Answer:
The equations have one solution at (5, -5).
Step-by-step explanation:
We are given a system of equations:
[tex]\displaystyle{\left \{ {{-2x+5y=-35} \atop {7x+2y=25}} \right.}[/tex]
This system of equations can be solved in three different ways:
Graphing the equations (method used)Substituting values into the equationsEliminating variables from the equationsGraphing the Equations
We need to solve each equation and place it in slope-intercept form first. Slope-intercept form is [tex]\text{y = mx + b}[/tex].
Equation 1 is [tex]-2x+5y = -35[/tex]. We need to isolate y.
[tex]\displaystyle{-2x + 5y = -35}\\\\5y = 2x - 35\\\\\frac{5y}{5} = \frac{2x - 35}{5}\\\\y = \frac{2}{5}x - 7[/tex]
Equation 1 is now [tex]y=\frac{2}{5}x-7[/tex].
Equation 2 also needs y to be isolated.
[tex]\displaystyle{7x+2y=25}\\\\2y=-7x+25\\\\\frac{2y}{2}=\frac{-7x+25}{2}\\\\y = -\frac{7}{2}x + \frac{25}{2}[/tex]
Equation 2 is now [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex].
Now, we can graph both of these using a data table and plotting points on the graph. If the two lines intersect at a point, this is a solution for the system of equations.
The table below has unsolved y-values - we need to insert the value of x and solve for y and input these values in the table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & a \\ \cline{1-2} 1 & b \\ \cline{1-2} 2 & c \\ \cline{1-2} 3 & d \\ \cline{1-2} 4 & e \\ \cline{1-2} 5 & f \\ \cline{1-2} \end{array}[/tex]
[tex]\bullet \ \text{For x = 0,}[/tex]
[tex]\displaystyle{y = \frac{2}{5}(0) - 7}\\\\y = 0 - 7\\\\y = -7[/tex]
[tex]\bullet \ \text{For x = 1,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(1)-7}\\\\y=\frac{2}{5}-7\\\\y = -\frac{33}{5}[/tex]
[tex]\bullet \ \text{For x = 2,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(2)-7}\\\\y = \frac{4}{5}-7\\\\y = -\frac{31}{5}[/tex]
[tex]\bullet \ \text{For x = 3,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(3)-7}\\\\y= \frac{6}{5}-7\\\\y=-\frac{29}{5}[/tex]
[tex]\bullet \ \text{For x = 4,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(4)-7}\\\\y = \frac{8}{5}-7\\\\y=-\frac{27}{5}[/tex]
[tex]\bullet \ \text{For x = 5,}[/tex]
[tex]\displaystyle{y=\frac{2}{5}(5)-7}\\\\y=2-7\\\\y=-5[/tex]
Now, we can place these values in our table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
As we can see in our table, the rate of decrease is [tex]-\frac{2}{5}[/tex]. In case we need to determine more values, we can easily either replace x with a new value in the equation or just subtract [tex]-\frac{2}{5}[/tex] from the previous value.
For Equation 2, we need to use the same process. Equation 2 has been resolved to be [tex]y=-\frac{7}{2}x+\frac{25}{2}[/tex]. Therefore, we just use the same process as before to solve for the values.
[tex]\bullet \ \text{For x = 0,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(0)+\frac{25}{2}}\\\\y = 0 + \frac{25}{2}\\\\y = \frac{25}{2}[/tex]
[tex]\bullet \ \text{For x = 1,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(1)+\frac{25}{2}}\\\\y = -\frac{7}{2} + \frac{25}{2}\\\\y = 9[/tex]
[tex]\bullet \ \text{For x = 2,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(2)+\frac{25}{2}}\\\\y = -7+\frac{25}{2}\\\\y = \frac{11}{2}[/tex]
[tex]\bullet \ \text{For x = 3,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(3)+\frac{25}{2}}\\\\y = -\frac{21}{2}+\frac{25}{2}\\\\y = 2[/tex]
[tex]\bullet \ \text{For x = 4,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(4)+\frac{25}{2}}\\\\y=-14+\frac{25}{2}\\\\y = -\frac{3}{2}[/tex]
[tex]\bullet \ \text{For x = 5,}[/tex]
[tex]\displaystyle{y=-\frac{7}{2}(5)+\frac{25}{2}}\\\\y = -\frac{35}{2}+\frac{25}{2}\\\\y = -5[/tex]
And now, we place these values into the table.
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
When we compare our two tables, we can see that we have one similarity - the points are the same at x = 5.
Equation 1 Equation 2
[tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & -7 \\ \cline{1-2} 1 & -33/5 \\ \cline{1-2} 2 & -31/5 \\ \cline{1-2} 3 & -29/5 \\ \cline{1-2} 4 & -27/5 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex] [tex]\begin{array}{|c|c|} \cline{1-2} \textbf{x} & \textbf{y} \\ \cline{1-2} 0 & 25/2 \\ \cline{1-2} 1 & 9 \\ \cline{1-2} 2 & 11/2 \\ \cline{1-2} 3 & 2 \\ \cline{1-2} 4 & -3/2 \\ \cline{1-2} 5 & -5 \\ \cline{1-2} \end{array}[/tex]
Therefore, using this data, we have one solution at (5, -5).
Solve x2 − 10x = −13.
A) 5 ± 2square root 3
B) 5 ± square root 38
C) 5 ± 2square root 2
D) 5 ± 3square root 2
Answer:
B
Step-by-step explanation:
First, let's rearrange the given equation into something more recognizable. If we add 13 to both sides, we now have the polynomial [tex]x^{2}-10x+13[/tex]. We can now use the quadratic formula to solve.
Remember that the quadratic formula is
[tex]\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}[/tex]
Substitute the numbers from the equation into the formula.
[tex]\frac{-(-10)+/-\sqrt{(-10)^{2}-4(1)(13) } }{2(1)}[/tex]
Simplify:
[tex]\frac{10+/-\sqrt{100-52} }{2}[/tex]
[tex]\frac{10+/-\sqrt{48} }{2}[/tex]
Here, I'm going to assume that there was a mistype in option B because if we divide out the 2 we end up with [tex]5+/-\sqrt{48}[/tex].
Hope this helps!
the picture is the answer
Answer:
4. 3
The answer is the last option, all you do is reduce
Step-by-step explanation:
rise over run = rise/run = 6/2
reduce,
6/2
3/1
3x
Please help I will brainliest!! Really urgent!!
Find the difference
and tell you me how you go it, not just the answer please!❤️
Answer:
1/3x - 1
Step-by-step explanation:
5/6x - 7 -1/2x + 6. - -6 turns it to +6
5/6x - 7 -3/6x + 6. Turn 1/2x to 3/6x to make the denominators the same
5/6x - 3/6x -7 + 6
2/6x -1
1/3x - 1
Can someone help me with this? am i supposed to graph
Answer:
Step-by-step explanation:
1). a(x) = -4x + 7 If x > 1
a(8) = -4(8) + 7
= -32 + 7
= -25
2). a(x) = 2x - x² If -6 < x ≤ 1
a(1) = 2(1) - 1²
= 2 - 1
= 1
3). a(x) = |x - 8| If x ≤ -6
a(-7) = |- 7 - 8|
= |-15|
= 15
4). a(x) = 2x - x² If -6 < x ≤ 1
a(-3) = 2(-3) - (-3)²
= -6 - 9
= -15
5). a(x) = 2x - x² If -6 < x ≤ 1
[tex]a(-\frac{1}{2})=2(-\frac{1}{2})-(-\frac{1}{2})^{2}[/tex]
= - 1 - [tex]\frac{1}{4}[/tex]
= [tex]-\frac{5}{4}[/tex]
6). a(x) = -4x + 7 If x > 1
[tex]a(\frac{9}{4})=-4(\frac{9}{4})+7[/tex]
= -9 + 7
= -2
Daniel received $150 for his birthday this year. this was $10 less than half the amount he received last year. How much money did Daniel receive for his birthday last year?
Answer:
He received $320 last year
Step-by-step explanation:
Answer:
$320
Step-by-step explanation:
2(150 + 10)= x. x=2(160) x=320. SO he actually got 320 dollars for his birthday last year.
what is the correct evaluation of 3x-x+2,when x is equal to -4?
14
-6
6
-14
Answer:
(b) -6
Step-by-step explanation:
=3x-x+2
=3(-4)-(-4)+2
=-12+4+2
=-12+6
=-6
Alexander owes $17.75 to his friend. He borrows $6.50 more from his friend. Which of the following numbers best represents Alexander’s total debt?
Answer:
$24.25
Step-by-step explanation:
$(17.75 + 6.5)
= $24.25
Hope this helped!
Is 16.4 greater than 16
Answer:
yea
Step-by-step explanation:
Yes.
16 could also be written as 16.0, or 16.00 or even 16.00000.
16.4 could also be written as 16.40, or 16.400.
And of course, you know 4 is greater than 0.
This is why 16.4 is greater.
When you add a decimal to a number, it always makes it larger. its like saying 16 and 4 tenths.
A manufacturer of women’s blouses has noticed that 80% of their blouses have no flaws, 15% have one flaw, and 5% have two flaws. If you buy a new blouse from this manufacturer, the expected number of flaws will be:_________
a. 0.15
b. 0.20
c. 0.80
d. 1.00
e. none of the above
Answer:
b
Step-by-step explanation:
80% +15% +5%=100
15/100= 0.15
5/100= 0.05
therfore
0.15 + 0.05 = number of flaws
=0.20
Based on the flaws that the manufacturer notices, we can infer that the expected number of flaws will be 0.25 which is e. none of the above.
The expected number of flaws is a weighted average of the percentages that have flaws:
=∑ (Percentage of flaws x Number of flaws)
The expected number of flaws is therefore:
= (80% x 0) + (15% x 1) + (5% x 2)
= 15% + 10%
= 0.25
In conclusion, you would expected the number of flaws to be 0.25.
Find out more at https://brainly.com/question/13412627.
Addison has a balance of $3,450 on her credit card that has an APR of 18%. She currently pays the minimum monthly payment of $86.25. If Addison wants to pay off her balance in 24 months, determine the monthly payments she would need to make. Choose the following modification with the least cuts to her current expenses that will allow Addison to pay off her balance in 24 months.
Income
WAgES
$2,278.00
EXPENSES
Rent
$950.00
Utilities
$232.45
Food/Clothes
$445.00
Entertainment
$270.00
Car
$200.00
Credit Card
$86.25
Cell Phone
$77.89
Net Income $16.41
a.
Addison can eliminate $73 from Food/Clothes and $100 from Entertainment.
b.
Addison can eliminate $45 from Food/Clothes and $41 from Entertainment.
c.
Addison can eliminate $25 from Food/Clothes and $22 from Entertainment.
d.
The minimum payment is enough to pay off the balance within 24 months.
ANSWER IS B)Addison can eliminate $45 from Food/Clothes and $41 from Entertainment.
Answer: (B) Addison can eliminate $45 from Food/Clothes and $41 from Entertainment.
Based on the information given, Addison should eliminate $45 from the money budget for Food/Clothes ($445.00) and $41 from Entertainment ($270.00).
Given the following data:
Balance = $3,450.APR = 18%.Monthly payment = $86.25.Time = 24 months (2 years).How to calculate monthly payment.Mathematically, the monthly payment for a credit card can be calculated by using this formula:
[tex]M=P(\frac{r}{1-(1+r)^{-nt}} )[/tex]
Where:
P is the principal.r is the interest rate.M is the monthly payment.t is the time.n is the number of times it's compounded.In this scenario, Addison should eliminate $45 from the money budget for Food/Clothes ($445.00) and $41 from Entertainment ($270.00) because they are the least cuts to her current expenses and they would avail her an opportunity to pay off her balance in 24 months (2 years).
Read more on monthly payment here: https://brainly.com/question/2151013
Select the correct answer.
A sphere has a diameter of 24 units. What is its volume in cubic units?
A. 576 cubic units
B. 1,728 cubic units
C. 2,304 cubic units
D 6,912 cubic units
Answer:
c
Step-by-step explanation:
Answer: C.2304
Step-by-step explanation:
volume for a sphere formula: V=4/3πr^3
[tex]V=4/3\pi r^3=4/3*\pi *12^3=7238.23\\7238.23/\pi \\=2304\\[/tex]
2.Marino paid a total of $706 for his accommodation in Seoul, South Korea. He will be spending 7 nights at his hotel.
a) Write an equation to help Marino figure out how much money he was charged in fees.
b) Determine the amount of money he was charged for fees.
Answer:
$4942
Step-by-step explanation:
a.A day accommodation=$706
7 days accommodation=$706x7days
Answer=$4942
b
Is this a function?explain your choice.be specific by describing the domain and range values that may be problematic.
Answer:
yes it is a function
Step-by-step explanation:
solve his problem for X and Y
Answer:
y = 5, 3; x = 171, 155
Step-by-step explanation:
8y - 15 = y^2
y^2-8y+15=0
y^2-3y-5y+15=0
y(y-3)-5(y-3)=0
(y-5)(y-3)=0
y can be 5 or 3.
x = 180 - (8y - 15)
x = 180 - (8(3)-15)
x = 180 - 9
x = 171
OR
x = 180 - (8(5) - 15)
x = 180 - 25
x = 155
6x = 10y - 10
x + y + 7 = 0
What is x and y?
Answer:
x=(-5)
y=(-2)
Step-by-step explanation:
Answer:
(-5, -2)
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDASAlgebra I
Equality PropertiesSolving systems of equations using substitution/eliminationStep-by-step explanation:
Step 1: Define systems
6x = 10y - 10
x + y + 7 = 0
Step 2: Rewrite systems
6x = 10y - 10
y = -x - 7
Step 3: Solve for x
Substitute: 6x = 10(-x - 7) - 10Distribute 10: 6x = -10x - 70 - 10Combine like terms: 6x = -10x - 80Add 10x to both sides: 16x = -80Divide 16 on both sides: x = -5Step 4: Solve for y
Define: x + y + 7 = 0Substitute: -5 + y + 7 = 0Combine like terms: y + 2 = 0Subtract 2 on both sides: y = -2And we have our answer!
10. Which of the following represents a linear function? *
I The area of a square in relation to its side
II The area of a circle in relation to its radius
III The perimeter of a square in relation to its side
IV The circumference of a circle in relation to its diameter
(a) I only
(b) II & III
(c) III & IV
(d) IV only
Substitute u = 26 into u + 34 to find the value of the left-hand side of the equation
Answer:
60
Step-by-step explanation:
The answer is 60 because the equation u = 26 tells us u is 26
So we can plug in 26 into u + 34
It should look like this 26 + 34 and it equals 60
pls mark brainliest
Cleo and her family fished for 3 days and caught 100 fish between them. They caught 12 fish on day 2 and 16 fish on day 3. How many fish did they catch on the first day.
Which equation is correct.
12x + 16 = 100
12x + 16 = 100
x + 12 + 16 = 100
x + 12 + 16 = 100
16x + 12 = 100
Answer:
x + 12 + 16 = 100
72 fishes
Step-by-step explanation:
Given parameters:
Number of days fished = 3days
Number of fishes caught = 100 fishes
Number of fish caught on day 2 = 12fishes
Number of fish caught on day 3 = 16fishes
Unknown:
Number of fish caught on the first day = ?
Solution:
Let the number of fishes caught on the first day = x;
Total number of fishes caught = No of fish on day 1 + No of fish on day 2 + number of fish on day 3
Insert the parameters and solve;
100 = x + 12 + 16
x = 100 - 28 = 72fishes
How do you find the original price of an item, given the tax percent and the final cost ?
Yvette invests $300 each quarter in a fixed-interest mutual fund paying annual
interest of 7% compounded quarterly. How much will her account have in it at
the end of 11 years?
Answer:
Step-by-step explanation:
The formula for calculating the amount after t years is expressed as;
A = P(1+r/n)*nt
P is the Principal (amount invested) = $300
r is the rate = 7% = 0.07
t is the time used to save = 11 years
n is time of compounding = 1/4 (quarterly)
Substitute;
A = 300 (1+0.07/(1/4))^(1/4)(11)
A = 300(1+4(0.07))^2.75
A = 300(1+0.28)^2.75
A = 300(1.28)^2.75
A = 300(1.9716)
A = 591.49
Hence the amount that will be in her account after 11 years is $591.49
Find n and r 10 points
Answer:
i think i can see the picture
Step-by-step explanation:
Select the correct answer.
Select the lightest weight.
1 750 g
I 0.7 kg
7.5 kg
705
g
7.05 kg
Answer:
1 750 g
Step-by-step explanation:
hhhahahahahahahaha
Which probability model would you use to describe the number of damaged printers in a random sample of 4 printers taken from a shipment of 28 printers that contains 3 damaged printers?A) HypergeometricB) BinomialC) UniformD) Poisson
Answer:
The answer is "Option A".
Step-by-step explanation:
The probability function is
[tex]\to P(X) = K_{{C}_{k}} \times \frac{N-K_{{C}_{n-k}}}{N_{C}_{n}}[/tex]
The population size (N)= 28
The number of success in population(K) = 3
The number of draws (n)= 4
Each day billy runs on a treadmill for 5 km and runs in the outdoor track for 6000 m in all how many meters does Billy run each day
Answer:
11000 meters
Step-by-step explanation:
1km=1000m
5km=5000m
5000+6000=11000m
If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?
Answer:
[tex]T_{2} = 200[/tex]
Step-by-step explanation:
Given
Geometry Progression
[tex]T_1 = 500[/tex]
[tex]T_4 = 32[/tex]
Required
Calculate the second term
First, we need to write out the formula to calculate the nth term of a GP
[tex]T_n = ar^{n-1}[/tex]
For first term: Tn = 500 and n = 1
[tex]500 = ar^{1-1}[/tex]
[tex]500 = ar^{0}[/tex]
[tex]500 = a[/tex]
[tex]a = 500[/tex]
For fought term: Tn = 32 and n = 4
[tex]32 = ar^{4-1}[/tex]
[tex]32 = ar^3[/tex]
Substitute 500 for a
[tex]32 = 500 * r^3[/tex]
Make r^3 the subject
[tex]r^3 = \frac{32}{500}[/tex]
[tex]r^3 = 0.064[/tex]
Take cube roots
[tex]\sqrt[3]{r^3} = \sqrt[3]{0.064}[/tex]
[tex]r = \sqrt[3]{0.064}[/tex]
[tex]r = 0.4[/tex]
Using: [tex]T_n = ar^{n-1}[/tex]
[tex]n = 2[/tex] [tex]r = 0.4[/tex] and [tex]a = 500[/tex]
[tex]T_{2} = 500 * 0.4^{2-1}[/tex]
[tex]T_{2} = 500 * 0.4^1[/tex]
[tex]T_{2} = 500 * 0.4[/tex]
[tex]T_{2} = 200[/tex]
Hence, the second term is 200
68. A table top and the floor are a model of parallel planes.
a. True
b. False
Answer:
true
Step-by-step explanation:
True the table top can go on forever without touching the floor.
2. The reciprocal of 4 3/6 is
a. 6/27
b. 6/30
c. 4 6/3
d. 6 3/4
Answer:
6/27
Step-by-step explanation:
[tex]4 \frac{3}{6} \\ \\ = \frac{4 \times 6 + 3}{6} \\ \\ = \frac{24 + 3}{6} \\ \\ 4 \frac{3}{6} = \frac{27}{6} \\ \\ reciprocal \: of \: 4 \frac{3}{6} = \frac{6}{27} [/tex]
Michael pays $30 to enter a state fair, plus $4 for each ride. Which of the following
equations represents his total cost?
A. y = 30x + 4
B. y = 34x
C. y = 4x + 30
D. y = 4x + 34
PLEASE HELPP!!!
Answer:
The required equation is:
[tex]y=4x+30[/tex]
So, Option C is correct option.
Step-by-step explanation:
Entry fee for fair = $30
Cost of one ride = $4
Cost of x rides = $4x
If y represents the total cost the equation will be sum, of entree fee and cost of x rides i.e
[tex]y=4x+30[/tex]
The required equation is:
[tex]y=4x+30[/tex]
So, Option C is correct option.
Can someone please help me and tell me if this is correct or no I’ll give brainliest
Please be honest
Answer: B
Step-by-step explanation: i googled it
How do you do this question?
Answer:
-0.391 < x < 0.391
Step-by-step explanation:
The Maclaurin series for cosine is:
cos(x) = ∑ (-1)ⁿ x²ⁿ / (2n)!
So the next term would be -x⁶/6!. When the absolute value of this is less than the error:
│-x⁶/6!│< 0.000005
x⁶ / 720 < 0.000005
x⁶ < 0.0036
-0.391 < x < 0.391