Which input value causes the loop body to execute a 2nd time, thus outputting "In loop" again? { String s = "Go"; while ((!s.equals("q"))&& (!s.equals("")) System.out.println("In loop"); 5 - scnr.nextO;
a) "Quit"
b) "q" only
c) "Q only
d) Either "q" or "Q"

Answer:

a block of data inside the packet

B will cause an error.

Allison needs to declare a type for variable i and use semi-colons.

The for statement should be for(int i = 0; i <=13; i++){

Question:

Vector testGrades contains NUM_VALS test scores. Write a for loop that sets sumExtra to the total extra credit received. Full credit is 100, so anything over 100 is extra credit. Ex: If testGrades = {101, 83, 107, 90}, then sumExtra = 8, because 1 + 0 + 7 + 0 is 8.

#include <iostream>

#include <vector>

using namespace std;  

int main() {

  const int NUM_VALS = 4;

  vector<int> testGrades(NUM_VALS);

  int i = 0;

  int sumExtra = -9999; // Assign sumExtra with 0 before your for loop  

  testGrades.at(0) = 101;

  testGrades.at(1) = 83;

  testGrades.at(2) = 107;

  testGrades.at(3) = 90;

   /* Your solution goes here  */

  cout << "sumExtra: " << sumExtra << endl;

  return 0;

}

Answer:

Replace /* Your solution goes here  */  with the following lines of code

sumExtra = 0;

do{

if(testGrades.at(i) > 100){

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

i++;

}

while(i<NUM_VALS);

Explanation:

In the complete question posted,  the variables sumExtra and i have already been declared an initialized.

So, the first thing we do in the solution is:

set  sumExtra to 0 using sumExtra = 0;

Then iterate through vector testGrades using i as the iterating variable

Here, I made used of a do while loop and the explanation is as follows:

do{

This line checks if current element of the vector is greater than 100

if(testGrades.at(i) > 100){

If yes, the extra digits above 100 is added to the sumExtra

sumExtra = sumExtra + (testGrades.at(i) - 100);

}

The counter is increased, here

i++;

}

The loop is continued while the iterating variable i is less than NUM_VALS which is 4

while(i<NUM_VALS);

import java.util.Scanner;

import java.util.Arrays;

public class JavaApplication30 {

   public static int max(int x, int y, int z){

       int[] arr = {x, y, z};

       Arrays.sort(arr);

       return arr[2];

   }

   public static int min(int x, int y, int z){

       int[] arr = {x, y, z};

       Arrays.sort(arr);

       return arr[0];

   }

   public static double average(int x, int y, int z){

       return  (double) (x + y + z) / 3;

   }

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Enter your first number");

       int x = scan.nextInt();

       System.out.println("Enter your second number");

       int y = scan.nextInt();

       System.out.println("Enter your third number");

       int z = scan.nextInt();

       System.out.println("Min is "+min(x,y,z));

       System.out.println("Max is "+max(x,y,z));

       System.out.println("Average is "+average(x,y,z));

   }

}

I hope this helps! If you have any more questions, I'll try my best to answer them.

Answer: It’s Letter (B) the other ones just don’t fit.

Explanation:

Mark me as brainlest please?!!

Answer:

b

Explanation: