The vector V is at a 72° angle and has a magnitude of 12.
Describe this vector using vector notation (Use the & and symbols.) (6 points)
Question 9
What is the angle of the vector described below? (3 points).
Please answer all questions will mark brainliest and give 5 stars
V=2x+3y
Answers
Answer:
Part 1
The vector can be expressed as follows;
r = 12, θ = 72°, ·v = (12, ∠72°), ·v ≈ 3.71·[tex]\mathbf{\hat i}[/tex] + 11.41·[tex]\mathbf{\hat j}[/tex] or
[tex]\mathbf{\cdot v}=\begin{bmatrix}3.71\\ 11.41\end{bmatrix} = \begin{pmatrix}3.71\\ 11.41 \end{pmatrix}[/tex]
Part 2
The angle of the vector is 56.31°
Explanation:
Part 1
The given parameters are;
The direction of the vector = 72°
The vector magnitude = 12
Therefore, the vector can be described in the following forms;
Polar form
1) Direct notation;
r = 12, θ = 72°
2) Ordered set
·v = (12, ∠72°)
Rectangular vector notation;
1) Unit vector notation
·v = vₓ[tex]\mathbf{\hat i}[/tex] + [tex]v_y[/tex][tex]\mathbf{\hat j}[/tex]
Where;
vₓ = 12 × cos(72) ≈ 3.71
[tex]v_y[/tex] = 12 × sin(72) ≈ 11.41
Therefore;
·v ≈ 3.71·[tex]\mathbf{\hat i}[/tex] + 11.41·[tex]\mathbf{\hat j}[/tex]
2) Matrix notation
[tex]\mathbf{\cdot v}=\begin{bmatrix}3.71\\ 11.41\end{bmatrix} = \begin{pmatrix}3.71\\ 11.41 \end{pmatrix}[/tex]
Part 2
The given vector is V = 2·x + 3·y
Therefore, the angle of the vector, θ = tan⁻¹(y/x) = tan⁻¹(3/2) ≈ 56.31°
The angle of the vector = 56.31°.
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One way:
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Another way:
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What force is needed to move a barrel 45-m if 3600 J of work are accomplished?
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Answer:
The answer is 80 NExplanation:
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[tex]f = \frac{w}{d} \\ [/tex]
where
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We have the final answer as
80 NHope this helps you
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Answers
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Answer:
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================================================
Work Shown:
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Answer:
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Answer:
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Explanation:
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[tex]6.6 \times 100 = 660[/tex]
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Answer:
Explanation:
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The level of toluene (a flammable hydrocarbon) in a storage tank may fluctuate between 10 and 400 cm from the top of the tank. since it is impossible to see inside the tank, an open-end manometer with water or mercury as the manometer fluid is to be used to determine the toluene level. one leg of the manometer is attached to the tank 500 cm from the top. a nitrogen blanket at atmospheric pressure is maintained over the tank contents. felder, richard m.; rousseau, ronald w.; bullard, lisa g.. elementary principles of chemical processes, 4th edition (page 81). wiley. kindle edition.
Answers
Complete Question
The complete question is shown on the first and second uploaded image
Answer:
When water is used the reading is [tex] R = 2281.6 \ cm [/tex]
When mercury is used the reading is [tex] R = 23.83 \ cm [/tex]
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Explanation:
From the question we are told that
The length of the leg of the manometer to the top of the tank is d = 500cm
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The pressure at the height of the both arms of the manometer corresponding to the base of the tank are equal
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Here
[tex]\rho_t [/tex] is the density of toluene with value [tex]\rho_t = 867 kg/m^3 [/tex]
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Here
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[tex]\rho_w = 1000 \ kg /m^3 [/tex]
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=> [tex] 867 (500 - 150 + R) = 1000 * R [/tex]
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[tex] \rho_t* (d - h + R) = \rho_m * h_f[/tex]
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Answer:
Energy plays an important role in many aspects of our lives. For example, we use electricity for lighting and cooling.
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Answer:
engery
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When a light ray enters water, its velocity is _________.
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Mass is always greater than weight.
Mass of an object changes based on location, weight stays constant.
Mass of an object is constant, weight changes based on location.
Mass and weight are the same measurement.
Answers
Answer:
Usually, the relationship between mass and weight on Earth is highly proportional; objects that are a hundred times more massive than a one-liter bottle of soda almost always weigh a hundred times more—approximately 1,000 newtons, which is the weight one would expect on Earth from an object with a mass slightly greater ...
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Gm; m2 The gravitational
constant G is 6.67 x 10-11 Nm2/kg?.
A. 5.84 x 10-6N
B. 4.37 % 105 N.
C. 1.46 10-4N
D. 2.92 x 10-5 N
Answers
Gravitational force between two cars are 2.92 × 10 ⁻¹¹ Nm²/kg.
The universal force of attraction happened between two objects is called as gravitational force.
The mass of the two cars, m₁ = 2565 kg
m₂ = 4264 kg
r = 5m
G = 6.67 ₓ 10 ⁻11 Nm²/kg
How gravitational force can be calculated?
Definition of gravitational force: The force of attraction between any two bodies is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.
F ∝ m₁ m₂ ÷ r²
where the force exerted between the two masses m₁ and m₂,
F = G (m₁ m₂) ÷ r²
where as, F - Gravitational force between two bodies,
G - Gravitational constant,
m₁ - mass of the first body,
m₂ - mass of the second body,
r² - square of the distance between two bodies.
F= 6.67 × 10⁻¹¹ Nm²/kg ( 2565 kg × 4264 kg) ÷ ( 5²)
Hence,
F = 2.92 × 10⁻⁵ N
Option D is correct answer.
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Muscles covert chemicals energy int
Answers
Answer:
Mechanical energy
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