What is the density of a bowling ball with a mass of 3.0 kg and a volume of 0.0050 m 3 ?

0.002 kg/m 3
0.015 kg/m 3
500 kg/m 3
600 kg/m 3

Answers

Answer 1

Answer:

600 kg/m³

Explanation:Formula to use

d = m/v

[] d is the density

[] m is the mass

[] v is the volume

Solving

[Formula] d = m/v

[Plug-in] d = 3/0.0050

[Divide] d = 600 kg/m³

Answer

0.002 kg/m³

0.015 kg/m³

500 kg/m³

600 kg/m³

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer 2

Answer:

[tex]\boxed {\boxed {\sf 600 \ kg/m^3}}[/tex]

Explanation:

We are asked to find the density of a bowling ball. The density of an object is its mass per unit volume. It is calculated by dividing the mass by the volume.

[tex]\rho= \frac{m}{v}[/tex]

The mass of the bowling ball is 3.0 kilograms and the volume is 0.0050 cubic meters.

m= 3.0 kg v= 0.0050 m³

Substitute the values into the formula.

[tex]\rho= \frac{3.0 \ kg}{0.0050 \ m^3}[/tex]

Divide.

[tex]\rho= 600 \ kg/m^3[/tex]

The density of the bowling ball is 600 kilograms per cubic meter.


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(1 point)

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Both directions of the reaction have stopped.

Answers

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So, dynamic equilibrium is a chemical equilibrium, which occurs when two reversible processes happen at the same speed in both directions. In this way, the concentrations of the reactants and products remain constant over time.

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I hope it's help u

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Answers

The molarity of the resulting solution obtained by mixing 658 mL of 0.250 M HCl solution with 325 mL of 0.600 M HCl solution is 0.366 M

We'll begin by calculating the number of mole of HCl in each solution. This can be obtained as follow:

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For solution 2:

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Next, we shall determine the total mole of HCl in the final solution. This can be obtained as follow:

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Mole of HCl in solution 2 = 0.195 mole

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Volume of solution 2 = 0.325 L

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Total Volume = 0.983 L

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Answers

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

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Numbers 1,2,3, and 5 are all O
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Hope it helps!

Brainliest pls!

Follow me! :)

Answer:

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[tex] \: \: \: \: \: \: [/tex]

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[tex] \: \: \: \: \: [/tex]

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Answer:

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Answers

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Answers

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