 × 2)

Therefore, l = 27.89 inches or l = 15.69

Therefore, w = (87.16 - 2·l)/2 = (87.16 - 2× 27.89)/2 = 15.69

or w = (87.16 - 2× 15.69)/2 = 27.89

Whereby the ratio of the width to the length of the original TV and the new TV are the same, we have;

15.69/27.89

w₂/l₂ for the new TV = 15.69/27.89

∴ w₂ = l₂ × 15.69/27.89

w₂² + l₂² = 70²

∴ (l₂ × 15.69/27.89)² + l₂² = 70²

l₂² × (15.69/27.89)² + l₂² = 70²

l₂²((15.69/27.89)² + 1) = 70²

l₂² = 70²/((15.69/27.89)² + 1) = 3722.04

l₂ = √(3722.04) ≈ 61.0

w₂ = l₂ × 15.69/27.89 = 61 × 15.69/27.89 ≈ 34.32

Therefore;

The perimeter of the new TV = 34.32 + 61 = 95.32 inches.

In this exercise we have to use the knowledge and information given to calculate the perimeter that will correspond to:

The perimeter of the new TV is approximately  95.32 inches

So the data for this exercise is from:

Let w be the width of the original TV and l be the length of the original TV, we have;

[tex]2*(w) + 2*(l) = 87.16\\\sqrt{(w^2 + l^2)} = 32[/tex]

Therefore, we have:

[tex]32^2 = w^2 + l^2\\w = (87.16 - 2*l)/2\\w = 43.58 - l\\32^2 = l^2 + (43.58 - l)^2\\l^2 + (43.58 - l)^2 - 32^2 = 0\\l^2 + 43.58^2 - (2 * 43.85 * l)+ l^2 - 32^2 = 0\\(2)*(l)^2 - 87.16*l + 875.2164 = 0[/tex]

By the quadratic formula, we have;

[tex]l = (87.16 +/- \sqrt{((-87.16)^2 - 4*2 * 875.2164))/(2 * 2)} )[/tex]

Therefore:

[tex]w = (87.16 - (2)*(l))/2 = (87.16 - 2* 27.89)/2 = 15.69\\w = (87.16 - 2* 15.69)/2 = 27.89[/tex]

Whereby the ratio of the width to the length of the original TV and the new TV are the same, we have;

w₂/l₂ for the new TV = [tex]15.69/27.89[/tex]

[tex]w_2 = (l_2)* (15.69/27.89)\\w_2^2 + l_2^2 = 70^2\\(l_2 *15.69/27.89)^2 + l^2_2 = 70^2\\l^2_2 * (15.69/27.89)^2 + l^2_2 = 70^2\\l^2_2((15.69/27.89)^2 + 1) = 70^2\\l^2_2 = 70^2/((15.69/27.89)^2 + 1) = 3722.04\\l_2 = \sqrt{(3722.04)} = 61.0\\w_2= l_2 * 15.69/27.89 = 61 * 15.69/27.89 = 34.32\\[/tex]  

The perimeter of the new TV :

[tex]P = 34.32 + 61 = 95.32[/tex]

See more about perimeter at brainly.com/question/6465134

Answer: Water: The battle between the clean vs the dirty :P

Step-by-step explanation:

Answer:

There wouldn't be a fraction form because its a whole number which is 9

The correct format of the question is

After an​ accident, police can use the formula [tex]v=2\sqrt{5L }[/tex] to estimate the​ speed, v, in miles per​ hour, that a car was traveling by measuring the length of the skid​ marks, L, in feet. Estimate the speed of a car that left skid marks 118 ft long. If the posted speed limit is 45 ​mi/h, was the car​ speeding? The speed of a car that left skid marks 118 ft long was about nothing ​mi/h.

Answer:

48.6mi/h, Yes the car was speeding.

Step-by-step explanation:

The speed of the car is given by  [tex]v=2\sqrt{5L }[/tex]

Skid length (L) = 118ft

V= [tex]2\sqrt{5*118}[/tex]

  = 2 [tex]\sqrt{590}[/tex]  

  =  2*24.3

V = 48.6mi/h

Since the speed limit is 45mi/h and the velocity of this driver is 48.6mi/h it is clear that was speeding by 3.6mi/h over speed limit.

Answer:

The drift angle is approximately 7.65° towards the East from the plane's heading

Step-by-step explanation:

The speed of the plane = 350 mph

The direction in which the plane flies N 40° E = 50° counterclockwise from the eastern direction

The speed of the wind = 40 mph

The direction of the wind = S 70° E = 20° clockwise from the eastern direction

The component velocities of the plane are;

[tex]R_{Plane}[/tex] = (350 × cos 50)·i + (350 × sin 50)·j

[tex]R_{Wind}[/tex] = (40 + cos 20)·i - (40 × sin 40)·j

The resultant speed of the plane = [tex]R_{Plane}[/tex] + [tex]R_{Wind}[/tex] = 265.915·i +242.404·j

The direction the plane is heading = tan⁻¹(242.404/265.915) ≈ 42.35°

Therefore, the drift angle = Actual Angle - Direction of the plane = 50 - 42.35 ≈ 7.65° towards the East

Answer: A. 5.89

Step-by-step explanation:

edge2020

Answer:

I think the answer would be A

Answer:

A

Step-by-step explanation:

Answer:

A. 12

Step-by-step explanation:

Answer:

The company manufactures 5 delta cars, 8 beta cars and 12 sigma cars.

Step-by-step explanation:

let in the motor company x number of delta cars, y number of beta cars and z number of sigma cars are manufactured.

from the condition given in the question we can write

9x + 13y + 9z = 257 ........ (1)

4x + 6y + 4z = 116 ........... (2) and    

3x + 4y + z = 59 ......... (3)

From equation (2) we get

9x + 13.5y + 9z = 261 ....... (4) {Multiplying with  both sides}

solving equations (1) and (4) we get

0.5y = 4

and ⇒ y = 8.

from equation (2) putting the value of y we get,  

4x + 4z = 116 - 48 = 68

⇒x + z = 17 .....(5)

Now, from equation (3) putting y = 8 we get,  

3x + z = 59 - 32 = 27 ....... (6)  

hence, solving equations (5) and (6) we get, 17 - x = 27 - 3x

⇒ 2x = 10

⇒ x = 5  

So, z = 17 - x = 12

therefore, the company manufactures 5 delta cars, 8 beta cars and 12 sigma cars.

The no. of apples on the tree today

= The no. of apples on the tree yesterday - 5

Let us take 'the no. of apples on the tree today' as 'x'

and 'the no. of apples on the tree today' as 'y'

Therefore, x = y - 5

Hope this is the thing u are looking for

Step-by-step explanation:

The product is carbon dioxide and water

Answer:

nile blue should be the correct answer

Step-by-step explanation:

Answer:

9

Step-by-step explanation:

formula for inverse proportion is y = [tex]\frac{k}{x}[/tex]

k is the constant of probability

to find k,

y is 12, x is 6

12 = [tex]\frac{k}{6}[/tex]

so x = 12 × 6

∴ k is 72

so y = [tex]\frac{72}{8}[/tex]

∴ y is 9

Answer:

y + (-3) = -8

Step-by-step explanation:

i just know

pls mark branliest

Answer:

34

Step-by-step explanation:

So -9x is 36,36-2=34

Answer:

34

Step-by-step explanation:

-9(-4)-2

36-2

34

Answer:

4t + 8

Step-by-step explanation:

t + 3t = 4t

4t + 8

Answer:

4t+8

Step-by-step explanation:

If you look at your equation t+8+3t you will notice how you have two t parts

part 1: t

part 2: 3t

Since they have the same variable or letter you are able to combine them. When you add them together you get 4t.

Then you just put your 8 back on to the equation! 4t+8

Answer and explanation:

A rectangle's width is longer than the length

And so given a rectangular lawn 4m by 10m,

the width of the lawn= 10m

the length of the lawn= 4m

If a garden of uniform width is added, then garden's width = 10m

The garden of uniform width is added to the width side of the rectangular lawn( since along the combined side length of the lawn and garden, another garden is added)

The garden added to the combined side length of the lawn and garden has width twice that of the garden = 2*10= 20m

Given that total area of the lawn and two gardens = 72m²

Total area of lawn and 2 gardens(Area of rectangle(lawn+2 garden's)) is length * width

= 4*10+ 10*x+ 20*y=72

Therefore equation for total area of lawn and both gardens is 40+10x+20y=72

Where x is length of second garden attached to the width side of the lawn and y is length of the garden attached to the combined length side of the lawn and first garden

x can be solved

40+10x+20y=72

10x+20y=72-40

10x+20y=32

10x=32-20y

x=32-20y/10

Y can be solved

40+10x+20y=72

10x+20y=72-40

10x+20y=32

20y=32-10x

y=32-10x/20