Two uniformly charged, infinite, nonconducting planes are parallel to a yz plane and positioned at x " #50 cm and x " )50 cm. The charge densities on the planes are #50nC/m2 and )25 nC/m2 , respectively. What is the magnitude of the potential difference between the origin and the point on the x axis at x " )80 cm? (Hint: Use Gauss’ law.)

Answers

Answer 1

Two uniformly charged, infinite, nonconducting planes are parallel to a yz plane and positioned at x = -50 cm and x = +50 cm. The charge densities on the planes are -50 nC/m² and +25 nC/m², respectively. What is the magnitude of the potential difference between the origin and the point on the x axis at x = +80 cm? (Hint:Use Gauss’ law.)

Answer:

ΔV = 2520 V

Step-by-step explanation:

We are given;

Charge density 1; σ1 = -50 nC/m² = -50 × 10^(-9) nC/m²

Charge density 2; σ2 = +25 nC/m² = +25 × 10^(-9) nC/m²

Now, formula for electric field strength is;

E = -(½ε)(|σ1| ± |σ2|)

ε is vacuum permittivity with a constant value as 8.85 × 10^(−12) C²/N.m²

|σ1| and |σ2| means we are taking the absolute values and would therefore not use the negative sign attached to them.

Now, in between x = 0 cm(0 m) and 50 cm (0.5 m), electric field generated by both charge densities would be in the same direction and thus;

E_in = -(½ε)(|σ1| + |σ2|)

E_in = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) + (25 × 10^(-9))]

E_in = -4200 V/m

In contrast, when x ≥ 50 cm (0.5 m), electric field generated by both charge densities would be in opposite directions and thus;

E_out = -(½ε)(|σ1| - |σ2|)

E_out = -(½ × 8.85 × 10^(−12)) × [(50 × 10^(-9)) - (25 × 10^(-9))]

E_out = 1400 V/m

The magnitude of the potential difference from the origin to x = 80 cm(0.8 m) is calculated as attached;

From the attachment, we see that;

ΔV = 2520 V

Two Uniformly Charged, Infinite, Nonconducting Planes Are Parallel To A Yz Plane And Positioned At X

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Step-by-step explanation:

Hi there !

144 | 2

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Process of elimination:

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Answers

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Answer:

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Step-by-step explanation:

Divide 14 by -7, then plug in the result(-2) in place of x.  Run this new equation(-7*-2=14) through your calculator to be sure it's correct.

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

A teacher instituted a new reading program at school. After 10 weeks in the​ program, it was found that the mean reading speed of a random sample of 19 second grade students was 90.7 wpm. What might you conclude based on this​ result? Select the correct choice below and fill in the answer boxes within your choice. ​(Type integers or decimals rounded to four decimal places as​ needed.)

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Complete question is;

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Answer:

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Step-by-step explanation:

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Sample size; n = 19

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

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===================================================

Explanation:

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Step-by-step explanation:

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Ok:

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

Del Gato Clinic's cash account shows a $11,589 debit balance and its bank statement shows $10,555 on deposit at the close of business on June 30. Outstanding checks as of June 30 total $1,829. The June 30 bank statement lists a $16 bank service charge. Check No. 919, listed with the canceled checks, was correctly drawn for $467 in payment of a utility bill on June 15. Del Gato Clinic mistakenly recorded it with a debit to Utilities Expense and a credit to Cash in the amount of $476. The June 30 cash receipts of $2,856 were placed in the bank's night depository after banking hours and were not recorded on the June 30 bank statement.

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Answer:

Adjusted bank balance $11,582

Adjusted book balance $11,582

Step-by-step explanation:

Preparation of bank reconciliation statements

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Add: Bank deposit $2,856

Total $13,411

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Adjusted bank balance $11,582

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