Two steel guitar strings have the same length. String A has a diameter of 0.489 mm and is under 410 N of tension. String B has a diameter of 1.27 mm and is under a tension of 809 N. Calculate the ratio of the wave speeds, vA/vB, in these two strings.

Answers

Answer 1

Answer:

Explanation:

vA / vB = √(TA/(m/L)) / √(TB/(m/L))

The lengths are the same, so the L divides out to 1

The material is identical so the mass will be directly proportional to the cross sectional area of the string

vA / vB = √(TA/(πdA²/4)) / √(TB/(πdB²/4))

π/4 is common so divides out to 1

vA / vB = √(TA/dA²) / √(TB/dB²)

vA / vB = √(410/0.489²) / √(809/1.27²)

vA / vB = 41.407 / 23.396

vA / vB = 1.8488961...

vA / vB = 1.85


Related Questions

Someone help me please !!!! Will mark Brianliest !!!!!!!!!!!!!!!!

Answers

Strain it , the sand didn’t dissolve in the solution it just settled in the bottom

Answer:

Decant it.

Explanation:

Pour the water/sugar solution off the sand. When the sand wants to start coming out as well, Stop and add fresh water to the beaker, stir to rinse the remaining solution into a less concentrated solution and decant again.

Repeat the dilution process until the mix is essentially sand and water, then drive the remaining water from the sand by drying.

14. Earthworms are crucial for forming soil. As they search for food by digging tunnels,
they expose rocks and minerals to the effects of weathering. Over time, this process
creates new soil. Worms are not the only living things that help to create soil. Plants
also play a part in the weathering process. As the roots of plants grow and seek out
water and nutrients, they help to break large rock fragments into smaller ones. Have
you ever seen a plant growing in a sidewalk? As the plants grows, its roots spread into
tiny cracks in the sidewalk. These roots apply pressure to the cracks, and, over time,
the cracks become larger, ice wedging can occur more readily. As the cracks expand,
more water can flow into them. When the water freezes, it expands and presses against
the walls of the cracks, which makes the cracks larger. Over time, the weathering
caused by water, plants, and worms help to form soil. QUESTION: Ice wedging, as
described in the passage, is an example of which of the following?
A mechanical weathering
B. Oxidation
C. chemical weathering
D. Hydrolysis

Answers

Ice wedging, as described in the passage, is an example of mechanical

weathering.

Mechanical weathering is also known as physical weathering and it

involves the breaking of rock into smaller particles without causing changes

in the chemical properties.Mechanical weathering is usually carried through

physical processes such as freezing and thawing etc.

In this scenario, we were told that water freezes, expands and presses

against the walls of the crack thereby breaking into smaller parts which is a

physical process hence mechanical weathering being present.

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An ammeter has azero offset error This fault will affect

Answers

Answer:

An ammeter has a zero offset error. This fault will affect. neither the precision nor the accuracy of the readings. only the precision of the readings.

The accuracy of the present measurement will be impacted by an ammeter's zero offset inaccuracy, but the precision of the measurement will not change.

What is resistance?

Resistance is the obstruction of electrons in an electrically conducting material.

                                                                                         

voltage = current ×resistance

How accurate measurement or reading is may be determined by its accuracy. The measurements will be off because of zero inaccuracy.

Thus, The precision of the measurement would not alter if an ammeter made a mistake with its zero offsets, but the accuracy of the current measurement would be decreased.

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4. If a charged body is negatively charged, it has excess of _______

Answers

Answer:

Electrons

Explanation:

Electrons are negatively charged sub-atomic particles, therefore when a body's negatively charged, it means that there's more electrons than protons.

Who actually asked Abraham to sacrifice his son?

Answers

Answer:

Allah asked Abraham(Ibrahim)

2. Define Lightning conductor. How does it work?

Answers

In Building, there are a host of protective devices that are installed to protect lives and properties, one of them is the Lightning Conductor that  a metal rod mounted on a structure and intended to protect the structure from a lightning strike. It works on the principle of induction

Principle of Operation of Lightning Conductor

The lightning conductor works on the principle of induction:

When a charged cloud passes by the building hosting the Lightning conductor, it gets a charge opposite to that of the cloud through the process of induction. They are Typically made from copper material.

Most Lightening conductors are made from copper materials.

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Would you die if you take the car keys out of the ignition and throw them in the back seat while you coast down a mountain-side in an attempt to save fuel and look cool for the girl in said back seat.

Answers

Answer:

bro what.

Explanation:

... is this an actual physics question?

A wire that is 1.0 m long with a mass of 90 g is under a tension of 710 N. When a transverse wave travels on the wire, its wavelength is 0.10 m. What is the frequency of this wave? ​

Answers

Answer:

890 Hz

I hope you liked my answer. Thank You!

The gradual increase in activity over time is called

Answers

Answer:Progression is the way in which an individual should increase the load. It is a gradual increase either in frequency, intensity, or time or a combination of all three components.

Explanation:

the gradual increase in activity over time is called progression

Transverse waves move particles back and forth along the same direction in which the waves travel.
True false question.
True
False

Answers

Answer:

False, I am pretty sure.

Explanation:

Transverse waves are always characterized by particle motion being perpendicular to wave motion. ... As a sound wave moves from the lips of a speaker to the ear of a listener, particles of air vibrate back and forth in the same direction and the opposite direction of energy transport.


A gold fish weighing 13g has a speed of 8.8m/s. What is its Kinetic energy

Answers

Answer:

0.47 J

Explanation:

This is the question I need help with

Answers

Answer:

Explanation:

If we ASSUME that a CCW torque is positive

τ = 10sin135[8.0] - 16sin90[4.0] + 19sin160[3.0] = 12 N•m

as the result is positive, the net torque is CCW.

when do we say a curvilinear motion is accelerated?​

Answers

Answer:

There always is an acceleration in a curvilinear motion, as the velocity vector changes, so always.

A person is drinking a glass of soda with ice.
which option describes the relative kinetic energy of molecules in and above the soda in the glass?

A. in : least energy
above : intermediate and greatest energy

B. in : greatest energy
above : least energy

C. in : least energy
above : greatest energy

D. in least and intermediate energy
above : greatest energy ​

Answers

The relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

The relative kinetic energy of gas molecules increases with increase in the mean distance between the gas molecules.

Also, relative kinetic energy of gas molecules increases with in the temperature of the gas molecules and decreases with a decrease in the temperature of the of the gas molecules;

ΔK.E ∝ T

The ice in the soda lowers the temperature of the gas molecules, thereby reducing their average speed which in turn reduces the average kinetic energy of the gas molecules in the soda.

Above the soda in the glass, the concentration of the gas molecules is less and their mean distance is greatest when compared to inside the soda. This results to an increase in the speed of the gas molecules which increases their average kinetic energy.

Thus,  the relative kinetic energy of molecules in the soda is least energy and above the soda in the glass is greatest energy.

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An object falls through the air, gaining speed as it falls. A student claims th
new energy, and so it breaks the law of conservation of energy. Which stat
why the student is incorrect? (1 point)
Energy can be created without breaking the law of conservation
Energy is converted from other forms, not created.
O Equal and opposite amounts of other energy are also created.
O Speed is not related to energy in any way.

Answers

Answer:

Energy is converted from other forms, not created

Explanation:

The ball has a decrease in potential energy which allows the kinetic energy, and therefore speed, to  increase

If a rocket experiences an acceleration generated by the gravity force between the earth and itself, what is this acceleration if the rocket flies 1000 km above the ground and the Earth's radius is 6.378 * 10 ^ 6 * r m. We know the Earth has a mass of 5.97*10^ 24 kg(in m/s^ 2 , G=6.67*10^ -11 N(m/kg)^ 2 ) ?
a 8.97
b 7.32
c 9.81
d 5.5
e 11.45

Answers

This question involves the concepts of Gravitational Force and Weight force.

The value of acceleration is "b. 7.32 m/s²".

At the given height the weight of the rocket must be equal to the gravitational force between rocket and the Earth:

[tex]W=F_G\\mg=\frac{GmM}{R^2}\\\\g=\frac{GM}{R^2}[/tex]

where,

g = acceleration = ?

G = universal gravitational constant = 6.67 x 10⁻¹¹ N.m²/kg²

M = mass of earth = 5.97 x 10²⁴ kg

R = Radius of Earth + Height = 6.378 x 10⁶ m + 1 x 10⁶ m = 7.378 x 10⁶ m

Therefore,

[tex]g=\frac{(6.67\ x\ 10^{-11}\ N.m^2/kg^2)(5.97\ x\ 10^{24}\ kg)}{(7.378\ x\ 10^6\ m)^2}[/tex]

g = 7.32 m/s²

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Would it be possible to direct the speeds that a coaster will reach before its ever placed on a track?How?

Answers

Yes, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.

According the principle of conservation of energy, the total kinetic energy is equal to the total potential energy.

[tex]P.E _i + K.E_i = P.E_f + K.E_f \\\\mgh_i + \frac{1}{2} mv_i^2 = mgh_f + \frac{1}{2} mv_f^2\\\\gh_i + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\g(0) + \frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\\frac{1}{2} v_i^2 = gh_f + \frac{1}{2} v_f^2\\\\v_i^2 = 2gh_f + v_f^2\\\\v_i^2 - 2gh_f = v_f^2\\\\v_f = \sqrt{v_i^2 - 2gh_f}[/tex]

where;

[tex]v_i[/tex] is the initial velocity of the roller coaster[tex]v_f[/tex] is the final velocity of the roller coaster[tex]h_f[/tex] is maximum height reached by the roller coaster

Thus, it is possible to determine the final speed of the rollercoaster if the initial speed and the height to be reached are known.

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Identify the types of motion a) The movement of a snail on the ground b) The strings of the guitar c) The whirling of stone tied with a thread

Answers

Answer:

1. friction, gravity,

Explanation:

18. Why is the sun included in this model of the water cycle?

A. The water cycle takes place in the atmosphere and and since the sun can be
seen through the atmosphere it make the model more detailed
B. The sun is the driving force that provides the energy that keeps the water cycle
going
C. The water cycle takes place in the hydrosphere and since the sun makes it
possible for us to see everything it is included in the picture.
D. The sun is part of condensation and run-off

Answers

Answer:

b

Explanation:

1st grade common sense

Please answer the question in the picture, worth 25 points

I will report any links or false answers immediately

Answers

Answer:

Option C, increases and decreases

Explanation:

When an object making noise approaches you, the wave frequency increases leading to a higher pitch. Conversely, when it moves away from you or retreats, the wave frequency decreases leading to a lower pitch. This can be observed in ambulance sirens.

The diagram below shows a child pulling a 50.-kg friend on a 20 kg sled by applying a 300. newton force on the sled rope at an angle of 40 degrees with the horizontal. The sled moves at constant velocity as the person pulls with the 300 N force.

Answers

The vertical component of the applied force on the sled is 192.84 N.

The given parameters:

Mass of the friend, M = 50 kgMass of the sled, m = 20 kgApplied force, F = 300 NInclination of the force, θ = 40 ⁰

The vertical component of the 300 N force is calculated as follows;

[tex]F_y= F \times sin(\theta)\\\\F_y = 300 \times sin(40)\\\\F_y = 192.84 \ N[/tex]

Thus, the vertical component of the applied force on the sled is 192.84 N.

Your question is not complete, the missing part of the question is below:

The vertical component of the 300 N force is approximately?

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if the force acting on a body of mass 40 k.g is doubled by how much will the acceleration change​

Answers

Answer:

Explanation:

Ignoring friction, the acceleration will double

F = ma

2F = m(2a)

25.Figure 22.22 shows a plot
of potential versus position
along the x-axis. Make a plot
of the x-component of the
electric field for this situation.

Answers

The relationship between the potential and the electric field allows to find the results for the value of the electric field as a function of the distance is:

In the attachment we see the graph of the electric field as a function of distance.

Electric potential is defined by the change in potential energy of a test charge between two points, between the value of the test charge.

          dV = - E . ds

          E = [tex]- \frac{dV}{ds} \ \hat s[/tex]  

Where the bold letters indicate vectors, V is the potential difference, E the electric field and s the path.

Let's apply this expression for each section of the given graph:

1) section from x₀ = 0 to x_f = 2 m, the potential is V₀ = 2 V is constant.

  The derivative of a constant is zero.

        E = 0

2) Section between x₀ = 2 and x_f = 4 m, the potential varies linearly from V₀ = 2 v to V_f = -2 V.

We look for the equation of the line.

       V-V₀ = m (x- x₀)

We carry out the derivative.

      E = - m i ^

The slope (m) is:

       [tex]m= \frac{V_f - V_o}{x_f- x_o}[/tex]  

Let's calculate.

       [tex]m= \frac{-2 -2}{4-2} = \ -2 \ V/m[/tex]  

Let's substitute.

       E =  [tex]2 \hat i \ V/m[/tex]  

         

3) From x₀ = 4 to x_f = 4.5 m, the potential varies from V₀ = -2 to V_f = 0.

We look for the equation of the line and we derive.

      E = - m i ^

Let's  substitute.

      [tex]m = \frac{0-(-2)}{4.5-4} = \ 4 V/m[/tex]  

    E = - 4 [tex]\hat i[/tex] V / m

4) From x₀ = 4.5 m to x_f = 6m.  The potential is constant and the derivative of a constant is zero.

      E = 0

5) From x₀ = 6m to x_f = 8 m, the potential changes linearly from v₀ = 0 to V_f = 1 V

We look for the equation of the line and we derive.

       E = - m i ^

       [tex]m = \frac{1-0}{8-6} = \ 0.5 \ V/m[/tex]  

      E = - 0.5 [tex]\hat i[/tex] V/m

6) From x₀ = 8m to x_f = 9m, the potential changes linearly from V₀ = 1 V to V_f = -1.

We look for the equation of the line and we derive.

       E = - m i ^

       [tex]m = \frac{-1-1}{9-8} = \ -2 \ V/m[/tex]

Let's substitute.

       E = 2 [tex]\hat i[/tex] V/m

7) From x₀ = 9m to x_f = 10 m, the potential changes linearly from V₀ = -1 V to V_f = -2 V

     

We look for the equation of the line and we derive.

       E = - m i ^

       [tex]m = \frac{-2+1}{10-9} = \ -1 \ V/m[/tex]

Let's substitute.

       E = 1 [tex]\hat i[/tex]  V/m

In the attachment we can see these Electric fields as a function of distance.

In conclusion, the relationship between the potential and the electric field we can find the results for the value of the electric field as a function of the distance is:

In the attachment we see the graph of the electric field as a function of distance.

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True or False. Abraham and Sarah were in agreement regarding God's command to sacrifice Isaac.

Answers

Answer:

Explanation:

Not in Genesis. The proposed sacrifice of Isaac was all Abraham's doing. Sarah was not present and could not, therefore offer any input. It might have been covered in other Jewish writings, but it is not recorded in Genesis.

Since the book most widely used by Everyone is the Bible, I would answer false.

Using the figure shown, if I₃= 1.17 A, then (I₁ , I₂) A is:

a- (3.17 , 2.00)
b- (1.33 , 0.17)
c- (1.67 , 0.50)
d- (1.27 , 0.10)

Answers

The value of the current in each arm of the circuit is given by Kirchhoff's

Rules.

The correct option for (I₁, I₂) is; b-. [tex]\underline{(1.33, \ 0.17)}[/tex]

Reasons:

By Kirchhoff's junction rule, we have that the sum of current at a junction is given as follows;

[tex]\displaystyle \mathbf{ \sum \limits_{k = 1}^ n I_K} = 0[/tex]

Which by the direction of the currents in the given circuit diagram, we have;

I₁ - (I₃ + I₂) = 0

Therefore;

I₁ = I₃ + I₂

According to Kirchhoff's loop rule theory, we have;

[tex]\displaystyle \mathbf{\sum \limits_{k = 1}^ n V_K} = 0[/tex]

In the loop having the 2 Volts emf., we have;

-I₃·R₁ + 2 + I₂·R₂ = 0

I₃ = 1.17 A

R₁ = 2 Ω

R₂ = 2 Ω

Which gives;

-1.17 × 2 + 2 + I₂×2 = 0

I₂ × 2 = 2.34 - 2 = 0.34

I₂ = 0.34 ÷ 2 = 0.17

I₂ = 0.17 A

From the loop having the 7 Volts emf. we have;

7 - 0.17×2 - I₁ × 4 - I₁ × 1 = 0

Which gives;

7 - 0.34 - 5·I₁ = 0

5·I₁ = 7 - 0.34 = 6.66

I₁ = 6.66 ÷ 5 = 1.332

Therefore;

[tex]\underline{\mathbf{(I_1, \, I_2)} = (1.33, \, 0.17)}[/tex]

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Suppose you want to make the demonstration more dramatic by attracting as much hair as possible with the balloon. Which of the following is the best choice to accomplish your goal? A. Decrease the electric force by holding the balloon closer to the hair. B. Increase the electric force by rubbing the balloon for a longer period of time. C. Decrease the electric force by using a larger balloon. D. Increase the electric force by holding the balloon farther away from the hair.

Answers

Answer:

B. Increase the electric force by rubbing the balloon for a longer period of time.

Explanation:

The work done by an electric force in moving a charge from point A to point B is 2.70 × 10‒3 J. The electric potential difference between the two points is VA ‒ VB = 50.0 V. What is the charge?

Answers

The charge moved by this electric force is [tex]5.4 \times 10^{-5} \; Coulombs[/tex].

Given the following data:

Work done = [tex]2.70 \times 10^{-3}\;Joules[/tex]Potential difference = 50.0 Volts

To determine the charge:

Mathematically, the work done by an electric force in moving a charge from one point to another is given by the formula:

[tex]W = PQ[/tex]

Where:

W is the work done.P is the electric potential difference.Q is the charge.

Making Q the subject of formula, we have:

[tex]Q =\frac{W}{P}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Q =\frac{2.70 \times 10^{-3}}{50}\\\\Q =5.4 \times 10^{-5} \; Coulombs[/tex]

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.
A distance-time graph indicates that an object travels 2 m in 2 s and then travels another 80 m during the next 40 s.

What is the average speed of the object?

Answers

Answer:

Explanation:distance-time =speed

a,V =s/t

V=2m/2s

V=1m/s

b,v=s/t

V=80m/40s

V= 2m/s

The average speed is 2m/s

identify the origins of breakdown when using a spectrum analyzer

Answers

Four regions of the electromagnetic spectrum that astronomers use when observing objects in the space are the following enumerated answers.

1. First is Ultraviolet

2. Next is Infrared

3. Then the radio

4. Lastly the Visible lights.

These are the answers to the problem.

An Astronaut lands on an Earthlike planet and drops a small lead ball with a mass from the top of her spaceship. The point of release is 25 m above the surface of the planet and the ball takes 5 s to reach the ground. The astronaut's mass is 80 kg. Astronaut weight on the planet is

PLEASE NO LINKS, REAL ANSWERS DON'T WASTE TIME.

Answers

First we have to find out the gravity on that planet. We use Newton second equation of motion. It is given as,

s = ut +(gt^2)/2

Distance s = 25m

Time t = 5 s

Velocity u = 0

By putting these values,

25 = 1/2.g.(5)²

g = 2

So the gravity on that planet is 2. Lets find out the weight of the astronaut.

Mass of the astronaut on earth m = 80 kg

Weight of astronaut on earth W = mg = (80)(9.8) = 784 N

Weight of astronaut on earth like planet = (80)(2) = 160 N

x = 160N

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