What are the domain and range of the function represented by the set of
ordered pairs?
{(-6, 12).(-3,-2), (1,0), (14,-4)}

What Are The Domain And Range Of The Function Represented By The Set Ofordered Pairs?{(-6, 12).(-3,-2),

Answers

Answer 1

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Domain = { -6 , -3 , 1 , 14 }

Range = { -4 , -2 , 0 , 12 }

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Thus the correct answer is (( B )) .

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Answer 2

Here, the domain and range of the function represented by the set of ordered pairs {(-6, 12).(-3,-2), (1,0), (14,-4)} is

{-6, -3, 1, 14} and {12, -2, 0, -4} respectively.

What is range?

We know that the range refers to all possible values of y, and the domain refers to all possible values of x.

How to solve it?

For (-6, 12), the x value = -6 and the y value = 12.

For (-3, -2), the x value = -3 and the y value = -2.

For (1, 0), the x value = 1 and the y value = 0.

For (14, -4), the x value = 14 and the y value = -4.

So, the domain is {-6, -3, 1, 14} and the range is {12, -2, 0, -4}.

Therefore the domain and range of the function represented by the set of ordered pairs {(-6, 12).(-3,-2), (1,0), (14,-4)} is

{-6, -3, 1, 14} and {12, -2, 0, -4} respectively. So, option B is correct.

Learn more about the range and domain here -

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Related Questions

Caleb runs laps at the local track. The circular track measures 70 feet across its diameter. How many feet will Caleb run if he stays on the outer edge of the track? (Round to the nearest whole number.)

Answers

Answer:

Caleb will run 237 ft

Step-by-step explanation:

Answer:

Caleb will run 220 ft.

Step-by-step explanation:

70 * pi = 220 ft

Andrew sold 45 tickets to the school play and Sara sold 60 tickets. Which of the following is equivalent to the ratio of the number of tickets Andrew sold to the number of tickets Sara sold?
a. 6:8
b. 8:10
c. 6:10
d. 10:12

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Answer:

a

Step-by-step explanation:

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An experimenter flips a coin 100 times and gets 58 heads. Find the 90% confidence interval for the probability of flipping a head with this coin.

a. [0.483, 0.677]
b. [0.383, 0.627]
c. [0.533, 0.538]
d. [0.483, 0.477]
e. [0.403, 0.677]
f. None of the above

Answers

Answer:

The correct option is f.

Step-by-step explanation:

The (1 - α)% confidence interval for the population proportion is:

[tex]CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

It is provided that an experimenter flips a coin 100 times and gets 58 heads.

That is the sample proportion of heads is, [tex]\hat p=0.58[/tex].

The critical value of z for 90% confidence level is, z = 1.645.

*Use a z-table.

Compute the 90% confidence interval for the probability of flipping a head with this coin as follows:

[tex]CI=\hat p\pm z_{\alpha/2}\cdot\sqrt{\frac{\hat p(1-\hat p)}{n}}[/tex]

     [tex]=0.58\pm 1.645\cdot\sqrt{\frac{0.58\times(1-0.58)}{100}}\\\\=0.58\pm 0.0812\\\\=(0.4988, 0.6612)\\\\\approx (0.499, 0.661)[/tex]

Thus, the 90% confidence interval for the probability of flipping a head with this coin is (0.499, 0.661).

The correct option is f.

In southern California, a growing number of individuals pursuing teaching credentials are choosing paid internships over traditional student teaching programs. A group of eight candidates for three local teaching positions consisted of five who had enrolled in paid internships and three who enrolled in traditional student teaching programs. All eight candidates appear to be equally qualified, so three are randomly selected to fill the open positions. Let Y be the number of internship trained candidates who are hired. Find the probability that two or more internship trained candidates are hired.

Answers

Answer:

The required probability = 0.7143

Step-by-step explanation:

From the information given:

From a group of eight candidates

The no. of candidates that enrolled in internships = 5

The no. of candidates that enrolled in teaching = 3

Also, supposed all the eight candidates are equally qualified;

Then, Let assume that:

Y to represent the number of internship trainee candidates hired.

N to represent no. of candidates in a group = 8

r to represent those who enrolled in paid internship = 5

Now, N - r = 3 (for those who enrolled in traditional teaching program)

Suppose; n represent the positions for local teaching which is given as 3;

Then; selecting 3 from 8 whereby some enrolled in internships and some in traditional teaching programs;

Then,  let assume Y is a random variable that follows a hypergeometric distribution; we have:

[tex]p(Y = y) = \left \{ {{\dfrac{ \bigg (^r_y \bigg)\bigg (^{N-r}_{n-y} \bigg) }{ \bigg ( ^N_n \bigg) } } _\atop { ^{0, otherwise} } } \right.[/tex]

[tex]p(Y = y) = \left \{ {{\dfrac{ \bigg (^5_y \bigg)\bigg (^{3}_{3-y} \bigg) }{ \bigg ( ^8_3 \bigg) } } } } \right, y= 0,1,2,3[/tex]

Thus, the probability that two or more internship trained candidates are hired can be computed as:

p(Y ≥ 2) = p(Y=2) + p(Y =3)

[tex]p(Y \geq 2) = \dfrac{ \bigg ( ^5_2\bigg) \bigg ( ^3_1 \bigg)}{\bigg (^8_3 \bigg)} + \dfrac{\bigg (^5_3 \bigg) \bigg (^3_0 \bigg)}{\bigg ( ^8_3\bigg)}[/tex]

[tex]p(Y \geq 2) = \dfrac{40}{56}[/tex]

[tex]\mathbf{p(Y \geq 2) = 0.7143}[/tex]

A city planner wants to construct a new road south of Town Hall and north of the Community Center. The city planner currently has the road plotted as a set of parallel lines as shown on the map. However, the current plan for the road would cover a historical marker. ( please help )


Which transformation should the city planner apply to this road so that it preserves the historical marker and still passes south of Town Hall and north of the Community Center?

translate the road up 2 units

translate the road up 4 units

translate the road down 2 units

translate the road down 4 units

Answers

Answer:

translate the road down 4 units

Hope this helps

Tell whether the angles are complementary or supplementary. Then find the value of x.

Answers

Answer:

Supplementary angles,

x = 50

Step-by-step explanation:

These angles are supplementary, meaning that they add up to form a 180-degree angle or a straight line.

Knowing this, now form and solve the equation,

76 + 2x + 4 = 180

Combine like terms,

76 + 2x + 4 = 180

80 + 2x = 180

Inverse operations,

80 + 2x = 180

-80           -80

2x = 100

/2    /2

x = 50

Example of a balance point

Answers

a home's loss of heat is equal to heat created in the home or when both sides of a seesaw are at an equal level.

I WILL MARK BRAINIEST
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Answers

B) Side length of B to side length of C is 4:5.

Perimeter of C is 280, so let's put that into the side length of C's place:

4:280

But the 4 also would have to change so let's figure out how much we multiplied 5 by to get 280:

280 / 5 = 56

So let's do 4 x 56 = 224

Our new ratio is 224:280

Therefore the perimeter of mirror B is 224cm.

C) Side length of A to side length of B is 3:4.

We know the perimeter of B from the previous part (224) so let's put that in the 4s place:

3:224

But we also have to change 3, so let's figure out how much we multiplied 4 by to get 224:

224 / 4 = 56

Therefore to determine A's perimeter we do 3 x 56 = 168.

Mirror A's perimeter is 168cm.

D) The side length of mirror A is the perimeter divided by 4 (as they are squares).

168 / 4 = 42. Side length of mirror A is 42cm.

E) Area of a square is side length squared, so the area of mirror A is 42².

42² = 1,764cm².

For what value of b, would the equation 34(12x−9)+b4=5−3(2−3x) have infinitely many solutions?

Answers

Answer:

23

Step-by-step explanation:

A normal random variable with mean and standard deviationboth equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?

Answers

Answer:

0.57142

Step-by-step explanation:

A normal random variable with mean and standard deviation both equal to 10 degrees Celsius. What is the probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit?

We are told that the Mean and Standard deviation = 10°C

We convert to Fahrenheit

(10°C × 9/5) + 32 = 50°F

Hence, we solve using z score formula

z = (x-μ)/σ, where

x is the raw score = 59 °F

μ is the population mean = 50 °F

σ is the population standard deviation = 50 °F

z = 59 - 50/50

z = 0.18

Probability value from Z-Table:

P(x ≤59) = 0.57142

The probability that the temperature at a randomly chosen time will be less than or equal to 59 degrees Fahrenheit

is 0.57142

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Answers

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a numerical or constant quantity placed before and multiplying the variable in an algebraic expression.

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Step-by-step explanation:

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Answers

No he is not correct .
Break apart the number 8,184
You will get
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The numbers we are comparing are 8000 and 80

80 x 10 = 800

The number we are looking for is 8000

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Step-by-step explanation:

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Answers

Answer:

14.49272

Step-by-step explanation:

16.852 × 0.86 = 14.49272

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

I believe the coefficient should be 7

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Answers

Answer:

2x2x7x8x5x3

=2*x2*x7*x8*x5*x3

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I think

Question 1 (1 point)
Mr. Whittaker had 24 bags of marbles. If 1/4 were red and 3/8 were yellow. How many were neither red or yellow
6
15
10
9

Answers

Answer:

the answer is 9

Step-by-step explanation:

3/8 = 9

1/4=6

9+6=15

24-15=9

so 9 is your answer

DONT FORGET TO MARK BRAINLIEST

What is the prime factorization of 5? Enter your answer as a product of prime numbers, like 2 x 3, or as a single prime number, like 17​

Answers

Answer:

The prime factorization of 5 is 5 x 1

Step-by-step explanation:

5 is a prime number but the only factors that make up 5 are 5 and 1

Hope this helps!

If point S is located at (0, 0), point T is located at (0, 6), point U is located at (12, 0), and point V is located at (0, 10), what are the coordinates of point W that makes

Answers

Answer:

(20,0)

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Answer:29045 is the answer

Step-by-step explanation:

A local zoo has two large snakes. The anaconda is currently 5.23 meters long and grows
1.27 meters every month. The python is 4.76 meters long and grows 2.04 meters per month.
How many months ( ) m does the zookeeper need to wait for the two snakes to be the
same length?

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Answers

for the anaconda  5.23 + 1.27 m  where m is the number of months,  and the total length is in meters

The anaconda starts at 5.23 meters and grows 1.27 meters each month for m months

for the python 4.76 + 2.04m   where m is the number of months, l is the length of the python in meters

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Evaluate -3- (-4) - (-2) + 1.

Answers

Answer:

4

Step-by-step explanation:

-3+4+2+1=4

In a certain assembly plant, three machines, B1, B2, B3, make 30%, 45%, and 25%, respectively, of the products. It is known from past experience that 2%, 3%, and 2% of the products made by each machine, respectively, are defective.
A. Suppose that a finished product is randomly selected. What is the probability that it is defective?
B. If a product were chosen randomly and found to be defective, what is the probability that it was made by machine B3.

Answers

Answer:

a. The probability that the finished product selected is defective is 2.45%.

b. The probability that product chosen randomly was defective and made by machine B3 is 20.41%.

Step-by-step explanation:

Let A represents the defective product.

We also have the following from the question:

P(B1) = Probability or percentage of the made by machine B1 = 30%, or 0.30

P(B2) = Probability or percentage of the made by machine B2 = 45%, or 0,45

P(B3) = Probability or percentage of the made by machine B3 = 25%, or 0.25

P(A/B1) = Probability or percentage of product B1 that is defective = 2%, or 0.02

P(A/B2) = Probability or percentage of product B2 that is defective = 3%, or 0.03

P(A/B3) = Probability or percentage of product B3 that is defective = 2%, or 0.02

We can therefore proceed as follows:

A. Suppose that a finished product is randomly selected. What is the probability that it is defective?

To determine this, the rules of elimination is applied and we have:

P(A) = (P(B1) * P(A/B1)) + (P(B2) * P(A/B2)) + (P(B3) * P(A/B3)) ………… (1)

Where;

P(A) = Probability that the selected product is defective = ?

Substitutes the values defined above into equation (1), we have:

P(A) = (0.30 * 0.02) + (0.45 * 0.03) + (0.25 * 0.02)

P(A) = 0.006 + 0.0135 + 0.005

P(A) = 0.0245, or 2.45%

Therefore, the probability that the finished product selected is defective is 2.45%.

B. If a product were chosen randomly and found to be defective, what is the probability that it was made by machine B3.

To calculate this, the Bayes’ rule is employed as follows:

P(B3/A) = (P(B3) * P(A/B3)) / [(P(B1) * P(A/B1)) + (P(B2) * P(A/B2)) + (P(B3) * P(A/B3))] = (P(B3) * P(A/B3)) / P(A)  ………….... (2)

Where;

P(B3/A) = The probability that product chosen randomly was defective and made by machine B3 = ?

Also, from the values already defined and obtained in part A, we have:

P(B3) = 0.25

P(A/B3) = 0.002

P(A) = 0.0245

Substituting the values into equation (2), we have:

P(B3/A) = (0.25 * 0.02) / 0.0245

P(B3/A) = 0.005 / 0.0245

P(B3/A) = 0.2041, or 20.41%

Therefore, the probability that product chosen randomly was defective and made by machine B3 is 20.41%.

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