when the object of mass m2 has descended a distance h, the potential energy of the system has decreased by

(a) The maximum possible acceleration of a car moving down this stretch of track is 2.38 m/s².

(b) The final speed of the car is 8.6 m/s.

The coefficient of friction acting on the inclined surface is calculated by applying the following formula.

μ = tanθ

where;

μ = tanθ

μ = tan (14)

μ = 0.25

The maximum possible acceleration of a car moving down this stretch of track is calculated as follows;

ma = μmg cosθ

a = μg cosθ

a = ( 0.25 x 9.8 m/s² ) x cos (14)

a = 2.38 m/s²

The final speed of the car when accelerating at maximum acceleration is calculated as follows;

s = distance travelled by the car = length of the incline

s = ( 1 m / 3.28 ft )  x ( 51 ft ) = 15.55 m

v² = u² + 2as

where;

v² = 0 + 2as

v² = 2as

v = √ ( 2as )

v = √ ( 2 x 2.38 x 15.55 )

v = 8.6 m/s

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4 cm hose diameter required of an ideal vacuum cleaner that could lift a 11 kg dog off the floor.

The internal diameter of your hose is the measurement across its width. There are two simple methods for measuring this.

Take a ruler to your hose and measure across the interior if you want it to be the same size as what you now have. Alternately, place a paper tube inside the aperture and measure across it.

You might try see if the spray attachment's existing type of fitting would accept that size. It never hurts to double-check, but most fitting like a 1 quick-connect coupler are universal.

The 5/8 diameter is the most prevalent size. It is a generally suitable size for your yard. The flow is also stronger. Using attachments like a hose nozzle, you want to manage that flow. In particular, if you have to lay it down while watering, you don't want to flood your yard. Additionally, it's perfect for filling up the kiddie pool or keeping an eye on your car. It is an excellent all-purpose hose.

Additionally, you'll discover that many hoses with diameters of 3/4 and 1/2 inches, which are slightly smaller than the 5/8 size, will also function well and are great for baskets and container plants. It enables a lovely trickle of water without endangering your sensitive plants.

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Answer: None of the options.

What is energy ?

-- energy, in physics, the capacity for doing work. It may exist in capacities, kinetic, thermal, electrical, chemical, nuclear, or other various forms.

-- There are, moreover, heat and work—i.e., energy in the process of transfer from one body to another

When we talk about uniform circular motion (constant speed) we yet have a changing velocity and therefore, acceleration.

How is this possible?

-- Well, velocity is a vector, and as a vector it has magnitude (the speed) and direction.

--  So, while an object performs a uniform circular motion, althought its speed is not changing, its direction does change.

-- And, since acceleration  is the variation of velocity  in time  , certainly there is acceleration here.

On the other hand, Inertia  is mathematically expressed as:

This means that for a system with a given axis of rotation and a given total mass , the greater the distance from the axis  to the object that performs the circular motion, the greater the inertia.

This also means that inertia depends directly on the mass of the system and the radius of the circular motion, therefore, as long as these elements exist, in a circular motion the inertia will always be different from zero.

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The  distance from the end of the pipe is the point where the stream of water meets the creek is 1.52 m.

The time taken for the water to fall from the given height is calculated as follows;

t = √ ( 2h / g )

where;

t =  √ ( 2 x 3.1 / 9.8 )

t = 0.8 s

The horizontal distance travelled by the stream of water is calculated as;

x = vt

x = 1.9 m/s  x 0.8 s

x = 1.52 m

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Simple machines are advantageous because they lessen labor requirements or enable people to undertake things that would otherwise be beyond their capacity.

The airplane, wedge, screw, lever, pulley, and wheel-and-axle are the six most typical simple machines. They are made to change the direction or strength of the force (remember that work is equal to force times distance), which makes the task easier to complete.

Simple machines including the axle, wheel and axle, pulleys, inclined plane, screw, wedge, and lever are frequently utilized. Although simple machines may increase or decrease the forces which can be applied on them, they have no effect on the overall amount of work required to complete the activity.

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The fox which is fleeing from a hunter encounters a 0.745 m tall fence and this fox can clear the fence with a height of up to 0.895 meters.

Velocity can be defined as the rate of change in the displacement of an object. It is a vector quantity as it has both the magnitude and direction. The change in velocity of an object is known as acceleration.

Given,

Initial velocity (u) = 7.50 m/s

Launch angle, θ = 45°

Height of fence = 0.745 m

Trajectory of Projectile is given by:

y = x tanθ - gx²/ 2u²cos²θ

For x = 1.99 m  

y = 1.99 × tan 45° - 9.8 × (1.99)²/ 2 × (7.5)² × (cos45°)²  

y = 1.99 × 1 - 9.8 × 3.96/ 2 × 56.25 × (1)²

y = 1.99 - 38.80/112.5

y = 1.99 - 0.345

y = 1.64m

At x = 1.99 m, the value of y = 1.64 m

Therefore, fox clear fence by a margin = 1.64 - 0.745 = 0.895 meters.

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613.25 N is the weight of water will be displaced by a 50 kg floating oak beam, if oak is 0.8 times dense of water.

Density of water, = 1000 kg/m³

Density of oak, = 0.8 × 1000 = 800 kg/m³

Floating of an object is possible if the upward force exerted by the water is equal to the weight of the object. And this upward force is equal to the weight of water displaced by the floating object.

Volume of the water displaced by the 50 kg oak, V = 50/800 = 0.0625 m³

Mass of the displaced water = 0.0625 × 1000 = 62.5 kg

Weight of the displaced water = 62.5 × 9.81 = 613.13 N.

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If it starts from rest can travel 1000m, in a straight path, and again it has to come to rest at the end of  1000m, then minimum 70s will be taken.

According to the question, the car starts off at a stop, travels up to a top speed of 20 m/s, and then comes to a stop. This implies that the vehicle must have first reached its maximum speed before braking to a stop.

Let, [tex]T_1[/tex] and [tex]T_2[/tex] be the time for acceleration (attaining maximum velocity) and deceleration (come to the rest) respectively.

Then,

[tex]T_1[/tex] = (Maximum velocity - initial velocity) / acceleration

⇒ [tex]T_1=\frac{20-0}{1}=20sec[/tex]

Then, distance travelled in time [tex]T_1[/tex],

⇒ [tex]S_1=UT_1+\frac{1}{2}aT_1^2[/tex]

⇒ [tex]S_1=0+\frac{1}{2}*1*20^{2}[/tex]

⇒ [tex]S_1= 200m[/tex]

Similarly,

⇒ [tex]T_2=\frac{0-20}{-1}=20sec[/tex]

⇒ [tex]S_2=UT_2+\frac{1}{2}aT_ 2^2[/tex]

⇒ [tex]S_2=(20*20)-(\frac{1}{2}*1*20^2)[/tex]

⇒ [tex]S_2=400-200=200m[/tex]

∴ Distance travelled at uniform velocity is

⇒ [tex]S = 1000-(S_1+S_2)[/tex]

⇒ [tex]S=1000-(200+200)=1000-400=600m[/tex]

This 600m is travelled at a speed of 20m/s.

and time of travel for constant velocity is

⇒ [tex]T_3=\frac{S}{V}[/tex]

⇒ [tex]T_3=\frac{600}{20}=30sec[/tex]

Hence, total time for travel

⇒ [tex]T=T_1+T_2+T_3=(20+20+30)sec=70sec[/tex]

On a V-T graph, it can be displayed here(See picture).

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The jet plane emits 149 914 decibels at 8.2 .

What is the jet plane?

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Answer:

they eat what is decomposing speeding up the decomposition

According to its definition, the net force is the total of all the forces operating on an object.So, 108.46 N force is exerted on the ball.

According to its definition, the net force is the total of all the forces operating on an object.

Mass can be propelled forward by net force.In motion or at rest, another force exerts its influence on the body.When a system contains a sizable number of forces, the term "net force" is employed.

It is given that,

Initial velocity of the baseball, u = 0

The baseball's final speed was 97 mph, or 43.36 m/s.

Mass of baseball, m = 0.15 kg

Distance, s = 1.3 m

(a) Let a be the acceleration of the baseball. Use third equation of motion as :

a = 43.36 /2*1.3

a = 723.11 m/s

Force is given by :

F = m a

F = 0.15 * 723.11= 108.46 N

So, 108.46 N force is exerted on the ball.

(b) The pitcher would need to increase the force so as to alter the required force to reach the same speed if the mass of the ball is decreased.

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The mass is dangling 4/5 of the length of the metre stick away from the right side if the mass of the metre stick is insignificant in comparison to the hanging mass.

The turning force on an item is measured by torque, which is computed by dividing the force by the separation from the pivot point.

Let's designate the forces on the left and right spring scales as F1 and F2, respectively.

F1 = 4F2, as we are aware.

The left side's torque is F1 * L, while the right side's torque is F2 * L (L is the distance from the right side).

Accordingly, F1 * L = F2 * L 4 F2 * L = F2 * L, the total torque on the left side must match the total torque on the right side.

It is evident that L = 4L/5.

In other words, the mass is dangling 4/5 of the way down the metre stick from the right side.

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The number of excess electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.

The number of extra electrons in each sphere can be calculated using Coulomb's law. Coulomb's law states that the repulsive force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them.

F = k * (q1 * q2) / d^2

where F is the repulsive force, q1 and q2 are the charges on the two spheres, d is the distance between the spheres, and k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2).

Since the repulsive force is 4.57 x 10-21 N and the distance between the spheres is 20 cm = 0.2 m, we can rearrange the equations to find the charge on each sphere.

q1 = sqrt(F * d^2 / k)

q1 = square root (4.57 x 10-21 N * (0.2 m)^2 / (8.99 x 10^9 Nm^2/C^2)) = 1.24 x 10^-19 C

So the number of extra electrons in each sphere is equal to 1.24 x 10^-19 C / 1.6 x 10^-19 C/electron = 0.78 x 10^19 electrons.

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Average vehicle spacing at higher traffic density is 35.4 m for a vehicle with a length of 4.7 m.

Let's assume that Traffic flows at 96 km/h as per international data.

We need to find average vehicle spacing.

It indicates that a 96 km stretch of traffic gets cleared in one hour. In addition, 2400 cars may be supported in one lane for an hour. It implies that at least 96km must be taken up by 2400 automobiles. Congestion results from more vehicles moving at the same speed but occupying a smaller space as the number of automobiles increases.

Here, the key to the issue is that you must just consider length. 96 kilometres equal 96,000 metres at this time. If 2400 automobiles take up this much space [just lengthwise], 1 car will take up 96000/2400 m. it is 40 metres. Therefore, each automobile may use up 40m. But the automobile is 4.2 metres long.

It can thus also have a free space of 40 - 4.6 = 35.4 m.

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The magnitude of the force that each sphere before contact and after contact are 1.438 × 10¹⁶ N and 3.5 × 10¹⁴ N respectively.

"Coulomb's law states that the force of attraction or repulsion between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between them." It runs on the same track as the two charges, which are thought of as point charges.

Q₁ = -20 C

Q₂ = +50 C

Distance d = 2.5 cm equals 0.025 metres

F = (k Q₁ Q₂)/d² = (8.99 × 10⁹ × 20×50) /(0.025)² = 1.438×10¹⁶ N

Given that, the charges have opposing signs, the force is alluring.

The charge on each sphere after contact,

Q = Q₁ + Q₂/2 = -20+ 50/2 = -20 + 25 = 5 C

Magnitude of force = k Q²/d² = (8.99× 10⁹ × 5²)/(0.025)² = 224.75× 10⁹/(0.000625) = 359600× 10⁹ = 3.5 × 10¹⁴ N

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The quantity of internal and mechanical energy that things contain fluctuates as a result of work.

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Answer:

net force=applied force

Explanation:

...........................................

Lighting uses typically range from 2 to 100 watts (W), depending on size and kind.

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The technician can either note that the density is more than 2.1 g/mL and halt the analysis, or he can add more liquid until the glass starts to float.

The density of a material is an indicator of how heavy it is in relation to its size. An object will float when submerged in water if its density is lower than that of the water, while sinking if its density is higher. A differentiating characteristic that is unrelated to a substance's volume is its density. By suspending a glass sample in a liquid solution, one can calculate the density of an unknown glass sample. The density of the liquid is then determined, either directly or by comparison with a glass sample.

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Due to changes in temperature and pressure, the substance can exist either as a solid or a gas.

Given The triple point temperature is, (T) = 17 ∘C

The pressure of substance at triple point (P) = 3.2atm

The triple point is the temperature at which a certain substance can exist in all three of its major forms (solid, liquid and gas). Generally speaking, there are three stages of states that can be used to classify the states of matter. At sea level, we will experience conditions with a pressure of 1 atm and a temperature of 25∘C. At the sea level surface of the Earth, the triple point temperature is exceeded and the pressure decreases. The material can therefore exist in both the solid and gas phases. As a result, we can draw the conclusion that the substance can exist in both a solid and a gaseous state due to temperature and pressure variations.

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The diagram that represents the position of a ball, at equal time intervals, as it falls freely is diagram B.

The acceleration of an item in free fall is -9.8 m/s/s. (The minus symbol represents a downward acceleration.) For any freely falling item, the acceleration in the kinematic equations is -9.8 m/s/s, whether or not this is explicitly stated.

vf = g x t where g is the acceleration of gravity. The value for g on Earth is 9.8 m/s/s. This formula is used to determine the object's speed after being dropped from rest for any period of time.

Therefore, the correct option is B. diagram B.

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The question is incomplete. Your most probably complete question is given below:  the options are attached below.

The normal force exerted on the mower is 290.8 N. The result is obtained by using the concept of Newton's first law.

Newton's first law states that every object will remain at rest or keep constantly moving in a straight line unless an external force acts upon it.

The equation of Newton's first law can be expressed as

∑F = 0

A gardener mows a lawn with a push mower with

Find the normal force exerted on the mower?

We use g = 9.8 m/s².

See the illustration picture of forces directions in the attachment!

The direction of normal force is up. Using the Newton's first law, we will add parallel forces.

∑F = 0

Fn - F sin θ - W = 0

Fn = F sin θ + W

Fn = 209 sin 32° + 18 × 10

Fn = 209 (0.53) + 180

Fn ≈ 290.8 N

Hence, the mower will exert the normal force of 290.8 N.

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The maximum acceleration that the flatbed truck can achive on wet concrete is 5[tex]m/s^{2}[/tex]

The maximum acceleration a truck can achieve on wet concrete is determined by the coefficient of friction between the two drive wheels and the surface.

Taking into account the coefficients of static and kinetic friction between the drive wheels and a wet concrete surface—0.7 and 0.5, respectively—the maximum acceleration of a truck with half its weight supported by its two drive wheels can be calculated using Newton's Second Law of Motion.

According to Newton's Second Law, F = ma, where F is force, m is mass and a is acceleration.

Since the truck has half its weight supported by its two drive wheels, we know that F = 0.5 mg (where m is mass and g is gravitational acceleration). Thus, when solving for a (acceleration), we have:

a = F/m

 = 0.5mg/m

 = 0.5g

 = 4.9 [tex]m/s^{2}[/tex] ≈ 5 [tex]m/s^{2}[/tex]

This means that on wet concrete with coefficients of static friction and kinetic friction at 0.7 and 0.5 respectively, the maximum acceleration a truck with half its weight supported by its two driving wheels can achieve is 5 [tex]m/s^{2}[/tex].

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The speed of the car truck combination is calculated to be 0.667 m/s and it is a type of inelastic collision.

Mass of the car m₁ = 700 kg

Velocity of the car u₁ = 20 m/s

Mass of the stationary truck m₂ = 1400 kg

Velocity of the stationary truck u₂ = 0

The momentum before collision is, m₁ u₁ = 700× 20 = 1400 kg m/s

As, we know from the principle of conservation of linear momentum,

momentum before the collision of trucks is equal to momentum after the collision of trucks.

The momentum after the collision is (m₁ + m₂) vf = 1400 kg m/s

(700 + 1400) vf = 1400

2100 vf = 1400

vf = 0.667 m/s

Now, let us compare kinetic energies before and after collision.

Kinetic energy before collision = 1/2 m₁ u₁² = 1/2 × 700× 20² = 14×10⁴ kg m/s

Kinetic energy after collision =1/2 (m₁+m₂) vf₂ = 1/2(700 + 1400) 0.667² = 467.13 kg m/s

As kinetic energy is not conserved, the type of collision is said to be an inelastic collision.

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Blinds window treatments will allow sunlight into his living room, but he needs to angle the light to avoid glare on his tv.

Even additional light will enter through the open window, further illuminating the space. You should think about some strategic lighting solutions for dark spaces in addition to trying to increase any available natural light.

East and west-facing windows frequently receive excessive sunlight, exposing these rooms to the sun at its hottest part of the day. The warmth in the room rises due to the sun's glare through these windows, which might make it difficult to read or watch television.

According to Lowe's, temporary heat-control window film should be used to cover windows that face south and west in order to reduce glare from the sun. This film is specifically created to prevent UV sun rays while yet allowing allowing some daylight to enter.

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angle to the shore should a person navigate a boat, which is maintaining a constant speed of 16 km/h, in order to reach a point directly opposite is 75.5 degrees.

Since the stream is flowing parallel alongside the shore, it takes the vector form of  v {stream} = [0,4]

the boat velocity is perpendicular to the stream, it's takes the vector form of  v{boat} = [-16,0]

The resultant velocity of the boat is the sum of the velocity of the boat and stream, thus it takes the form

v{total} =  [-16,0] +  [0,4]

           = [ -16,4]

the cosine of angle to the shore,

                  cos {theta} = v{total} . v {stream} / ||v{total} || x ||v {stream}||

                                     =  [ -16,4] . [0,4] / (16x4)

                                     = 16/64

                                     = 0.25

                       angle = 75.7 degrees.

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For the given statement the Electric flux through the surface is 0.54 N m 2 /C.

Note: we are considering the distance between two charges to be 0.1 m

Electric flux in electromagnetism is a measurement of the electric field passing through a certain surface. The SI unit for the scalar quantity known as electric flux is newton-meters squared per coulomb (N m 2 /C). N · m 2 /C )

The electric flux passing through a surface can be calculated using the equation:

Φ = E * A = (k * q1 + k * q2) / r^2 * A

k = Coulomb's constant = 8.99 x 10^9 N * m^2 / C^2

r = distance between the charges = 0.1 m

A = surface area = 0.1 m * 0.1 m = 0.01 m^2

Now if we calculate:

Φ = (k * q1 + k * q2) / r^2 * A =  [(0.01 m^2)]* [(8.99 x 10^9 N * m^2 / C^2) *( 6.8 x 10^-12 C)] + [(8.99 x 10^9 N * m^2 / C^2) * (2 x 10^-12 C)] / (0.1 m)^2 = 0.54 N * m^2 / C.

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The amount of the charge flowing through the terminals of the battery is found to be 0.084C.

The voltage of the battery is given to be 12 V and the capacitance of the capacitor is given to be 7 micro F.

As per the standard relations, the amount of the charge flowing through the terminal of the battery will be given by,

Q = CV

Where,

Q is the charge through the battery,

C is the capacitance of the capacitor,

V is the voltage of the battery.

Putting all the values,

Q = 12 x 7/1000

Q = 0.084 C.

So, the charge flowing is 0.084 C.

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The correct option is (b) i.e. optical system. It is made up of a laser, optical filters, light-collecting optics, and beam-shaping components.

A scanner assembly, as it relates to digital imaging and document scanning, typically consists of a laser, optical filters, light-collecting optics, and beam-shaping devices. The laser is used to project a precise, concentrated beam of light onto the surface of the plate or document being scanned. Optical filters are used to control the wavelength and intensity of the light being used. Light-collecting optics, such as lenses, are used to focus the beam of light onto the plate or document. Finally, beam-shaping devices, such as mirrors or prisms, are used to guide the beam of light as it scans across the plate or document. The scanner assembly is designed to move the beam of light back and forth across the plate in a controlled manner, capturing an image of the plate or document as it does so.

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Question - The part of the reader that consists of a laser, optical filters, light-collecting optics, and beam-shaping devices that is designed to project and guide a precisely controlled laser beam back and forth across the plate as the plate moves through the scan area is the

a) photodetector

b) optical system

c) drive mechanism

d) photostimulable luminescence

Frequency and wavelength​ is 100m/s.

Pictures for Calculate the frequency and wavelength. The formula for frequency expressed in terms of time is given as follows: f = 1/T, where T is the duration of a cycle expressed in seconds and f is the frequency expressed in hertz. The frequency formula is stated as f = / where denotes the wave speed and the wavelength of the wave.

Explanation:

In 3 seconds, the source is generating 15 waves.

In a second, there are 15/3 waves, or 5 waves, produced.

Thus, the frequency is 5 Hz.

assuming that the wave length /2 = 10 cm

so that =20 cm

speed = frequency *wavelength v=5*20

v=100m/s.

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