What is the length of
BC
X + 9
2x - 8
Enter your answer in the box.
units
х
B
1

Answer: You just need to count the shaded squares, and if half of the square is shaded, it counts as 1. Therefore, the area is 42 square units.

Answer:

The correct answare would be 3.54 x 10^22 N  

Answer:

2^2 * 3^2 * 7

Step-by-step explanation:

Keep dividing by prime numbers:

2 ) 252

2)  126

3)    63

3)    21

        7

so 252 = 2*2*3*3*7

= 2^2 * 3^2 * 7

Answer:

x = - 0.89

Step-by-step explanation:

x - 8.2 = - 9.09

x = - 9.09 + 8.2

x = - 0.89

Answer:

-0.89

Step-by-step explanation:

Answer:

x=-3

Step-by-step explanation:

This is a one step solution all you do is divide 5 into -15

-15/5 = -3

so -3 = x

Answer:

lets get started

Step-by-step explanation:

Answer:

no you're not wrong go with your gut

Step-by-step explanation:

Answer:

differentiate

for example what is difference between this and that

Answer:

85.5

Step-by-step explanation:

Answer:

(2*2 3+2) * (4*2 3-1/2)

(4*5) * (8*3-0.5) = (8*2.5)

20*200

4000

Answer:

Step-by-step explanation:

by the property of corresponding angles (2x +16) and (3x-12) will be equal

working uot from the equation 3x-12 = 2x+16 we get x=28

and we know that 3x-12 and y are supplementry as they form a linear pair

from that we will get the equation - 3x-12 + y = 180 and we know the value of x sowe will get y as 108

Answer:

23 Dimes and 8 Quarter.

Step-by-step explanation:

Important info:

31 Coins worth a total of $4.30

Note:

Dimes = .10

Quarters = .25

10 Dimes = 1.00

4 Quarter = 1.00

Question to Answer:

How many of each type of coin does she have?

Solution:

Lets get rid of the .30 cent in $4.30 so

.30 = 3 Dimes

Now $4.00,

4.00-1.00 of quarter

=

3.00 and 4 quarter..

Right now we have 3 Dimes and 4 Quarter = $1.30.

And that 7 Coins worth of $1.30.

3.00-2.00= 1.00 and 20 Dimes so now we have

23 Dimes and 4 Quarter.

And that add up to 27.

1.00-1.00 of Quarter = 4 Quarter.

so 31 worth a total of $4.30.

So that's 23 Dimes and 8 Quarter.

Check Work:

23 Dimes = $2.30 and 8 Quarter = $2.00

$2.30 + $2.00 = 4.30

Hence, The Correct Answer is 23 Dimes and 8 Quarter.

~[ RevyBreeze }~

Answer:

i think its 16

Step-by-step explanation:

Answer:

(−∞,5)

Step-by-step explanation:

-2x>-10

x<5

Answer:

$57.45

Step-by-step explanation:

102.45=2x-12.45

2x= 102.45+12.45

2x=114.90

x= 114.90/2

x=$57.45

Answer:

e=19.6h

Step-by-step explanation:

If in 21 hours, she earns 411.60 dollars, then we need to find how much she makes in ONE hour.

21 h            1 hour

--------- = ------------------

411.60 dollars    xdollars

To get from 21 to 1, I would have to divide by 21, right? So, do the same for the denominators.

411.60 / 21= $19.6

Now, since we know the unit rate, we can make an equation!

e=19.6h

Answer:

  ∠J = 60°

Step-by-step explanation:

The Law of Cosines tells you ...

  j² = k² +l² -2kl·cos(J)

Solving for J gives ...

  J = arccos((k² +l² -j²)/(2kl))

  J = arccos((14² +80² -74²)/(2·14·80)) = arccos(1120/2240) = arccos(1/2)

  J = 60°

_____

Additional comment

It is pretty rare to find a set of integer side lengths that result in one of the angles of the triangle being a rational number of degrees.

Answer:

60

Step-by-step explanation:

Answer:

The parent graph is translated 2 to the left and up 6 units.

Step-by-step explanation:

The +2 moves the  parent 2 units to the left and the + 6 moves it up 6 units.

Given :-

To Find :-

Solution :-

The equation of the line p is ,

[tex]\sf\blue{\longrightarrow}[/tex] y = 5/3x - 4

On comparing to slope intercept form of the line which is y = mx + c , we have ,

[tex]\sf\blue{\longrightarrow}[/tex] m = 5/3

Now as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be ,

[tex]\sf\blue{\longrightarrow} m_{\perp} = -3/5[/tex]

Now here the line q passes through the point (-10,-3) . So on using the point slope form of the line we get ,

[tex]\sf\blue{\longrightarrow} y - y_1 = m(x-x_1)[/tex]

[tex]\sf\blue{\longrightarrow}[/tex] y - (-3) = -3/5[ x-(-10)]

[tex]\sf\blue{\longrightarrow}[/tex] y +3 = -3/5(x+10)

[tex]\sf\blue{\longrightarrow}[/tex] y+3 = -3/5x - 6

[tex]\sf\blue{\longrightarrow}[/tex] y +9 = -3/5x

[tex]\sf\blue{\longrightarrow}[/tex] y = - 3/5x - 9

Hence the required answer is y = -3/5x - 9 .

Answer:

For Perpendicular lines you have to know

Step-by-step explanation:

Slope of P ×slope of q=-1 (always since they are perpned..)

so as P has the slope 5/3 in order to optain - 1 the slope of q should be negative of the inverse of p

so q solpe =-3/5 then lets try (5/3)×(-3/5)? =-1 yes

And be aware that you have to know the formula of straight line : y-ypoint=slope(x-xpoint) or y=ax+b

so y+3=-3/5(x+10) ===> y=-3/5x - 30/5 - 3

uniting the denominater ==>y=-3/5x - 45/5

so that q equation is :y=-3/5x - 9

Answer:

Their highest common factor is the number 9

Answer:

ababababababababbbababbbababbababaaaaaabababbababab

Step-by-step explanation:

hru and thank u for this question

Answer:

dsvrg

Step-by-step explanation:

Answer:

Step-by-step explanation:

To find out ∠B, we need to find out what is ∠A. We are given one clue that the outer angle of ∠A is 143°. Can we use this clue and find out ∠A? Let's find out!

Since we have found ∠A, we can now find ∠B.

Conclusion:

We have finally found out our answer and our answer is '∠B = 82°'.

[tex]GeniusUser[/tex]

Answer: no.

Explanation:

As an example, let's use y=2/3x-8.

In this formula, the 2/3 before the x I the slope of the problem. The -8 would be the y-intercept. You use this formula to find both of those to graph a line, you do not multiply the slope and the x together.

Answer:

22 , 34 , 124

Step-by-step explanation:

hope this helps!

Answer:

7,308,630

Step-by-step explanation:

Calculated it.

Answer:

x = 125

Step-by-step explanation:

Given equation:

[tex]\log_224-\log_23=\log_5x[/tex]

[tex]\textsf{Apply the Quotient log law}: \quad \log_ax - \log_ay=\log_a\frac{x}{y}[/tex]

[tex]\implies \log_2\left(\dfrac{24}{3}\right)=\log_5x[/tex]

[tex]\implies \log_28=\log_5x[/tex]

Rewrite 8 as 2³:

[tex]\implies \log_2(2^3)=\log_5x[/tex]

[tex]\textsf{Apply the Power log law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies 3\log_22=\log_5x[/tex]

[tex]\textsf{Apply log law}: \quad \log_aa=1[/tex]

[tex]\implies 3(1)=\log_5x[/tex]

[tex]\implies \log_5x=3[/tex]

[tex]\textsf{Apply log law}: \quad \log_ab=c \iff a^c=b[/tex]

[tex]\implies 5^3=x[/tex]

[tex]\implies x=125[/tex]

Answer:

Multiply the number in the parantheses by 3. Then subtract them.

Step-by-step explanation: