What is the greatest number of tens that can live in the tens house?

Answer: The volume of a rectangular prism is given by the formula V = lwh, where l, w, and h are the length, width, and height, respectively.

For the first rectangular prism, we have:

V1 = 5 x 7 x 1 = 35 cubic inches

For the second rectangular prism, we have:

V2 = 9 x 7 x 4 = 252 cubic inches

To find the total volume of the figure, we add the volumes of the two rectangular prisms:

V = V1 + V2 = 35 + 252 = 287 cubic inches

Therefore, the volume of the figure is 287 cubic inches.

Step-by-step explanation:

Length οf the smaller οf the twο missing sides (the secοnd leg) is 80

In mathematics, the Pythagοrean theοrem οr Pythagοras' theοrem is a fundamental relatiοn in Euclidean geοmetry between the three sides οf a right triangle. It states that the area οf the square whοse side is the hypοtenuse (the side οppοsite the right angle) is equal tο the sum οf the areas οf the squares οn the οther twο sides.

Let x be the length οf the smaller οf the twο missing sides (the secοnd leg). Then the length οf the larger missing side (the hypοtenuse) is (x + 2), since the twο sides are cοnsecutive even integers.

By the Pythagοrean theοrem, we have:

[tex]18^2 + x^2 = (x + 2)^2[/tex]

Simplifying and expanding the right side, we get:

[tex]324 + x^2 = x^2 + 4x + 4[/tex]

Subtracting x^2 frοm bοth sides, we get:

324 = 4x + 4

Subtracting 4 frοm bοth sides, we get:

320 = 4x

Dividing bοth sides by 4, we get:

x = 80

Therefοre, the length οf the smaller οf the twο missing sides (the secοnd leg) is 80.

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The current yield of the bond is 11.76% and the yield to call is 19.51%.

The current yield of the bond can be calculated using the following formula:

Current Yield = (Annual Interest Payment/Bond Price) * 100

In this case, the annual interest payment is 10% of the face value of the bond (5 * $100 = $500). The bond price is $41, so the current yield is 11.76%:

Current Yield = ($500/$41)*100 = 11.76%.

The bond is callable at 103 as of 2032, so the call premium is 103 – 41 = 62. This means that if the bond is called, the investor will receive an additional payment of $62 per bond (5 * $62 = $310). The yield to call is the total annual return the investor will receive if the bond is called:

Yield to Call = (Annual Interest Payment + Call Premium)/Bond Price * 100

In this case, the yield to call is:

Yield to Call = ($500 + $310)/$41 * 100 = 19.51%.

This means that if the bond is called in 10 years, the investor will receive an annual return of 19.51%.

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A DVD club charges nonmembers $20. 50 to purchase a DVD. Members pay $18 per DVD for a one-time membership cost of $25. The cost is the same for members and nonmembers on the first purchase is 10.

Let's call the number of DVDs "d". For non-members, the cost of purchasing d DVDs is:

Cost for non-members = 20.50d

For members, the cost of purchasing d DVDs is:

Cost for members = 25 + 18d

We want to find the value of d for which the cost is the same for members and non-members. In other words, we want to find the value of d that satisfies the equation:

20.50d = 25 + 18d

To solve for d, we can start by subtracting 18d from both sides of the equation:

2.50d = 25

Then, we can divide both sides by 2.50:

d = 10

Therefore, the cost will be the same for members and non-members on the first purchase if the number of DVDs purchased is 10.

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As per the given distance, the angle that is made by the ramp with the ground is 19.1 degrees

Let's call the angle we're trying to find theta (θ). We can use the tangent function to calculate θ, as follows:

tan(θ) = opposite / adjacent

We know the opposite side (height of the ramp) is 3.5ft, and the adjacent side (distance along the ground) is 10ft. Plugging these values into the tangent equation, we get:

tan(θ) = 3.5 / 10

We can solve for θ by taking the inverse tangent (also known as arctan) of both sides:

θ = arctan(3.5 / 10)

Using a calculator, we find that θ is approximately 19.1 degrees. Therefore, the ramp makes an angle of 19.1 degrees with the ground.

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The percentage of college seniors' undergraduate major that is engineering is 36.25%.

To calculate the percentage of college seniors' undergraduate major that is engineering, we need to find the proportion of students who majored in engineering out of the total number of students surveyed.

We see that out of the 400 college seniors surveyed, 145 majored in engineering. Therefore, the proportion of students who majored in engineering is 145/400. To convert this proportion to a percentage, we multiply it by 100. So, (145/400) x 100 = 36.25%.

Therefore, 36.25% of the college seniors surveyed had an undergraduate major in engineering.

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The distance after 79 minutes is 11 miles.

We know that the distance can be modeled with a linear equation like:

y = ax + b

Where a is the slope and b is the y-intercept.

We know that if the line passes through two points (x₁, y₁) and (x₂, y₂) then the slope can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

Here we know the points (39, 45) and (61, 26.3)

Then we can write:

a = (26.3 - 45)/(61 - 39) = -0.85

So we can write:

y = -0.85*x + b

To find the value of b we can replace the values of one of the points, i will use (39, 45) to get.

45 = -0.85*39 + b

45 + 0.85*39 = b

78.15 = b

So the line is:

y =  -0.85*x + 78.15

The distance after 79 minutes is.

y =  -0.85*79 + 78.15

y = 11

The distance left is 11 miles.

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The area under the curve of the given function from x=1 to x=5 is -64.17.

The area under a curve is the area between the curve and the x-axis in a certain range. To calculate the area under a curve, we will use the definite integral of the function. The definite integral of a function f(x) from x=a to x=b is defined as

[tex]∫baf(x)dx[/tex]

For the given function f(x) = x^3 - 5x^2 + 2x + 8, the definite integral from x=1 to x=5 is

[tex]∫51(x^3 - 5x^2 + 2x + 8)dx = [x^4/4 - 5x^3/3 + x^2 - 8x]5[/tex]

Substituting x=1 and x=5 gives

[54 - 5(125)/3 + 25 - 8(5)] = -64.17

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we can tentatively conclude that the data is reasonably well-approximated by a normal distribution, but further analysis may be needed to confirm this conclusion.

To create a normal probability plot, we need to first sort the data in ascending order and then calculate the corresponding z-scores for each observation based on the normal distribution. We can then plot the observed z-scores against the expected z-scores on a normal distribution.

Here is the sorted data:

5.04  5.08  6.09  7.55  8.04  8.32  8.51  9.34  9.7   9.74  

10.49 10.94 11.2   11.68 12.39 12.9   14.05 14.64 28.34

And here are the corresponding z-scores calculated based on the normal distribution:

diff

-1.77 -1.74 -1.53 -1.17 -1.04 -0.96 -0.90 -0.72 -0.67 -0.65

-0.41 -0.29 -0.24 -0.17 0.06  0.21  0.48  0.65  3.09

The plot appears to be fairly linear, which suggests that the data could have come from a population that is normally distributed. However, there are a few points that deviate slightly from the line, particularly the two extreme points on the right-hand side. This suggests that there may be some skewness or outliers in the data that are causing deviations from normality.

Overall, we can tentatively conclude that the data is reasonably well-approximated by a normal distribution, but further analysis may be needed to confirm this conclusion.

the complete question is :

"The following data represent a random sample of the number of shares of a pharmaceutical​ company's stock traded for 20 days in 2000. Use a normal probability plot to assess whether the sample data could have come from a population that is normally distributed.

4.78 9.7 11.2 8.32 14.64

6.09 10.49 9.74 12.9 14.05

5.04 9.34 12.39 7.55 28.34

8.51 10.94 5.08 8.04 11.68

Please create a normal probability plot and interpret your findings."

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The interval of the expression x ≤ 3 and x ≥ -3 is (-3, 3).

To graph a linear equation with one variable, first solve the problem, then find the answer on the axis (number line), and place a point there. We have seen that graphs often provide information that the original equation would not have shown. The graphs of one-variable linear equations do not provide much, if any, information, but they provide as a basis for graphs with greater dimensions.

The given inequality is x ≤ 3 and x ≥ -3.

Since, the signs are less than and equal to and more than and equal to we use solid dots to represent the number 3 and -3 on the number line.

Also, the expression requires all the numbers between 3 and -3. Thus, the interval is:

(-3, 3).

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By answering the above question, we may state that expressions  Researcher A: Value Frequency 3  2 4  1

In mathematics, you can multiply, divide, add, or take away. The following is how an expression is put together: Numeric value, expression, and math operator The elements of a mathematical expression include numbers, parameters, and functions. It is feasible to use contrasting words and expressions. Any mathematical statement containing variables, numbers, and a mathematical action between them is known as an expression, often known as an algebraic expression. As an example, the expression 4m + 5 is composed of the expressions 4m and 5, as well as the variable m from the above equation, which are all separated by the mathematical symbol +.

Researcher A:

Value Frequency

3                 2

4                 1

8                  1

10               2

12              1

13                1

14               2

16                 2

17               2

19                 1

21                 1

22               2

24                2

25               2

26                   2

27             2

29               3

31                 2

32                    1

33                  2

34                    2

35                   1

37                   1

40                 1

44                 2

47                   1

Researcher B:

Value Frequency

3                 2

4                 1

6                      1

8               2

13              1

14               3

16             2

17                 1

18                  2

21                 3

22                 2

23              2

24              2

25              2

26            1

28                  1

29                 2

31              2

33                2

34               1

35                   1

41                2

42             1

44                   1

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Answer:

If Benny makes $20 an hour babysitting, his 35% increase would be:

35% of $20 = 0.35 x $20 = $7

This means that Benny could make an extra $7 per hour if he babysits an extra kid. Therefore, his new hourly wage would be:

$20 + $7 = $27

So, if Benny babysits an extra kid, he could make $27 per hour.

Step-by-step explanation:

Answer:

4 th option bcoz [tex]x^{y+2}=x^{y}x^{2[/tex]

Nikki applied to 3x colleges.

To determine the number of colleges Nikki applied to, we need to multiply the number of colleges Diego applied to by 3. Hence, the answer is represented by the mathematical expression 3x.

In this problem, 'x' represents the number of colleges Diego applied to. Nikki, on the other hand, applied to 3 times as many colleges as Diego did.

So, to find out the total number of colleges Nikki applied to, we multiply the number of colleges Diego applied to ('x') by 3.

Hence, the correct mathematical expression for the number of colleges Nikki applied to would be 3x.

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Answer:

See below.

Step-by-step explanation:

Please check the assumptions.  I did not see a graph, so made assumptions in the calculations,

Given that for 10 guests, the total cost is $20, we can calculate a rate of $2/guest ( the unit rate).  This seems too inexpensive, even for a hot dog and soft drink.  But going on that, we can establish the relationship between x (the number of guests) and y (the total cost) as y = ($2/guest)*x.

The list of numbers does not provide a clear undertanding of what is being requested,  The attached spreadheet calculates a number of guest options based on a rate of $2/guest.  The area in green are the second list of values based on the numbers of guests.

Answer: For each increase in budget by $1 million, the predicted score increases by 0.145 points.

Answer:

Step-by-step explanation:

wheres the table

The standard deviation of her total weekly pay is approximately $262.25 and the mean is $1075

Let X be the number of cars the salesperson sells in a week. Then, X follows a normal distribution with mean μ = 3.1 and standard deviation σ = 1.1.

The total weekly pay Y is given by the equation:

Y = $300 + $250X

Using the properties of means and variances of linear combinations of random variables, we can find the mean and standard deviation of Y as follows:

Mean of Y:

E(Y) = E($300 + $250X) = $300 + $250E(X) = $300 + $250(3.1) = $1075

Therefore, the mean of her total weekly pay is $1075.

Standard deviation of Y:

Var(Y) = Var($250X) = $250^2Var(X) = $250^2(1.1^2) = $68,750

Since the standard deviation is the square root of the variance, we have:

SD(Y) = sqrt($68,750) ≈ $262.25

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Answer:

x = 4

Step-by-step explanation:

- 6 + [tex]\frac{x}{4}[/tex] = - 5 ( add 6 to both sides )

[tex]\frac{x}{4}[/tex] = 1 ( multiply both sides by 4 to clear the function )

x = 4

The rectangular sidewalk for Liam to build the pathway, [tex]36[/tex] stones are required.

The rectangular shape in two dimensions has four aspects, four corners, & four sharp angles (90°). Equal and equal opposing sides make form a rectangle. As a two-dimensional form, the rectangles comprises length and breadth just like its 2 components.

Because a square is indeed a parallelogram with all specific corners at right angles, every square is also a rectangle. To be a square, a rectangle's sides must all have the same length, hence not all rectangles are squares.

Area of the walkway [tex]=length * width[/tex]

[tex]24*6=144[/tex] square feet

Area of each stone [tex]= length of each side * width of each side[/tex]

[tex]=2ft*2ft=4[/tex] square feet

Number of stones needed [tex]=\frac{Area of walkway }{Area of each stone}[/tex]

Number of stones needed [tex]=\frac{144}{4}=36[/tex] stones

Therefore, Liam will need [tex]36[/tex] stones to make the walkway.

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The formula that expresses the fact that f(x, y) is a distance 8 from the origin can be found using the distance formula for two points on the coordinate plane, (0, 0) and (x, y).

The distance formula is given by d = √(x2−x1)2+(y2−y1)2where (x1, y1) = (0, 0) and d = 8. Thus, we have8 = √(x2−0)2+(y2−0)2Squaring both sides gives8^2 = (x2−0)2+(y2−0)2which simplifies to64 = x2+y2

Therefore, the formula that expresses the fact that f(x, y) is a distance 8 from the origin isx2+y2= 64.

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The value of the required number is - 10  

To find the unknown number represent the number with a variable 'x' and form a linear equation according to the condition given in the problem.

Solve the resultant equation for the value variable 'x' by adding or subtracting the same number on both sides.

Here we have

A number decreased by 16 and the result was -26.

Let 'x' be the number

According to the given data,

=> x - 16 = - 26

Add 16 on both sides

=> x - 16 + 16 = - 26 + 16

=> x = - 10

Hence,

The value of the required number is - 10  

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Check the picture below.

[tex]\textit{Law of sines} \\\\ \cfrac{\sin(\measuredangle A)}{a}=\cfrac{\sin(\measuredangle B)}{b}=\cfrac{\sin(\measuredangle C)}{c} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{39}{\sin(53^o)}=\cfrac{JN}{\sin(65^o)}\implies \cfrac{39\sin(65^o)}{\sin(53^o)}=JN\implies 44.3\approx JN \\\\\\ \cfrac{39}{\sin(53^o)}=\cfrac{JS}{\sin(62^o)}\implies \cfrac{39\sin(62^o)}{\sin(53^o)}=JS\implies 43.1\approx JS[/tex]

Make sure your calculator is in Degree mode.

The Half-Life of the material is 13.86 hours. The mass of the material remaining at any time t can be expressed as:
M(t) = 50e^(-0.05t), where t is measured in hours.

The amount of time needed for a number (of material) to decrease to half of its original value is known as the half-life (symbol t12). In nuclear physics, the phrase is frequently used to indicate how rapidly unstable atoms decay radioactively or how long steady atoms last.

The mass of the material after 4 hours is M(4) = 50e^(-0.2) ≈ 31.4 grams. The half-life of the material can be found by solving for when M(t) = 25 grams:
t = ln(2)/0.05 ≈ 13.86 hours.

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Method 1: Factoring

m^2 + 7m + 10

We need to find two numbers that multiply to 10 and add up to 7. These numbers are 2 and 5.

m^2 + 2m + 5m + 10

(m + 2)(m + 5)

n^2 + 9n + 18

We need to find two numbers that multiply to 18 and add up to 9. These numbers are 3 and 6.

n^2 + 3n + 6n + 18

(n + 3)(n + 6)

p^2 - 6p + 8

We need to find two numbers that multiply to 8 and add up to -6. There are no such numbers, so we cannot factor this quadratic.

Method 2: Quadratic Formula

m^2 + 7m + 10

a = 1, b = 7, c = 10

m = (-b ± sqrt(b^2 - 4ac)) / 2a

m = (-7 ± sqrt(7^2 - 4(1)(10))) / 2(1)

m = (-7 ± sqrt(9)) / 2

m = -5 or -2

n^2 + 9n + 18

a = 1, b = 9, c = 18

n = (-b ± sqrt(b^2 - 4ac)) / 2a

n = (-9 ± sqrt(9^2 - 4(1)(18))) / 2(1)

n = (-9 ± sqrt(9)) / 2

n = -3 or -6

p^2 - 6p + 8

a = 1, b = -6, c = 8

p = (-b ± sqrt(b^2 - 4ac)) / 2a

p = (6 ± sqrt(6^2 - 4(1)(8))) / 2(1)

p = (6 ± sqrt(16)) / 2

p = 2 or 4

Therefore, the solutions to the quadratics are:

m^2 + 7m + 10 = (m + 2)(m + 5) or m = -5 or -2

n^2 + 9n + 18 = (n + 3)(n + 6) or n = -3 or -6

p^2 - 6p + 8 = (p - 2)(p - 4) or p = 2 or 4

The 90% confidence interval for the difference in mean response times between the cell phone and control group is given as follows:

(12.6, 82.2).

The estimate of the differences is given as follows:

585.3 - 537.9 = 47.4.

The standard error for the distribution of each sample is given as follows:

Hence the standard error for the distribution of differences is given as follows:

sqrt(16.4² + 12.8²) = 20.8.

The critical value, using a t-distribution calculator, for a two-tailed 90% confidence interval, with 27 + 27 - 2 = 52 df, is t = 1.6747.

The lower bound of the interval is given as follows:

47.4 - 1.6747 x 20.8 = 12.6.

The upper bound of the interval is of:

47.4 + 1.6747 x 20.8 = 82.2.

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Answer:

Triangular base

Step-by-step explanation:

It possesses all attributes except from triangular base

Answer:

[tex]x=\frac{5}{2},\:x=3[/tex]

Step-by-step explanation:

[tex]\mathrm{Factor\:}2x^2-11x+15[/tex]

[tex]\mathrm{Break\:the\:expression\:into\:groups}[/tex]

[tex]\left(2x^2-5x\right)+\left(-6x+15\right)[/tex]

[tex]\mathrm{Factor\:out}\:x\:\mathrm{from}\:2x^2-5x:\quad \:x\left(2x-5\right)[/tex][tex]\mathrm{Factor\:out}\:-3\:\mathrm{from}\:-6x+15:\quad \:-3\left(2x-5\right)[/tex]

[tex]x\left(2x-5\right)-3\left(2x-5\right)[/tex]

[tex]\mathrm{Factor\:out\:common\:term\:}2x-5[/tex]

[tex]\left(2x-5\right)\left(x-3\right)[/tex]

[tex]\mathrm{Using\:the\:Zero\:Factor\:Principle:\quad \:If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0[/tex]

[tex]2x-5=0\quad \mathrm{or}\quad \:x-3=0[/tex]

[tex]\mathrm{Solve\:}\:2x-5=0:\quad x=\frac{5}{2}[/tex]

[tex]\mathrm{Solve\:}\:x-3=0:\quad x=3[/tex]

[tex]\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}[/tex]

[tex]x=\frac{5}{2},\:x=3[/tex]

Step-by-step explanation:

1. Calculate the mean for each sample.

Sample #

1

234

2

3

5

6

7

8

9

O ACCESS Virtual Learning 2022

Sample Items

(1, 1, 2, 0)

(2, 2, 0, 1)

(1, 1, 1, 2)

(2,0, 1, 0)

(2, 2, 0, 1)

(1, 1, 2, 3)

(3, 2, 0, 0)

(1, 1, 1, 1)

(3, 1, 1, 1)

x