two forces act concurrently on an object on a horizontal frictionless surface. their resultatn force has the largest magnitude when the angle between the forces is

The distance traveled by the egg after 2 seconds is 19.6 m.

The given parameters:

The distance traveled by the egg after 2 seconds is calculated as follows;

[tex]h = v_0_y t + \frac{1}{2} gt^2\\\\[/tex]

where;

[tex]h = 0 \ + \ \frac{1}{2} \times 9.8 \times (2)^2\\\\h = 19.6 \ m[/tex]

Thus, the distance traveled by the egg after 2 seconds is 19.6 m.

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Answer:

Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.  The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.

Explanation:

Since potential energy increases with increase in the separation distance, Jamal should move the toy car that will create the largest separation distance.The magnetic force that will act on the vehicles as he moves the cars away from each other will decrease because magnetic force is inversely proportional to the separating distance between the cars.

Answer: oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.ANSWER HERE: This mean that volcanos are producing these new islands and it is creating a chain of different islands all over Hawaii.

Answer:

Oceanic crust moved over the hot spot, each recently formed volcano was carried away from the hot spot toward the northwest, cutting off its source of lava. Meanwhile, a new island was forming so that over time a chain of islands was produced extending away from the hot spot.

Answer:

This is the answer that I got.

Explanation:

Just check over it once.

Answer:

the volume changes overtime

sometimes because of weather, temperature ...

Explanation:

From the information in the question, the acceleration of the cart is 2.55 ms-2.

We can find the acceleration using the following information from the question;

u = 0.9 m/s

v = 6 m/s

a =  2.0 seconds

But;

a = v - u/t

v = final velocity

u = initial velocity

t = time

a = 6 - 0.9/2 = 2.55 ms-2

Force= ma

m = mass

a = acceleration

F = 6 kg × 2.55 ms-2

F = 15.3 N

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Answer:

69 meters

Explanation:

Answer:

the answer is the rollar coster

Explanation:

because the rollar coster is

Answer:

It should be fibre optic cable , buried underground

The planet that Punch should travel to in order to weigh 118 lb is Pentune.

The mass of Punch will be constant in every planet;

[tex]W = mg\\\\m = \frac{W}{g}\\\\m = \frac{236}{g}[/tex]

The acceleration due to gravity of each planet with respect to Earth is calculated by using the following relationship;

[tex]F = mg = \frac{GmM}{R^2} \\\\g = \frac{GM}{R^2}[/tex]

where;

For Planet Tehar;

[tex]g_T =\frac{G \times 2.1M}{(0.8R)^2} \\\\g_T = 3.28(\frac{GM}{R^2} )\\\\g_T = 3.28 g[/tex]

For planet Loput:

[tex]g_L =\frac{G \times 5.6M}{(1.7R)^2} \\\\g_L = 1.94(\frac{GM}{R^2} )\\\\g_L = 1.94g[/tex]

For planet Cremury:

[tex]g_C =\frac{G \times 0.36M}{(0.3R)^2} \\\\g_C = 4(\frac{GM}{R^2} )\\\\g_C = 4 g[/tex]

For Planet Suven:

[tex]g_s =\frac{G \times 12M}{(2.8R)^2} \\\\g_s = 1.53(\frac{GM}{R^2} )\\\\g_s = 1.53 g[/tex]

For Planet Pentune;

[tex]g_P =\frac{G \times 8.3 }{(4.1R)^2} \\\\g_P = 0.5(\frac{GM}{R^2} )\\\\g_P = 0.5 g[/tex]

For Planet Rams;

[tex]g_R =\frac{G \times 9.3M}{(4R)^2} \\\\g_R = 0.58(\frac{GM}{R^2} )\\\\g_R = 0.58 g[/tex]

The weight Punch on Each Planet at a constant mass is calculated as follows;

[tex]W = mg\\\\W_T = mg_T\\\\W_T = \frac{236}{g} \times 3.28g = 774.08 \ lb\\\\W_L = \frac{236}{g} \times 1.94g =457.84 \ lb\\\\ W_C = \frac{236}{g}\times 4g = 944 \ lb \\\\ W_S = \frac{236}{g} \times 1.53g = 361.08 \ lb\\\\W_P = \frac{236}{g} \times 0.5 g = 118 \ lb\\\\W_R = \frac{236}{g} \times 0.58 g = 136.88 \ lb[/tex]

Thus, the planet that Punch should travel to in order to weigh 118 lb is Pentune.

The complete question is below:

Which planet should Punch travel to if his goal is to weigh in at 118 lb? Refer to the table of planetary masses and radii given to determine your answer.

Punch Taut is a down-on-his-luck heavyweight boxer. One day, he steps on the bathroom scale and "weighs in" at 236 lb. Unhappy with his recent bouts, Punch decides to go to a different planet where he would weigh in at 118 lb so that he can compete with the bantamweights who are not allowed to exceed 118 lb. His plan is to travel to Xobing, a newly discovered star with a planetary system. Here is a table listing the planets in that system (find the image attached).

In the table, the mass and the radius of each planet are given in terms of the corresponding properties of the earth. For instance, Tehar has a mass equal to 2.1 earth masses and a radius equal to 0.80 earth radii.

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We are given –

Sun, r= 1.5×10¹¹ m

We are asked to find the gravitational attraction between the sun and the earth.

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\sf F = \dfrac{GMm}{r²}}[/tex]

Substituting values, we get –

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}\times 5.98×10^{24}\times 1.99×10^{30}}{(1.5×10^{11})^2}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = \dfrac{6.67×10^{-11}×5.98×10^{24}×1.99×10^{30}}{2.25×10^{22}}[/tex]

[tex]\qquad[/tex] [tex]\twoheadrightarrow\bf F = 35.27×10^{21}[/tex]

[tex]\qquad[/tex] [tex]\pink{\twoheadrightarrow\bf F = 3.53×10^{22} N}[/tex]

______________________________________________

Answer:

Multiply the acceleration by time to obtain the velocity change:

Example:

Velocity change = 6.95 * 4 = 27.8 m/s . Since the initial velocity was zero, the final velocity is equal to the change of speed. You can convert units to km/h by multiplying the result by 3.6: 27.8 * 3.6 ≈ 100 km/h

Answer:

A quick way of describing density is to describe an object as heavy or light for its size. Pumice stone, unlike regular rock, does not sink in water because it has a low density. An ironwood branch is very dense and sinks in water.

Hope that helps. x

Answer:

Pumice is trapped in gas when the temperature is warm, but as the temp drops, it becomes dense, due to air bubbles. Iron wood is denser than water, thus making it sink.

Explanation:

Answer:

i have not study it till now

Explanation:

sorry i don't know

Answer:

concave lens focal length 2m

Answer:

This question assumes that the car accelerates at the same rate as when it went from 0 to 60km/h

24.29m/s or 87.4km/h

Explanation:

Let's find the acceleration of the car:

let vi=0, vf=60km/h (16.67m/s), Δt = 8.0s

a = (vf-vi)/Δt

a = (16.67m/s-0)/8.0

a = 2.08m/s^2

Now we can use this acceleration to find vf in the second part:

50km/h is 13.89m/s

a = (vf-vi)Δt

vf = aΔt + vi

vf = 2.08m/s^2*5.0+13.89m/s

vf = 24.29m/s (87.4km/h)

Answer:

A major difference between tangential acceleration and centripetal acceleration is their direction. Centripetal means “center seeking”. ... Tangential acceleration results from the change in magnitude of the tangential velocity of an object. An object can move in a circle and not have any tangential acceleration.

The direction of acceleration is a key distinction between tangential acceleration and centripetal acceleration. Centripetal is defined as "center-seeking." The amount of an object's tangential velocity changes, which causes tangential acceleration. Without experiencing any tangential acceleration, an item can move in a circle.

Acceleration is the rate at which the speed and orientation of a moving object change over time. When a spot or object moves faster or slower along a straight line, it is said to be accelerated. Even though the speed is constant, motion on a circle accelerates so because the direction is always shifting. Both by and to acceleration for all other types of motion.

It is a vector quantity because it has both magnitude and direction.

Any object's rotation experiences tangential acceleration, which is the speed at which the tangential velocity fluctuates. When an object is moving, it behaves in a tangential direction. An object moving in a circle will also experience the very same tangential velocity action.

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[tex]\\ \sf\Rrightarrow V=\dfrac{W}{Q}[/tex]

[tex]\\ \sf\Rrightarrow V=\dfrac{9}{1}[/tex]

[tex]\\ \sf\Rrightarrow V=9V[/tex]

The student who did the most work is student 2 with 2500 Joules.

Given the following data:

To determine which of the students did the most work:

Mathematically, the work done by an object is given by the formula;

[tex]Work\;done = Force \times distance[/tex]

For student 1:

[tex]Work\;done = 500 \times 1.2[/tex]

Work done = 600 Joules

For student 2:

[tex]Work\;done = 500 \times 5[/tex]

Work done = 2500 Joules.

Therefore, the student who did the most work is student 2 with 2500 Joules.

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Answer:student 2 did the most work

Explanation:student 2 did more work because he pushed it up 5 m instead of 1.2.

Answer:Answer:

See diagram for answers. The force and acceleration vectors are directed inwards towards the center of the circle and the velocity vector is directed tangent to the circle.

Explanation:

Answer:

1) A 1L bottle, with a height of 30cm, full of water is emptied. The bottle is filled with oil (density = 920 kg/m^3). Calculate the change in pressure of the bottom of the first bottle. If you decide to put potatoes (assume its density is  1,8 kg/m^3), each one of a volume V = 10 cm^3, will they float?

2) The fusion temperature of the Nitrogen is -210°C and its boiling temperature is 77K. Calculate the difference between the fusion temperature and the boiling temperature.

Answer:

Determine the coordinates of two points on the line. Calculate the difference between these two locations' y-coordinates (rise). Calculate the x-coordinate difference between these two places (run). Divide the y-coordinate difference by the x-coordinate difference (rise/run or slope).

Answer:

4.16875×10^-9

Explanation:

given,

mass(M1)=20kg

mass(M2)= 50kg

distance(d)=4m

gravitational constant value (G)=6.67×10^-11

we know,

gravitational force=(Gm1m2)÷d^2

=(6.67×10^-11×20×50)÷4^2

=(6.67×10^-8)÷16

= 4.16875×10^-9

The mass, the initial and the final temperature would let you  determine the heat transfer between two substances.

Heat transfer refers to the movement of thermal energy from one location or substance to another as a result of a difference in temperature. There are three primary mechanisms for heat transfer: conduction, convection, and radiation.

Conduction is the transfer of heat through direct contact of substances, such as when heat travels from a hot pan to your hand through the handle.

Convection is the transfer of heat through the movement of a fluid, such as when hot air rises and cool air sinks.

To determine the heat transfer between two substances, you need to measure their mass, initial temperature, and final temperature. With these measurements, you can calculate the change in temperature (AT) and use the equation Q = mcAT to determine the heat transfer. The specific heat capacities of both substances can be looked up.

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Answer:

  5.60 m/s

Explanation:

His initial potential energy is equal to his final kinetic energy.

  mgh = 1/2mv^2

  2gh = v^2 . . . . . . . multiply by 2/m

  v = √(2gh) = √(2(9.81 m/s²)(1.6 m)) = √(31.392 m²/s²)

  v ≈ 5.60 m/s

_____

Additional comment

The mass is irrelevant in the equations we typically use for this purpose.

Answer:

-4,200,000 J

Explanation:

The force winds up unchanged, at 100 N.