which has the shorter bond lengths in Alkane,alkene and alkynes​

Answers

Answer 1

Answer:

alkanes

Alkynes have the strongest bond. Followed by alkenes and then alkanes. This is because in alkynes there are 3 bonds between at least two carbons


Related Questions

Calculate the amount of energy That an obsect Can absorb from Yellow light Whose wave length is 589 nm.​

Answers

Explanation:

E = hf

c= f × lamda

f= c/ lamda

c= speed of light

f= frequency

lamda = wavelength

E = h c/ lamda

E = 6.626 × 10^-34 Js × 3 × 10^8 ms-1 / 589 × 10^-9 m

= 3.37 × 10^15 J

An unknown hydrocarbon compound was analyzed for hydrogen by elemental analysis and results show that it contains 15.88 % H. What is the empirical formula

Answers

Answer:

C4H9

Explanation:

If H = 15.88%

Then C = 100.00 – 15.88 = 84.12

Divide each % value by respective atomic mass

H = 15.88/1 = 15.88

C = 84.12/12 = 7.01

Divide through by smaller value

H = 15.88/7.01 = 2.26

C = 7.01/7.01 = 1

Remove fraction , multiply by 4

H = 9

C = 4

Empirical formula = C4H9

The hydrocarbon could be ( C4H9)2 = C8H18 = octane.

What do we call the repeating units of a larger molecule?

Answers

Answer:

Brainlest

Explanation:

A polymer is a molecule made up of repeating units. These units, called “monomers”, form a long molecular chain. It might have branches, or it might just be one straight line of molecules, each connected in the same way. A monomer of polyethylene

How much heat is required to increase the temperature of 150 g of water from
38°C -55°C?

Answers

Answer:

-55°C

Explanation:

Bwcause 38°C is gonna make it colder so thats why you should use that.

Help please With this :)))

Answers

Answer: 3

Explanation:

4. The half-life of C-14 is 30 years. If a scientist had 100.0 g at the beginning, how
many grams would be left after 120 years has elapsed?
Half Lives
0
1
2
Time (years)
Amount (grams)
Show table

Answers

Answer:

6,25 gm

Explanation:

4. The half-life of C-14 is 30 years. If a scientist had 100.0 g at the beginning, how

many grams would be left after 120 years has elapsed?

10 years would be 120/30 = 4 half lives0

s0 the fraction of c-14 left would be four (1/2) multiplied together

1/2 X 1/2 X 1/2 X 1/2 = 1/16

SO 1/16 OF THE 100.0 gm would be left

100.0/16  = 6,25 gm

What happens to iron in a bolt as the bolt rusts?
A. It undergoes a chemical change.
O B. It undergoes a physical change
O C. The mass of the atoms decrease
O D. It changes into a different element.
a

Answers

Answer:

it undergoes a chemical change

A mixture of two gases with a total pressure of 2.78 atm contains 0.70 atm of Gas A. What is the partial pressure of Gas B in atm

Answers

Answer:

2.08 atm

Explanation:

Here we use Dalton's Law of Partial Pressures: Pa+Pb=Ptotal. 0.70 atm + Pb = 2.78 atm. To find the missing pressure of gas b we subtract .7 from the 2.78

dentify the parts of the atom that are labeled in the diagram.

Answers

Answer:

Our current model of the atom can be broken down into three constituents parts – protons, neutron, and electrons. Each of these parts has an associated charge, with protons carrying a positive charge, electrons having a negative charge, and neutrons possessing no net charge.

identify key concept/terminologies about solution or concentration of solution?

pls help me

thanks~​

Answers

Answer :

[tex] \: [/tex]

Concentration of Solutions

Recall that a solution consists of two components: solute (the dissolved material) and solvent (the liquid in which the solute is dissolved). The amount of solute in a given amount of solution or solvent is known as the concentration. The two most common ways of expressing concentration are molarity and molality.

Molarity

The molar concentration (M) of a solution is defined as the number of moles of solute (n) per liter of solution (i.e, the volume, V solution):

M = n / V solution

The units of molarity are mol/L, often abbreviated as M.

For example, the number of moles of NaCl in 0.123L of a 1.00M solution of NaCl can be calculated as follows:

[tex]0.123 \: l \: \: of \: solution \: \times \: \frac{1.00 \: mole}{1.00 \: l \: of \: solution \: } \: \\ = 0.123 \: moles[/tex]

Molality :

The molal concentration (m) of a solution is defined as the number of moles of solute (n) per kilogram of solvent (i.e., the mass of the solvent, msolvent):

[tex]m = \frac{n}{v \: solution} [/tex]

For example, the number of moles of NaCl dissolved in 0.123kg of H2O (the solvent), in order to make a 1.00m solution of NaCl, can be calculated as follows:

[tex]0.123 \: kg \: of \: solvent \: = \frac{1.00 \: mole}{1.00 \: kg \: of \: solvent \: } \\ = 0.123 \: moles[/tex]

Hey :3 please help with this. Will mark brainlist if you’re right

Answers

Answer: 4

Explanation:

Recreational drug users often obtain the drug as a white powder with unknown purity. Some users snort the power, whereas others make a solution and take it orally or inject it. To achieve a ketamine high, users usually need to take between 0.1 mg/kg and 1 mg/kg of ketamine. However, taking 2 mg/kg can lead the user to experience a K-hole or to enter an unconscious state.

If the user dissolves exactly 1 g of ketamine in 1/4 cup of water, what is the concentration of ketamine in milligrams per milliliter (mg/mL)? 1 cup=236.5 mL
What volume, in milliliters, of the recreational ketamine in the previous question would a 59.0 kg user need to take to experience a high at 0.600 mg/kg?
How many milliliters would that same user need to take to become unconscious at 2.00 mg/kg?

Answers

If a user dissolves exactly 1 g of ketamine in 1/4 cup of water, the resulting concentration is 16.91 mg/mL. A 59.0 kg user would have to consume 2.09 mL of this solution to experience a high of 0.600 mg/kg. The same user would have to consume 6.98 mL of this solution to become unconscious at 2.00 mg/kg.

Part 1

A user dissolves exactly 1 g of ketamine in 1/4 cup of water.

Given 1 cup = 236.5 mL, the volume of 1/4 cup of water is:

1/4 cup × (236.5 mL/1 cup) = 59.13 mL

1 g of ketamine is dissolved in 59.13 mL of water. The concentration of ketamine, in mg/mL, is:

C = 1000 mg / 59.13 mL = 16.91 mg/mL

Part 2

The volume of this solution that a 59.0 kg user (body mass) would have to consume to experience a high at 0.600 mg/Kg is:

[tex]59.0 kgBM \times \frac{0.600mgKetamine}{1kgBM} \times \frac{1mL Soluiton}{16.91mgKetamine} = 2.09 mL[/tex]

Part 3

The volume of this solution that a 59.0 kg user (body mass) would have to consume to become unconscious at 2.00 mg/kg is:

[tex]59.0 kgBM \times \frac{2.00mgKetamine}{1kgBM} \times \frac{1mL Soluiton}{16.91mgKetamine} = 6.98 mL[/tex]

If a user dissolves exactly 1 g of ketamine in 1/4 cup of water, the resulting concentration is 16.91 mg/mL. A 59.0 kg user would have to consume 2.09 mL of this solution to experience a high of 0.600 mg/kg. The same user would have to consume 6.98 mL of this solution to become unconscious at 2.00 mg/kg.

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list several characteristics of ligroin​

Answers

- Petroleum fraction consisting mostly of [tex]C_{7}[/tex] and [tex]C_{8}[/tex] hydrocarbons

- The fraction is also called heavy naphtha

- Boiling in the range 90‒140 °C

- Ligroin is used as a laboratory solvent

- Ligroin it also esed as a motor fuel or as a solvent for fats and oils in dry cleaning

         [] All of these are different characteristics of ligroin​

         [] If you need more let me know  

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

For the formula shown, how many sulfur atoms are represented?

Answers

Answer:

Your answer would be 6

Answer:

1 it is 1

Explanation:

Very easy science 5th grade WILL MARK As brain list if owned by today

Answers

Answer:

A

Explanation:

According to the chart, A tv turns into heat, light, and sound energy.

What is epoxy?
………………..

Answers

Answer:

Epoxy is the family of basic components or cured end products of epoxy resins.


Any of a class of adhesive plastics or other materials that are polymers of epoxides

agine that you are just outside the International Space Station (ISS) orbiting Earth, working in space. You brought your speaker with you so you could listen to some music while you work. You find the right song, and you hit play. What do you hear? Write your response below in complete sentences. 3) Include the answers to these questions in your response: • Would you hear your music? • Why or why not?

Answers

Answer:

There is no atmosphere outside the space station, so there is nothing to vibrate, therefor there is no sound.you better install your earphones in your space suit.

Explanation:

Imagine that you are just outside the International Space Station (ISS) orbiting Earth, working in space. You brought your speaker with you so you could listen to some music while you work. You find the right song, and you hit play. What do you hear? Write your response below in complete sentences.

Include the answers to these questions in your response: •

Would you hear your music? •

Why or why not?

You need matter that can vibrate and finally vibrate your ear drum in order to transmit sound waves. that you hear

There is no atmosphere outside the space station, so there is nothing to vibrate, therefor there is no sound.you better install your earphones in your space suit.

You will hear no music as there is no sound in the space because there are no molecules to vibrate.

Why no sound in the space?

Sound is generally considered a form of energy that consists of mechanical waves which travel in a medium. Sound is produced by a vibrating body which generates a disturbance in the medium and the medium helps to propagate the sound.

The medium of sound transmission is air where the molecules in the air are in the form of longitudinal waves. The vibrating body generates a disturbance in the rarefaction and compression of waves. The disturbance of the particles of the surrounding medium produces sound.

Sound always requires a medium to be traveled and reach its destination. As space does not have any medium for sound to generate disturbance. Space has a vacuum due to which sound cannot be heard in space.

Therefore, you will hear no music when you play a song in the space.

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Calculate the mass of 5.3 moles of chloric acid (HClO3). Explain the process or show your work by including all values used to determine the answer.

Answers

Answer:

447.64 grams

Explanation:

To find the mass when given moles, it is a pretty simple process.

I start by finding the molar mass of chloric acid, which comes out to 84.46 grams/mol. To find the MM (molar mass), you just take the mass of each element in the molecule from the periodic table and add them all together.

After this, you set up the equation by taking the moles given and multiplying it by the molar mass. This gives you the new value in grams (since we cancelled out the moles). I have attached my work below.

I hope this helps! :^)

The mass of 5.3 moles chloric acid has been 447.85 g.

The mass of 1 mole of a compound has been equivalent to the molar mass of the compound. The molar mass of a compound has been the sum of the constituent atoms in a formula unit.

The molar mass (mwt) of chloric acid has been given as:

[tex]mwt=m_H\;+\;m_C_l\;+\;(m_O\;\times\;3)[/tex]

By substituting the values for the mass of constituent atoms, the molar mass has been given as:

[tex]mwt=1\;+\;35.5\;+\;16\;\times\;3\\mwt=36.5\;+\;48\\mwt=84.5[/tex]

The molar mass of chloric acid has been 84.5 g/mol.

The mass of 1 mole of chloric acid has been 84.5 g/mol. The mass of 5.3 moles chloric acid has been:

[tex]\rm 1\;mol=84.5\;g\\5.3\;mol=5.3\;\times\;84.5\;g\\5.3\;mol=447.85\;g[/tex]

The mass of 5.3 moles chloric acid has been 447.85 g.

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Which one of the following salts has the highest molar solubility in water?

Answers

Answer:

Correct option is

C

Ag

2

CO

3

; K

sp

=6.2×10

−12

(A) For CaCO

3

,S=

Ksp

=

8.7×10

−9

=9.3×10

−5

M

(B) For CuS,S=

Ksp

=

8.5×10

−45

=9.2×10

−23

M

(C) For Ag

2

CO

3

,S=(Ksp/4)

1/3

=(6.2×10

−12

/4)

1/3

=1.15×10

−4

M

(D) For Pb(IO

3

)

2

,S=(Ksp/4)

1/3

=(2.6×10

−13

/4)

1/3

=4×10

−5

M

Hence, Ag

2

CO

3

has the greatest molar solubility in pure water.

The table below provides data about a gas sample. Which of the following can be determined using the data?
Volume 2.0 L
Pressure 3.6 atm
Temperature 323 K
the chemical composition of the gas
the condensation temperature of the gas
the number of moles in the sample
the distance between gas molecules in the sample

Answers

Explanation:

Tabel di bawah ini memberikan data tentang sampel gas. Manakah dari berikut ini yang dapat ditentukan dengan menggunakan data? Volume 2,0 L Tekanan 3,6 atm Suhu 323 K komposisi kimia gas suhu kondensasi gas jumlah mol dalam sampel jarak antar molekul gas dalam sampel

Explanation:

....

해바라기해바라기해바라기해바라기

PLEASE ANSWER ASAP!!!
The movement of tectonic plates in two different locations is shown below:

Two blocks labeled Location A and Location B are shown. The block labeled A has a vertical line in the middle. On the left of the line there is an arrow pointing down. On the right of the vertical line there is an arrow pointing up. At Location B the top layer of the block shows two horizontal arrows pointing towards each other. The portion of this block on the right is shown moving down.
Which statement is most likely true?

Subduction occurs in both locations.

The magnetic orientation of rocks may change in Location A and subduction occurs in Location B.

Subduction occurs in Location A and the magnetic orientation of rocks may change in Location B.

Answers

Answer: its a and b

Explanation:its very simple and the reason is bc yea

Answer:

B

Explanation:

The answer is B because it said subduction i guess. And I got it right! Hope this helps to anyone that is looking at this!

How are sound and light similar? How are they different?

Answers

They are
Both forms of energy that travels in waves

They are different because:
Sound is a mechanical wave
Light is a transverse wave
Light is way faster
Sound has to travel through a medium (substance) but light is electro magnetic (meaning it doesn’t need to travel through anything and it can travel a vacuum e.g light travel in space)

Answer:

Sound requires a medium to move through; light does not.

Sound and light are similar in that both are forms of energy that travel in waves.

Explanation:

Sound and light are similar in that both are forms of energy that travel in waves. They both have properties of wavelength, freqency and amplitude. Sound can only travel through a medium (substance) while light can travel through empty space. Sound is a form of mechanical energy caused by vibrations of matter.

Light waves DO NOT require a medium, they travel fastest in empty space; Sound waves REQUIRE a medium, they travel fastest in dense material like solids. Sound is a longitudinal wave.

A 32.1 mole sample of gas has a temperature of 21 Celsius and a pressure of 2280.0 torr. What is the volume of the gas?

Answers

The volume of the gas is 27 ml

The calculation can be done as follows

The first step is to convert the pressure to atm

convert 2280 tors to atm

760 tors= 1 atm

= 2280/780

= 3 atm

The formula is

PV= nRT

The next step is to write out the parameters

Pressure= 3 atm

Temperature= 21 °C

no of moles= 32.1 mole

volume= ?

(r)constant= 8.314

3 × v= 32.1×8.314×21

3v= 81.080

V= 81.080/3

V= 27 ml

Hence the volume of the gas is 27 ml

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PLEASE HELP
1. A closed bottle contains a mixture of Ar and O2 at 25.3°C. If the partial pressure of Ar in
the bottle is 0.447 atm and the total pressure of the bottle is 1.024 atm, what is the partial
pressure of O2 in the bottle?

Answers

Answer: 0.79 atm

Explanation:

The Ideal Gas Law is PV=nRT.

since both Ar and O2 have the same volume and temperature, the only variable causing the differnce in pressure betwwen the 2 gases is the number of moles

the total pressure = the partial pressure of Ar + the partial  pressure of O2

1.024 atm = 0.447 amt + ?

so  

? = 1.24 -0,447 = 1.24 - 0.45= 0.79 atm

the total pressure of the bottle is 1.024 atm, what is the partial

pressure of O2 in the bottle? is PV

A chemical reaction occurs when _________.

A. Chemical Bonds are build
B. A new substance is created
C. Chemical Bonds are broken
D. All of the Above

Answers

Answer:

C. Chemical Bonds are broken

Explanation:

A chemical reaction occurs when chemical bonds are broken.

Chemical reactions occur when chemical bonds between atoms are formed or broken.

Hope this helps :)

Answer:

c: chemical bonds are broken

Explanation:

the broken bonds then create new bonds, rearranging the atoms into a new substance :)

HELPP
explain the difference between molecular and empirical formulas. Which types of compounds are described by the terms formula mass and molecular mass. Use an example to show the steps in calculating the formula mass for K2CO3

Answers

Answer:

In the previous section, we discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, we were able to determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, we will explore how to apply these very same principles in order to derive the chemical formulas of unknown substances from experimental mass measurements.

Explanation:

tally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound. For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows:

\displaystyle \%\text{H}=\frac{\text{mass H}}{\text{mass compound}}\times 100\%%H=

mass compound

mass H

×100%

\displaystyle \%\text{C}=\frac{\text{mass C}}{\text{mass compound}}\times 100\%%C=

mass compound

mass C

×100%

If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:

\displaystyle \%\text{H}=\frac{2.5\text{g H}}{10.0\text{g compound}}\times 100\%=25\%%H=

10.0g compound

2.5g H

×100%=25%

\displaystyle \%\text{C}=\frac{7.5\text{g C}}{10.0\text{g compound}}\times 100\%=75\%%C=

10.0g compound

7.5g C

×100%=75%

True or false?

Increasing the temperature can help slow down chemical reactions by "burning away" unnecessary molecules

Answers

True because increasing the temperature it gets hotter

4. A student performs four trials of an investigation to determine the boiling point of water. How should the student handle the results?
A. The student should take the average of the minimum and maximum value of the results.
B. The student should use the value that is closest to 100ºC.
C. The student should use the maximum value of the results.
D. The student should take the average of the results from all four trials.

Answers

Answer:

i think its D

Explanation:

In order to get maximum accuracy, student should take average of results from all four trials.

What is accuracy?

Accuracy  in terms of chemistry can be defined as to how close a measurement is to the true value.There are three types of accuracy:

1) Point accuracy-It means accuracy is present at that point of scale only.It does not give any information about the accuracy of the instrument.

2)Percentage of true value--It is the accuracy  which is determined by identifying accuracy of the instrument  and comparing it with the measured true value.

3)Percentage of scale range- It is the accuracy  which determines accuracy of the measurement.

Accuracy in case of instruments  is neglected up  to ±0.5 percent.Accuracy of measurements can be increased by taking multiple measurements and taking into account human errors.

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(50 POINT) use this to answer: https://phet.colorado.edu/sims/html/acid-base-solutions/latest/acid-base-solutions_en.html

Describe how you could adjust the settings of the simulation to increase the number of red (H3O+) and blue (A-) particles in the solution of equilibrium. In three to four sentences, justify your answer and explain how and why this would change the pH of the solution.

Answers

The addition of more acid or base will increase the number of H3O+ and A- particles thereby decreasing and increasing the pH of the solution respectively.

What is an acid-base titration?

An acid-base titration is one in which an acid is added to a given volume of base in order to neutralize it.

When more of acid is added to a solution of a base than is required to neutralize it, the solution becomes acidic.

Similarly, when more base is use to neutralize an acid than is required, the solution becomes alkaline.

In the given simulation, (H3O+) is the acid while (A-) is the base.

By adding increasing the quantity of acid added, the number of H3O+ particles will increase. This will reduce the pH of the solution.

Also, the adding more base to the solution, the number of A- particles in the solution will increase. This will increase the pH of the solution.

Therefore, addition of more acid or base will increase the number of H3O+ and A- particles thereby decreasing and increasing the pH of the solution respectively.

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Ethanol (C₂H₆O) is combusted in air according to the following reaction: C₂H₆O(l) + O₂(g) → CO₂(g) + H₂O(l) How many moles of water would be produced by the complete combustion of 44.5 grams of ethanol in the presence of excess oxygen?

Answers

2.89 moles of water would be produced by the complete combustion of 44.5 grams of ethanol in the presence of excess oxygen.

According to this question, the following reaction between ethanol and oxygen is given:

C₂H₆O(l) + O₂(g) → CO₂(g) + H₂O(l)

However, this equation is not balanced. The balanced equation is as follows:

C₂H₆O + 3O₂ → 2CO₂ + 3H₂O

According to this equation, 1 mole of ethanol produces 3 moles of water.

We convert 44.5g of ethanol to moles by dividing by its molar mass as follows:

mole = 44.5g ÷ 46.07g/mol

mole = 0.966mol of ethanol

If 1 mole of ethanol produces 3 moles of water.0.966mol of ethanol will produce (0.966 × 3) = 2.89mol

Therefore, 2.89 moles of water would be produced by the complete combustion of 44.5 grams of ethanol in the presence of excess oxygen.

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