Segment KJ = 8, JI = x+6 and KI = 2x+8.
8
X + 6
K.
1
J
2x + 8
Find the values below. Be sure to show all your work.
a. Find x. [Respond Here]
b. Find the length of KI. [Respond Here]
Answers
Answer:
a). x = 6
b). Length of KI = 20 units
Step-by-step explanation:
From the picture attached,
a). Length of KI = length of KJ + length of JI
By substituting lengths of the segments given in the picture,
(2x + 8) = 8 + (x + 6)
2x + 8 = x + 14
2x - x = 14 - 8
x = 6
b). Length of KI = (2x + 8)
By substituting x = 6 in the expression,
Length of KI = 2(6) + 8
= 12 + 8
= 20 units
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Answer:
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Anand needs to hire a plumber. He's considering a plumber that charges an initial fee of \$65$65dollar sign, 65 along with an hourly rate of \$28$28dollar sign, 28. The plumber only charges for a whole number of hours. Anand would like to spend no more than \$250$250dollar sign, 250, and he wonders how many hours of work he can afford. Let HHH represent the whole number of hours that the plumber works.
Answers
Answer:
Anand can afford is 6hoursStep-by-step explanation:
Let H represent the whole number of hours that the plumber works.
given that the fixed cost is $65
and the hourly cost is $28
also given that Anand has a total of $250 with him
the total cost can be expressed in terms of the number of hours H as
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we can now solve for H
250-65=28H
185=28H
divide both sides by 28
H=185/28
H=6.60714285714
"The plumber only charges for a whole number of hours."
So the number of hours Anand can afford is 6hours
Answer:
Anand can afford is 6hours
Step-by-step explanation:
Let H represent the whole number of hours that the plumber works.
given that the fixed cost is $65
and the hourly cost is $28
also given that Anand has a total of $250 with him
the total cost can be expressed in terms of the number of hours H as
250=65+28H
we can now solve for H
250-65=28H
185=28H
divide both sides by 28
H=185/28
H=6.60714285714
"The plumber only charges for a whole number of hours."
So the number of hours Anand can afford is 6hours