Satoko has 30 tokens to spend at an arcade. The three lines represent the cost of playing Satoko's three
favorite games for various numbers of times.

Answer:

open the bracket

(4X+)-3X-2-72+X=X

4X+(-3X)-74+X=X

X-74+X=X

2X-74=X

then collect the term

-74=X-2X

-74=-X

divide by negative every side then you get

X=74

Answer:

x = 4

Step-by-step explanation:

Use elimination method.

-----------------

3x + 5y = 10

-(1x + 5y) = -1(2)

-1x -5y = -2

------Simiplify------

2x = 8

x = 4

Answer:

x=-2

Step-by-step explanation:

7x - 4 = -18

+ 4. +4

7x = -14

÷7. ÷7

x=-2

Answer:

Step-by-step explanation:

7x - 4 = -18?

7x - 4 = -18

7x = -18 + 4

7x = -14

x = -14 : 7

x = -2

-----------------

check

7 * (-2) - 4 = -18

-14 - 4 = -18

-18 = -18

the answer is good

Answer:

c is my opinion

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

trust me.

Answer:

how do u want the formula because there is no numbers

Answer:

8

Step-by-step explanation:

whatever was done to y needs to be done to  x.

in this case (y) was 2x so you need to 2x (x) making 4 into 8

Answer:

15360m3

Step-by-step explanation:

a=l*w*h

1.6m*80m*120m

=15360m3

Answer:

Step-by-step explanation:

If the roots of p(x) are a, b, c, then it factors as ...

  p(x) = (x -a)(x -b)(x -c)

and the expanded form is ...

  p(x) = x^3 -(a+b+c)x^2 +(ac +b(a+c))x -abc

The requirement that the coefficients match the roots means we have three equations in three unknowns:

  a = -(a+b+c)

  b = ac +b(a+c)

  c = -abc

The attachment shows the solutions to these equations. The solutions are found by making the substitutions ...

This leaves us with two equations in two unknowns that can be graphed on a Cartesian plane. The graph of the second equation is a circle:

  x(1 -a -y) -ay = 0   ⇒   (x +1)^2 +y^2 = 1

The graph of the first equation is the union of the line y=0 and two hyperbolas. The points of intersection between this graph and the circle are ...

  (x, y) = (-2, 0), (-1, -1), (0, 0)   ⇒   (a, b, c) = (1, -2, 0), (1, -1, -1), (0, 0, 0)

The three polynomials that correspond to these values are shown above and in the attachment.

_____

Additional comment

There is an irrational fourth solution to the requirement that the roots match the coefficients.

Answer:

R=11cm, r=3cm

Step-by-step explanation:

π(R²-r²) = π(121-9) = 112π cm² = 35.63cm².

hope this helps you.

Answer:

5. (-1,-1)

6. (6,-9)

8. (1,2)

9. (-1,0)

Step-by-step explanation:

5. first you add -6 and 6 to cancel out the x and solve for y..once you have your y plug it back into the equation to find x

6. your going to subtract 7 and 8, and then 2 and 2 (this will cancel your ys). solve for x and then plug back in to solve for y.

7. plug -3x+5 into the second equation to find x then plug your x into the first equation to find y

8. same as above but with x then find y

Answer:

70%

Step-by-step explanation:

Therefore, we can conclude that the required percentage is 70% that is 70% of 80 is 56.

Hopes This Helps :)

Answer:

x=-2

Step-by-step explanation:

−8x−10=4x+14

-8x-4x=14+10

-12x=24

[tex]\frac{-12x}{-12} = \frac{24}{-12}[/tex]

x = -2

Answer:

Its answer is 32.33

Step-by-step explanation:

Answer:  The y-intercept is 5.

Step-by-step explanation:

We can write what we know in the form of a slope intercept equation,

y=mx + b,

where m is the slope and b the y-intercept (the value of y when x=0).

We are given the slope:

y = -(2/3)x + b

We need a value of b that forces the line through the point (-3,7).  Enter the point and solve for b:

y = -(2/3)x + b

7 = -(2/3)*(-3) + b  for  (-3,7)

7 = 2 + b

b = 5

The equation becomes y = -(2/3)x + 5

The y-intercept is 5.

See attachment.

Answer:

46.28

Step-by-step explanation:

rectangle = 10×4 = 40 ft²

semicircle = 1/2×3.14×2×2 = 6.28 ft²

area of this figure is 40+6.28 = 46.28 ft²

Answer:

No, they can NEVER make supplementary angles.

Step-by-step explanation:

Two angles are supplementary when they add to 180 degrees. Since two obtuse angles have their angles greater than 90 degrees, they can never be supplementary. Let's take the angles as 91 degrees (the lowest whole obtuse measure). 91 + 91 = 182, which is more than 180.

Therefore, the answer is no.

Answer:

Adding two obtuse angles can never make supplementary angles.

Step-by-step explanation:

An obtuse angle has a measure of greater than 90°, and less than 180°.  

Supplementary angles are two angles whose sum add up to 180°.

We must determine whether adding two obtuse angles can make them supplementary angles through the following example.

Suppose that we have two obtuse angles:

m ∠ 1 = 90.1°

m∠ 2 = 90.1°

Let us add these two obtuse angles together to determine whether their sum is at most 180°.

m ∠ 1 + m ∠ 2 = ?

90.1° + 90.1° = 180.2°

Since their sum is greater than 180°, then it means that they are not supplements.

Adding two obtuse angles will have a sum of greater than 180°, thus making them invalid as supplementary angles.

Answer:

46 bc 250 -20 =230 and 230÷5= 46

Answer:

9.2 ft

Step-by-step explanation:

140 - 9.6 - 10.2*8 - 19.8*2 = 9.2

mark me as brainliest PLEASE

Answer:

An independent system of equations

Answer:

non of them are there any other answers

Step-by-step explanation:

2-5=-3

1/5*1/5=1/25

(-5)(-5)=25

1/2*1/2*1/2*1/2=1/16

(-2)(-2)(-2)(-2)(-2)=-32

This function is neither even nor odd.

We have

f(x) = 5x² + 2x + 1

f(-x) = 5 (-x)² + 2 (-x) + 1 = 5x² - 2x + 1

- f(x) = -5x² - 2x - 1

but neither f(-x) = f(x) nor f(-x) = -f(x).

Answer:

26.2 cm

Step-by-step explanation:

Area = (b1 + b2)/2 * h

401.92 = (x + 14.4)/2 * 19.8

Divide each side by 19.8

20.2989 = (x + 14.4)/2

Multiply each side by 2

40.6 = x + 14.4

Subtract 14.4 from each side

x = 26.2

Answer:

116.82

Step-by-step explanation:

Since your trying to find a missing base

19.8 x 14.4= 285.12

   401.94-285.12=116.82

Hopes This Helps

The common denominator of the given expression is [tex]5y+6.[/tex]

Given expression,

[tex]\dfrac{y+\frac{y-3}{3} }{\frac{5}{9} +\frac{2}{3y} }[/tex].

We have to find the common denominator.

On solving the numerator and denominator of the  given expression,

[tex]\dfrac{y+\frac{y-3}{3} }{\frac{5}{9} +\frac{2}{3y} }= \dfrac{\frac{3y+y-3}{3} }{\frac{5y+6}{9y} }[/tex]

       [tex]= \dfrac{\frac{4y-3}{3} }{\frac{5y+6}{9y} }[/tex]

[tex]= \dfrac{4y-3}{3} \times\dfrac{9y}{5y+6}[/tex]

Or,[tex]\dfrac{y+\frac{y-3}{3} }{\frac{5}{9} +\frac{2}{3y} }= \dfrac{3y(4y-3)}{5y+6}[/tex]

Hence the common denominator of the above expression is given by [tex]5y+6.[/tex]

For more details follow the link:

https://brainly.com/question/357568

Answer:

Not A 3y(y – 3)

Not B y(y – 3)

it is either C 3Y or D 3

x = -8, x = 7. It can also be put into coordinate form based off what the website is looking for.

But solutions to a quadratic equation is essentially where the line crosses the 'x' line.

Answer:

252960

Step-by-step explanation:

3720 x 68 = 252960

hope it's helpful

[tex]3720 \times 68 = 372 \times 10 \times 68 = 372 \times 68 \times 10 = 25296 \times 10 = 252960[/tex]

Their earnings would be the same after 4 hours

Let the number of hours be x, and the weekly earning be y

So, the given parameters are:

Kimi

So, the equation for Kimi's weekly earning is:

[tex]y =9x + 8[/tex]

Jordan

So, the equation for Jordan's weekly earning is:

[tex]y = 7x + 16[/tex]

Equate both equations

[tex]7x + 16 = 9x + 8[/tex]

Collect like terms

[tex]9x - 7x = 16 - 8[/tex]

[tex]2x =8[/tex]

Divide both sides by 2

[tex]x =4[/tex]

Hence, their earnings would be the same after 4 hours

Read more about linear equations at:

https://brainly.com/question/13729904

Answer:

1. parallel

2. perpendicular

Step-by-step explanation:

[tex]\qquad[/tex]_________________________

[tex]\bf Multiplying\:by\:\: \purple{ \dfrac{5+\sqrt{3}}{5+\sqrt{3}}}\\[/tex]

[tex]\qquad[/tex][tex] \longrightarrow \bf \dfrac{1}{5 - 2\sqrt{3} } \times \dfrac{5 + 2\sqrt{3} }{5 + 2\sqrt{3} }\\ [/tex]

[tex]\qquad[/tex][tex]\longrightarrow \sf \dfrac{1(5 + 2\sqrt{3}) }{(5 - 2\sqrt{3})(5 + 2\sqrt{3}) } [/tex]

[tex]\qquad[/tex][tex]\longrightarrow \sf \dfrac{5 + 2\sqrt{3} }{ {(5)}^{2} - (2 \sqrt{3})^{2} } [/tex]

[tex]\qquad[/tex][tex] \longrightarrow \sf \dfrac{5 + 2 \sqrt{3} }{(5 \times 5) - (2 \times 2 \times \sqrt{3} \times \sqrt{3} )} [/tex]

[tex]\qquad[/tex][tex] \longrightarrow \sf \dfrac{5 + 2 \sqrt{3} }{(25) - (12)} [/tex]

[tex]\qquad[/tex][tex] \purple{ \longrightarrow \bf \dfrac{5 + 2 \sqrt{3} }{13} } [/tex]

[tex]\qquad[/tex]_________________________

Answer is 2/(5+√13)

Rationalize the denominator 1/ (5-2√3)