The two types of simple machine make up this compound machine are the screw and the lever.
What is the simple machine?A screw is a simple machine that consists of a spiral groove or ridge, called a thread, wrapped around a cylinder or cone. When the screw is rotated, it can be used to hold two objects together or to lift an object by turning it into a threaded hole.
Therefore, A lever is a simple machine that consists of a rigid bar that pivots on a fixed point, called a fulcrum. A force applied to one end of the lever can be used to lift or move an object at the other end. Lever can be classified into three classes depending on the position of the load, effort and fulcrum.
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A taxi hurries 95 km in 1 7/12 hours. What is its average speed in kilometers per hour?
85.83 km/hr is the average speed it travels at.
Explain about the speed.An object's speed can be determined if you are aware of the distance it covers in a given period of time. An automobile, for instance, is moving at a pace of 70 miles per hour if it covers 70 miles in an hour (miles per hour).
Speed (or rate, r) is a scalar quantity that represents the amount of distance travelled (d) over the amount of time changed (t), as shown by the equation r = d/t.
Distance divided by time can be used to calculate speed. The speed is determined by dividing the distance travelled (say, 3 meters) by the passing time (say, 3 seconds) (one meter per second) Speed is hence the rate at which an object's position changes in any direction.
By converting 7/12 to a decimal (7/12 = 0.58), you may determine how many hours are in total.
1 plus 0.58 equals 1.58 hours when you add up the total time.
Subtract the overall time from the entire distance (95km) (1.58 hours).
The result, 95 kilometers divided by 1.58 hours, is 85.83 km/h, which is the average speed.
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given two strings s and t, both consisting of lowercase english letters and digits, your task is to calculate how many ways exactly one digit could be removed from one of the strings so that s is lexicographically smaller than t after the removal. note that we are removing only a single instance of a single digit, rather than all instances (eg: removing 1 from the string a11b1c could result in a1b1c or a11bc, but not abc).
I came up with this test case myself. If s = '3ab' and t = 'cd', return 1. If s = '123ab' and t = '423cd', return 6.
What are lexicograph?The study of lexicons is called lexicography, and it is separated into two distinct academic fields. It involves the creation of dictionaries. [1]
The process of compiling, writing, and editing dictionaries is known as practical lexicography.
Theoretical lexicography is the academic study of the semantic, orthographic, syntactic, and paradigmatic characteristics of the lexicon (vocabulary) of a language. It also develops theories of the elements and structures of dictionaries that connect the data in dictionaries, the information needs of users in various contexts, and the most effective ways for users to access the data included in printed and electronic dictionaries. This practise is sometimes known as "metalexicography."
On what defines lexicology as different from lexicography, there is some debate. Some people use the term "lexicology" to refer to theoretical lexicography, whereas others do not.
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kicked the ball in the air with an initial velocity of 12m/s at an angle of 40° above the horizontal. If the ball travels a horizontal distance of 15m , how long will it fly in the air?
The soccer ball rose 5.24 meters in the air.
VO =?, max H =?, range = 25m, angle A = 40°
Projectile motion is being used in this situation. Range = vo2 * sin 2A / g is the formula for range. calculating the initial velocity vo's square and its original value.
Range is equal to vo2*sin2A/g.
VO2 * SIN (2 * 40°) / 9.8 m/s = 25 m
vo2 = sin 80° / 9.8 m/s / 25 m
2 vo = 15.77 m/s and 2 vo = 248.8 (m/s) respectively.
The ball's starting speed is 15.77 m/s.
The height of the object, max H, can be calculated as follows: max H = vo * (sin A) * 2g max H = 248.8 (m/s) * (sin 40°) * 19.6 m/s * 2g max H = 5.24 meters
The soccer ball rose 5.24 meters in the air.
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Some crosswalks timers are set in consideration that persons older than 65 walk at an average pace of 2.9 ft/sec. Describe how you determined your pace, or average walking speed, in feet per second, by a method of your choice. How does your pace compare to the average pace of persons older than 65?
You can determine the average walking speed by registering the distance covered by different people in the same group. My pace is higher than people older than 65.
How to determine the walking pace?You can determine your average walking pace by recording information about the distance you cover in feet and the second it takes you to cover that distance. Here is an example:
450 feet / 100 seconds = 4.5 feet per second
How does my pace compare to the average of persons older than 65?My pace is faster than the walking pace of someone who is 65.
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At what distance of 1m from the source intensity of sound is 2 w / m² . What is the power of this wave
Answer:
25.13274 W (WATT) (Sound Power of the Sound Source)
134.002 dB (Sound Power Level)
An object is thrown straight up. Which of the following is true about
the sign of work
done by the gravitational force while the object moves up and then
down?
A.Work is positive on the way up, work is positive on the way down
B. Work is negative on the way up, work is negative on the way down
C.Work is negative on the way up, work is positive on the way down
D.Work is positive on the way up, work is negative on the way down E.
Work is zero the way up, work is zero on tâ
The correct option is C. Sign of Work is negative on way up and negative on way down due to gravitational force.
The definition of work is the energy that is either added to or subtracted from something by applying force along a displacement. For a constant force acting in the same direction as the motion, the work is simply equal to the product of the force's magnitude and the distance travelled.
A thrown object's acceleration due to gravity will cause negatively deaccelerate when we throw it vertically upwards.
We represented deacceleration by a (-) sign.
Thus, we may conclude that any work completed when an object is thrown upwards is negative since it defies gravity.
Now, g is accelerating force as it movies in direction of gravity when object comes downwards to earth. Work done when object moves down is positive.
Consequently, the best option will be option (C)
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a 56-kg pole vaulter running at 11 m/s vaults over the bar. her speed when she is above the bar is 1.4 m/s. neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar.
The altitude of the pole vaulter as she crosses the bar would be 6.1 meter due to energy conservation.
The energy is the first one, but when you jump you're in the air, so you have potential energy due to gravity, and kinetic energy because you're still moving in 1.4 m/s.
Using conservation of energy,
KEi+ PEi = PEf+ KEf
PE = mgh
KE = 0.5mv²
Now, m= 56 kg v= 1.4 m/s
so solving,
h= 6.1 meter
So, The altitude of the pole vaulter as she crosses the bar would be 6.1 meter due to energy conservation.
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A steel wire of length 1.93 m with circular cross section must stretch no more than 0.240 cm when a tensile (stretching) force of 450 N is applied to each end of the wire. What minimum diameter is required for the wire?
The minimum diameter required for the wire is 1.48 m when A steel wire of length 1.93 m with a circular cross-section must stretch no more than 0.240 cm when a tensile (stretching) force of 450 N is applied to each end of the wire.
Given,
wire length, l = 1.93 m
Δl = 0.240 cm = 0.24 x 10⁻² m
F = 450 N
we know that, young's modulus for steel
Y = 2.1 x 10¹¹ N/m²
let the radius of the wire is r
we know that,
Y = Fl/AΔl = (450 x 1.93)/(3.14 x r² x 0.24 x 10⁻²)
r² = 5.486 x 10⁻⁷ m²
or r = 7.4 x 10⁻⁴ m
so diameter of wire is d = 2r = 2 x 7.4 x 10⁻⁴ m
d = 1.48 x 10⁻³ m or d = 1.48 mm
Therefore, the minimum diameter required for the wire is 1.48 m when A steel wire of length 1.93 m with a circular cross-section must stretch no more than 0.240 cm when a tensile (stretching) force of 450 N is applied to each end of the wire.
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a 1200 kg safe is 2.1 m above a heavy-duty spring when the rope holding the safe breaks. the safe hits the spring and compresses it 56 cm . What is the spring constant.
When a 1200 kilogram safe is 2.1 m above a heavy-duty spring and the rope holding the safe breaks, the spring constant is 199,136 N/m (roughly 200 kN/m). The safe collides with the spring, compressing it by 56 cm.
What is kinetic energy?In physics, an object's kinetic energy is the energy it has as a result of its motion. It is defined as the amount of work required to accelerate a body of a given mass from rest to a certain velocity. The body retains its kinetic energy after gaining it during acceleration until its speed changes. Kinetic energy is the energy that an item has as a result of its movement. If we wish to accelerate an item, we must apply force to it. Using force demands us to put in effort. After work is completed, energy is transferred to the item, and the thing moves at a new constant speed.
Here,
The spring constant is 200kN/m.
The work done on the spring by the the free falling safe is equal to the kinetic energy of the spring:
W1 =1/2kx²
The work done on the safe by gravity is the potential energy of the spring:
W2 = (mass of safe) x g x (height)
= 1000kg x 9.8 m/s^2 x (2 + 0.54)m
=1000kg x 9.8 m/s^2 x (2.54)m
= 24,892 N-m
W2 = W1 =24892 N-m
W=1/2kx²
Therefore, k = 199136 kN/m.
The spring constant is 199,136 N/m approximately 200 kN/m when a 1200 kg safe is 2.1 m above a heavy-duty spring when the rope holding the safe breaks. the safe hits the spring and compresses it 56 cm.
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Landon and Jocelyn are partners in pair figure skating. Last weekend, they perfected the death spiral element for inclusion in their upcoming competition. During this maneuver, Landon holds Jocelyn by the hand and swings her in a circle while she maintains her blades on the ice, stretched out in a nearly horizontal orientation. Determine the net force that must be applied to Jocelyn (m = 47.3 kg) if her center of mass rotates in a circle with a radius of 0.915 m once every 1.13 seconds.
The net force that must be applied to Jocelyn is 139 Newton.
How to calculate the net force?The net force acting on Jocelyn during the death spiral can be determined using the equation:
F = m * a
where F is the net force, m is her mass (47.3 kg), and a is her centripetal acceleration.
To find the centripetal acceleration, we can use the equation:
a = v^2 / r
where v is her velocity and r is the radius of rotation.
We know that Jocelyn completes one rotation every 1.13 seconds, so we can calculate her velocity:
v = 2 * pi * r / T
where T is the time for one rotation
Plugging in the known values:
v = 2 * pi * 0.915 m / 1.13 s
v = 5.09
Now we can substitute the value of v into the centripetal acceleration equation:
a = v^2 / r
a = 5.09² / 0.915
a = 28.3
F = ma
F = 47.3 × 28.3
F = 1339 Newton
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002 (part 2 of 3) 10.0 points what is the magnitude of the potential difference vy x across the terminals y and x of the battery? answer in units of v. answer in units of v. 003 (part 3 of 3) 10.0 points what power is dissipated by the internal resistance of the battery? answer in units of w. answer in units of w.
The power dissipated by the battery is 100V2/R.
What is power dissipated?Power dissipated is the rate at which energy is converted from one form to another. It refers to the amount of energy that is lost due to heat or vibration when electricity flows through a component or system. Power dissipation is an important concept in electrical engineering since it affects the efficiency, reliability and temperature of a system.
The power dissipated by the internal resistance of the battery can be calculated using the formula P=IV,
where I is the current and V is the potential difference across the terminals. Since we know that V = 10V,
we can calculate I by dividing V by the internal resistance (R) of the battery: I = 10V/R.
The power dissipated by the battery is then given by P = IV = (10V/R)*(10V) = 100V2/R.
Thus,
In units of watts, the power dissipated by the battery is 100V2/R.
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An object's speed is 3.6 m/s with a momentum of 180 kgm/s. What is the mass of the object?
Answer:
To solve the problem we must know the concept of momentum.
What is Momentum?
Momentum is defined as the product of the mass of an object and the velocity of an object. It is a vector quantity.
$$\rm{Momentum = velocity \times Mass$$
The mass of the object is 50 kg.
Given to us
velocity of the object = 3.60 m/s
momentum of the object = 180 kg m/s
Mass of the object
We know that momentum is the product of the mass of the object and the velocity of the object,
$$\rm{Momentum = velocity \times Mass$$
Substitute the values,
180 = 3.60 \times \rm Mass180=3.60×Mass
\rm Mass = \dfrac{180\ kg\ m/s}{3.6\ m/s}Mass=
3.6 m/s
180 kg m/s
\rm Mass = 50\ kgMass=50 kg
Hence, the mass of the object is 50 kg.
Infant brain mapping is being used to assess perceptual and cognitive activities including which of the following?
Language
Hearing
Vision
Infant brain mapping is being used to assess perceptual and cognitive activities including Vision, Hearing, and Language.
The very early offspring of humans are called infants or babies. Infant is a formal or specialized synonym for the phrase baby. It comes from the Latin word infants, which means "unable to talk" or "speechless." Other organisms' young may also be referred to by the names.
In everyday speech, an infant that is only a few hours, days, or even a few weeks old is referred to as a newborn. In medical contexts, an infant in the first 28 days following delivery is referred to as a newborn or neonate (from the Latin neonates, newborn); the word is applicable to premature, full-term, and postmature newborns.
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Two small identical conducting spheres are placed with their centers 0.30m apart. One is given a charge of 12 X 10^-9C, the other a charge of -18 X 10^-9C.
a.Find the electrostatic force exerted on one sphere by the other.
b. The spheres are connected by a conducting wire. Find the electrostatic force between the two after equilibrium is reached, where both spheres have the same charge.
a. 12*10^-5 N attractive is the force exerted on one sphere by the other. b. 9*10^-7 N repulsive is the force between the two after equilibrium is reached, where both spheres have the same charge.
The force between two charged particles is calculated as
F= q1*q2*K/r^2 .......................(i)
where q1 is the charge of the first body, q2 is the charge of the second body and r is the distance between them Here K is a constant that has the values of 9*10^9.
So for the finding a.
12 X 10^-9* -18 X 10^-9*9*10^9/(o.3)^2 ............ From ( i)
9*12*18*10^-9/0.09 which results to 12*10^-5 N
And Similarly for b we need to find the total average charge of both bodies will be.
(q1+q2)/2 ......(ii) (12 - 18)/2 => -6/2 = -3 nC .................( from ii)
and using (i) (3X10^-9)^2*9*10^9/ (o.3)^2 ...... (As q1 =q2)
which results in 9*10^-7 N
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which of the following forces is an example of a contact force
a) gravitational force
b) magnetic force
c) electric force
d) frictional force
Answer:
d) frictional force
Explanation:
What Is a Contact Force?
Contact force is the phrase used to describe a push/pull interaction that occurs when an object comes into contact with another object.
The only force where there is contact between two bodies in the answer choices is frictional force
Answer
d) frictional force
some psychologists believe that eating disorders representative fence against unconscious conflicts related to sexual development. These psychologists have adopted a _____ approach to eating disorders.
Some psychologists believe that eating disorders represent a defense against unconscious conflicts related to sexual development. These psychologists have adopted a Psychoanalytic approach to eating disorders.
What is a Psychoanalytic approach?A psychoanalytic approach is based on the idea that our unconscious thoughts, feelings, and motivations can have a powerful influence on our behavior by focusing on helping individuals to gain insight into their unconscious processes, recognize and resolve conflicts, and modify their behavior.
Therefore, with this data, we can see that a Psychoanalytic approach is based on unconscious mental processes to develop a cure.
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Classify each of the following failures by identifying its category in Fig. 1.1, and explain the reasons for each choice in one or two sentences: (a) The plastic frames on eyeglasses gradually spread and become loose. (b) A glass bowl with a small crack breaks into two pieces when it is immersed, while still hot, into cold water (c) Plastic scissors develop a small crack just in front of one of the finger rings (d) A copper water pipe freezes and develops a lengthwise split that causes a leak (e) The steel radiator fan blades in an automobile develop small cracks near the base of the blades
We classified each of the following failures by identifying its category in the Figure shown:
Plastic eyeglass frames gradually stretch and loosen. This is an example of creep failure.A glass bowl with a small crack breaks into two pieces when immersed, still hot, in cold water. This is an example of thermal shock failure.A plastic scissors has a small crack just in front of one of the finger rings. This is an example of fatigue failure.A copper water pipe freezes and develops a longitudinal crack that causes a leak. This is an example of brittle fracture.The steel fan blades on the radiator fan are leaking. This is an example of creep failure.Explanation of each of the failures of the mentioned materials:This is an example of creep failure, which occurs when a material is subjected to constant stress over time and causes it to deform. Plastic eyeglass frames stretch and loosen due to constant stress from wearing them. This is an example of thermal shock failure, which occurs when a material is subjected to a sudden change in temperature, causing it to crack or break. The glass bowl broke in two when immersed in cold water while it was still hot. This is an example of fatigue failure, which occurs when a material is subjected to repeated cycles of stress, causing it to eventually crack or break. The plastic scissors developed a small crack due to repeated stress from use. This is an example of brittle fracture, which occurs when a material is subjected to high stress and fractures without any significant deformation. The copper water pipe froze and split longitudinally due to the high stress from the freezing temperatures. This is an example of creep failure, which occurs when a material is subjected to constant stress over time and causes it to deform. Steel radiator fan blades developed small cracks due to the constant stress of being used while an automobile develops small cracks near the base of the blades.Learn more about material failures:
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positive charge is distributed uniformly on a plastic rod bent to form a quarter-circular arc (figure 1). figure1 of 1 a positively charged rod is bent so that it forms a concave rightward arc symmetrical about a horizontal dashed line going through the center of the rod. the center of curvature of the bent rod is marked with a black dot. part a what is the direction of the electric field at the center of the circle?
Radial direction of the electric field at the center of the circle.
What are Electric field?Take into consideration the little equivalent arc elements on either side of the horizontal first. Now determine the electric field they caused, how to fix it, and how to eliminate the ones that were directed in the other direction. Now, swap out the common expression for the electric field caused by charge density, integrate over the arc's length, and you'll get the necessary electric field.
The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field.
It can also refer to a system of charged particles' physical field. Electric charges and time-varying electric currents are the building blocks of electric fields.
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a student conducted an experiment where they burned a 5g strip of magnesium metal in an open flame. the result was a 3.5g of white ash collected in a crucible, a bright white flame, and smoke.
This experiment undoubtedly brought about the ignition of magnesium metal, which is an exceptionally receptive metal that promptly consumes within the sight of oxygen.
The ash gathered in the crucible is logical to the excess buildup of the magnesium after it has gone through ignition. The bright white fire and smoke are likewise normal for magnesium consumption.
As the metal consumes at a high temperature and produces a bright light. The ash gathered in the crucible is in all probability magnesium oxide, which is a white fine substance.
The weight of the ash(3.5g) is not exactly the underlying load of the magnesium strip (5g), this is because of the deficiency of magnesium as a gas during the burning system.
The contrast between the weight of the ash and the underlying load of the magnesium strip addresses the weight of the magnesium that was lost as a gas during the combustion.
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an object's elevation is a perspective cue to . group of answer choices distance shape shadowing size
A monocular cue called linear perspective helps us understand the depth and distance of an object.
Any depth indication that may be interpreted solely by one eye is referred to as a monocular cue. In contrast, binocular cues call for the use of both eyes in order to perceive depth and distance.
Things that are nearby seem to move more quickly than objects that are farther away thanks to a depth perception cue called motion parallax. It is a form of monocular cue, or a cue for depth perception, that may be seen with just one eye.
Perception time is the amount of time it takes to become aware of a situation and realize that stopping is necessary. About three-quarters of a second may pass during this. Less experienced drivers frequently take longer to recognize a threat. The distance a car goes during this time is called perception distance.
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find the time-domain voltage over the capacitor using phasor domain techniques. the voltage and current source are both ac (cos) sources with frequency of 1mhz and with the amplitudes of 12 v and 20ma, respectively. assume that, r1
To find the time-domain voltage over the capacitor using phasor domain techniques, we need to first convert the circuit to the phasor domain by replacing the time-varying voltage and current sources with their phasor equivalents. The phasor equivalents of the voltage and current sources are:
V_s = 12 V * e^(j2pift)
I_s = 20mA * e^(j2pift)
where f is the frequency of the sources (1 MHz) and t is time.
The phasor voltage across the capacitor can be found using the following equation:
V_C = V_s - I_s * (R_1 + R_2 + j2pifL) - I_s * (1/(j2pifC))
Substituting in the values for the resistance and reactance of the circuit, we get:
V_C = 12 V * e^(j2pift) - 20mA * e^(j2pift) * (1000 Ohm + 2000 Ohm + j2pi10^620e-6 H) - 20mA * e^(j2pift) * (1/(j2pi10^6200e-12 F))
Simplifying, we get:
V_C = 12 V * e^(j2pift) - 20mA * e^(j2pift) * (3000 Ohm + j40pi) - 20mA * e^(j2pift) * (5e5 Ohm)
So, the phasor voltage across the capacitor is V_C = 12 V * e^(j2pift) - 0.02 A * e^(j2pift) * (3000 Ohm + j40pi) - 0.02 A * e^(j2pift) * (5e5 Ohm)
Finally, to find the time-domain voltage over the capacitor, we need to take the inverse Fourier transform of the phasor voltage. This can be done using the following equation:
v_c(t) = real (V_C * e^(-j2pift))
Substituting in the value for V_C, we get:
v_c(t) = real (12 V * e^(j2pift) - 0.02 A * e^(j2pift) * (3000 Ohm + j40pi) - 0.02 A * e^(j2pift) * (5e5 Ohm)
Complete question:
Find the time-domain voltage over the capacitor using phasor domain techniques. The voltage and current source are both AC (sine) sources with frequency of 1MHz and with the amplitudes of 12 V and 20mA, respectively. Assume that, R_1 = 1 k Ohm, R_2 = 2k Ohm, C = 200pF, and L = 20mu H.
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a car burns fuel with a density of 700 kg/m3 under atmospheric conditions that produce an air density of 1.2 kg/m3. the car has a fuel rating of 36 mpg (miles per gallon) at a speed of 60 mph (miles per hour) and a frontal cross-section of 4.5 feet by 2.5 feet. 1. calculate
The drag coefficient of the car is calculated as equal to 0.0947.
What is drag coefficient ?A dimensionless quantity that is used to quantify the drag or resistance of an object in a fluid environment, such as air or water is called drag coefficient.
60 mph = 26.8 m/s
1 mpg = 0.425144 liters/kilometer
36 mpg = 15.60512 liters/kilometer
4.5 ft * 2.5 ft = 11.25 ft^2 = 1.042 m^2
The drag force can be calculated as:
Fd = 0.5 * Cd * A * r * v^2
where, Cd = drag coefficient (unitless), A = frontal area of the car (m^2), r = air density (kg/m^3), v = velocity of the car (m/s)
So, Fd = (15.60512 liters/kilometer) * 4.5 kg/liter / (3600 sec/hour) = 0.0066 N
Cd = Fd / (0.5 * A * r * v^2)
Cd = 0.0066 N / (0.5 * 1.042 m^2 * 1.2 kg/m^3 * 26.8 m/s^2) = 0.0947
The drag coefficient of the car is 0.0947.
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Note: The question given on the portal is incomplete. here is the complete question.
Question: A car burns fuel with a density of 700 kg/m3 under atmospheric conditions that produce an air density of 1.2 kg/m3. the car has a fuel rating of 36 mpg (miles per gallon) at a speed of 60 mph (miles per hour) and a frontal cross-section of 4.5 feet by 2.5 feet. 1. calculate the drag coefficient of the car.
The speed of a pendulum is greatest (a) when the pendu- kinetic energy is a minimumb) when the pendu lum's acceleration is a maximum, (c) when the pendulum's potential energy is a minimumof the preceding
Answer:
Explanation:
b. when the pendulum's acceleration is a maximum.
The speed of a pendulum is greatest when the acceleration of the pendulum is at a maximum. This occurs when the pendulum is at the bottom of its swing, where the force of gravity is causing the greatest acceleration. At this point, the pendulum's kinetic energy is at a maximum and potential energy is at a minimum.
7. object has a mass of and is moving in the direction. it collides with object , which has a mass of 2 and is initially at rest. after the collision, object has a final velocity of in the direction. which of the following best describes the impulse object exerts on object during the collision? -2MV - Mv 0 +Mv E +2Mv
-2Mv best describes the impulse object exerts on object during the collision.
In physics, collision, which is also known as impact can be explained as the abrupt, powerful coming together in close proximity of two bodies, such as two pool cues, a golf club and a ball, a hammer.
Accidents can be generally defined as the following: A collision which occurs whenever two vehicles collide violently.
First collision is literally defined as the impact that a car suffers when it hits another object, and second collision is the impact suffered by the occupant, or occupants, of a crashed car, against the impacted car. Given the information on the question, that would be a first collision.
2Mv Mv +Mv +2Mv
2Mv Mv = Mv -2Mv
2(Mv)= Mv
Mv= -2Mv
-2Mv
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Which of the following describes a benefit of the fact that oll never wears out?
Because oll never wears out, it can be used again and again.
Because oll never wears out, farmers will never run out of it.
Because oll never wears out, it never needs to be replaced.
O Because oll never wears out, its cost remains low.
The option that best describes the benefit of the fact that oll never wears out is that oll never wears out, it can be used again and again.
The correct option is A.
What is the benefit of durability in materials?Durability is the ability of material to last in usage for a long time.
Duravle materials provides benefits to the owners in that it:
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two hypothetical metals are created with different elements that have the same atomic mass (g/mole) and the same atomic radius. metal a has a density of 9.50 g / cm 3 and metal b has a density of 8.73 g / cm 3 . if one of these metals has a bcc lattice structure and the other has an fcc lattice structure, identify the structure that corresponds to each of one of them. justify your answer.
Metal A has a more density(9.50 g/cm³) for the same atomic mass, so it is more likely to have an FCC lattice structure, whereas metal B has a comparatively less density(8.73 g/cm³), so it is more likely to have BCC lattice structure.
A body-centered cubic (bcc) lattice structure has 8 atoms at the corners of a cube and one atom in the center of the cube. This structure has a lower density compared to face-centered cubic (fcc) lattice structure, which has atoms at the corners and the centers of each face of a cube.
According to the given densities, metal A with a density of 9.50 g/cm³ is likely to have an FCC lattice structure, while metal B with a density of 8.73 g/cm³ is likely to have a BCC lattice structure. This is because the FCC structure has a higher density due to the more close-packed arrangement of atoms compared to the bcc structure.
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after being kicked, a soccer ball flies upward into the air, slowing down as it reaches its maximum height.T/F
False. As the soccer ball reaches its maximum height, it begins to slow down and then fall back to the ground due to the force of gravity.
What is gravity?Gravity is a natural force of attraction that exists between any two objects with mass. It is the weakest of the four fundamental forces of nature and acts over a very short distance. It is responsible for keeping the planets in orbit around the sun and for keeping objects on the earth's surface. Gravity also affects the motion of objects in the air, causing them to accelerate downward toward the ground. In addition, gravity affects the tides and other oceanic phenomena. On a smaller scale, gravity affects the movement of particles such as electrons and protons.
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Each choice below describes how a few astronomical phenomena are related to time periods. Which list is entirely correct? (Careful: some lists are partially correct.) A) Earth's rotation defines a day.The cycle of the Moon's phases takes about a month.Earth's orbit defines a year.Earth's cycle of axis precession takes 26,000 years. B) Earth's rotation defines a day.The cycle of the Moon's phases takes about a week.Earth's orbit defines a year.Earth's cycle of axis precession defines a month. C) Earth's rotation defines a day.The Sun's rotation defines a week.The Moon's rotation defines a month.Earth's orbit defines a year.D) Earth's rotation defines a day.The saros cycle of eclipses defines a month.Earth's orbit defines a year.Earth's cycle of axis precession takes 26,000 years.
The correct list is D) Earth's rotation defines a day. The saros cycle of eclipses defines a month.
What is Earth's rotation?Earth's rotation is the rotation of the planet around its own axis. This axis is an imaginary line that passes through the North and South Poles. Earth rotates from west to east, which is why the Sun appears to rise in the east and set in the west. The length of a day is determined by the time it takes for Earth to make one full rotation around its axis.
Earth's orbit defines a year.Earth's cycle of axis precession takes 26,000 years. This is because the Earth's rotation defines a day, the saros cycle of eclipses defines a month, the Earth's orbit defines a year, and the Earth's cycle of axis precession takes 26,000 years.
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A bottle with a volume of 195 U. S. fluid gallons is filled at the rate of 1.7 g/min. (Water has a density of 1000 kg/m3, and 1 U.S. fluid gallon = 231 in.3.) How long does the filling take?
The time that have been taken by the liquid is 4.4 * 10^5 min.
How long does it take to be filled?The question that we have been asked here is about the rate of the filling of the bottle. We can see that we have been given the volume of the bottle clearly.
We know that the volume of the solution that we have is 195 U. S. fluid gallons or 0.74 m^3. Then we have that;
Density = mass/volume
mass = Density * volume
= 0.74 m^3 * 1000 Kg/m^3
= 740 Kg or 740000 g
Rate = mass/time
Time = mass/rate
Time = 740000 g/1.7 g/min.
= 4.4 * 10^5 min
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In professional football some players have microphones in their helmets that allow them to communicate with coaches on the sideline what is this indicate
The involvement of microphones in the helmet of some professional football players for the purpose of communication shows that there is an immense advancement in technology.
What are microphones?A microphone is defined as a device that is can be used to magnify a sound through its conversation to electrical signals.
Professional football is a type of game that is played by train individuals and it's made up of two teams that plays against each other.
The introduction of microphones in the helmet of these footballer helps them to effectively communicate with their coaches near by which was not soo years back.
Therefore this can be said to be an advancement in technology.
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