Answer:
loyalty
Explanation:
Which could describe the properties of sedimentary rock?
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Answer:
☝ Some of the properties of sedimentary rocks
List some of the most common injuries that can occur from sports. Please hurry!
I will give you branilest!
A race car exerts 18,344 N while the car travels at an acceleration of 92.54 m/s2. What is the mass of the car? (Use the formula m=F/a)
Answer:
The answer is 198.23 kg
Explanation:
To find the mass of an object given it's mass and acceleration we use the formula
where
m is the mass
F is the force
a is the acceleration
From the question
a = 92.54 m/s²
F = 18,344 N
We have
We have the final answer as
198.23 kg
Answer:
198.22
Explanation:
using m=f/a you divide the force by the acceleration to get the mass (18344 / 92.54) = 198.22
The airport has a new plane that can go from 0 miles per hour to 100 miles per hour in 10 seconds. What is being described about the new plane?
a. acceleration
b. speed
c. velocity
d. magnitude
Answer:
acceleration
Explanation: how fast something can get to a certain speed
A proposed space station includes living quarters in a circular ring 58.0 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth
Answer:
The angular speed [tex]w = 0.5813 \ rad/s[/tex]
Explanation:
From the question we are told that
The diameter is d = 58.0 m
Generally for the occupants feel that they have the same weight as they do on Earth then the centripetal acceleration of the circular ring must be equal to the acceleration due to gravity this can be mathematically represented as
[tex]a_c = g[/tex]
Here [tex]a_c[/tex] is the centripetal acceleration which is mathematically represented as
[tex]a_c = w^2 * r[/tex]
Here r is the radius of the circular ring
=> [tex]w^2 * r = g[/tex]
=> [tex]w = \sqrt{\frac{g}{r} }[/tex]
=> [tex]w = \sqrt{\frac{9.8}{ \frac{d}{2} } }[/tex]
=> [tex]w = \sqrt{\frac{9.8}{ \frac{58.0 }{2} } }[/tex]
=> [tex]w = 0.5813 \ rad/s[/tex]
You are traveling through the forest and encounter an ancient well. You want to know how deep the well is. If you drop a coin and hear it hit the bottom of the well in 3 seconds, how deep is the well?
what is the acceleration of a cat who starts from rest and moves 11.5 m in 2.8 s?
Answer:
The acceleration is 4
Explanation:
use the formula v= change in position/change in time for vecter quantity's which will be in word problems that say acceleration or velocity.
If an object has zero acceleration, does it have to have zero velocity?
Answer:
Yes, the velocity would also be zero.
Explanation:
Acceleration is the change in velocity over time, therefore, there has to be a change in velocity for something to accelerate. which means without acceleration, the object has no velocity.
define density with a suitable formula
Answer:
ratio between m/v
or d= m/v
m= mass
v= volume
2. True or false?
Forensic entomology uses the study of insects to help criminal investigations.
Can you help me please! Love you
Answer:
I think its B. wait...U love ME?????
a tractor with 2000 kg of mass pulls a plow equal to 80.0 kg, exerting a 200 N force on it. The tractor and plow set moves horizontally to the right with an acceleration of 0.500 m / s2. The resistance force that the soil exerts on the plow has a modulus, in Newton, equal to?
Answer:
The resistance force that the soil exerts on the plough is 160 Newtons.
Explanation:
Fr = m.a
Fr = 80. 0,5
Fr = 40 N
Ft - F = Fr
200 - F = 40
F = 200 - 40
F = 160 Newtons
Consider a wire of length L =0.30 m that runs north-south on a horizontal surface. There is a current I = 0.50 A flowing north in tie wire. The Earth's magnetic field at this location has a magnitude of 0.50 gauss (or, in SI units. 0.5 x 10^—4 and points north and 38 degrees down from the horizontal, toward the ground. What is the size of the magnetic force on the wire due to the Earth's magnetic field?
Answer:
The size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.
Explanation:
To determine the size of the magnetic force on the wire due to the Earth's magnetic field,
The magnetic force is given by the formula
F = ILB sinθ
Where F is the magnetic force on the wire
I is the electric current in Amperes (A)
L is is the length of wire in meters (m)
B is the magnetic field in Tesla (T)
and θ is the angle between current and magnetic field
From the question,
L = 0.30 m
I = 0.50 A
B = 0.50 gauss = 0.5 × 10⁻⁴ T (NOTE: 1 Gauss = 10⁻⁴ Tesla)
θ = 38°
Now, putting the values into the equation
F = ILB sinθ
F = 0.50 × 0.30 × 0.5 × 10⁻⁴ sin38°
F = 7.5 × 10⁻⁶ (0.61566)
F = 4.62 × 10⁻⁶ N
Hence, the size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.
How can you predict the number of swings an 80 cm pendulum will make in 15 seconds?
Which statement is true of the electric field at a distance from the source charge?
A it is independent of the source charge
B It is directly proportional to the source charge
C it is inversely proportional to the source charge
D it is directly proportional to the distance
Answer:
It is directly proportional to the source charge.
Explanation:
I found it pretty sure it's right hit me up on my insta
desiignerjoe173
Velocity is the
i. distance travelled per unit time
il. time taken per unit distance
a.
9.
ii. time taken per unit displacement
iv. displacement per unit time
Okay, hun. Velocity is a vector quantity that measures displacement over a period of time. Velocity = Speed/Time (v=s/t). Hope this helped you. I took physics over 4 years ago. I'm more of a biology/chemistry person. (I major in those)
A train is traveling at a speed of 50km/hr. How.many hours will it take the train to travel 800 km?
Answer:
It would take 16 hours
Explanation:
800 divided by 50 = 16
Brainly pls
Answer: [tex]t[/tex] = 16
Explanation:
Hey there! I will give the following reason, if you have any questions feel free to ask me in the comments below.
Because a train is traveling at a speed of 50 km/hr and a train needs to travel 800 km, you would need to divide the distance by the speed to find the hours.
Formula: [tex]t[/tex] = [tex]\frac{distance}{speed}[/tex]
The distance would be 800, and the speed would be 50.
[tex]t = \frac{800}{50}[/tex]
Simplify.
[tex]t = 16[/tex]
~I hope this helps you! :)~
PEOPLE PLEASE HELP ASAP!!!-How does Force effect acceleration?
Answer:
If the force is higher then the resitance o fht eobject then force will make object accelerate.
Explanation:
Does that make sense. If you need something else as an answer tell me in the comments and please mark with a heart and brainliest. If you don't mind
We know:
Force =Mass×Accerlation
[tex]∴Accerlation = \dfrac{force}{mass} [/tex]
So by seeing this formula we came to know that accerlation is directly proportional to force and inversely proportional to mass.
So by increase of force acceleration also increases.
How far from the home did Karen and her mother travel during the first hour of the trip?
Answer:
none cuz she was too bus yelling at the cashier at the gas station
Determine the acceleration that an unbalanced force of 28 N gives to a 6.8 kg mass.
Answer:
4.12 m/s^2
Explanation:
unbalanced force means the presence of resultant force (net force)
[tex]net \: force \: = mass \times accleration[/tex]
f = 28N
m = 6.8kg
a = ?
? = 28/6.8
= 4.1176...
approximately = 4.12 m/s^2
Occupants of cars hit from behind, even at low speed, often suffer serious neck injury from whiplash. During a low‑spee rear‑end collision, a person's head suddenly pivots about the base of the neck through a 50∘ angle, a motion that lasts 220 ms.The distance from the base of the neck to the center of the head is typically about 20 cm, and the head normally comprises about 6.0% of body weight.Model the motion of the head as having a uniform speed over the course of its pivot. Compute answers to two significant figures.1. What is the acceleration ????centacent of the head during the collision?2. What force ????F does the neck exert on the head of a 65 kg65 kg person in the collision? Neglect the force of gravity on the head, and report the answer in units of both newtons and pounds.3. Would headrests mounted to the backs of the car seats help protect against whiplash? Why or why not?a. Yes. A headrest applies an upward force on the head, along the direction of the neck, that cancels the downward force applied by the neck.b. Yes. A headrest ensures that both the head and the body experience the same forward force at roughly the same time.c. No. A headrest applies a mostly horizontal force to the head, so does not affect the mostly vertical force applied by the neck during whiplash.d. No. A headrest reduces the angle traversed by the head, not the speed of the head relative to the body, thus it does not affect the force that the neck applies to the head.
Answer:
a) a= 19 m/s2, b ) F = F = 38 N
c) the correct one is B
Explanation:
1) To solve this exercise, let's use the concept of torque, let's start by looking for the mass of the mass of the head, which is 65 of 65 kg
m= 0.06 65 = 3.9 kg
torque is defined
τ = F x R
the bold indicate vectors
τ = F R sin θ
the force is the weight of the head and the distance R = 0.20 m
τ = mg R sin θ
τ = 3.9 9.8 0.2 sin 50
τ = 5.86 N m
Newton's second law expression for rotational motion is
τ = I α
In general, the head is approximated by a sphere, so the moment of foolishness with respect to the base of the neck (turning point) using the parallel axis theorem is
I = I_sphere + m d²
Neck height data is not indicated, so we will assume that it is zero (d = 0)
I = 2/5 m R²
angular and linear acceleration are related
a = α R
α = a / R
let's replace
τ = 2/5 mR² (a / R)
a = 5/2 τ / mR
let's calculate
a = 5/2 5.86 / (3.9 0.2)
a = 18.8 m / s²
a= 19 m/s²
2) as the neck and the head are related, the forces are action and reaction, therefore the neck force is
F = m g
F = 3.9 9.8 = 38.2 N
F = 38 N
3) He asks us about the efficiency of the headrest, after reviewing the different alternatives, the correct one is B
Yes. A headrest ensures that both the head and the body experience the same forward force at approximately the same time.
In a car's suspension system, each wheel is connected to a vertical spring; these springs absorb shocks when the car travels on bumpy roads. In one car, each spring has a spring constant of 4.6 × 10⁴ N/m.
If this 1300 kg car is driven at 23 m/s through the bottom of a circular dip in the road that has a radius of 600 m, by how much do these springs compress compared to when the car is driven on a flat road?
Answer:
6.23 mm
Explanation:
The vertical acceleration at the bottom of the dip (in addition to that required to counter gravity) is ...
a = v²/r = (23 m/s)²/(600 m) = 529/600 m/s²
Then the force on the car (in addition to that required to counter gravity) is ...
F = Ma = (1300 kg)(529/600 m/s²) = 1146 1/6 N
The additional force supplied by each of the 4 springs is 1/4 of this, so the additional spring compression is ...
((1146 1/6 N)/4)/(4.6×10^4 N/m) ≈ 0.00623 m = 6.23 mm
The springs are compressed an additional 6.23 mm to provide the required vertical acceleration.
_____
We have to assume that the path followed by the car's center of mass has a radius of 600 m. We're also assuming that the rotational motion of the car about its center of mass does not require any differential force between front and back springs, as it will be at a constant rate for a constant speed through the dip. And, we assume that the mass of the car is evenly among the four springs (often not the case).
Answer:
Explanation:
Given this 1300 kg car is driven at 23 m/s through a circular dip in the road of radius of 600m,
its centrifugal acceleration = speed^2 / radius
= 23^2 / 600
= 0.8817 m/s^2
The centrifugal force in turn = mass * acceleration
= 1300 * 0.8817
= 1146.17 N
This force is absorbed by suspension springs of the four wheels.
Given spring constant of 4.6 x 10^4 N/m and 4 springs total,
the extra compression = Force / number of springs / spring constant
= 1146.17 / 4 / 4.6 x 10^4
= 0.006229 m
= 6.23 mm
Note that this is the extra compression on springs during drive-through of the dip compared to when the car is driven on a flat road. There is a constant compression on springs due to weight of the car which is the same whether the car is driving through a dip or on a flat road.
A car is traveling with a velocity of 20 M/S and has a weight (mass) of 1000 kg. The car has kinetic energy calculate it
Answer:
200000 joules or 200 kilojoules
Explanation:
Kinetic energy = 1/2m(v^v)
Kinetic energy = 1/2*1000* 20^20
Kinetic energy = 500*400
Kinetic energy = 200000 joules or 200 kilojoules
shannon dropped his ICP textbook. how fast was it going after 3 seconds? how far did it fall? please guys help mee quickly pleaseeee
¡Hola!
For this problem, first, lets recabe information:
v = 0 m/s
t = 3 s
g = 9,82 m/s²
v' = ?
d = ?
First, for calculate the final velocity:
v' = v + g * t
v' = 0 m/s + 9,82 m/s² * 3 s
v' = 29,46 m/s [tex]\leftarrow \boxed{\text{Velocity} }[/tex]
Now, for calculate how far did it fall:
d = v * t + g * t^2 / 2
Like v = 0 m/s, we can simplificate equation:
d = g * t^2 / 2
d = 9,82 m/s² * (3 s)^2 / 2
d = 9,82 m/s² * 9 s² / 2
d = 88,38 m / 2
d = 44.19 m [tex]\leftarrow \boxed{\text{Distance} }[/tex]
¡Buena suerte!
A projectile is fired into the air at an angle of 50° above ground level and hits a target downrange. Neglecting air drag, it will also hit the target if fired at the same speed at an angle of
Answer:
18 m/s
Explanation:
Range of a projectile on level ground is:
R = v₀² sin(2θ) / g
14.3 m = v₀² sin(2×13°) / 9.8 m/s²
v₀ = 17.9 m/s
Rounded to two significant figures, the launch speed was 18 m/s.
If the bullet is launched at an angle of 50 degrees above ground level, the target will be struck. The angle remains the same. The launch angle obtained is 50 degrees.
Given:
The initial shot was fired at an angle of 50 degrees above ground.
The projectile's starting velocity (v) and magnitude of velocity will remain constant if it is shot at the same pace.
Let the angle of the projectile is x,
The horizontal component of velocity can be calculated as follows:
[tex]v(x) = v * cos(x)[/tex]
We can write:
since the horizontal part of velocity remains constant:
[tex]v(x1) = v(x2)[/tex]
[tex]cos(50) = cos(x)[/tex]
[tex]50 = x[/tex]
Therefore, if the projectile is launched at the same speed at a 50° angle above ground level, it will strike the target.
To know more about the projectile:
https://brainly.com/question/13388411
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The correct response is given when the angle is asked a question.
2 physical properties for manganese
A shell is fired from a mortar over level terrain. The firing speed is 59 m/s and the mortar is aimed 70° above the horizontal. Find the range of the shell.
Answer:
228.23m
Explanation:
Vy=59sin70=55.44m/s
x=V0t+1/2at^2
0=55.44t-4.9t^2
t=11.31s
Vx=59cos70=20.18m/s
Range=20.18*11.31=228.23m
PLEASE HELP
What do safety symbols look like? What do they mean? Provide at least three examples.
Answer: Safety symbols have a triangle shape, usually the colors are red, orange, and yellow. On the symbol of an element there can be a line going across diagonal They can have symbols that have a person slipping to let you know if someones mopping you may slip. Others may have one that has fire that lets you know fire may happen. And last but not least others can have deers on them to let you deers are on the street/road. Hope this helps.
Explanation:
A 58.72 kg person holding a steel ball stands motionless on a frozen lake.
The person then throws the ball, which propels the person at 1.05 m/s to the
right and the ball 3.75 m/s to the left. If the initial momentum of the system is
zero, what is the mass of the steel ball?
Answer: 16.44 kg
Explanation:
how does 'g' at a point vary with the distance from the centre of earth?
Answer:
No gravity
Explanation:
because their is not gravity on earth and also close to the sun but not as close as mecury