The graph models the projected populations, in thousands, of two towns after x years. Both towns experience a 1.9% annual growth rate.

Answer:

[tex] 2x \sec^2 (x^2 + 5) [/tex]

Step-by-step explanation:

[tex] f(x) = \tan (x^2 + 5) [/tex]

[tex] \dfrac{d}{dx} \tan u = \sec^2 u \dfrac{d}{dx} u [/tex]

[tex] \dfrac{d}{dx} \tan (x^2 + 5) = \sec^2 (x^2 + 5) \dfrac{d}{dx} (x^2 + 5) [/tex]

[tex] \dfrac{d}{dx} \tan (x^2 + 5) = [\sec^2 (x^2 + 5)]2x [/tex]

[tex] \dfrac{d}{dx} \tan (x^2 + 5) = 2x \sec^2 (x^2 + 5) [/tex]

40.0*10 is the answer

actually it is 400 but u want in decimal so it is 40.0*10

Answer:

40.0*10

Step-by-step explanation:

have a good day!

Answer:

the answer is equal to 10x+15y

Answer:

#1 and # 3 maybe

Soooooooory if this wrong, This is the type of question I would get stuck on... O////O

Answer:

b = 24/5

General Formulas and Concepts:

Pre-Alg

Step-by-step explanation:

Step 1: Define equation

12 = 5/2b

Step 2: Solve for b

Step 3: Check

Plug in b to verify it's a solution.

Answer:

3. 7.2

4. 20

Step-by-step explanation:

Answer:

0.036%

Step-by-step explanation:

Answer:

Step-by-step explanation:

80/100 ⋅ 4.5 = 360% because...

80/100 = 80% ( wait that's not the reason. )

Here, 80/100 = 0.8 ⋅ 4.5 = 3.6 and if you move

the decimal point two times to the left, you get 0.036%

Hope this helps! <3

Answer:

450mL : 1L   =    9 : 20

Step-by-step explanation:

recall that 1L = 1000 mL,

450 mL : 1L  can be expressed as

450mL : 1000 mL   (we can simplify this with the following steps)

450 : 1000     (divide both sides by 10)

45 : 100  (divide both sides by 5)

9 : 20  (answer)

Answer: Slope = 5/4

y-intercept = 2

Step-by-step explanation:

We have the table:

Months, m            Plant height in inches, n

0                           2

2                           4.5

4                            7

6                            9.5

We want a linear relationship to represent this table.

A linear relationship can be written as:

y = a*x + b

where a is the slope and b is the y-axis intercept.

For a line that passes through the points (x1, y1) and (x2, y2), the slope can be written as:

a = (y2 - y1)/(x2 - x1).

In this case we can select any pair of points, for example, i will choose the first two:

(0, 2) and (2, 4.5)

Then the slope is:

a = (4.5 - 2)/(2 - 0) = (2.5/2) = 1.25 = 5/4

Then our line can be written as:

y = (5/4)*x + b

To find the value of b, we can replace the values of any of the points in the equation, for example, i will use the point (0, 2) or x = 0, y = 2.

2 = (5/4)*0 + b

2 = b

Then our equation is:

y = (5/4)*x + 2.

Slope = 5/4

y-intercept = 2

Answer:

d

Step-by-step explanation:

I took the k12 test

Answer:

The two people should stand 40 feet from the center so that they can hear each other whisper

Step-by-step explanation:

From the question

Width of the gallery = 100 feet

Width = 2a

a = Width/2

a = 100/2 = 50 feet

Height of the gallery = b = 30 feet

Hence, the distance is

d² = a² - b²

d = √a² - b²

d = √50² - 30²

d = √2500 - 900

d = √1600

d = 40 feet

Hence, the two people should stand 40 feet from the center so that they can hear each other whisper.

Answer:

Step-by-step explanation:

(B). - 28.7

Answer:

This is not possible. Perpendicular lines are opposite but there are no opposites of 0

Step-by-step explanation:

Answer:

A.

Step-by-step explanation:

Answer:

The answer is the first option.

Step-by-step explanation:

Answer:

The third choice

Step-by-step explanation:

We need to find the slope and y-intercept of the line and then put it into y = mx = b form. To find the slope, pick a point on the line; I will use (-2, 5); count how many units up you need to go to get to the next point on the line, which in this case it would be 3. The count how many to the right or left you would need to go, which is 1 to the left. Moving left means a negative, so it is -1. Your slope fraction would be [tex]\frac{3}{-1}[/tex] , since slope is rise over run. You can sub this fraction in for m in y = mx + b, which will give you a revised equation of y = -3x = b. To find the y intercept, or b, just find the point where the line crosses the y-axis, which is -1. So, the equation is now y = -3x - 1.The correct answer is third choice.

Answer:

55+25h=t

Step-by-step explanation:

Answer:

7.75-10°

Step-by-step explanation:

Answer:

Step-by-step explanation:

Busy Village is how many times the population of Boring Town?

Answer:

x=17, y=9

Step-by-step explanation:

(5x - 38)° = (3x - 4)°

2x = 34

x=17

(5(17)-38))=47

90°+47°+(7y-20)=180°

7y-20=43°

y=9

The value of x is 17 and y is 9.

Following are the properties of parallel lines,

Given:

<1 = 7y -20

<2 = 5x - 38

<3 = 90

exterior angle = 3x -4

Using alternate interior angle

5x - 38 = 3x-4

2x = 34

x=17

So, <2 = (5(17)-38))

<2 =47

Using angle sum property

90°+47°+(7y-20)=180°

7y-20=43°

y=9

Hence, the value of x is 17 and y is 9.

Learn more about parallel lines here:

https://brainly.com/question/16701300

#SPJ5

Answer:

1.325 x 10 -2

Step-by-step explanation:

That is the answer and I know 100% that it is correct

Answer:

x= 24

Step-by-step explanation:

Quotient means divide, increased means add

x/3 + 12 =20

Subtract 12 from each side

x/3 +12-12 = 20-12

x/3=8

Multiply each side by 3

x/3 * 3 =8*3

x= 24

Answer:700 / n, the quotient of 700 and a number. 2w, two times a ... h - 3, three less than a number ... 20 + m, 20 more than a number. x - 12, a number decreased by 12.

Step-by-step explanation:

Answer:

The amount of money Jake had left after his purchase is $10.85

Step-by-step explanation:

The amount of Fruit Chews Jake selected = 1.6 pounds

The amount of Jelly Beans Jake selected = 2.6 pounds

The sales tax = $0.52

The amount of money Jake had to spend = $25

The table of values are;

Price Per Pound     [tex]{}[/tex]                  

Fruit Chews = $4.70

Jelly Beans = $2.35

Chocolate = $3.50

The amount of money Jake had to spend $25

The total amount of the candies Jake bought = 1.6 × $4.70 + 2.6 × $2.35 = $13.63

The total amount Jake spent = The total amount of the candies Jake bought + The sales tax

The total amount Jake spent = $13.63 + $0.52 = $14.15

The amount of money Jake had left after his purchase = The amount of money Jake had to spend - The total amount Jake spent

The amount of money Jake had left after his purchase =  $25 - $14.15 = $10.85

The amount of money Jake had left after his purchase = $10.85.

Answer:

40

Step-by-step explanation:

Answer:

1) Perfect square, 2) Perfect square, 3) Not a perfect square, 4) Perfect square, 5) Perfect square, 6) Not a perfect square, 7) Perfect square, 8) Not a perfect square, 9) Not a perfect square, 10) Not a perfect square.

Step-by-step explanation:

From Algebra we must remember that a trinomial is a perfect square if and only if:

[tex](a+b)^{2} = a^{2}+2\cdot a\cdot b + b^{2}[/tex], [tex]\forall \,a,b\in\mathbb{R}[/tex] (Eq. 1)

Now we proceed to prove each trinomial:

1) [tex]a^{2}+2\cdot a +1[/tex]:

If [tex]a^2 =a^2[/tex] and [tex]b^{2} = 1[/tex], then [tex]a = \pm a[/tex] and [tex]b =\pm 1[/tex]. Therefore, [tex]2\cdot a\cdot b = 2\cdot (\pm a)\cdot (\pm 1) = \pm 2\cdot a[/tex]. In a nutshell, we conclude that this polynomial is a perfect square.

2) [tex]4+4\cdot a +a^{2}[/tex]

If [tex]a^{2} = 4[/tex] and [tex]b^{2} = a^{2}[/tex], then [tex]a = \pm 2[/tex] and [tex]b = \pm a[/tex]. Therefore, [tex]2\cdot a \cdot b = 2\cdot (\pm 2)\cdot (\pm a) = \pm 4\cdot a[/tex]. In a nutshell, we conclude that this polynomial is a perfect square.

3) [tex]a^{2}-3\cdot a +9[/tex]

If [tex]a^{2} = a^{2}[/tex] and [tex]b^{2} = 9[/tex], then [tex]a = \pm a[/tex] and [tex]b = \pm 3[/tex]. Therefore, [tex]2\cdot a \cdot b = 2\cdot (\pm a)\cdot (\pm 3) = \pm 6\cdot a[/tex]. In a nutshell, we conclude that this polynomial is not a perfect square.

4) [tex]4\cdot a^{2}+24\cdot a + 36[/tex]

If [tex]a^{2} = 4\cdot a^{2}[/tex] and [tex]b^{2} = 36[/tex], then [tex]a = \pm 2\cdot a[/tex] and [tex]b = \pm 6[/tex]. Therefore, [tex]2\cdot a \cdot b = 2\cdot (\pm 2\cdot a)\cdot (\pm 6) = 24\cdot a[/tex]. In a nutshell, we conclude that this polynomial is a perfect square.

5) [tex]a^{4}-10\cdot a +25[/tex]

If [tex]a^{2} = a^{4}[/tex] and [tex]b^{2} = 25[/tex], then [tex]a = \pm a^{2}[/tex] and [tex]b = \pm 5[/tex]. Therefore, [tex]2\cdot a \cdot b = 2\cdot (\pm a^{2})\cdot (\pm 5) = \pm 10\cdot a^{2}[/tex]. In a nutshell, we conclude that this polynomial is a perfect square.

6) [tex]25\cdot a^{2}+20\cdot a + 9[/tex]

If [tex]a^{2} = 25\cdot a^{2}[/tex] and [tex]b = 9[/tex], then [tex]a = \pm 5\cdot a[/tex] and [tex]b = \pm 3[/tex]. Therefore, [tex]2\cdot a \cdot b = 2\cdot (\pm 5\cdot a)\cdot (\pm 3) = \pm 30\cdot a[/tex]. In a nutshell, we conclude that this polynomial is not a perfect square.

7) [tex]a^{2}\cdot b^{2}-14\cdot a \cdot b + 49[/tex]

If [tex]a^{2} = a^{2}\cdot b^{2}[/tex] and [tex]b^{2} = 49[/tex], then [tex]a = \pm a\cdot b[/tex] and [tex]b = \pm 7[/tex]. Therefore, [tex]2\cdot a\cdot b = 2\cdot (\pm a\cdot b)\cdot (\pm 7) = \pm 14\cdot a \cdot b[/tex]. In a nutshell, we conclude that this polynomial is a perfect square.

8) [tex]a^{2}-2\cdot a -1[/tex]

If [tex]a^{2} = a^{2}[/tex] and [tex]b^{2} = -1[/tex], then [tex]a = \pm a[/tex] and [tex]b = \pm i[/tex]. Therefore, [tex]2\cdot a \cdot b = \pm 2\cdot a \cdot i[/tex]. In a nutshell, we conclude that this polynomial is not a perfect square.

9) [tex]16\cdot a^{2} + 24\cdot a +36[/tex]

If [tex]a^{2} = 16\cdot a^{2}[/tex] and [tex]b^{2} = \pm 36[/tex], then [tex]a = \pm 4\cdot a[/tex] and [tex]b = \pm 6[/tex]. Therefore, [tex]2\cdot a \cdot b = 2\cdot (\pm 4\cdot a)\cdot (\pm 6) = \pm 48\cdot a[/tex]. In a nutshell, we conclude that this polynomial is not a perfect square.

10) [tex]10+6\cdot a +a^{2}[/tex]

If [tex]a^{2} = 10[/tex] and [tex]b^{2} = a^{2}[/tex], then [tex]a = \pm\sqrt{10}[/tex] and [tex]b = \pm a[/tex]. Therefore, [tex]2\cdot a \cdot b = \pm 2\cdot \sqrt{10}\cdot a[/tex]. In a nutshell, we conclude that this polynomial is not a perfect square.

The initial amount this student is paid is 0 and this can be determined by using the two-point slope form of the line.

Given :

The given table represents the number of hours a student worked and the amount of money the student earned.

The following steps can be used in order to determine the initial amount this student is paid:

Step 1 - The two-point form of the line can be used in order to determine the initial amount this student is paid.

Step 2 - So, the linear equation that represents the given situation is:

[tex]\rm \dfrac{d-50}{h-8}=\dfrac{93.75-50}{15-8}[/tex]

Step 3 - Simplify the above expression.

[tex]\rm \dfrac{d-50}{h-8}=6.25[/tex]

d - 50 = 6.25h - 50

d = 6.25h

Step 4 - Now, substitute the value of (h = 0) in the above expression.

d = 0

Therefore, the correct option is D) There is no base pay.

For more information, refer to the link given below:

https://brainly.com/question/11897796

Answer:

A. X>-7

Step-by-step explanation:

So the equation is

X-5>-12

You add 5 on both sides to get the X by itself. You add it because you have to get rid of the -5 and to get to 0 you would add 5.

Which leaves you with X>-7

Answer:

A.) [tex]x>-7[/tex]

Step-by-step explanation:

Solve this the way you would solve an equation: isolate the variable.

Use inverse operations. Add 5 to both sides:

[tex]x-5+5>-12+5\\\\x>-7[/tex]

Since this can't be simplified further, x is greater than -7.

:Done

Answer: 4,1,2,2

explanation: I did it on edge 2021

Answer:

y(3x + 4y)(x + 8y)

General Formulas and Concepts:

Alg I

Step-by-step explanation:

Step 1: Define expression

3x²y + 28xy² + 32y³

Step 2: Simplify

SOLVING STEPS...

STEP1

FACTOR OUT y FROM THE EXPRESSION

SO ITS

[tex]y \times (3x {}^{2} + 28xy + 32y {}^{2} )[/tex]

STEP2

WRITE 28y AS A SUM

STEP3

FACTOR OUT 3x2 + 24xy

SO IT'S

[tex]y \times (3x \times (x + 8y) + 4xy + 32y {}^{2} )[/tex]

STEP4

FACTOR OUT 4xy + 32y2

SO IT'S

[tex]y \times (3x \times (x + 8y) + 4y \times (x + 8y) \: )[/tex]

STEP5

FACTOR OUT (3x × ( x + 8y ) + 4y × ( x + 8y ) )

SO THE ANSWER IS

[tex]y \times (x + 8y) \times (3x + 4y)[/tex]

GAVE ME THE BRAINLIEST IF MY ANSWER WAS HELPFUL...

Answer:

y=-3x+2

Step-by-step explanation:

Same slope = parallel. You can aso double check this answer by either graphing using the desmos online graphing calculator or by plugging in the point into the equation y = -3(2) + 2 --> y = -6 + 2 --> y = -4, so we are correct.

Answer:

y=-3x+2

Step-by-step explanation:

In this equation the slope is the same as the original equation (-3), but has a different y-intercept meaning that this line is parallel. As for satisfying the requirement that the line is parallel and passes through (2,-4), I plugged the coordinates into the equation y=-3x+b to get  -4=-3(2)+b, and then found what b would have to equal to make the equation true.

(plus I put my answer into a graphing calculator to check my work)

Answer:

a b d

Step-by-step explanation:

bigbrain

The additional information that could be used to prove that ΔABC ≅ ΔPTQ using AAS or ASA are:

1. ∠B ≅ ∠P and BC ≅ PQ

2. ∠A ≅ ∠T and AC = TQ = 3.2cm

4. ∠A ≅ ∠T and BC ≅ PQ

Recall:

We are given:

∠C ≅ ∠Q

To prove that ΔABC ≅ ΔPTQ by ASA, the additional information needed are:

Alternatively, the ASA can be used if the following additional information is given:

Using the AAS Congruence Theorem, the additional information needed would be:

In summary, the additional information that could be used to prove that ΔABC ≅ ΔPTQ using AAS or ASA are:

1. ∠B ≅ ∠P and BC ≅ PQ

2. ∠A ≅ ∠T and AC = TQ = 3.2cm

4. ∠A ≅ ∠T and BC ≅ PQ

Learn more about Congruence Theorem on:

https://brainly.com/question/2102943