The no. Of adel beads to that of claire's beads was the ratio 7 :4 .When adel gave 68 beads to claire the ratio become 25 :41 . How many beads did claire did claire have finally

Answer:

37 beads

Step-by-step explanation:

Given that:

Adel : Claire = 7 : 4

Let Adel be = A;  &

Let Claire be = C

A: C = 7 : 4

[tex]\dfrac{A}{C} =\dfrac{7}{4}[/tex]

7C = 4A

[tex]C = \dfrac{4A}{7}[/tex] --- (1)

When Adel gave 68 beads to claire, we have:

C + 68 = 25:41

[tex]\dfrac{A}{C+68}= \dfrac{25}{41}[/tex]

25(C + 68) = 41A

C + 68 = [tex]\dfrac{41}{25}A[/tex]

[tex]C = \dfrac{41}{25}A - 68[/tex] --- (2)

Equating (1) and (2) together;

[tex]\dfrac{4 * A}{7} = \dfrac{41 *A}{25} - 68[/tex]

[tex]\dfrac{4 * A}{7}-\dfrac{41 *A}{25} = - 68[/tex]

[tex]\dfrac{100A - 287 A}{175} =- 68[/tex]

[tex]\dfrac{-187A}{175} = -68[/tex]

- 187 A = 175 × (-68)

-187 A = - 11900

A = - 11900/ -187

A ≅ 64

From; [tex]C = \dfrac{4A}{7}[/tex]

[tex]C = \dfrac{4*64}{7}[/tex]

C = 36.57

C ≅ 37 beads

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