Trig Identities---
1. Use the pythagorean identity
Find cotθ if cosθ = 1/7 and the value exists in the first quadrant.

I have a calculus exam tomorrow and have no idea how to solve this equation, please provide a detailed explanation. I'm slow.

Answer:

The answer is (f.g)(x) = 12x^2 - 9.

Step-by-step explanation:

To find (f.g)(x), we need to apply the composition of functions formula, which is:

(f.g)(x) = f(g(x))

First, we need to find g(x):

g(x) = 3x^2

Now, we need to plug g(x) into f(x) in place of x:

f(g(x)) = 4(g(x)) - 9

= 4(3x^2) - 9

= 12x^2 - 9

Therefore, (f.g)(x) = 12x^2 - 9.

Hope this helps, I'm sorry if it doesn't! If you need more help, ask me! :]

In triangles ABC and PQR, the ratio of the measure of side AB and side PQ is 2 : 3 and the ratio of the measure of sides BC and QR is 2 : 3. Thus, AB/PQ = BC/QR. Also, the m∠B = m∠Q. The ratio of two pairs of corresponding sides is congruent and the included angle is equal. Hence, ΔABC  ~ ΔPQR by SAS similarity theorem.

SAS similarity theorem is a theorem in geometry that stands for "Side-Angle-Side Similarity Theorem".

This theorem states that if two triangles have two pairs of corresponding sides that are proportional in length, and the included angles between these sides are congruent (have the same measure), then the two triangles are similar.

We can see that examining the two triangles, it is clear that it is in line with SAS similarity theorem.

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Answer:

To find the price of 3 tons of concrete, we need to first figure out how much Trey paid per ton of concrete.

Since Trey paid 42 dollars for 2/3 ton of concrete, we can set up a proportion:

2/3 ton = 42 dollars

1 ton = x dollars

To solve for x, we can cross-multiply:

(2/3) * x = 42 * 1

2x = 126

x = 63

So, Trey paid 63 dollars per ton of concrete.

To find the price of 3 tons of concrete, we can multiply the cost per ton by the number of tons:

3 tons * $63/ton = $189

Therefore, the price of 3 tons of concrete is $189.

Answer:

Propaganda: ideas or statements spread to promote one side's views and present an opposing side negatively.

Front: the front lines where combat between opposing armies occurs.

Free enterprise system: an economic system characterized by private or corporate ownership of capital goods.

Allied Forces: the military alliance of the USA, Britain, France, and other countries during WWII.

Axis Powers: Germany, Italy, Japan.

The equation would be y = 0.50x + 10.00, and we have drawn the graph for the same.

What is the graph of the equation?

The graph of an equation is a visual representation of the set of all solutions (points) that satisfy the equation.

To find the equation of the line, we use the slope-intercept form of a linear equation, which is:

y = mx + b

where m is the slope of the line and b is the y-intercept (the point where the line crosses the y-axis).

In this case, we are given the slope of the line (0.50) and the y-intercept (10.00), so we can simply substitute these values into the equation:

y = 0.50x + 10.00

This gives us the equation of the line in slope-intercept form. We can use this equation to find the cost of a cab ride for any distance x (in miles) by substituting the value of x into the equation and solving for y (the fare).

Now let's draw the graph of the equation y = 0.50x + 10.00, we get

Hence, the equation would be y = 0.50x + 10.00, and we have drawn the graph for the same.

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Answer:

(36 × $7) - $15 = $252 - $15 = $237

Answer:

A

Step-by-step explanation:

Range referes to the smallest and largest values, so the answer you have circles is correct.

Good Job!

Answer: A) Range

Step-by-step explanation:

The range is the difference between the biggest and smallest numbers (or, in this case, folders). If Jack wants to find a notebook that will fit a small and large folder, he will need to find the range.

The features of the given function are;

y-intercept at (0,10)

vertical asymptote of x = -4

A function is a relation in which each possible input value leads to exactly one output value. We say “the output is a function of the input.” The input values make up the domain, and the output values make up the range.

The function is given as;

g(x) = f(x + 4) + 8

The domain of a function is a set of all possible input values while the range of a function is defined as a set of all possible output values.

A vertical asymptote of a graph is a vertical line x = a where the graph tends toward positive or negative infinity as the inputs approach a.

Thus, vertical asymptote is x = -4.

The he feat will be at (0, 10)

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The formula d=b2−4ac when solved for b = ± [tex]\sqrt{d +4ac}[/tex]. Option B

Subject of formula is defined as a variable that is being solved for in an equation.

It is the variable that is made to stand out in an equation. It is the variable that is made to stand alone on one end of the equality sign.

From the information given, we have that;

d=b2−4ac

Now, collect the like terms

d + 4ac = b²

Find the square root of both sides, we have that;

b = [tex]\sqrt{d + 4ac}[/tex]

Insert the plus-minus sign to show the interval, we have;

b = ± [tex]\sqrt{d +4ac}[/tex]

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The measure οf the third angle c is 20 degrees.

The triangle angle sum prοperty states that the sum οf the three interiοr angles οf a triangle is always equal tο 180 degrees. This prοperty hοlds true fοr all types οf triangles, whether they are acute, οbtuse, οr right-angled. The prοperty can be expressed as fοllοws:

Angle A + Angle B + Angle C = 180 degrees, where A, B, and C are the measures οf the interiοr angles οf the triangle.

38 + 122 + c = 180

Tο sοlve fοr c, we can simplify the left side οf the equatiοn:

160 + c = 180

Subtracting 160 frοm bοth sides, we get:

c = 20

Therefοre, the measure οf the third angle c is 20 degrees.

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Complete question:

Two angles in a triangle are 38° and 122°. Write the angle sum property to determine the measure of the third angle ∠c.

[Hint: Angle sum property = ∠a+ ∠b+ ∠c = 180°]

The perimeter of the triangle will be 36.

The value of x in the triangle will be 101°.

The value of y will be 3x

It should be noted that the total sum of the angles that are in a triangle is 180°. It should be noted that the triangle is a Equilateral Triangle. In this case, since one of the sides is 12, the perimeter will be:

= 12 + 12 + 12

= 36

The value of x in the triangle will be:

= 180° - (22 + 57)

= 180° - 79°

= 101°.

The value of y will be 3x as vertically opposite angles are equal.

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The false comparison is: 35 degrees centigrade cooler than 100 degrees Fahrenheit.

In mathematics and computer programming, an expression is a combination of one or more values, variables, operators, and functions that are evaluated to produce a result.

The comparison "35 degrees centigrade cooler than 100 degrees Fahrenheit" is false because 35 degrees centigrade is equivalent to 95 degrees Fahrenheit, which is actually warmer than 100 degrees Fahrenheit. Therefore, it is incorrect to say that 35 degrees centigrade is cooler than 100 degrees Fahrenheit.

Therefore, the false comparison is: 35 degrees centigrade cooler than 100 degrees Fahrenheit.

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Answer:

the area where the grass will be planted is 25,920 square meters.

Step-by-step explanation:

To calculate the area where the grass will be planted, we need to multiply the length and breadth of the sports field.

Area = length x breadth

Area = 162m x 160m

Area = 25,920 square meters

Therefore, the area where the grass will be planted is 25,920 square meters.

Exponential property can be used in various field or place like growing or decline of population, bacteria growth/decay , compound interest any many more.

Exponential property states that when we multiply  two power with same base we add the exponents.

                 [tex]a^{m} *b^{n } = (a*b)^{m + n}[/tex]

When we divide  two power with same base we subtract the exponents.

                  [tex]a^{m} \div b^{n} = (a \div b)^{m-n}[/tex]

When have to find the power of power we multiply the exponents.

                  [tex](a^{m} )^{n} = a^{m*n}[/tex]

Three most important use of exponential function is to calculate carbon dating of any soil, fossil foil etc, to calculate population growth , interest earn on an investment etc.

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The inverse functions and the domains and ranges of the inverse functions can be presented as follows;

A. The inverse function of f(x) is; [tex]f^{-1}(x) = \frac{3-x}{7\cdot x}[/tex]

B. f(g(x)) = [tex]\frac{3}{7\times \frac{(3-x)}{7\cdot x} + 1}[/tex] = x

C. The inverse function reverses the effect of the function. The inverse function is therefore;

x [tex]{}[/tex]      y

10[tex]{}[/tex]     5

6[tex]{}[/tex]      8

5[tex]{}[/tex]      9

4[tex]{}[/tex]      13

2) Domain; 10, 6, 5, 4

Range; 5, 8, 9, 13

An inverse function maps the output, or y-value of a function to the input value or x-value of the function.

2. A. f(x) = 3/(7·x + 1)

The inverse function can be found as follows;

Let f(x) = y

y = 3/(7·x + 1)

(7·x + 1) = 3/y

7·x = (3/y) - 1 = (3 - y)/y

x = (3 - y)/(7·y)

Plugging in x = f⁻¹(x), and y = x, to get;

B. g(x) = (3 - x)/(7·x)

f(x) = 3/(7·x + 1)

f(g(x)) = 3/(7 × ((3 - x)/(7·x)) + 1) = 3/(((3 - x)/(x)) + 1) = 3/(3/x - 1 + 1)

3/((3/x - 1 + 1) = 3/(3/x) = 3 × x/3 = x

Therefore; f(g(x)) = 3/(7 × ((3 - x)/(7·x)) + 1) = x

C. The inverse of the function is the function that produces the input of the function from the function's output, therefore, the inverse of the function can be presented as follows;

x [tex]{}[/tex]     y

10[tex]{}[/tex]    5

6[tex]{}[/tex]     8

5[tex]{}[/tex]     9

4[tex]{}[/tex]     13

2) The domain is the set of the possible inputs of the function, and the range is the set of the possible outputs of the function.

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The general form of the equation of this quadratic function is f(x) = x² - 2x + 1.

In Mathematics, the standard form of a quadratic equation is represented by the following mathematical equation;

ax² + bx + c = 0

Based on the information provided about this quadratic equation, it comprises the following ordered pairs;

Center (h, k) = (1, 0),

(x, y) = (0, 1).

By substituting the ordered pairs into the standard form of a quadratic equation, we have:

f(x) = a(x - h)² + k

1 = a(0 - 1)² + 0

1 = a

Therefore, the required quadratic equation is given by:

f(x) = 1(x - 1)² + 0

f(x) = (x - 1)(x - 1)

f(x) = x² - x - x + 1

f(x) = x² - 2x + 1

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The ball strikes the grοund after apprοximately 1.07 secοnds.

Time: a measured οr measurable periοd during which an actiοn, prοcess, οr cοnditiοn exists οr cοntinues.

Speed: the rate at which sοmething mοves, οperates, οr happens.

Distance: the amοunt οf space between twο pοints οr οbjects.

We can sοlve this prοblem using the kinematic equatiοns οf mοtiοn. We knοw the initial velοcity (u = 7.30 m/s), the initial height (h = 2.91 m), and we want tο find the time taken fοr the ball tο hit the grοund (t).

Let's use the kinematic equatiοn that relates the final pοsitiοn (s), initial pοsitiοn (h), initial velοcity (u), acceleratiοn (a), and time (t):

[tex]s = h + ut + (1/2)at^2[/tex]

Since the ball is thrοwn vertically dοwnwards, the acceleratiοn is [tex]-9.81 m/s^2[/tex] (negative because it is in the οppοsite directiοn tο the initial velοcity).

At the mοment the ball hits the grοund, its final pοsitiοn s is zerο. Therefοre, we can rewrite the equatiοn as:

[tex]0 = h + ut + (1/2)at^2[/tex]

Solving for t, we get:

[tex]t = [-u\±\sqrt{(u^2 - 2ah)} ] / a[/tex]

We take the positive solution, since time cannot be negative. Substituting the values we get:

[tex]t = [ -7.30 \± \sqrt{((7.30)^2 - 2(-9.81)(2.91))} ] / (-9.81)[/tex]

[tex]t = [ -7.30 \± \sqrt{ (53.25)} ] / (-9.81)[/tex]

t ≈ 1.07 s οr t ≈ 0.31 s

The negative sοlutiοn dοesn't make physical sense in this cοntext, sο we discard it. Therefοre, the ball strikes the grοund after apprοximately 1.07 secοnds.

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Since the distance was measured to the nearest metre, the upper bound for the distance is 101 metres.

1. To calculate the lower bound for Kelly's average speed, we need to divide the lower bound distance by the upper bound time. Since the distance was measured to the nearest metre, the lower bound for the distance is   [tex]99[/tex] Metres.

Since the time was measured to the nearest hundredth of a second, the upper bound for the time is  [tex]10.53[/tex] seconds. Therefore, the lower bound for Kelly's average speed is:

[tex]99/10.53 = 9.411[/tex]  metres per second (to three decimal places)

2. To calculate the upper bound for the perimeter of the regular hexagon, we need to multiply the upper bound length of a side by 6.

Since the length was measured to the nearest millimetre, the upper bound for the length is [tex]3.601 cm[/tex]  (since 3.6005 cm would round up to 3.601 cm). Therefore, the upper bound for the perimeter is:

[tex]6 x\times3.601 = 21.606 cm[/tex]   (to three decimal places)

3. To calculate the upper bound for the area of the rectangle, we need to multiply the upper bounds for the length and width. Since the length is correct to the nearest cm, the upper bound for the length is 35.5 cm (since 34.5 cm would round up to 35 cm).

Since the width is correct to the nearest cm, the upper bound for the width is 26.5 cm (since 25.5 cm would round up to 26 cm). Therefore, the upper bound for the area is:

 [tex]35.5 \times 26.5 = 942.25 cm^2[/tex] (to two decimal places)

4. To calculate the lower bound for Kelly's average speed, we need to divide the upper bound distance by the lower bound time.

Since the time was measured to the nearest hundredth of a second, the lower bound for the time is 10.51 seconds. Therefore, the lower bound

(d) To calculate the lower bound for Kelly's average speed, we need to divide the lower bound of distance by the upper bound of time.

The lower bound of distance is 99.5m (since the measurement was rounded down to the nearest metre).

The upper bound of time is 10.525s (since the measurement was rounded up to the nearest hundredth of a second).

So, the lower bound for Kelly's average speed is:

speed = distance / time [tex]= 99.5 / 10.525 = 9.45260637[/tex] ...

We need to round this to two decimal places to match the precision of the time measurement, giving us:

speed = [tex]9.45 m/s[/tex]

Therefore, the figures on the calculator display are: 99.5 ÷ 10.525 = 9.45260637... ≈ 9.45.

The length of the rectangle is measured as 645 mm correct to the nearest 5 mm. This means that the actual length could be anywhere between 642.5 mm and 647.5 mm (since rounding up or down depends on the decimal value being greater or less than 0.5 respectively).

Similarly, the width of the rectangle is measured as 400 mm correct to the nearest 5 mm. This means that the actual width could be anywhere between 397.5 mm and 402.5 mm.

5. To calculate the lower bound for the area of the rectangle, we need to find the product of the smallest possible length and width.

Smallest possible length [tex]= 642.5 mm[/tex]

Smallest possible width  [tex]= 397.5 mm[/tex]

Area = length x width

Lower bound for area = [tex]642.5 mm x 397.5 mm = 255542.5 mm²[/tex]

Rounding this off to 3 significant figures, we get the final answer as 2.56 x 10^5 mm².

Therefore, the lower bound for the area of the rectangle is [tex]2.56 x 10^5[/tex]  mm².

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Answer: An array is a collection of items of same data type stored at contiguous memory locations.

Step-by-step explanation: There you go dude happy to help

Answer:

Coefficient, the coefficient is the number before the variable

Step-by-step explanation:

The mathematical word that describes both 2.25 and 6.75 in the expression 2.25x + 6.75x - 5.5 is "coefficients."

An expression contains one or more terms with addition, subtraction, multiplication, and division.

We always combine the like terms in an expression when we simplify.

We also keep all the like terms on one side of the expression if we are dealing with two sides of an expression.

Example:

1 + 3x + 4y = 7 is an expression.

3 + 4 is an expression.

2 x 4 + 6 x 7 – 9 is an expression.

33 + 77 – 88 is an expression.

We have,

In this expression,

2.25 and 6.75 are coefficients of the variables x, which means that they multiply the variable x.

The term 5.5 is a constant because it does not contain a variable.

Thus,

The mathematical word that describes both 2.25 and 6.75 in the expression 2.25x + 6.75x - 5.5 is "coefficients."

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The value of the expression -x³ + 3x² - x + 20 when x = -1 is 23.

Given the expression in the question;

-x³ + 3x² - x + 20

To determine the value of the expression,

First, we substitute -1 for x in the expression:

-( -1 )³ + 3( -1 )² − ( -1 )) + 20

Next, we simplify each term using the order of operations (also known as PEMDAS):

-( -1 )³ = -( -1 ) = 1

(recall that the exponent is evaluated first, then the negative sign is applied)

3( -1 )² = 3(1) = 3

(recall that the exponent is evaluated first)

-( -1 ) = 1

(recall that subtracting a negative is the same as adding a positive)

Now, putting these simplified terms back into the original expression, we get:

1 + 3 + 1 + 20

Finally, we add these terms together to get the final answer:

23

Therefore, the value of the expression is 23.

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Answer:

50 sweets

Step-by-step explanation:

Let's work through the problem step by step:

The student starts with x sweets.

She gives away 20 sweets to her friends, so she is left with (x - 20) sweets.

One third of the remainder is equal to one fifth of the original number of sweets. In other words, (1/3)(x - 20) = (1/5)x.

To solve for x, we can start by multiplying both sides of the equation by 15 (the least common multiple of 3 and 5) to eliminate the fractions:

5(x - 20) = 3x

5x - 100 = 3x

2x = 100

x = 50

Therefore, the original number of sweets was 50.

Answer:

38°

Step-by-step explanation:

this equal to 38° because angle EGD and angle IGJ are corresponding angles

Answer:

C.

Step-by-step:

The measure of angle A is congruent to the measure of angle P.

Answer:

See below.

Step-by-step explanation:

We're asked to prove that ΔSTV ≅ ΔTUW.

Let's begin by reviewing what was given to us.

Because we already have one side and an angle congruent, we need to prove that another angle or side is congruent.

Our goal is to find a Congruency Postulate to prove that ΔSTV ≅ ΔTUW.

As we can see in the diagram, ∠STV ≅ ∠UTV as they're vertical angles. This is possible because Line Segment SV ≅ & ║ Line Segment TW.

We are now able to prove that ΔSTV ≅ ΔTUW with the Angle-Side-Angle Triangle Congruency Postulate (ASA). We proved, and were given 2 angles, and 1 side.

Summary:

∠STV ≅ ∠UTV | Vertical Angles.

ΔSTV ≅ ΔTUW | ASA.

Equations that have infinitely many solutions are:

B. 3x+8-x=3+5+2x

D. 5-4x+7= −2 (2x - 6)

An equation has infinitely many solutions when you try to solve the equation and you get a variable or a number equal to itself.

A. 3 (x + 4) = 2x - 7

3x + 12 = 2x - 7

3x -2x = -7 -12

x = -19

B. 3x+8-x=3+5+2x

3x -x - 2x =3 + 5 - 8

0 = 0

This equation has infinitely many solutions.

C. (4x − 8) = 2x − 4 + 12

4x − 2x =  − 4 + 12 + 8

2x = 16

x = 8

D. 5-4x+7= −2 (2x - 6)

5 - 4x + 7 = −4x + 12

-4x + 4x = 12 - 7 - 5

0 = 0

This equation has infinitely many solutions.

E. 4-3x - 8 = 2x + 7 - 5x

-3x - 2x + 5x = 7 + 8 - 4

0 = 11

Therefore, options B and D has infinitely many solutions.

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Answer:

YOU HAVE TO USE THE VECTORS AS WELL MATRIX TO GET THE SOLUTION OF THIS QUESTION

Answer:

We can use the distance formula to find the distance between the center of the circle (2, -3) and the point (-1, -6), which should be equal to the radius of the circle.

Step-by-step explanation:

Distance = √[(x2 - x1)² + (y2 - y1)²]

Distance = √[(-1 - 2)² + (-6 - (-3))²]

Distance = √[(-3)² + (-3)²]

Distance = √(18)

So the radius of the circle is equal to √(18) or approximately 4.24.

The domain and range of given graph is Domain: (-∞, ∞) Range: (0, ∞)

What is Function ?

Function can be defined in which it relates an input to output.

The horizontal axis (x-axis) represents the input values, while the vertical axis (y-axis) represents the output values.

To identify the domain and range of this function from the graph, we can look at the values that the function takes on as well as the values that are excluded.

From the graph, we can see that the function appears to be increasing without bound as the input values increase. This means that the domain of the function is all real numbers or (-∞, ∞).

We can also see that the function appears to be taking on only positive values, and never touches or crosses the x-axis. This means that the range of the function is all positive numbers or (0, ∞).

Therefore, The domain and range of given graph is Domain: (-∞, ∞) Range: (0, ∞)

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